Select group by query

Question

I'm wanting to exclude 3 values from the group by clause within a select statement, how would I achieve this with the following select statement:
SELECT Distinct
ClientName AS Client,
Service AS Serv,
MAX(Stat.DateLastRun) AS DateRun,
(Files1Hour) as '1 Hour',
(Files3Hour) as '3 Hour',
(Files6Hour) as '6 Hour',
(NoMatch) as 'No Match'
FROM Stat
Group by Service,ClientName
Basically I want the rows with distinct Client Names (ClientName) and Services (Service) with the biggest date.

Answer 1

PleASe post DDL, so that people do not have to guess what the keys, constraints, Declarative Referential Integrity, data types, etc. in your schema are. Learn how to follow ISO-11179 data element naming conventions and formatting rules. You have no idea
and are doing display formatting in the database! Temporal data should use ISO-8601 formats. Code should be in Standard SQL as much as possible and not local dialect. 
This is minimal polite behavior on SQL forums. 
We seldom have to use SELECT DISTINCT in a corrected designed schema. Why did you destroy the few valid data element names you had with garbage names?   
>> Basically I want the rows with distinct client names (client_name) and services (service_code) with the biggest [sic: most recent? Dates have no magnitude] date. <<
SELECT client_name, service_code,
       MAX(run_date) OVER (PARTITION BY client_name, service_code)
       AS last_run_date,
-- we have no idea what these columns mean, but they look like a repeated group in violation of 1NF. 
       files_1_hour, files_3_hour, files_6_hour, no_match
FROM Stat;
What to follow the rules are try again? 
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