Select stmts with Having Clause

Hi,
Can some body help me to improve the performance of the below query...
select t.seq_no,t.contract_id,t.date_from from test_plan_tab t
group by t.seq_no,t.contract_id,t.date_from
having (select count(*)
from test_plan_tab p
where p.contract_id = t.contract_id
and p.date_from = t.date_from) > 1
The having clause will reduce the performance of the above query I guess...
Thanks And Best Regards,
/Dinesh...

If Seq_no is unique then try this
SELECT MIN(t.seq_no),contract_id,t.date_from,count(*) from test_plan_tab t
group by t.contract_id,t.date_from
HAVING COUNT(*) > 1or
you can try as fsitja said, but you can omit the group by as the partition has already been done on grouping columns
SELECT seq_no, contract_id, date_from
  FROM (SELECT t.seq_no, t.contract_id, t.date_from, COUNT(*) over(PARTITION BY contract_id, date_from) tot
          FROM test_plan_tab t)
WHERE tot > 1Regards,
Prazy

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    Mani wrote:
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  • Query, Having clause

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    union all
    select 5 tp, 0 sm_1, 0 sm_2, 'b' from dual
    union all
    select 5 tp, 0 sm_1, 0 sm_2, 'c' from dual)
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    2 select 1 tp, 0 sm_1, 1 sm_2, 'a' code from dual
    3 union all
    4 select 1 tp, 0 sm_1, 2 sm_2, 'b' from dual
    5 union all
    6 select 2 tp, 3 sm_1, 0 sm_2, 'c' from dual
    7 union all
    8 select 3 tp, 0 sm_1, 2 sm_2, 'a' from dual
    9 union all
    10 select 4 tp, 0 sm_1, 1 sm_2, 'a' from dual
    11 union all
    12 select 4 tp, 2 sm_1, 3 sm_2,'b' from dual
    13 union all
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    15 union all
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    17 union all
    18 select 5 tp, 0 sm_1, 0 sm_2, 'b' from dual
    19 union all
    20 select 5 tp, 0 sm_1, 0 sm_2, 'c' from dual)
    21 select tp, SUM(sm_1), SUM(sm_2), code from t
    22 group by tp, code
    23 /
    TP SUM(SM_1) SUM(SM_2) CODE
    1 0 1 a
    1 0 2 b
    2 3 0 c
    3 0 2 a
    4 0 1 a
    4 2 3 b
    4 2 3 c
    5 0 0 a
    5 0 0 b
    5 0 0 c
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      3     union all
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    13     union all
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    16 select 5 tp, 0 sm_1, 0 sm_2, 'a' from dual
    17 union all
    18 select 5 tp, 0 sm_1, 0 sm_2, 'b' from dual
    19 union all
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    22  from   (select tp,
    23                 SUM(sm_1) sm_1,
    24                 SUM(sm_2) sm_2,
    25                 code,
    26                 count(*) over (partition by tp) ct_tp,
    27                 count(*) over (partition by tp, SUM(sm_1), SUM(sm_2)) ct,
    28                 row_number() over (partition by tp order by null) rn
    29          from t
    30          group by tp, code)
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    32  and     case when sm_1 = 0 and sm_2 = 0 and ct_tp-ct > 0 then 0 else 1 end = 1;
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             1          0          1 a
             1          0          2 b
             2          3          0 c
             3          0          2 a
             4          0          1 a
             4          2          3 b
             4          2          3 c
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      3     union all
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      5     union all
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    17 union all
    18 select 5 tp, 1 sm_1, 0 sm_2, 'b' from dual
    19 union all
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    22  from   (select tp,
    23                 SUM(sm_1) sm_1,
    24                 SUM(sm_2) sm_2,
    25                 code,
    26                 count(*) over (partition by tp) ct_tp,
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    28                 row_number() over (partition by tp order by null) rn
    29          from t
    30          group by tp, code)
    31  where   decode(ct,ct_tp,rn,1)=1
    32  and     case when sm_1 = 0 and sm_2 = 0 and ct_tp-ct > 0 then 0 else 1 end = 1;
            TP       SM_1       SM_2 C
             1          0          1 a
             1          0          2 b
             2          3          0 c
             3          0          2 a
             4          0          1 a
             4          2          3 b
             4          2          3 c
    5 1 0 b
    5 2 0 c
    9 rows selected.Nicolas.

  • Having clause with Analytic function

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            20      10875
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  • Group by clause and having clause in select

    hi frnds
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  • Use of Where and having clause

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    |   0 | SELECT STATEMENT    |      |     6 |    12 |
    |*  1 |  FILTER             |      |       |       |
    |   2 |   SORT GROUP BY     |      |     6 |    12 |
    |   3 |    TABLE ACCESS FULL| T1   |     6 |    12 |
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  • Dynamic select query with dynamic where condition

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    Thanks,
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    Code***************
    PARAMETERS: p_tabnam      TYPE tabname,
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    * Creation of the "where" clause
    APPEND p_where1 TO lt_where.
    * Creation of the "having" clause
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    * THE dynamic select
    SELECT          (lt_sel_list)
           FROM     (p_tabnam)
           INTO CORRESPONDING FIELDS OF TABLE <lt_outtab>.
    *       WHERE    (lt_where).

    Hi Sanket,
    The above given logic of mine works for you, put the code in the If condition and try-
    just like below:
    IF NOT P_EBELN IS INITIAL.
    lt_where = '& = ''&'' '.
    REPLACE '&' WITH p_ebeln INTO lt_where.
    REPLACE '&' WITH field_value INTO lt_where.
    SELECT (lt_sel_list) INTO CORRESPONDING FIELDS OF TABLE <lt_outtab>
    FROM (p_tabnam)
    WHERE (lt_where).
    ENDIF.
    thanks\
    Mahesh

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