Query, Having clause

Question

I have a test data, like this
with t as (
select 1 tp, 0 sm_1, 1 sm_2, 'a' code from dual
union all
select 1 tp, 0 sm_1, 2 sm_2, 'b' from dual
union all
select 2 tp, 3 sm_1, 0 sm_2, 'c' from dual
union all
select 3 tp, 0 sm_1, 2 sm_2, 'a' from dual
union all
select 4 tp, 0 sm_1, 1 sm_2, 'a' from dual
union all
select 4 tp, 2 sm_1, 3 sm_2,'b' from dual
union all
select 4 tp, 2 sm_1, 3 sm_2, 'c' from dual
union all
select 5 tp, 0 sm_1, 0 sm_2, 'a' from dual
union all
select 5 tp, 0 sm_1, 0 sm_2, 'b' from dual
union all
select 5 tp, 0 sm_1, 0 sm_2, 'c' from dual)
SQL> with t as (
2 select 1 tp, 0 sm_1, 1 sm_2, 'a' code from dual
3 union all
4 select 1 tp, 0 sm_1, 2 sm_2, 'b' from dual
5 union all
6 select 2 tp, 3 sm_1, 0 sm_2, 'c' from dual
7 union all
8 select 3 tp, 0 sm_1, 2 sm_2, 'a' from dual
9 union all
10 select 4 tp, 0 sm_1, 1 sm_2, 'a' from dual
11 union all
12 select 4 tp, 2 sm_1, 3 sm_2,'b' from dual
13 union all
14 select 4 tp, 2 sm_1, 3 sm_2, 'c' from dual
15 union all
16 select 5 tp, 0 sm_1, 0 sm_2, 'a' from dual
17 union all
18 select 5 tp, 0 sm_1, 0 sm_2, 'b' from dual
19 union all
20 select 5 tp, 0 sm_1, 0 sm_2, 'c' from dual)
21 select tp, SUM(sm_1), SUM(sm_2), code from t
22 group by tp, code
23 /
TP SUM(SM_1) SUM(SM_2) CODE
1 0 1 a
1 0 2 b
2 3 0 c
3 0 2 a
4 0 1 a
4 2 3 b
4 2 3 c
5 0 0 a
5 0 0 b
5 0 0 c
10 rows selected
SQL>
And I want to get this result
TP SUM(SM_1) SUM(SM_2) CODE
1 0 1 a
1 0 2 b
2 3 0 c
3 0 2 a
4 0 1 a
4 2 3 b
4 2 3 c
5 0 0 a
E.g. if SM_1 = SM_2(all of the rows) In group of tp, then return random rows with tp = 5, if
5 0 0 c
5 1 2 a
5 3 1 b
then return
5 1 2 a
5 3 1 b
And I don't undersatnd how it's do with Having Clause.
Thank you!

Answer 1

SQL> with t as (
  2     select 1 tp, 0 sm_1, 1 sm_2, 'a' code from dual
  3     union all
  4     select 1 tp, 0 sm_1, 2 sm_2, 'b' from dual
  5     union all
  6     select 2 tp, 3 sm_1, 0 sm_2, 'c' from dual
  7     union all
  8     select 3 tp, 0 sm_1, 2 sm_2, 'a' from dual
  9     union all
10     select 4 tp, 0 sm_1, 1 sm_2, 'a' from dual
11     union all
12     select 4 tp, 2 sm_1, 3 sm_2,'b' from dual
13     union all
14     select 4 tp, 2 sm_1, 3 sm_2, 'c' from dual
15     union all
16 select 5 tp, 0 sm_1, 0 sm_2, 'a' from dual
17 union all
18 select 5 tp, 0 sm_1, 0 sm_2, 'b' from dual
19 union all
20 select 5 tp, 0 sm_1, 0 sm_2, 'c' from dual)
21  select tp, sm_1, sm_2, code
22  from   (select tp,
23                 SUM(sm_1) sm_1,
24                 SUM(sm_2) sm_2,
25                 code,
26                 count(*) over (partition by tp) ct_tp,
27                 count(*) over (partition by tp, SUM(sm_1), SUM(sm_2)) ct,
28                 row_number() over (partition by tp order by null) rn
29          from t
30          group by tp, code)
31  where   decode(ct,ct_tp,rn,1)=1
32  and     case when sm_1 = 0 and sm_2 = 0 and ct_tp-ct > 0 then 0 else 1 end = 1;
        TP       SM_1       SM_2 C
         1          0          1 a
         1          0          2 b
         2          3          0 c
         3          0          2 a
         4          0          1 a
         4          2          3 b
         4          2          3 c
5 0 0 a
8 rows selected.
SQL> with t as (
  2     select 1 tp, 0 sm_1, 1 sm_2, 'a' code from dual
  3     union all
  4     select 1 tp, 0 sm_1, 2 sm_2, 'b' from dual
  5     union all
  6     select 2 tp, 3 sm_1, 0 sm_2, 'c' from dual
  7     union all
  8     select 3 tp, 0 sm_1, 2 sm_2, 'a' from dual
  9     union all
10     select 4 tp, 0 sm_1, 1 sm_2, 'a' from dual
11     union all
12     select 4 tp, 2 sm_1, 3 sm_2,'b' from dual
13     union all
14     select 4 tp, 2 sm_1, 3 sm_2, 'c' from dual
15     union all
16 select 5 tp, 0 sm_1, 0 sm_2, 'a' from dual
17 union all
18 select 5 tp, 1 sm_1, 0 sm_2, 'b' from dual
19 union all
20 select 5 tp, 2 sm_1, 0 sm_2, 'c' from dual)
21  select tp, sm_1, sm_2, code
22  from   (select tp,
23                 SUM(sm_1) sm_1,
24                 SUM(sm_2) sm_2,
25                 code,
26                 count(*) over (partition by tp) ct_tp,
27                 count(*) over (partition by tp, SUM(sm_1), SUM(sm_2)) ct,
28                 row_number() over (partition by tp order by null) rn
29          from t
30          group by tp, code)
31  where   decode(ct,ct_tp,rn,1)=1
32  and     case when sm_1 = 0 and sm_2 = 0 and ct_tp-ct > 0 then 0 else 1 end = 1;
        TP       SM_1       SM_2 C
         1          0          1 a
         1          0          2 b
         2          3          0 c
         3          0          2 a
         4          0          1 a
         4          2          3 b
         4          2          3 c
5 1 0 b
5 2 0 c
9 rows selected.Nicolas.