Semaphore release error

I am making my first attempt at using semaphores,and am getting error 1111 when I go to release the semaphore.  I have read several posts on this error, but saw none that seem to offer a solution.  As you can see, I created a semaphore with a size of 1, and I have wired in a -1 to the timeout of the acquire semaphore.  How did the release get executed without the semaphore being acquired?
Jim
LV 2013
Attachments:
Create.png ‏2 KB
SemaphoreError.png ‏50 KB

Hi Ravens Fan,
My code is a bit too large to upload.  I have 2 parallel loops.  The top loop (next to the obtain semaphore reference) is my event structure.  The timeout event checks the status of my hardware (temperature, pressure etc.) to protect the system when idling.  The lower "main loop" is where all of the production sequence is.  As both loops need to talk to the same modules, I added the semaphore.  I thought that with a semaphore of size 1 I could avoid this problem.
Jim
LV 2013

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