Setting order of sorting through JDBC

Hi there, could somebody please advice - we need to change order of sorting in Oracle 10g. We are using JDBC to connect to a database, and it is possible to have different language in the database rather than on the client computer. We found setting environment variable for language (for Unix - 'LANG') solves the problem, but we can't set this variable within our Java application, so we need some way to sspecify order of sorting through JDBC driver or soemthing like that.
We tried to create proxy JDBC driver and invoke "ALTER SESSION" after connection established, but that doesn't work for us.
Thanks in advance.

set NLS_LANG and NLS_SORT on the clientSorry, you mean do something from outside Java application? The thing we are not allowed to set some environment variables or do something else, we can only do something with JDBC driver I guess, or probably something from our Java application.

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    Dear All,
    I am quite new to Apple and just a learner on Apple-scripts. Its been quite a task to learn.. I would require some help on a few things..
    The script will eventually use numbers to send email and get the user inputs and any yet to reach there..
    After going through lots of scripts to sort through the address book and make a clean address book, i found they are quite slow in processing takes about 20~30 Minutes to get through 2000 Contacts..
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    repeat with j from 1 to count of Dup_email
    set tempdata to item j of Dup_email
    if onlyDupEList does not contain {tempdata} then add tempdata to group theGroupEmail
    end repeat
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    global MsgTitle
    on run
    set MsgTitle to "Search for Duplicates in Address Book Contacts"
    display dialog ¬
    "This Script takes a while to finish" & return & "maybe 10 min or More..." & return & "Depending on the Address Book Contacts." & return & return & "Hence Allow it to run for the while" with title MsgTitle ¬
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    end if
    if rtnValue is "Contact Name" then
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    save
    end if
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    repeat with i from 1 to number of items in the_names
    set theName to item i of the_names
    -- return theName
    if theName is not in biglist then
    copy theName to end of biglist
    else
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    repeat with i from 1 to number of items in counter
    set this_item to item i of counter
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    add this_item to group theGroup
    end repeat
    -- return counter as string
    end if
    end if
    -- captures the Contacts without Name ---
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    repeat with i from 1 to number of items in counterList
    set this_item to item i of counterList
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    add this_item to group theGroupNoName
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    end repeat
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    set Last_Name to last name of person i as string
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    -- display dialog first_name & " : " & Last_Name
    set end of NoNameList to (id of person i)
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    -- if (name of groups of testdata does not contain theGroupNoEmail) then
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    "This Script Finished Processing Address Book Contacts the Duplicates are in the group" with title MsgTitle ¬
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    giving up after 5
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    set theGroupNoEmail to "Only Phone Numbers"
    set thegroupNoPhone to "Only Email Id's"
    set theGroupNoData to "No Email or Phone"
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    set ListofPhones to value of phone of people -- the_phones
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    -- return ListEmail_Dup
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    set thePhones to item i of ListofPhones
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    repeat with j from 1 to count of thePhones
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    end if
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    -- return ListPhone_Dup
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    set dataEmailUniq to item 1 of tempdata
    set dataPersonUniq to item 2 of tempdata
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    set end of Dup_email to dataPersonUniq
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    set tempdata to item j of ListPhone_Uniq
    set dataPhoneUniq to item 1 of tempdata
    set dataPersonUniq to item 2 of tempdata
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    add testdata to group theGroup
    set testdata to person id dataPersonUniq
    add testdata to group theGroup
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    end if*)
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    set tempdata2 to item i of No_PhoneList
    if tempdata1 is equal to tempdata2 then
    set flagE to true
    exit repeat
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    giving up after 5
    end tell
    end Get_dup
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    Hello Srikanth Kamath,
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    main()
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    script o
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    property xx : {1, 2, 3, 4, 5} -- list of parents
    property yy : {{"g", "h"}, {"a", "b"}, {"b", "e", "f"}, {"e"}, {"c", "d"}} -- list of children per parent
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    property pp : {} -- list of children tagged by parent; i.e, lits of {child, parent}
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    property rr : {}
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    set x to my xx's item i
    set y to my yy's item i
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    set end of my pp to {p's contents, x}
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    end repeat
    --return pp -- {{"g", 1}, {"h", 1}, {"a", 2}, {"b", 2}, {"b", 3}, {"e", 3}, {"f", 3}, {"e", 4}, {"c", 5}, {"d", 5}}
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    property xx : aa -- to be sorted in place
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    property yy : {} -- list of children per parent; given later
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    (* omitted (same as the previous) *)
    -- (2) sort tagged list by child as key
    (* omitted (same as the previous) *)
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    (* omitted (same as the previous) *)
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    Good luck,
    Hiroto
    Message was edited by: Hiroto

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