Simple code, but confusing

Question

class C{
static int f1(int i) {
System.out.print(i + ",");
return 0;
public static void main (String[] args) {
int i = 0;
i = i++ + f1(i);
System.out.print(i);
}}When the above code compile and run, it give 0,1 (I am confused how?)
when it pass the value its passing as 1 then the value should remain same when it returns zero.
and it should be like i = 1 + 0;
As per my idea it should give 1,1
Can any one explain clearly how it works here ?

Answer 1

PrasannA@java wrote:
Hi all, thanks for the post
Finally I got it what actually happening.
If some one still not clear, can check the below link which explains in detail.
[http://www.coderanch.com/t/244938/Programmer-Certification-SCJP/post-increment-confusion]
That other thread doesn't explain much; the expression to be evaluated can be written as A+B where:
A: i++
B: f(i)
Java evaluates this expression from left to right so,
A: i++ has the value 0 while i has the value 1
B: f(i) method f will be called with the value 1 (see A)
B1: in method f the value of i is printed and 0 is returned
B2: so the value of sub-expression B is 0
Therefore the value of the entire expression is 0+0 == 0 which is printed next.
Therefore the entire output will be 1,0
kind regards,
Jos