Simple sql stetment with 2 SUM - wrong result :-(

Hi guys,
here's a simple question that drives me crazy.
when I do this,
SELECT SUM(CSV_net.cur_amount) AS net_Accumulated
from csv_net_production as csv_net
where ID='5530500'
GROUP BY ID I get: 35188 //this is the right answer.
but when I'm doing this:
SELECT SUM(CSV_net.cur_amount) AS net_Accumulated, SUM(CSV.cur_amount) AS accumulated
from csv_net_production AS csv_net, csv_production AS CSV
where csv.ID='5530500'
AND csv_net.ID=csv.ID
GROUP BY csv.IDI get:
598196 607476 //wrong anser.
can anyone advise why?
thanks

thanks DrClap
ok, I can see that 17*35188=527820
but how can I correct the statement and have the right results ??

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A very strange problem that can result in wrong financial calculations and big mistakes...
If we have SUM function for some range of cells and one of them is treated as text string (I mean it's number in fact but Number is sure it's text string). than SUM function calulates ALL cells except this sell silently without errors and results in wrong result.
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I think anybody working with financial or other important data can imagine how dangerous this SUM behaviour is.... I encountered several times that when importing data from Excel or by other ways numbers are imported as text strings. So if I have a lot of cells I'm not sure if all those cells are correctly styled or some of them for some unknown reason is treated as text string.
In Microsoft Excel there is a very right solution. In MS Excel if any cell in the SUM is wrong format the SUM function simply provides error as a result. But in Numbers SUM doesn't tell us about error, it simply provides us with a wrong result!
With formal logic the way SUM works in Numbers is total idiotism. If I ask to SUM B1:B5 than I definitely ask to sum ALL 5 cells, not 4, not 3, not 6 but 5 definite cells. If Numbers can't sum those exactly those 5 cells the only answer of the function should be ERROR.
But Apple Numbers answers me some result of summing those cells that it's able to sum. Apple Numbers SUM function is not confused that I asked for SUM of 5 (not 4 or 3) cells and I expect to have this sum as a result.
In fact Apple uses the right logic when we use another formula. If we use =B1B2+B3+B4B5 and any cell contains text string that we'll have error result the sam as in Microsoft Excel. So in this example Numbers behaves correctly.
So why SUM (B1:B5) can provide totally different result as =B1B2+B3+B4B5?

alexb2 wrote:
So when I set format for my number as my local currency it's displayed as 123 XXX (XXX is my currency but it's not in latin). I see it's not only displayed but also stored as 123 XXX. That's different from Excel that stores only numbers in cells and shows number with prefix or suffix - Numbers storex number with prefix or suffix.
No, you get this behavior because the original sheet is displaying values as currencies. I assumes that the import process pass it as a string because he doesn't recognize it as a currency value. As far as I know, Numbers stores the currency entries as a pure number and an indicator of the used currency.
Here is an example.
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<sf:cell-style-ref sfa:IDREF="SFTCellStyle-46"/>
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<sf:SFTCellStylePropertyFormatType>
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Of course, if the original currency string is not recognized, it can't be described as such a feature and the value is treated as a simple string.
So may be at some moment my 123 XXX is treated like string value.
Yes, find and replace is a nice tool when importing data - thanks for the tip. the last problem is with already Numbers files that were imported not today (or even createde as Numbers file) where some cell becomes string value after some editing.
Here again, if you edit a currency string and replace it to a not recognized one, the result will be logically a string.
There is an other way to give this result:
copy a value from a cell formatted as XAM currency (just an example)
paste it in a cell whose format is currency Euro (once again it's just an example).
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The culprit is not the program, it's the user.
I had several times this situation and last time I found error only because I have my budget in 2 programs - in Numbers and in another special budgeting program. As each program has advantages I have in fact 2 instances of the same budget.
And when I changed some string in Numbers and another program I noticed the sum is different. I was sure it's another program somewhere buggy but noticed than Numbers simply ignores one of the budget strings and sums without it... In fact it was even not the string I changed, I remember I changed the buggy string about a week ago but I haven't compared budgets that time so my budget had a mistake for some time till I noticed it. If I used only Numbers without copy of budget in another program may be even today I won't notice the mistake.
The same situation happened not once.
I think that the choice made by Apple for SUM() is correct. You feel that it is wrong. It's useless to debate more, we will not change the behavior of the function.
I try to give a workaround.
The neater one is to add columns as I described in my first response.
The given formula will clearly flag cells which aren't containing numerical values. If you move the SUM from the original range to the new one, the oddities will be flagged automatically.
Here is an alternate workaround:
The currency is XAM.
In B4 I introduced a typo so the value is no longer a numerical one.
Given that, the sum in the footer doesn't count the 34 (which is the normal behavior).
In column C1 I entered =1*B
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Looking at this footer will flag columns where a value may be "wrong" so, it will be necessary (but easy) to scan the column's content to find the red triangle(s).
Yvan KOENIG (from FRANCE lundi 13 octobre 2008 13:27:40)

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Hi,
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SQL>
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RESOURCE_NAME
RESOURCE LIMIT
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COMPOSITE_LIMIT
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SESSIONS_PER_USER
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KERNEL     DEFAULT
CTRU
CPU_PER_CALL
KERNEL     DEFAULT
CTRU
LOGICAL_READS_PER_SESSION    KERNEL     DEFAULT
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KERNEL     DEFAULT
CTRU
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CTRU
CONNECT_TIME
KERNEL     DEFAULT
CTRU
PRIVATE_SGA
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CTRU
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CTRU
PASSWORD_LIFE_TIME
PASSWORD 180
CTRU
PASSWORD_REUSE_TIME
PASSWORD DEFAULT
CTRU
PASSWORD_REUSE_MAX
PASSWORD 5
CTRU
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CTRU
PASSWORD_LOCK_TIME
PASSWORD .002
CTRU
PASSWORD_GRACE_TIME
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Rem
Rem $Header: utlpwdmg.sql 02-aug-2006.08:18:05 asurpur Exp $
Rem
Rem utlpwdmg.sql
Rem
Rem Copyright (c) 2006, Oracle. All rights reserved.
Rem
Rem    NAME
Rem      utlpwdmg.sql - script for Default Password Resource Limits
Rem
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Rem
Rem    MODIFIED   (MM/DD/YY)
Rem    suren       05/09/13 - customise for NIHI use
Rem    asurpur     05/30/06 - fix - 5246666 beef up password complexity check
Rem    nireland    08/31/00 - Improve check for username=password. #1390553
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Rem    asurpur     12/12/96 - Changing the name of password_verify_function
Rem    asurpur     05/30/96 - New script for default password management
Rem    asurpur     05/30/96 - Created
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      i_char := to_char(i);
      if NLS_LOWER(username)|| i_char = NLS_LOWER(password) THEN
        raise_application_error(-20005, 'Password same as or similar to user name ');
      END IF;
    END LOOP;
   -- Check if the password contains at least one letter, one digit
   -- 1. Check for the digit
   isdigit:=FALSE;
   m := length(password);
   FOR i IN 1..10 LOOP
      FOR j IN 1..m LOOP
         IF substr(password,j,1) = substr(digitarray,i,1) THEN
            isdigit:=TRUE;
             GOTO findchar;
         END IF;
      END LOOP;
   END LOOP;
   IF isdigit = FALSE THEN
      raise_application_error(-20008, 'Password must contain at least one digit, one character');
   END IF;
   -- 2. Check for the character
   <<findchar>>
   ischar:=FALSE;
   FOR i IN 1..length(chararray) LOOP
      FOR j IN 1..m LOOP
         IF substr(password,j,1) = substr(chararray,i,1) THEN
            ischar:=TRUE;
             GOTO endsearch;
         END IF;
      END LOOP;
   END LOOP;
   IF ischar = FALSE THEN
      raise_application_error(-20009, 'Password must contain at least one digit, and one character');
   END IF;
   <<endsearch>>
   -- Check if the password differs from the previous password by at least
   -- 3 letters
   IF old_password IS NOT NULL THEN
     differ := length(old_password) - length(password);
     differ := abs(differ);
     IF differ < 3 THEN
       IF length(password) < length(old_password) THEN
         m := length(password);
       ELSE
         m := length(old_password);
       END IF;
       FOR i IN 1..m LOOP
         IF substr(password,i,1) != substr(old_password,i,1) THEN
           differ := differ + 1;
         END IF;
       END LOOP;
       IF differ < 3 THEN
         raise_application_error(-20011, 'Password should differ from the old password by at least 3 characters');
       END IF;
     END IF;
   END IF;
   -- Everything is fine; return TRUE ;
   RETURN(TRUE);
END;
alter profile ctru limit password_verify_function verify_function_11g;
alter profile default limit password_verify_function verify_function_11g;
alter profile web_and_it limit password_verify_function verify_function_11g;

okay,... I just saw another website which shows I should put in the 'replace <oldpwd>' clause in.
This works in SQL Developer:     alter user sutemp identified by carport999 replace garage999;
So why does the 'password' command fail?     (Developers: it would also be helpful to have the ORA- error displayed as opposed to 'Failed to change password')

Wrong results after upgrading 10g database to 11.2.0.2.6

Hi,
Do anyone know, why the following query results are different?
Not Working query:
sql1:
select col1 from tab1
where col1 = (select '123' from dual)
Working query:
sql2:
select col1 from tab1
where col1 = '123';
Both the sql1 and sql2 are returning same reseults in 10g database , but not in 11g.

Pl post OS details along with sample outputs and explain plans from the the sql1 statement from the two databases. These MOS Docs may help also
Things to Consider Before Upgrading to 11.2.0.2 to Avoid Poor Performance or Wrong Results [ID 1320966.1]
Wrong Results on 11.2.0.2 with Function-Based Index and OR Expansion [ID 1264550.1]
Wrong Results/No Rows for Sql Involving Functions in 11.2.0.2. [ID 1380679.1]
HTH
Srini

Simple sql stetment with 2 SUM - wrong result :-(

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