Socket with Python

Question

Hi guys, I'm trying to make a socket connection between Flash and Python but, I'm getting a Security Error with policy file.
Tried this:
Python:
import socket
serverSocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
serverSocket.bind(('', 2020))
serverSocket.listen(1)
conn, addr = serverSocket.accept()
while True:
    data = conn.recv(1024)
    if not data: break
    if "<policy-file-request/>\0" in data:
        conn.send("""<?xml version="1.0"?><cross-domain-policy><allow-access-from domain="*" to-ports="*"/></cross-domain-policy>""")
    conn.send(data)
Flash:
Security.loadPolicyFile("xmlsocket://127.0.0.1:2020");
It isn't working, someone can help me?!

Answer 1

To add to Mike's answer, the only caveat is that the server needs an appropriate clientaccesspolicy.xml file at the root level (http://yourserver/clientaccesspolicy.xml), or a completely open crossdomain.xml file, for the editor and built apps to be able to communicate with it. There's a help topic which explains this in the context of LV web services, but it's true for Web UI Builder to be able to communicate with arbitrary web servers also.
Since it sounds like you control all the web servers in question, it shouldn't be too difficult to get this file in place, though.