[Solved] bash diff util for directories needed

Question

Hi there
I have two dirs with nearly the same content.
Lets call them A and B.
A contains some files which are not in B, I want to a list of these files. I do not care about files existing in both dirs which have not the same content. It's only about the files existing or not.
My first thought was something like that
$ find A > contentOfA
$ find B > contentOfB
$ diff contentOfA contentOfB
but here I also get files which are in B but not in A.
Is there an easier way to do this?
Regards,
Keen
Last edited by keen90 (2011-09-25 15:18:44)

Answer 1

Use 'comm' instead of diff - 'man comm'.
comm -23 contentOfA contentOfB
should do.
You can use diff like this
[karol@black ~]$ tree
├── A
│   ├── a
│   ├── b
│   ├── c
│   └── d
└── B
├── a
├── b
├── e
└── f
2 directories, 10 files
[karol@black ~]$ diff A B
Only in A: c
Only in A: d
Only in B: e
Only in B: f
Last edited by karol (2011-09-25 14:38:21)