[SOLVED] problem using variable in "for do" loop statement

Question

As 'm fairly new to scripting in linux there are still many things I don't know about the regular syntax. So I've made a script where in a variable $nb I retain the number of lines from the result of a series of commands. I have to use a variable as the number of lines from the output is not the same all the time.
To finish my script I need to use a for loop something like this
for i in {1..$nb}
do
echo "bla bla bla $i"
done
the thing is if $nb, for example, has the value 29 it outputs
bla bla bla {1..29}
without doing any loop.
So how can I use a variable, to define the edge of an interval in a for statement ?
Last edited by I'mGeorge (2011-06-18 16:19:16)

Answer 1

The sanctioned method in Bash is using a C style for loop:
for ((i=0; i<nb;i++)); do
done
Because brace expansion is performed before parameter expansion, a range like {1..$nb} will fail.