Some hints required

Hi,
We have Solaris 8 with Forte 6 update 2
Don't tell its out of life before i complete ;-)
We are planning to move to Sun Studio 10.
We use third party softwares like Orbix, Ilog, Roguewave, Xerces, to name the main ones.
The machine specifications are
SunOS sunfirev240 5.8 Generic_108528-22 sun4u sparc SUNW,Sun-Fire-V240
Any help regarding this rollover?
Any specific problems that we might face?
Thanks

I'm glad to hear you are upgrading to a current compiler. :-)
In practice, we find that some third-party software vendors do things in their code or build processes that don't follow the rules for using Sun compilers. Third-party code sometimes contains hacks that are not supported by Sun and don't work on all compiler releases. We work with vendors directly to help them get their code working properly.
Apart from that, later compilers do a better job of finding errors in code that earlier compilers missed.
A good first step is to ask the various 3rd-party vendors whether they support Sun Studio 10, and if you need to upgrade their software to use Studio 10.
Once you resolve the third-party issues (if any) I suggest just installing the new compiler and rebuilding everything.

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Hi David,
Thanks, I hadn't looked at the note.
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Some rows requires Link&some don't require link in LinkToAction tablecolumn

Hi,
I code in WebDynpro for java.
I have a column in a table which is a LinkToAction.
Only for specific values which i get to this column, i require link and for others i do not want a link to appear in this column in that particular row.
For example, i query a RFC and get values for this LinkToAction column. If values i got from RFC is "Seats Available", i require a link in this column in that row.
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Thanks,
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Hi Bhuvana,
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Pls give some hints on this algurithum

in a 4x4 chess grids, so 16 squares
i have four pieces person, wumpus , pit, gold
person is player in chess.you muss move it.
person would fall in pit, person would grab gold
person would be eaten by wumpus,
so i must radomly inintialize proper positions for
4 pieces.and also. other pieces couldnot encircle
person, could still leave a space for person to
move.
please any of you have good algurithum of it?
or give some hints?
thanks in advance

OK, here's a basic methodology from the vaults of my brain:
__0 __1 __2 __3
__4 __5 __6 __7
__8 __9 _10 _11
_12 _13 _14 _15
Given four squares, numbered as above, you need to randomly place three items
(wumpus, pit, gold), then place the person so that they are able to move,
correct? I suppose that the person should be able to reach gold, pit, and
wumpus?
Consider a slightly larger square:
- X X X X -
- X X X X -
- X X X X -
- X X X X -
- - - - - -This has the original square in the middle with some border to allow proper
numerical manipulation.
OK, now we take the blocks and add them numerically to an array:
String[] board = new String(36);Looking back at the larger block above, given a square, it must not be the
case that:
(board[squareIndex + 6] is border or taken and
board[squareIndex - 6] is border or taken and
board[squareIndex - 1] is border or taken and
board[squareIndex + 1] is border or taken)
and it must be the case that 6 < squareIndex < 29Lets look at a full listing of possible indices in the array:
0 1 2 3 4 5
6 7 8 9 10 11
12 13 14 15 16 17
18 19 20 21 22 23
24 25 26 27 28 29
30 31 32 33 34 35If you take each index, divide by 7 and add index modulo 7
(int i = index/7 + index % 7) you get the following result:
0 1 2 3 4 5
6 7 2 3 4 5
6 7 2 3 4 5
6 7 8 3 4 5
6 7 8 9 4 5
6 7 8 9 10 5
We've already set the requirement that 6 < index < 29, leaving the following:
6 7 2 3 4 5
6 7 2 3 4 5
6 7 8 3 4 5
6 7 8 9 4 5
So,
if int i = (index/7 + index%7), then i < 5 or i> 6 (i != 5 && i !=6), giving a
test for a valid square within the array, if needed.
As long as one of the adjoining squares (I'm assuming lateral movement only)
is open, then the person can be placed and still move. Of course, for all
items to be accessible, then none of the items can be blocked, and all of
the placed items must be checked after a new item selects a position to
make sure that all is well; if a position for an item is chosen that blocks
another item, then choose a different position and try again.
It will speed things up if you can keep track of the failed positions so you
know not to try them again, as well as keeping track of placed items so you
don't try to place two items in the same square.
Are there better ways to do this? No doubt; this is a quick shaking-of-the-
tree to see what fell out, but hopefully it will give you some place to start.
I haven't coded a Wumpus in over 20 years; thanks for the trip down memory
lane!

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ITunes (11.3 64bit) cannot run because some its required files are missing. Please reinstall iTunes.

just set up my new laptop lenovo x240.
Windows 7 SP1.
itunes 64bit 11.3
first install went fine. then I tried to move my preexisting library. the library did not show the apps. so I tried around. Treid to re-install itunes.
Since I did, after the re-install, iTunes gives me the error message "iTunes cannot run because some its required files are missing. Please reinstall iTunes."
I tried the -_> link: Removing and reinstalling iTunes and other software components for Windows Vista, Windows 7, or Windows 8
unfortunately it did not resolve. please, advise... I am quite desperate... and surprised this is happening, since I am on a clean corporate laptop.
perhaps, can someone also steer me to a corner, where I can deactivate the cloud install pop-up ones starting iTunes?

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Need some hints on using dbms_crypto

Hello,
I need some hints on using the dbms_crypto package to generate some password for the OID userpassword attribute. The passwordstring is stored in a format {CRYPT}dasdasdawdww, {SHA}jfsklefjskldjkdlkldf, {MD4}dfdsfgsdgdfewwe or {MD5}fsdfsdadsgdfg where the keyword in the curly brackets describes the encryption methods. I think CRYPT means DES, SHA means SHA-1.
The key for the DES encryption for UNIX password authentification is in the first 2 letters of the encrypted string. I wanna have an encryption function which encrypts the clear type passwords in the right format like this perl script:
#!/bin/perl
print crypt($ARGV[0],"HS");
#: crypt.pl Test123 # program fetch
HSF0Sx2zdrLoQ
Regards
Holger

Hello,
meanwhile I made some investigations on the Problem
I tried this code:
DECLARE
input_string       VARCHAR2 (200) := 'Test123';
output_string      VARCHAR2 (200);
encrypted_raw      RAW (2000);             -- stores encrypted binary text
decrypted_raw      RAW (2000);             -- stores decrypted binary text
num_key_bytes      NUMBER := 256/8;        -- key length 256 bits (32 bytes)
key_bytes_raw      RAW (32);               -- stores 256-bit encryption key
encryption_type    PLS_INTEGER :=          -- total encryption type
                         DBMS_CRYPTO.ENCRYPT_DES
                       + DBMS_CRYPTO.CHAIN_CBC
                       + DBMS_CRYPTO.PAD_PKCS5;
BEGIN
        DBMS_OUTPUT.PUT_LINE ( 'Original string: ' || input_string);
        key_bytes_raw := UTL_I18N.STRING_TO_RAW ( 'HS' );
        encrypted_raw := DBMS_CRYPTO.ENCRYPT
                        src => UTL_I18N.STRING_TO_RAW (input_string, 'AL32UTF8'
                        typ => encryption_type,
                        key => key_bytes_raw
-- The encrypted value "encrypted_raw" can be used here
        DBMS_OUTPUT.PUT_LINE ( 'Encrypted string: ' || encrypted_raw);
        decrypted_raw := DBMS_CRYPTO.DECRYPT
                        src => encrypted_raw,
                        typ => encryption_type,
                        key => key_bytes_raw
        DBMS_OUTPUT.PUT_LINE ('Decrypted string: ' || UTL_I18N.RAW_TO_CHAR (decr
ypted_raw, 'AL32UTF8'));
        DBMS_OUTPUT.PUT_LINE ('Encrypted Char string: ' || UTL_I18N.RAW_TO_CHAR
(encrypted_raw, 'AL32UTF8'));
END;
/and got these error messages:
ERROR at line 1:
ORA-28234: key length too short
ORA-06512: at "SYS.DBMS_CRYPTO_FFI", line 3
ORA-06512: at "SYS.DBMS_CRYPTO", line 10
ORA-06512: at line 15In the next try:
DECLARE
input_string       VARCHAR2 (200) := 'Test123';
output_string      VARCHAR2 (200);
encrypted_raw      RAW (2000);             -- stores encrypted binary text
decrypted_raw      RAW (2000);             -- stores decrypted binary text
num_key_bytes      NUMBER := 256/8;        -- key length 256 bits (32 bytes)
key_bytes_raw      RAW (32);               -- stores 256-bit encryption key
encryption_type    PLS_INTEGER :=          -- total encryption type
                         DBMS_CRYPTO.ENCRYPT_DES
                       + DBMS_CRYPTO.CHAIN_CBC
                       + DBMS_CRYPTO.PAD_PKCS5;
BEGIN
        DBMS_OUTPUT.PUT_LINE ( 'Original string: ' || input_string);
        key_bytes_raw := UTL_I18N.STRING_TO_RAW ( 'HS12345678901234' );
        encrypted_raw := DBMS_CRYPTO.ENCRYPT
                        src => UTL_I18N.STRING_TO_RAW (input_string, 'AL32UTF8'
                        typ => encryption_type,
                        key => key_bytes_raw
-- The encrypted value "encrypted_raw" can be used here
        DBMS_OUTPUT.PUT_LINE ( 'Encrypted string: ' || encrypted_raw);
        decrypted_raw := DBMS_CRYPTO.DECRYPT
                        src => encrypted_raw,
                        typ => encryption_type,
                        key => key_bytes_raw
        DBMS_OUTPUT.PUT_LINE ('Decrypted string: ' || UTL_I18N.RAW_TO_CHAR (decr
ypted_raw, 'AL32UTF8'));
        DBMS_OUTPUT.PUT_LINE ('Encrypted Char string: ' || UTL_I18N.RAW_TO_CHAR
(encrypted_raw, 'AL32UTF8'));
END;
/I got some results which have nothing in common with the perl script:
Original string: Test123
Encrypted string: DE5668CD7762074C
Decrypted string: Test123
Encrypted Char string: ?h?bL
PL/SQL procedure successfully completed.Come to think of it I doubt if DBMS_CRYPTO is the right way to solve my problem. Any further hints?
Regards Holger

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And I'm sharing the connection through PPPoe
...unless, of course, I'm totally misunderstanding your question @@;
I'm a complete tehcno noob =__=;

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Give some hints that in a table control , first row will be editable and

pls,
give some hints that in a table control , first row will be editable and
rest of the rows will be non-editable.

Hi,
Take the group1 for all the textboxes in table control as 'ABC'.
Use this code, its working:-
it_zekpo is my internal table w/o header line,
wa_zekpo is work area.
Name of input/output fields on screen are:-
wa_zekpo-field1,
wa_zekpo-field2, and so on...
At screen flow-logic
PROCESS BEFORE OUTPUT.
* MODULE status_8003.
LOOP WITH CONTROL po_tb.
    MODULE read_data.
ENDLOOP.
PROCESS AFTER INPUT.
* MODULE user_command_8003.
LOOP WITH CONTROL po_tb.
    MODULE modify_data.
ENDLOOP.
In PBO
*&      Module READ_DATA OUTPUT
MODULE read_data OUTPUT.
READ TABLE it_zekpo INTO wa_zekpo INDEX po_tb-current_line. "po_tab is table control name
"enable only first row and disable rest rows in table control.
IF sy-subrc EQ 0.
    IF sy-tabix GE 2.
      IF screen-group1 = 'ABC'.
        LOOP AT SCREEN.
          SCREEN-INPUT = 0.
          SCREEN-ACTIVE = 0.
        ENDLOOP.
        MODIFY SCREEN.
      ENDIF.
    ENDIF.
"disable empty rows
ELSE.
    IF screen-group1 = 'ABC'.
      LOOP AT SCREEN.
        SCREEN-INPUT = 0.
        SCREEN-ACTIVE = 0.
      ENDLOOP.
      MODIFY SCREEN.
    ENDIF.
ENDIF.
data : line_count type i.
describe it_zekpo
lines line_count.
po_tb-lines = line_count + 10.
"to increase the number of lines in table control dynamically
ENDMODULE.                 " READ_DATA OUTPUT
In PAI
*&      Module MODIFY_DATA INPUT
MODULE MODIFY_DATA INPUT.
MODIFY IT_ZEKPO FROM WA_ZEKPO INDEX po_tb-currentline.
ENDMODULE.                 " MODIFY_DATA INPUT
Hope this solves your problem.
Thanks & Regards,
Tarun Gambhir

Some help required with logic for a dynamic sql query

i have below code but not sure how to resolve this problem - what i need is to be able to dynamically
the problem:
i have a rabbge of paratmeters coming in from a form and need to be able to create a dynamic query string to go into a prepared statement object.
the problem i have is there are 2 fields year range and year.
if year range is none i need to create the query string as such :
where the value of year can be serached on exactly
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how can i create the intial query string ie.- what are the possible things that i can do. - i'm thinking of things like putting some type of between or such type query statement - but not at all sure how the syntax would go - ie. how would i use the year value and how would i create this dynamic part of the query string so that the JDBC regonises it?
thanks for any help.
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Saish - thanks a lot for the code example.
Although, i think its far too advanced for me to understand and try to manipulate it and fit my problem. I'm pretty new to programming as you can probably see from my simple if else type statements. But i'm going to give it a try and see how it goes.
could you please be kind enough to demonstrate how i could use the above syntax to do the following. --
i have a year being entered in form . in the database there is a column year volume which contains year in single year value format and also in a year range value format - thus as in below - how could i do this -
eg.
user can enter a value in the year field a single value or a range value - then he can select +/-5 or 10 yrs range on that value - the DB holds the values as single values and ranges as below -
one suggested apporach is as follows if a single user is alloweed to enter only a single value in the filed and select a query range +/- 5 etc..
volume year of �1926-1928� and the user enters �1927�, the query has to find all records where
look for records that are �less than or equal to� 1927. It then has to check to see if it contains a range. For those that it finds containing a range, it has to work out what the �upper� year is and check to see if that is �greater than or equal� to 1927. If it is, then that is a possible matchanother approach that is suggested is to have a drop down with all years from databse and user is only llowed to select value from drop down and following logic is suggested :
Because volumes can be received as ranges (e.g. 1964-1966), some extra coding is required where the user asks for a Year Range (such as + or � 5).
Using the Year selected from the dropdown list, split it into 2 values, a low year and a high year. For example, if �1965-1968� is selected from the year dropdown, split it into �1965� and �1968� for the low year and high year respectively. If �1964� is selected from the year dropdown, split it into �1964� and �1964�. Now take the Year Range that the user has entered into account. For example, if the user has entered 5, subtract 5 from the low year and add 5 to the high year. Using these values, include the following search criteria in the query to the database:-
(<low year>     BETWEEN
             left (VOLUME_YEAR, charindex ('-',VOLUME_YEAR + '-') - 1)
     AND     right (VOLUME_YEAR, charindex ('-',VOLUME_YEAR + '-') - 1))
OR     (<high year>     BETWEEN
             left (VOLUME_YEAR, charindex ('-',VOLUME_YEAR + '-') - 1)
     AND     right (VOLUME_YEAR, charindex ('-',VOLUME_YEAR + '-') - 1))regards - i think if i could solve the first approach that would be something good as its most user freindly
thanks

Password hint required in password reset through console

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Hi Jay,
i follwed your steps i am getting the below error when i am trying to start manageservers with nodemangers.
<Dec 14, 2010 4:02:47 AM EST> <Critical> <WebLogicServer> <BEA-000386> <Server subsystem failed. Reason: weblogic.security.SecurityInitializationException: Authentication denied: Boot identity not valid; The user name and/or password from the boot identity file (boot.properties) is not valid. The boot identity may have been changed since the boot identity file was created. Please edit and update the boot identity file with the proper values of username and password. The first time the updated boot identity file is used to start the server, these new values are encrypted.
weblogic.security.SecurityInitializationException: Authentication denied: Boot identity not valid; The user name and/or password from the boot identity file (boot.properties) is not valid. The boot identity may have been changed since the boot identity file was created. Please edit and update the boot identity file with the proper values of username and password. The first time the updated boot identity file is used to start the server, these new values are encrypted.
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     at weblogic.security.service.CommonSecurityServiceManagerDelegateImpl.initialize(Unknown Source)
     at weblogic.security.service.SecurityServiceManager.initialize(Unknown Source)
     at weblogic.security.SecurityService.start(SecurityService.java:141)
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     Truncated. see log file for complete stacktrace
>
<Dec 14, 2010 4:02:47 AM EST> <Notice> <WebLogicServer> <BEA-000365> <Server state changed to FAILED>
I tried with deleting ldap folder also.
Regards
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I am new to Mac book pro world, wanted to run some games from website, or downloads. They require install of "Flash" f appl. Could this cause any damage to the Mac Operating System? (I'm used to the PC Microsoft world)
Thanks, Tom

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Issues with some apps requiring administrative privileges after installing Mavericks

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Quite annoying. Reinstalling the app didn't solve the issue. Instead, Finder integration seems now gone.
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If I hit "Quit", the message comes out after some seconds. I used XQuatz to run Inkscape, which I have now replaced with iDraw, but the issue is still annoying.
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I think this may now well be a keychains issue.
Resetting your keychain in Mac OS X
http://support.apple.com/kb/TS1544?viewlocale=en_US
OS X: Keychain Access asks for keychain "login" after changing login password
http://support.apple.com/kb/HT1631?viewlocale=en_US
OS X Mavericks: Lock or unlock your keychain
http://support.apple.com/kb/PH13823?viewlocale=en_US
Open Keychain Access, which is in the Utilities folder within the Applications folder.
From the Keychain Access menu, choose Preferences.
Click General, then click Reset My Default Keychain.
Authenticate with your account login password.
Quit Keychain Access.
Restart your computer.

Some hints required

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