Sort-Merge outer join, why? when?

Hi All,
How Oracle runs/optimizes outer joins has always been my subject of curiocity.
In Oracle documentation V 10.1 -> Performance tuning guide -> Chap. 14 ( The Query Optimizer) -> Go almost at the bottom
There is a small section of "Sort Merge outer joins".
It has a sentence
"When an outer join cannot drive from the outer (preserved) table to the inner (optional) table, it cannot use a hash join or nested loop joins. Then it uses the sort merge outer join for performing the join operation"
Can you help me understanding this ??
Thanks in advance

You actually need a sort-merge join sometimes: a join on inequality can't be run as a hash join, and may be very inefficient as a nested loop.
e.g.
select ...
where  del.delivery_date between ord.order_date + 5 and ord.order_date + 8Unfortunately there are other cases where a sort merge join could be a very efficient join mechansim - because of suitable indexes - but the optimizer won't take it because there is a bug (from my perspective, at any rate) in the cost for sorting.
Regards
Jonathan Lewis
http://jonathanlewis.wordpress.com
http://www.jlcomp.demon.co.uk

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    In the SQL Reference you can find an example

  • Using full outer join of subqueries named using with clause

    Hi,
    I am trying to create a view which is having 2 subqueries vol1 & vol2 with WITH clause. I am joining those 2 subqueries in the main query with FULL OUTER JOIN.
    When i compile that view in a tool like pl/sql developer, It has been compiled successfully.
    But when i call the view creation script from SQL command prompt, It is throwing error as
    from vol1 FULL JOIN vol2 o ON (vol1.ct_reference = vol2.ct_reference and vol1.table_name = vol2.table_name
    ERROR at line 29:
    ORA-00942: table or view does not exist
    Kindly advise whats going wrong.

    that's line 29. Maybe you get a better idea if you strip your operation of all the unneccessary elements until it works.
    There are some known bugs with subquery factoring (aka with clause) and also with ANSI join syntax, but it is hard to tell what happens here based on your description. But one thing is strange - if it is not a result of formatting (not formatting): I would expect the asterisk beneath the unknown table and not beneath the key word FULL.
    P.S.: my editor makes me think it's rather a proportional font thing. Have I already said that I don't like proportional font for SQL code examples?

  • Sample code and senarios to use outer join?

    We know the ABAP4 syntax for inner join, but never tried outer join and we even don't know if there is any outer join syntax in ABAP4 or not.  Would be very appreciated if some ABAP expert here let us know if there is any outer join and list the difference between inner join and outer join with detailed senarios or when we would use outer join or when to use inner join?  Also give a sample code on the outer join if there is any in ABAP?
    Thanks and we will give you reward points!

    Hye..
    Left outer join between table 1 and table 2 where column D in both tables set the join condition:
    Table 1                      Table 2
    A
    B
    C
    D
    D
    E
    F
    G
    H
    a1
    b1
    c1
    1
    1
    e1
    f1
    g1
    h1
    a2
    b2
    c2
    1
    3
    e2
    f2
    g2
    h2
    a3
    b3
    c3
    2
    4
    e3
    f3
    g3
    h3
    a4
    b4
    c4
    3
    |--|||--|
        Left Outer Join
        |--||||||||--|
        | A  | B  | C  | D  | D  | E  | F  | G  | H  |
        |--||||||||--|
        | a1 | b1 | c1 | 1  | 1  | e1 | f1 | g1 | h1 |
        | a2 | b2 | c2 | 1  | 1  | e1 | f1 | g1 | h1 |
        | a3 | b3 | c3 | 2  |NULL|NULL|NULL|NULL|NULL|
        | a4 | b4 | c4 | 3  | 3  | e2 | f2 | g2 | h2 |
        |--||||||||--|
    Example
    Output a list of all custimers with their bookings for October 15th, 2001:
    DATA: CUSTOMER TYPE SCUSTOM,
          BOOKING  TYPE SBOOK.
    SELECT SCUSTOMNAME SCUSTOMPOSTCODE SCUSTOM~CITY
           SBOOKFLDATE SBOOKCARRID SBOOKCONNID SBOOKBOOKID
           INTO (CUSTOMER-NAME, CUSTOMER-POSTCODE, CUSTOMER-CITY,
                 BOOKING-FLDATE, BOOKING-CARRID, BOOKING-CONNID,
                 BOOKING-BOOKID)
           FROM SCUSTOM LEFT OUTER JOIN SBOOK
             ON SCUSTOMID = SBOOKCUSTOMID AND
                SBOOK~FLDATE = '20011015'
           ORDER BY SCUSTOMNAME SBOOKFLDATE.
      WRITE: / CUSTOMER-NAME, CUSTOMER-POSTCODE, CUSTOMER-CITY,
               BOOKING-FLDATE, BOOKING-CARRID, BOOKING-CONNID,
               BOOKING-BOOKID.
    ENDSELECT.
    Reward if helpful.
    Thanks.
    Imran.

  • One-to-one two sided relationship causing two outer joins.

    We have a fairly simple one-to-one relationship between two objects A and
    B. A maps to table A, B maps to table B. A holds a foreign key to B. Both
    classes hold a reference to each other.
    What we are trying to achieve is to load both A and B with a single
    intelligent SQL query. The only thing we can achieve is either two queries
    or one query with two outer joins.
    When both A and B have the other in the default fetch group and
    EagerFetchMode set to join, Kodo dispatches is something like this:
    SELECT whatever FROM A t0 LEFT OUTER JOIN B t1 ON t0.B_ID = t1.ID LEFT
    OUTER JOIN A t2 ON t1.ID = t2.B_ID
    The obvious problem with this is that is is going to be very innefficient.
    Isn't the second join needed?
    If the eager fetch mode is kept the same but A is removed from the default
    fetch group of B then we get two queries. The first one is a left outer
    join between A and B and loads all the columns from both A and B. (At this
    point in a debugger, A holds a reference to B, but B's reference to A is
    null). The second query fetchs all columns from B. But still the reference
    to A is null. It's only when we actually navigate to A from a B that the
    reference is populated. (Luckily no query is executed at this point).
    Is there anyway to achieve the loading of both objects with a single SQL
    query dispatched by Kodo?

    You should be able to get what you want by querying for the B instance with A in
    its default fetch group (but keeping B out of A's default fetch group). It
    shoudl result in one query with a single outer join, and no additional queries
    when you traverse the A.B relation.
    The reason for the two joins/queries in other scenarios is that Kodo treats each
    direction of the relation as a separate relation that has to be fetched on its
    own. The reason the above solution should work is that when the A record is
    read, the foreign key values for the B record are cached. When you traverse the
    A.B relation after both A and B are loaded, Kodo matches these cached foreign
    key values to the B instance in the PM cache and doesn't require a DB trip.

  • Why, when I sync my iPhone does it always take all my apps out of their neat sorted little boxes of twelve Apps organised by a commonality and rearrange them over a dozen screens in random order? Each time I sync, I have a 1hr long task of relocating apps

    Why, when I sync my iPhone does it always take all my apps out of their neat sorted little boxes of twelve Apps organised by a commonality and rearrange them over a dozen screens in random order? Each time I sync, I have a 1hr long task of relocating apps.
    Why no tleave them spread out I hear you ask... That is not practicable. I then have 12 pages to scan rather than just two. I need a solution... :-P

    I realize this is an old thread but I'm having the same problem after upgrading my software today. Kinda surprised there are no solutions at all with 88 views.  I have an iPod touch btw, not an iPhone, but it prob wouldn't make much difference in this case.
    The thing is, I get the screen(s) looking EXACTLY as I want on iTunes...just perfect (which is what I believe everyone else is experiencing as well).  When we go to sync tho, it does whatever it wants to do.  After syncing, all the apps are there, it's just that for me, it puts them in some type of random order.  I have 72 apps and this is absolutely ridiculous!
    Thanks in advance for any fixes anyone might have...

  • Not using Index when SDO_RELATE in Spatial Query is used in LEFT OUTER JOIN

    I want to know for every City (Point geometry) in which Municipality (Polygon geometry) it is.
    Some cities will not be covered by any municipality (as there is no data for it), so its municipality name should be blank in the result
    We have 4942 cities (point geometries)
    and 500 municipalities (polygon geometry)
    SELECT T1.NAME as City, T2.NAME as Municipality
    FROM CITY T1
    LEFT OUTER JOIN MUNICIPALITY T2 ON SDO_RELATE(T1.GEOM, T2.GEOM, 'MASK=ANYINTERACT') = 'TRUE'The explain plan for this query is:
    SELECT STATEMENT
      FILTER
        Filter Predicates
          MDSYS.SDO_RTREE_RELATE(T1.GEOM, T2.GEOM, 'mask=ANYINTERACT querytype=window ') = 'TRUE'
        MERGE JOIN
          TABLE ACCESS              CITY               FULL                            11
          BUFFER                                       SORT                        100605
              TABLE ACCESS          MUNICIPALITY       FULL                            20So the cost is in the BUFFER (whatever that is), it takes +2000 seconds to run this, it is not using the spatial index.
    And we are not getting all rows, but only the ones interacting with a municipality, e.g. 2436 rows.
    But I want all rows, including the ones not interacting with any Municipality.
    When we want only those cities that actually are in a municipality, I use a different query and it will use the index.
    SELECT T1.NAME as City, T2.NAME as Municipality
    FROM CITY T1, MUNICIPALITY T2
    WHERE SDO_RELATE(T1.GEOM, T2.GEOM, 'MASK=ANYINTERACT') = 'TRUE'I get (only) 2436 rows (as expected) in 5 seconds (it is fast) and the explain plan shows it is using the spatial index.
    But in this case, I am not getting any cities not inside any municipality (of course)
    SELECT STATEMENT
       NESTED LOOPS
          TABLE ACCESS                   MUNICIPALITY       FULL                22
          TABLE ACCESS                   CITY               BY INDEX ROWID      22
             DOMAIN INDEX                CITY_SDX                                0
                Access Predicates
                   MDSYS.SDO_RTREE_RELATE(T1.GEOM, T2.GEOM, 'mask=ANYINTERACT querytype=window ') = 'TRUE'I always thought a LEFT OUTER JOIN would return all rows from the Table, whatever happens in the next,
    but it seems the query has been rewritten so that it is now using a Filter Predicate in the end, which filters those geometries having no interaction.
    As an example I also do thing alphanumerically, I do get 4942 rows, including the ones which have no Municipality name.
    In this case the names must match, so its only for testing if the LEFT OUTER JOIN returns stuff correctly, which it does in this case.
    SELECT T1.NAME as City, T2.NAME as Municipality
    FROM CITY T1
    LEFT OUTER JOIN MUNICIPALITY T2 ON T1.NAME = T2.NAMEIs this an Oracle Spatial bug, e.g. not return 4942 rows, but only 2436 rows on the first query?
    Note all tests performed on Oracle 11g R2 (11.2.0.1.0)

    Patrick,
    Even so, your geoms in the relate were the wrong way around.
    Also, I don't recall you saying (or showing) that you wanted the municipality geometry returned. Still,
    no matter, easy to do.
    Here are some additional suggestions. I don't have your data so I have had to use some of my own.
    set serveroutput on timing on autotrace on
    SELECT T1.SPECIES as City,
           (SELECT T2.ADMIN_NAME FROM AUSTRALIAN_STATES T2 WHERE SDO_ANYINTERACT(T2.GEOM, SDO_GEOM.SDO_BUFFER(T1.GEOM,10000,0.5,'UNIT=M')) = 'TRUE') as Municipality,
           (SELECT T2.GEOM       FROM AUSTRALIAN_STATES T2 WHERE SDO_ANYINTERACT(T2.GEOM, SDO_GEOM.SDO_BUFFER(T1.GEOM,10000,0.5,'UNIT=M')) = 'TRUE') as geom
      FROM GUTDATA T1;
    762 rows selected
    Elapsed: 00:00:21.656
    Plan hash value: 2160035213
    | Id  | Operation                   | Name                       | Rows  | Bytes | Cost (%CPU)| Time     |
    |   0 | SELECT STATEMENT            |                            |   762 | 49530 |     5   (0)| 00:00:01 |
    |   1 |  TABLE ACCESS BY INDEX ROWID| AUSTRALIAN_STATES          |     1 |   115 |     0   (0)| 00:00:01 |
    |*  2 |   DOMAIN INDEX              | AUSTRALIAN_STATES_GEOM_SPX |       |       |     0   (0)| 00:00:01 |
    |   3 |  TABLE ACCESS BY INDEX ROWID| AUSTRALIAN_STATES          |     1 |   115 |     0   (0)| 00:00:01 |
    |*  4 |   DOMAIN INDEX              | AUSTRALIAN_STATES_GEOM_SPX |       |       |     0   (0)| 00:00:01 |
    |   5 |  TABLE ACCESS FULL          | GUTDATA                    |   762 | 49530 |     5   (0)| 00:00:01 |
    Predicate Information (identified by operation id):
       2 - access("MDSYS"."SDO_ANYINTERACT"("T2"."GEOM","SDO_GEOM"."SDO_BUFFER"(:B1,10000,0.5,'UNIT=M'))='TRUE')
       4 - access("MDSYS"."SDO_ANYINTERACT"("T2"."GEOM","SDO_GEOM"."SDO_BUFFER"(:B1,10000,0.5,'UNIT=M'))='TRUE')
       Statistics
                   7  user calls
               24576  physical read total bytes
                   0  physical write total bytes
                   0  spare statistic 3
                   0  commit cleanout failures: cannot pin
                   0  TBS Extension: bytes extended
                   0  total number of times SMON posted
                   0  SMON posted for undo segment recovery
                   0  SMON posted for dropping temp segment
                   0  segment prealloc tasksThe above can look messy as you add more (SELECT ...) attributes, but is is fast (though can't use in Materialized Views).
    /* The set of all cities not in municipalities */
    SELECT T1.SPECIES                 as City,
           cast(null as varchar2(42)) as municipality,
           cast(null as sdo_geometry) as geom
      FROM GUTDATA T1
    WHERE NOT EXISTS (SELECT 1
                         FROM AUSTRALIAN_STATES T2
                        WHERE SDO_ANYINTERACT(T2.GEOM, SDO_GEOM.SDO_BUFFER(T1.GEOM,10000,0.5,'UNIT=M')) = 'TRUE')
    UNION ALL
    /* The set of all cities in municipalities */
    SELECT T1.SPECIES    as City,
           T2.ADMIN_NAME as Municipality,
           T2.GEOM       as geom
      FROM GUTDATA T1
           INNER JOIN
           AUSTRALIAN_STATES T2 ON (SDO_ANYINTERACT(T2.GEOM, SDO_GEOM.SDO_BUFFER(T1.GEOM,10000,0.5,'UNIT=M')) = 'TRUE');
    762 rows selected
    Elapsed: 00:00:59.953
    Plan hash value: 2854682795
    | Id  | Operation           | Name                       | Rows  | Bytes | Cost (%CPU)| Time     |
    |   0 | SELECT STATEMENT    |                            |    99 | 13450 |    38  (87)| 00:00:01 |
    |   1 |  UNION-ALL          |                            |       |       |            |          |
    |*  2 |   FILTER            |                            |       |       |            |          |
    |   3 |    TABLE ACCESS FULL| GUTDATA                    |   762 | 49530 |     5   (0)| 00:00:01 |
    |*  4 |    DOMAIN INDEX     | AUSTRALIAN_STATES_GEOM_SPX |       |       |     0   (0)| 00:00:01 |
    |   5 |   NESTED LOOPS      |                            |    61 | 10980 |    33   (0)| 00:00:01 |
    |   6 |    TABLE ACCESS FULL| AUSTRALIAN_STATES          |     8 |   920 |     3   (0)| 00:00:01 |
    |*  7 |    TABLE ACCESS FULL| GUTDATA                    |     8 |   520 |     4   (0)| 00:00:01 |
    Predicate Information (identified by operation id):
       2 - filter( NOT EXISTS (SELECT 0 FROM "AUSTRALIAN_STATES" "T2" WHERE "MDSYS"."SDO_ANYINTERACT"("T2"."GEOM","SDO_GEOM"."SDO_BUFFER"(:B1,10000,0.5,'UNIT=M'))='TRUE'))
       4 - access("MDSYS"."SDO_ANYINTERACT"("T2"."GEOM","SDO_GEOM"."SDO_BUFFER"(:B1,10000,0.5,'UNIT=M'))='TRUE')
       7 - filter("MDSYS"."SDO_ANYINTERACT"("T2"."GEOM","SDO_GEOM"."SDO_BUFFER"("T1"."GEOM",10000,0.5,'UNIT=M'))='TRUE')
       Statistics
                   7  user calls
              131072  physical read total bytes
                   0  physical write total bytes
                   0  spare statistic 3
                   0  commit cleanout failures: cannot pin
                   0  TBS Extension: bytes extended
                   0  total number of times SMON posted
                   0  SMON posted for undo segment recovery
                   0  SMON posted for dropping temp segment
                   0  segment prealloc tasksMuch slower but Materialized View friendly.
    This one is a bit more "natural" but still slower than the first.
    set serveroutput on timing on autotrace on
    /* The set of all cities in municipalities */
    WITH municipal_cities As (
      SELECT T1.ID         as City,
             T2.ADMIN_NAME as Municipality,
             T2.GEOM       as geom
        FROM GUTDATA T1
             INNER JOIN
             AUSTRALIAN_STATES T2 ON (SDO_ANYINTERACT(T2.GEOM, SDO_GEOM.SDO_BUFFER(T1.GEOM,10000,0.5,'UNIT=M')) = 'TRUE')
    SELECT T1.ID           as City,
           T2.Municipality as Municipality,
           T2.GEOM         as geom
      FROM GUTDATA          T1
           LEFT OUTER JOIN
           municipal_cities T2
           ON (T2.CITY = T1.ID);
    762 rows selected
    Elapsed: 00:00:50.228
    Plan hash value: 745978991
    | Id  | Operation             | Name              | Rows  | Bytes | Cost (%CPU)| Time     |
    |   0 | SELECT STATEMENT      |                   |   762 | 44196 |    36   (3)| 00:00:01 |
    |*  1 |  HASH JOIN RIGHT OUTER|                   |   762 | 44196 |    36   (3)| 00:00:01 |
    |   2 |   VIEW                |                   |    61 |  3294 |    33   (0)| 00:00:01 |
    |   3 |    NESTED LOOPS       |                   |    61 | 10980 |    33   (0)| 00:00:01 |
    |   4 |     TABLE ACCESS FULL | AUSTRALIAN_STATES |     8 |   920 |     3   (0)| 00:00:01 |
    |*  5 |     TABLE ACCESS FULL | GUTDATA           |     8 |   520 |     4   (0)| 00:00:01 |
    |   6 |   INDEX FAST FULL SCAN| GUTDATA_ID_PK     |   762 |  3048 |     2   (0)| 00:00:01 |
    Predicate Information (identified by operation id):
       1 - access("T2"."CITY"(+)="T1"."ID")
       5 - filter("MDSYS"."SDO_ANYINTERACT"("T2"."GEOM","SDO_GEOM"."SDO_BUFFER"("T1"."GEOM",10000,0.5,'UNIT=M'))='TRUE')
       Statistics
                   7  user calls
               49152  physical read total bytes
                   0  physical write total bytes
                   0  spare statistic 3
                   0  commit cleanout failures: cannot pin
                   0  TBS Extension: bytes extended
                   0  total number of times SMON posted
                   0  SMON posted for undo segment recovery
                   0  SMON posted for dropping temp segment
                   0  segment prealloc tasksFinally, the Pièce de résistance: trick the LEFT OUTER JOIN operator...
    set serveroutput on timing on autotrace on
    SELECT T1.SPECIES    as City,
           T2.ADMIN_NAME as Municipality,
           T2.GEOM       as geom
      FROM GUTDATA           T1
           LEFT OUTER JOIN
           AUSTRALIAN_STATES T2
           ON (t2.admin_name = to_char(t1.ID) OR
               SDO_ANYINTERACT(T2.GEOM, SDO_GEOM.SDO_BUFFER(T1.GEOM,10000,0.5,'UNIT=M')) = 'TRUE');
    762 rows selected
    Elapsed: 00:00:50.273
    Plan hash value: 158854308
    | Id  | Operation           | Name              | Rows  | Bytes | Cost (%CPU)| Time     |
    |   0 | SELECT STATEMENT    |                   |   762 | 92964 |  2294   (1)| 00:00:28 |
    |   1 |  NESTED LOOPS OUTER |                   |   762 | 92964 |  2294   (1)| 00:00:28 |
    |   2 |   TABLE ACCESS FULL | GUTDATA           |   762 | 49530 |     5   (0)| 00:00:01 |
    |   3 |   VIEW              |                   |     1 |    57 |     3   (0)| 00:00:01 |
    |*  4 |    TABLE ACCESS FULL| AUSTRALIAN_STATES |     1 |   115 |     3   (0)| 00:00:01 |
    Predicate Information (identified by operation id):
       4 - filter("T2"."ADMIN_NAME"=TO_CHAR("T1"."ID") OR
                  "MDSYS"."SDO_ANYINTERACT"("T2"."GEOM","SDO_GEOM"."SDO_BUFFER"("T1"."GEOM",10000,0.5,'UNIT=M'))='TRUE')
       Statistics
                   7  user calls
                   0  physical read total bytes
                   0  physical write total bytes
                   0  spare statistic 3
                   0  commit cleanout failures: cannot pin
                   0  TBS Extension: bytes extended
                   0  total number of times SMON posted
                   0  SMON posted for undo segment recovery
                   0  SMON posted for dropping temp segment
                   0  segment prealloc tasksTry these combinations to see what works for you.
    Interestingly, for me, the following returns absolutely nothing.
    SELECT T1.SPECIES    as City,
           T2.ADMIN_NAME as Municipality
      FROM GUTDATA           T1
           LEFT OUTER JOIN
           AUSTRALIAN_STATES T2
           ON (SDO_ANYINTERACT(T2.GEOM, SDO_GEOM.SDO_BUFFER(T1.GEOM,10000,0.5,'UNIT=M')) = 'TRUE')
    MINUS
    SELECT T1.SPECIES    as City,
           T2.ADMIN_NAME as Municipality
      FROM GUTDATA           T1
           LEFT OUTER JOIN
           AUSTRALIAN_STATES T2
           ON (t2.admin_name =  to_char(t1.ID) OR
               SDO_ANYINTERACT(T2.GEOM, SDO_GEOM.SDO_BUFFER(T1.GEOM,10000,0.5,'UNIT=M')) = 'TRUE');(I leave it to you to see if you can see why as the LEFT OUTER JOIN seems to be working correctly for me but I am not going to dedicate time to detailed checking of results.)
    Note all tests performed on Oracle 11g R2 (11.2.0.1.0)
    If you get the answer you want: mark the post as answered to assign points.
    regards
    Simon

  • Nested loop join v/s Sort merge

    I have seen that nested loops are better if the inner table is being indexed, because for each outer table row, we are looking for a match in the inner table. But is there any case when optimizer still goes for a nested loop even if there is no index on the inner table. That is my first question ?
    My second question := When doing a sort merge join oracle has to sort both result sets and then merge them. Oracle says that if both the row sets, if already sorted is definately better for performance. Ya thats obvious. But back to my upper question, when there is no index on the inner table, is it the situation when oracle goes for a sort merge join ?

    My response should really have examples but since I do not have any handy I will just say about your first question. If there is no index available from table A to table B yes it is possible a nested loop join may still be used and table B read via full table scan within a nested loop. If table B is very small and consists of only a block or two this may be relatively efficient plan. It is more likely you sould see table B full scanned and the result feed into a hash join, but I have seen the plan you mention.
    Back before hash joins were introduced with 7.3 (if my memory is correct) you would see sort/merge joins used more often than you do now. Generally speaking no index on the join conditions would exist for this option to be chosen.
    If you really want to know why and sometimes what the optimizer is going to do buy Jonathan Lewis's book Cost-Based Oracle Fundamentals. If explains the optimizer in more depth than any other source I know of.
    HTH -- Mark D Powell --

  • Difference between merge-Not matched and left outer join

    Why should Merge-Not Matched be used instead of left outer join? I believe both will enable comparison of 2 tables. So what is the difference. Please advice.
    mayooran99

    MERGE is way to encapsulate all conditions within single statement
    The equivalent implementation using join would require three different statements 
    1 UPDATE using INNER JOIN
    1 INSERT using LEFT JOIN
    and 1 DELETE using LEFT JOIN in reverse order
    Both approaches work fine
    so all that you need to do is left join operation to find difference you can use either
    But MERGE has one additional advantage in case you need to get output from MERGE and use it for further manipulation like further insert to child table
    I've explained it here
    http://visakhm.blogspot.in/2014/09/t-sql-tips-multifaceted-merge-statement.html
    Please Mark This As Answer if it solved your issue
    Please Vote This As Helpful if it helps to solve your issue
    Visakh
    My Wiki User Page
    My MSDN Page
    My Personal Blog
    My Facebook Page

  • Popup LOV fails in firefox when using an outer join!!!

    I have a popup lov which contains at least 2 outer joins in my query. The popup renders fine in IE but i get the error message:
    "Popup List of Values query is invalid, a display and a return value are needed, the column names need to be different"
    when launching the popup from Firefox (1.5.0.2)
    Anyone got any idea why this works in IE but fails in Firefox?
    Cheers
    Duncan

    Hello,
    Duncan – If you'll run your example code on SQL*Plus, you'll see that for department "OPERATIONS" there is no returned value. This could happen with outer join. The problem can be with the way FF is interpreting this non-value. I didn't try it my self, but maybe if you'll use display null value with your LOV, it will solve the problem. Another possible option is to use NVL() on the returned value.
    Chris – Some of the Apex team members, like Carl, are using FF as their main browser. There are some compatibility issues with the last version of FF, but from that, to your conclusion of Apex only support IE, there's a long road.
    Regards,
    Arie.

  • Why is Discoverer adding outer joins?

    Hi,
    I have set up standard joins (i.e. no outer joins) between one master and two detail folders in the Admin. For some reason when I create a report using the three folders, Discoverer is making them outer joins. Note: This query will cause a fan trap but there is a business reason for doing so (disable fan trap detection is checked). I'm using Plus/Web for the report.
    Why is Discoverer adding outer joins?
    Thanks, Andrew
    This is what I expect (note one master joined to two details):
    SELECT
    O125508.BUSINESS_TRANSACTION_CODE,
    O141221.SOURCE,
    O141221.AMOUNT
    FROM IRIS.IRS_ACQUIRED_INFO_V O125508,
    IRIS.IRS_FUNDINGS_V O141221,
    IRIS.IRS_FUNDING_SELECTIONS_V O144361
    WHERE ( ( O125508.BUSINESS_TRANSACTION_ID = O141221.BUSINESS_TRANSACTION_ID )
    AND ( O125508.BUSINESS_TRANSACTION_ID = O144361.BUSINESS_TRANSACTION_ID )
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    AND ( O125508.BUSINESS_TRANSACTION_CODE = :"Business Transaction Code" )
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