Split XML file using SAX

Hello
Can some one tell me How do I go about splitting a large XML int smaller files using the SAX Parser.
I have ruled out the use of dom taking memory overhead into consideration.
I should be able to pass the number of records that go into each files
dynamically.
If some one can share their code snippet, that would be great
cheer
rachans

I need each split file to be well formed, its not just chopping the big file into pieces...
the structure of large file is something like this
<root>
<header>
</header>
<body>
<records>
</records>
<records>
</records>
</body>
</root>
now the split file looks like this
<root>
<header>
</header>
<body>
<records>
</records>
</body>
</root>
I will need to split by a number, if say 2 then each file will have 2 records.....the header is the same for all files...hope this explanation helps..

Similar Messages

How can we get tag of XML file using SAX

Hi ,
I'm parsing one SAX parser , I'have almost done this parsing. i have faced problem for one case, i'e how can we get tag from XML file using SAX parser?
XML file is
<DFProperties>
<AccessType>
<Get/>
</AccessType> <Description>
gdhhd
</Description>
<DFFormat>
<chr/>
</DFFormat>
<Scope>
<Permanent/>
</Scope>
<DFTitle>gsgd</DFTitle>
<DFType>
<MIME>text/plain</MIME>
</DFType>
</DFProperties>
I want out like GET and Permanent... means this one tag which is present inside of another tag.
Handler class like
public void startElement(String namespaceURI, String localName,
               String qName, Attributes atts) throws SAXException {
if(_ACCESSTYPE.equals(localName)){
               accessTypeElement=ACCESSTYPE;
public void characters(char[] ch, int start, int length)
               throws SAXException {
if (_ACCESSTYPE.equals(_accessTypeElement)) {
               String strValue = new String(ch, start, length);
               System.out.println("Accestype-----------------------------> " + strValue);
               //System.out.println(" " + strValue);
public void endElement(String namespaceURI, String localName, String qName)
               throws SAXException {
if (_ACCESSTYPE.equals(localName)) {
               _accessTypeElement = "";
. please any body help me

Hi ,
I have one problem,Please help me.
1. How can I'll identify where exactly my Node is ended,means how how can we find corresponding nodename? in partcular place
<Node> .............starttag1
<NodeName>Test</NodeName>
<Node>................starttag2
<nodeName>test1</NodeName>
</Node>..................endtag2
<Node>.....................starttag3
<NodeName><NodeName>
<Node> .........................starttag4
<NodeName>test4</NodeName>
</Node>.......enddtag4
</Node>...........end tag3
</Node>............endtag1
my code is below
private final String _NODENAME = "NodeName";
private final String _NODE = "Node";
private String _nodeElement = "";
     private String _NodeNameElement = "";
public void startElement(String namespaceURI, String localName,
               String qName, Attributes atts) throws SAXException {
if (_NODENAME.equals(localName)) {
               NodeNameElement = NODENAME;
if(_NODE.equals(localName)){
     System.out.println("start");
     if (_NODENAME.equals(localName)) {
               NodeNameElement = NODENAME;
public void characters(char[] ch, int start, int length)
               throws SAXException {
if (_NODENAME.equals(_NodeNameElement)) {
               String strValue = new String(ch, start, length);
               String sttt=strValue;
               System.out.println("NODENAME: ************* " + strValue);
if(_NODE.equals(_nodeElement)){
               if (_NODENAME.equals(_NodeNameElement)) {
                    String strValue = new String(ch, start, length);
                    String sttt=strValue;
                    System.out.println("nodevalue********** " + strValue);
public void endElement(String namespaceURI, String localName, String qName)
               throws SAXException {
if (_NODENAME.equals(localName)) {
               _NodeNameElement = "";
if(_NODE.equals(localName)){
               System.out.println("NODENAME: %%%%%%%%%");
please help me. How can I figure node ending for particular nodename

SAX: How to create new XML file using SAX parser

Hi,
Please anybody help me to create a XML file using the Packages in the 5.0 pack of java. I have successfully created it reading the tag names and values from database using DOM but can i do this using SAX.
I am successful to read XML using SAX, now i want to create new XML file for some tags and its values using SAX.
How can i do this ?
Sachin Kulkarni

SAX is a parser, not a generator.Well,
you can use it to create an XML file too. And it will take care of proper encoding, thus being much superior to a normal textwriter:
See the following code snippet (out is a OutputStream):
PrintWriter pw = new PrintWriter(out);
      StreamResult streamResult = new StreamResult(pw);
      SAXTransformerFactory tf = (SAXTransformerFactory) TransformerFactory.newInstance();
      //      SAX2.0 ContentHandler.
      TransformerHandler hd = tf.newTransformerHandler();
      Transformer serializer = hd.getTransformer();
      serializer.setOutputProperty(OutputKeys.ENCODING, "UTF-8");//
      serializer.setOutputProperty(OutputKeys.DOCTYPE_SYSTEM,"pdfBookmarks.xsd");
      serializer.setOutputProperty(OutputKeys.DOCTYPE_SYSTEM,"http://schema.inplus.de/pdf/1.0");
      serializer.setOutputProperty(OutputKeys.METHOD,"xml");
      serializer.setOutputProperty(OutputKeys.INDENT, "yes");
      hd.setResult(streamResult);
      hd.startDocument();
      //Get a processing instruction
      hd.processingInstruction("xml-stylesheet","type=\"text/xsl\" href=\"mystyle.xsl\"");
      AttributesImpl atts = new AttributesImpl();
      atts.addAttribute("", "", "someattribute", "CDATA", "test");
      atts.addAttribute("", "", "moreattributes", "CDATA", "test2");
       hd.startElement("", "", "MyTag", atts);
String curTitle = "Something inside a tag";
          hd.characters(curTitle.toCharArray(), 0, curTitle.length());
    hd.endElement("", "", "MyTag");
      hd.endDocument();
You are responsible for proper nesting. SAX takes care of encoding.
Hth
;-) stw

Buiding xml file using SAX parser of JAXP

Please send me xml building using the sax parser.This is the urgent requirement ,iam not geeting how to solve this problem.so please anybody can help with one best example

You don't build an XML file with a parser. A parser reads an XML file and converts it to some internal representation. Try reading this tutorial:
http://java.sun.com/xml/jaxp/dist/1.1/docs/tutorial/

How to Create XML file with SAX parser instead of DOM parser

HI ALL,
I am in need of creating an XML file by SAX parser ONLY. As far as my knowledge goes, we can use DOM for such purpose(by using createElement, creatAttribute ...). Can anyone tell me, is there any way to create an XML file using SAX Parser only. I mean, I just want to know whether SAX provides any sort of api for Creatign an element, attribute etc. I know that SAX is for event based parsing. But my requirement is to create an XML file from using only SAX parser.
Any help would be appreciated
Thanx in advance
Kaushik

Hi,
You must write a XMLWriter class yourself, and that Class extends DefaultHandle ....., the overwrite the startElement(url, localName, qName, attributeList), startDocument(), endElement().....and so on.
in startElement write your own logic about how to create a new element and how to create a Attribute list
in startDocument write your own logic about how to build a document and encodeType, dtd....
By using:
XMLWriter out = new XMLWriter()
out.startDocument();
Attribute attr1 = new Atribute();
attr1.add("name", "value");
out.startElement("","","Element1", attr1);
Attribute attr2 = new Atribute();
attr2.add("name", "value");
out.startElement("","","Element2", attr2);
out.endElement("","","Element2");
out.endElement("","","Element1");
out.endDocument();

How to create new XML file using retreived XML content by using SAX API?

hi all,
* How to create new XML file using retreived XML content by using SAX ?
* I have tried my level best, but output is coming invalid format, my code is follows,
XMLFileParser.java class :-
import java.io.StringReader;
import java.io.StringWriter;
import javax.xml.transform.OutputKeys;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerConfigurationException;
import javax.xml.transform.TransformerException;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMResult;
import javax.xml.transform.sax.SAXSource;
import javax.xml.transform.sax.SAXTransformerFactory;
import javax.xml.transform.sax.TransformerHandler;
import javax.xml.transform.stream.StreamResult;
import org.w3c.dom.Document;
import org.xml.sax.Attributes;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.XMLFilterImpl;
public class PdfParser extends XMLFilterImpl {
    private TransformerHandler handler;
    Document meta_data;
    private StringWriter meta_data_text = new StringWriter();
    public void startDocument() throws SAXException {
    void startValidation() throws SAXException {
        StreamResult streamResult = new StreamResult(meta_data_text);
        SAXTransformerFactory factory = (SAXTransformerFactory) SAXTransformerFactory.newInstance();
        try
            handler = factory.newTransformerHandler();
            Transformer transformer = handler.getTransformer();
            transformer.setOutputProperty(OutputKeys.ENCODING, "UTF-8");
            transformer.setOutputProperty(OutputKeys.INDENT, "yes");
            handler.setResult(streamResult);
            handler.startDocument();
        catch (TransformerConfigurationException tce)
            System.out.println("Error during the parse :"+ tce.getMessageAndLocation());
        super.startDocument();
    public void startElement(String namespaceURI, String localName,
            String qualifiedName, Attributes atts) throws SAXException {
        handler.startElement(namespaceURI, localName, qualifiedName, atts);
        super.startElement(namespaceURI, localName, qualifiedName, atts);
    public void characters(char[] text, int start, int length)
            throws SAXException {
        handler.characters(text, start, length);
        super.characters(text, start, length);
    public void endElement(String namespaceURI, String localName,
            String qualifiedName) throws SAXException {
        super.endElement("", localName, qualifiedName);
        handler.endElement("", localName, qualifiedName);
    public void endDocument() throws SAXException {
    void endValidation() throws SAXException {
        handler.endDocument();
        try {
            TransformerFactory transfactory = TransformerFactory.newInstance();
            Transformer trans = transfactory.newTransformer();
            SAXSource sax_source = new SAXSource(new InputSource(new StringReader(meta_data_text.toString())));
            DOMResult dom_result = new DOMResult();
            trans.transform(sax_source, dom_result);
            meta_data = (Document) dom_result.getNode();
            System.out.println(meta_data_text);
        catch (TransformerConfigurationException tce) {
            System.out.println("Error occurs during the parse :"+ tce.getMessageAndLocation());
        catch (TransformerException te) {
            System.out.println("Error in result transformation :"+ te.getMessageAndLocation());
} CreateXMLFile.java class :-
Sax.startDocument();
Sax.startValidation();
Sax.startElement("", "pdf", "pdf", new AttributesImpl());
Sax.startElement("", "basic-metadata", "basic-metadata", new AttributesImpl());
String xmp_str = new String(meta_data.getByteArray(),"UTF8");
char[] xmp_arr = xmp_str.toCharArray();
Sax.characters(xmp_arr, 0, xmp_arr.length);
Sax.endElement("", "pdf", "pdf");
Sax.endValidation();
Sax.endDocument();
Sax.endElement("", "basic-metadata", "basic-metadata");* In CreateXMLFile.java
class, I have retreived the xml content in the meta_data object, after that i have converted into character array and this will be sends to SAX
* In this case , the XML file created successfully but the retreived XML content added as an text in between basic-metadata Element, that is, retreived XML content
is not an XML type text, it just an Normal text Why that ?
* Please help me what is the problem in my code?
Cheers,
JavaImran

Sax.startDocument();
Sax.startValidation();
Sax.startElement("", "pdf", "pdf", new AttributesImpl());
Sax.startElement("", "basic-metadata", "basic-metadata", new AttributesImpl());
String xmp_str = new String(meta_data.getByteArray(),"UTF8");
char[] xmp_arr = xmp_str.toCharArray();
Sax.characters(xmp_arr, 0, xmp_arr.length);
</code><code>Sax.endElement("", "basic-metadata", "basic-metadata");</code>
<code class="jive-code jive-java">Sax.endElement("", "pdf", "pdf");
Sax.endValidation();
Sax.endDocument();
* I HAVE CHANGED MY AS PER YOUR SUGGESTION, NOW SAME RESULT HAS COMING.
* I AM NOT ABLE TO GET THE EXACT OUTPUT.,WHY THAT ?
Thanks,
JavaImran{code}

Parsing an xml file using xerces DOM parser

Hi
I want to parse a simple xml file using DOM parser.
The file is
<Item>
     <SubItem>
          <title>SubItem0</title>
          <attr1>0</attr1>
          <attr2>0</attr2>
          <attr3>0</attr3>
     </SubItem>
     <SubItem>
          <title>SubItem1</title>
          <attr1>1</attr1>
          <attr2>0</attr2>
          <attr3>0</attr3>
     </SubItem>
     <SubItem>
          <title>SubItem2</title>
          <attr1>1</attr1>
          <attr2>1</attr2>
          <attr3>0</attr3>
          <SubItem>
               <title>SubItem20</title>
               <attr1>2</attr1>
               <attr2>1</attr2>
               <attr3>0</attr3>
          </SubItem>
          <SubItem>
               <title>SubItem21</title>
               <attr1>1</attr1>
               <attr2>1</attr2>
               <attr3>0</attr3>
          </SubItem>
     </SubItem>
</Item>
I just want to parse this file and want to store the values in desired datastructures,
I am trying using DOM parser, since it gives a tree structure, which is ok in this case.
public void init()
          InputReader ir     =new InputReader("Habsys");
          Document      doc     =ir.read("Habitat");
          System.out.println(doc);
          traverse(doc);
private void traverse(Document idoc)
          NodeList lchildren=idoc.getElementsByTagName("SubItem");
          for(int i=0;i<lchildren.getLength();i++)
               String lgstr=lchildren.item(i).getNodeName();
               if(lgstr.equals("SubItem"))
                    traverse(lchildren.item(i));
private void traverse (Node node) {
int type = node.getNodeType();
if (type == Node.ELEMENT_NODE)
System.out.println ("Name :"+node.getNodeName());
if(!node.hasChildNodes())
System.out.println ("Value :"+node.getNodeValue());
NodeList children = node.getChildNodes();
if (children != null) {
for (int i=0; i< children.getLength(); i++)
traverse (children.item(i));
But I am not getting required results, a lot of values I am getting as null
Could anybody tell me how to retrieve the data from the xml file, I simply want to read data and store it in data structures. For eg, for tag Subitem with title as ' SubItem1' has attr1 as '1', attr2 as'0' and attr3 as '0'.
Thanks
Gaurav

Check This Sample Code....
public void amethod(){
DocumentBuilderFactory dbf = null;
DocumentBuilder docBuilder = null;
Document doc = null;
try{
     dbf = DocumentBuilderFactory.newInstance();
     db = dbf.newDocumentBuilder();
     doc = db.parse(New File("path/to/your/file"));
     Node root = doc.getDocumentElement();
     System.out.println("Root Node = " + root.getNodeName());
     readNode(root);
}catch(FactoryConfigurationError fce){ fce.printStackTrace();
}catch(ParserConfigurationException pce){ pce.printStackTrace();
}catch(IOException ioe){ ioe.printStackTrace();
}catch(SAXException saxe){ saxe.printStackTrace();
private void readNode(Node node) {
System.out.println("Current Node = " + node.getNodeName());
readAttributes(node);
readChildren(node);
private void readAttributes(Node node) {
if (!node.hasAttributes())
     return;
System.out.println("Attributes:");
NamedNodeMap attrNodes = node.getAttributes();
for (int i=0; i<attrNodes.getLength(); i++) {
Attr attr = (Attr)attrNodes.item(i);
System.out.println(attr.getNodeName() + " => " + attr.getNodeValue());
private void readChildren(Node node) {
if (!node.hasChildNodes())
     return;
System.out.println("Value/s:");
NodeList childNodes = node.getChildNodes();
for (int i=0; i<childNodes.getLength(); i++) {
Node child = (Node)childNodes.item(i);
if (child.getNodeType() == Node.ELEMENT_NODE) {
readNode(child);
continue;
if (child.getNodeType() == Node.TEXT_NODE) {
if (child.getNodeValue()!=null)
System.out.println(child.getNodeValue());

How to write as XML file using java 1.5

hi all,
i am trying to create an XML file using java 1.5. I took a XML creating java file which was working with java 1.4 and ported same file into java 1.5 with changes according to the SAX and DOM implmentation in java 1.5 and tried to compile. But while writing as a file it throws error "cannot find the symbol."
can any body help me out to solve this issue.......
thankx in advance
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.w3c.dom.NamedNodeMap;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;
import org.xml.sax.DocumentHandler;
import org.xml.sax.InputSource;
import org.xml.sax.helpers.ParserFactory;
import java.io.*;
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
               dbf.setNamespaceAware(true);
DocumentBuilder db = dbf.newDocumentBuilder();
Document xmlDoc = db.newDocument();
// this creates the xml document ref
// parent node reference
Element rootnd = (Element) xmlDoc.createElement("ALL_TABLES");
// root node
xmlDoc.appendChild(rootnd);
Element rownd = (Element) xmlDoc.createElement("ROW");
rootnd.appendChild(rownd);
Element statusnd = (Element) xmlDoc.createElement("FILE_STATUS");
rownd.appendChild(statusnd);
statusnd.appendChild(xmlDoc.createTextNode("Y")
FileOutputStream outpt = new FileOutputStream(outdir + "//forbranch.xml");
Writer outf = new OutputStreamWriter(outpt, "UTF-8");
//error is occuring here Since write method is not available in the Document class
xmlDoc.write(outf);
outf.flush();

Hi,
when I look in the JDK1.4.2 specification I don't see any write method in the Document interface.
However, your solution is the Transformer class. There you transform your DOM tree into any output you need. Your code sould look something like this:     TransformerFactory tf = TransformerFactory.newInstance();
     // set all necessary features for your transformer -> see OutputKeys
     Transformer t = tf.newTransformer();
     t.transform(new DOMSource(xmlDoc), new StreamResult(file));Then you have your XML file stored in the file system.
Hope it helps.

Edit an XML file with SAX

Dear all, I am so confused�.
I have been trying for the last few days to understand how sax works� The only thing I understood is:
DefaultHandler handler = new Echo01();
SAXParserFactory factory = SAXParserFactory.newInstance();
        try {
            out = new OutputStreamWriter(System.out, "UTF8");
            SAXParser saxParser = factory.newSAXParser();
            saxParser.parse(file , handler);
        } catch (Throwable t) {
            t.printStackTrace();
        System.exit(0);
    }Ok, I assign the SAXParser the xml file and a handler. The parser parses and throws events that the handler catches. By implementing some handler interface or overriding the methods of an existing handler (e.g DeafultHandler class) I get to do stuff�
But still, suppose I have implement startElement() method of DefaultHandler class and I know that the pointer is currently placed on an element e.g. <name>bob</name>. How do I get the value of the element, and if I manage to do that, how can I replace�bob� with �tom�?
I would really appreciate any help given� just don�t recommend http://java.sun.com/webservices/jaxp/dist/1.1/docs/tutorial/ because although there are interesting staff in there, it does not solve my problem�

Maybe SAX is not the right tool for you.
With SAX, you implement methods like startElement and characters that get called as XML data is encountered by the parser. If you want to catch it or not, the SAX parser does not care. In your case, the "bob" part will be passed in one or more calls to characters. To safely process the data, you need to do something like build a StringBuffer or StringBuilder in the constructor of the class, and then in the startElement, if the name is one you want to read, set the length to zero. In the characters method, append the data to the StringBuilder or StringBuffer. In the endElement, do a toString to keep the data wherever you want.
This works for simple XML, but may need to be enhanced if you have nested elements with string values that contain other elements.
On the other hand, if your file is not huge, you could use DOM. With DOM, (or with JDOM, and I would expect with Dom4J -- but I have only used the first two) you do a parse and get a Document object with the entire tree. That allows you to easily (at least it is easy once you figure out how to do it) find a node like the "name" element and change the Text object that is its child from a value of "bob" to "tom". With DOM, you can then serialize the modified Document tree and save it as an XML file. SAX does not have any way to save your data. That burden falls to you entirely.
Dave Patterson

Exception thrown while reading an XML file using Properties

Exception thrown while reading an XML file using Properties.
Exception in thread "main" java.util.InvalidPropertiesFormatException: org.xml.sax.SAXParseException:
The processing instruction target matching "[xX][mM][lL]" is not allowed.
at java.util.XMLUtils.load(Unknown Source)
<?xml version="1.0"?>
<Config>
     <Database>
          <Product>FX.O</Product>
          <URL>jdbc:oracle:thin:@0.0.0.0:ABC</URL>
     </Database>
</Config>Am I missing anything?

Thanks a lot for all yr help.I have got the basics of
the DTD
However,when I say thus
<!DOCTYPE Config SYSTEM "c:/PartyConfig">
?xml version="1.0"?>
<Config>
     <Database>
          <Product>FX</Product>
          <URL>jdbc:oracle:thin:@0.0.0.0:ABC</URL>
     </Database>
</Config>I get the error
Invalid system identifier: file:///c:/ParyConfig.dtd
Please advise?for goodness sake, how many times do I have to tell you that you can't just expect the Properties class to accept arbitrary XML in any format? it reads XML in the format I linked to, and nothing else. Properties is not a general purpose XML binding. you can't do what you're trying to do with it. read this and in particular pay attention to the following
The XML document must have the following DOCTYPE declaration:
<!DOCTYPE properties SYSTEM "http://java.sun.com/dtd/properties.dtd">
Furthermore, the document must satisfy the properties DTD described above.
you are not reading my answers properly, are you? kindly do so

How to retrieve data (xml file) using jsp

I am a newbie to xml. I have decided to store my information in the xml file. may I know how can I retrieve my information from the xml file?
Thanx in advance.

I am a newbie to xml. I have decided to store my
information in the xml file. may I know how can I
retrieve my information from the xml file?
Thanx in advance.You can get the information from the XML file using one of the parsers available, such as Xerces http://xml.apache.org, and JDOM as an API.
Using this you have the option of having a SAXParser or a DOMParser.
SAX (Simple API for XML) is an event based parser, so if you know the XML structure, and need to find a certain element, you can just look for the element name,and retrieve the value of the element, it's attributes and its children.
DOM(Document Object Model)represents the XML as a tree, but uses more resources as it stores the entire tree in memory. But it is good in that you can traverse the whole tree.
JDOM would be a good idea too. If you download this, you can use it's API, which is very good, that will use the parser on your system (Xerces). I would definately recommend JDOM.

How to read the attribute of the xml file using jaxb

Thanks,
Buddy as i have a issue i have to read the xml file using jaxb and xml file contains this data and i have read the attribute like name , desc and action for a particular menu name pls tell the code how to do this it will be a great favour to me
thanx in advance
Rasool
<contextmenu>
<menu name='Lead' >
<menuitem name='newlead' desc='New Lead' action='/leads.do?dispatch=insert' />
<menuitem name='editlead' desc='Edit Lead' action='' />
<menuitem name='leadinfo' desc='Lead Information' action='' />
</menu>
<menu name='Cases' >
<menuitem name='' desc='' action='' />
<menuitem name='' desc='' action='' />
<menuitem name='' desc='' action='' />
</menu>
<menu name='Contact' >
<menuitem name='' desc='' action='' />
<menuitem name='' desc='' action='' />
<menuitem name='' desc='' action='' />
</menu>
</contextmenu>

What my program do is to get the encoding of XML files and convert them to UTF-8 encoding files, while I need this "encoding" information of the original XML document thus I can convert...
After reading specifications and JDOM docs, the truth turns to be disappointed, no function is provided to get this information in JDOM level 2(the current released one), while it's promissed that this function will be provided in JDOM level API....
Thanx all for your help and attention!!!

How to read the data from Excel file and Store in XML file using java

Hi All,
I got a problem with Excel file.
My problem is how to read the data from Excel file and Store in XML file using java excel api.
For getting the data from Excel file what are all the steps i need to follow to get the correct result.
Any body can send me the code (with java code ,Excel sheet) to this mail id : [email protected]
Thanks & Regards,
Sreenu,
[email protected],
india,

If you want someone to do your work, please have the courtesy to provide payment.
http://www.rentacoder.com

Getting error while running the XML file using XML Publisher Desktop

Hi all,
We have successfully loaded the XML file using XML Publisher Desktop. But when we preview the same using PDF format we are getting the following error.
Font Dir: C:\Program Files\Oracle\XML Publisher Desktop\Template Builder for Word\fonts
Run XDO Start
RTFProcessor setLocale: en-us
FOProcessor setData: C:\Documents and Settings\smanmadh\Desktop\ProductCompensationDT.xml
FOProcessor setLocale: en-us
java.lang.NullPointerException
     at oracle.apps.xdo.template.fo.area.PageNumber.formatString(PageNumber.java:104)
     at oracle.apps.xdo.template.fo.IDManager.registerId(IDManager.java:44)
     at oracle.apps.xdo.template.fo.area.AreaTree.registerLastPageJoinSeq(AreaTree.java:1106)
     at oracle.apps.xdo.template.fo.area.AreaTree.incrementJoinSequenceIndex(AreaTree.java:219)
     at oracle.apps.xdo.template.fo.area.AreaTree.registerLastPageDocument(AreaTree.java:1089)
     at oracle.apps.xdo.template.fo.area.AreaTree.forceOutput(AreaTree.java:471)
     at oracle.apps.xdo.template.fo.elements.FORoot.end(FORoot.java:58)
     at oracle.apps.xdo.template.fo.FOHandler.endElement(FOHandler.java:386)
     at oracle.xml.parser.v2.XMLContentHandler.endElement(XMLContentHandler.java:196)
     at oracle.xml.parser.v2.NonValidatingParser.parseElement(NonValidatingParser.java:1212)
     at oracle.xml.parser.v2.NonValidatingParser.parseRootElement(NonValidatingParser.java:301)
     at oracle.xml.parser.v2.NonValidatingParser.parseDocument(NonValidatingParser.java:268)
     at oracle.xml.parser.v2.XMLParser.parse(XMLParser.java:149)
     at oracle.apps.xdo.template.fo.FOProcessingEngine.process(FOProcessingEngine.java:279)
     at oracle.apps.xdo.template.FOProcessor.generate(FOProcessor.java:1022)
     at RTF2PDF.runRTFto(RTF2PDF.java:626)
     at RTF2PDF.runXDO(RTF2PDF.java:460)
     at RTF2PDF.main(RTF2PDF.java:251)
Thanks in Advance.
Sudeep.

This is BI related. You will get a quicker answer from the BI Publisher forum
BI Publisher

Error while running the XML file using XML Publisher Desktop

Hi All,
We have successfully loaded the XML file using XML Publisher Desktop.But when we try to preview it using the PDF format we are getting the following error.
Font Dir: C:\Program Files\Oracle\XML Publisher Desktop\Template Builder for Word\fonts
Run XDO Start
RTFProcessor setLocale: en-us
FOProcessor setData: C:\Documents and Settings\smanmadh\Desktop\ProductCompensationDT.xml
FOProcessor setLocale: en-us
java.lang.NullPointerException
     at oracle.apps.xdo.template.fo.area.PageNumber.formatString(PageNumber.java:104)
     at oracle.apps.xdo.template.fo.IDManager.registerId(IDManager.java:44)
     at oracle.apps.xdo.template.fo.area.AreaTree.registerLastPageJoinSeq(AreaTree.java:1106)
     at oracle.apps.xdo.template.fo.area.AreaTree.incrementJoinSequenceIndex(AreaTree.java:219)
     at oracle.apps.xdo.template.fo.area.AreaTree.registerLastPageDocument(AreaTree.java:1089)
     at oracle.apps.xdo.template.fo.area.AreaTree.forceOutput(AreaTree.java:471)
     at oracle.apps.xdo.template.fo.elements.FORoot.end(FORoot.java:58)
     at oracle.apps.xdo.template.fo.FOHandler.endElement(FOHandler.java:386)
     at oracle.xml.parser.v2.XMLContentHandler.endElement(XMLContentHandler.java:196)
     at oracle.xml.parser.v2.NonValidatingParser.parseElement(NonValidatingParser.java:1212)
     at oracle.xml.parser.v2.NonValidatingParser.parseRootElement(NonValidatingParser.java:301)
     at oracle.xml.parser.v2.NonValidatingParser.parseDocument(NonValidatingParser.java:268)
     at oracle.xml.parser.v2.XMLParser.parse(XMLParser.java:149)
     at oracle.apps.xdo.template.fo.FOProcessingEngine.process(FOProcessingEngine.java:279)
     at oracle.apps.xdo.template.FOProcessor.generate(FOProcessor.java:1022)
     at RTF2PDF.runRTFto(RTF2PDF.java:626)
     at RTF2PDF.runXDO(RTF2PDF.java:460)
     at RTF2PDF.main(RTF2PDF.java:251)
Any pointers will be of great help.
Thanks in Advance
Sudeep.

2¢
I had a similar error which when I searched, came up with this thread.
My issue was resolved after I discovered that my RTF template was not really RTF. It was sill in MS Word DOC format. This was discovered by reviewing two templates in NOTEPAD. The MS-DOC files have a lot of "special" characters in them. My RTF was not really RTF.
After doing a SAVE AS - RTF format, then the preview worked as expected.
Just Sharing...
--Tim

Split XML file using SAX

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