Buiding xml file using SAX parser of JAXP
Please send me xml building using the sax parser.This is the urgent requirement ,iam not geeting how to solve this problem.so please anybody can help with one best example
You don't build an XML file with a parser. A parser reads an XML file and converts it to some internal representation. Try reading this tutorial:
http://java.sun.com/xml/jaxp/dist/1.1/docs/tutorial/
Similar Messages
-
SAX: How to create new XML file using SAX parser
Hi,
Please anybody help me to create a XML file using the Packages in the 5.0 pack of java. I have successfully created it reading the tag names and values from database using DOM but can i do this using SAX.
I am successful to read XML using SAX, now i want to create new XML file for some tags and its values using SAX.
How can i do this ?
Sachin KulkarniSAX is a parser, not a generator.Well,
you can use it to create an XML file too. And it will take care of proper encoding, thus being much superior to a normal textwriter:
See the following code snippet (out is a OutputStream):
PrintWriter pw = new PrintWriter(out);
StreamResult streamResult = new StreamResult(pw);
SAXTransformerFactory tf = (SAXTransformerFactory) TransformerFactory.newInstance();
// SAX2.0 ContentHandler.
TransformerHandler hd = tf.newTransformerHandler();
Transformer serializer = hd.getTransformer();
serializer.setOutputProperty(OutputKeys.ENCODING, "UTF-8");//
serializer.setOutputProperty(OutputKeys.DOCTYPE_SYSTEM,"pdfBookmarks.xsd");
serializer.setOutputProperty(OutputKeys.DOCTYPE_SYSTEM,"http://schema.inplus.de/pdf/1.0");
serializer.setOutputProperty(OutputKeys.METHOD,"xml");
serializer.setOutputProperty(OutputKeys.INDENT, "yes");
hd.setResult(streamResult);
hd.startDocument();
//Get a processing instruction
hd.processingInstruction("xml-stylesheet","type=\"text/xsl\" href=\"mystyle.xsl\"");
AttributesImpl atts = new AttributesImpl();
atts.addAttribute("", "", "someattribute", "CDATA", "test");
atts.addAttribute("", "", "moreattributes", "CDATA", "test2");
hd.startElement("", "", "MyTag", atts);
String curTitle = "Something inside a tag";
hd.characters(curTitle.toCharArray(), 0, curTitle.length());
hd.endElement("", "", "MyTag");
hd.endDocument();
You are responsible for proper nesting. SAX takes care of encoding.
Hth
;-) stw -
How to Create XML file with SAX parser instead of DOM parser
HI ALL,
I am in need of creating an XML file by SAX parser ONLY. As far as my knowledge goes, we can use DOM for such purpose(by using createElement, creatAttribute ...). Can anyone tell me, is there any way to create an XML file using SAX Parser only. I mean, I just want to know whether SAX provides any sort of api for Creatign an element, attribute etc. I know that SAX is for event based parsing. But my requirement is to create an XML file from using only SAX parser.
Any help would be appreciated
Thanx in advance
KaushikHi,
You must write a XMLWriter class yourself, and that Class extends DefaultHandle ....., the overwrite the startElement(url, localName, qName, attributeList), startDocument(), endElement().....and so on.
in startElement write your own logic about how to create a new element and how to create a Attribute list
in startDocument write your own logic about how to build a document and encodeType, dtd....
By using:
XMLWriter out = new XMLWriter()
out.startDocument();
Attribute attr1 = new Atribute();
attr1.add("name", "value");
out.startElement("","","Element1", attr1);
Attribute attr2 = new Atribute();
attr2.add("name", "value");
out.startElement("","","Element2", attr2);
out.endElement("","","Element2");
out.endElement("","","Element1");
out.endDocument(); -
How can we get tag of XML file using SAX
Hi ,
I'm parsing one SAX parser , I'have almost done this parsing. i have faced problem for one case, i'e how can we get tag from XML file using SAX parser?
XML file is
<DFProperties>
<AccessType>
<Get/>
</AccessType> <Description>
gdhhd
</Description>
<DFFormat>
<chr/>
</DFFormat>
<Scope>
<Permanent/>
</Scope>
<DFTitle>gsgd</DFTitle>
<DFType>
<MIME>text/plain</MIME>
</DFType>
</DFProperties>
I want out like GET and Permanent... means this one tag which is present inside of another tag.
Handler class like
public void startElement(String namespaceURI, String localName,
String qName, Attributes atts) throws SAXException {
if(_ACCESSTYPE.equals(localName)){
accessTypeElement=ACCESSTYPE;
public void characters(char[] ch, int start, int length)
throws SAXException {
if (_ACCESSTYPE.equals(_accessTypeElement)) {
String strValue = new String(ch, start, length);
System.out.println("Accestype-----------------------------> " + strValue);
//System.out.println(" " + strValue);
public void endElement(String namespaceURI, String localName, String qName)
throws SAXException {
if (_ACCESSTYPE.equals(localName)) {
_accessTypeElement = "";
. please any body help meHi ,
I have one problem,Please help me.
1. How can I'll identify where exactly my Node is ended,means how how can we find corresponding nodename? in partcular place
<Node> .............starttag1
<NodeName>Test</NodeName>
<Node>................starttag2
<nodeName>test1</NodeName>
</Node>..................endtag2
<Node>.....................starttag3
<NodeName><NodeName>
<Node> .........................starttag4
<NodeName>test4</NodeName>
</Node>.......enddtag4
</Node>...........end tag3
</Node>............endtag1
my code is below
private final String _NODENAME = "NodeName";
private final String _NODE = "Node";
private String _nodeElement = "";
private String _NodeNameElement = "";
public void startElement(String namespaceURI, String localName,
String qName, Attributes atts) throws SAXException {
if (_NODENAME.equals(localName)) {
NodeNameElement = NODENAME;
if(_NODE.equals(localName)){
System.out.println("start");
if (_NODENAME.equals(localName)) {
NodeNameElement = NODENAME;
public void characters(char[] ch, int start, int length)
throws SAXException {
if (_NODENAME.equals(_NodeNameElement)) {
String strValue = new String(ch, start, length);
String sttt=strValue;
System.out.println("NODENAME: ************* " + strValue);
if(_NODE.equals(_nodeElement)){
if (_NODENAME.equals(_NodeNameElement)) {
String strValue = new String(ch, start, length);
String sttt=strValue;
System.out.println("nodevalue********** " + strValue);
public void endElement(String namespaceURI, String localName, String qName)
throws SAXException {
if (_NODENAME.equals(localName)) {
_NodeNameElement = "";
if(_NODE.equals(localName)){
System.out.println("NODENAME: %%%%%%%%%");
please help me. How can I figure node ending for particular nodename -
Updating XML file using DOM parser
Hi,
Can someone help me, how to update following XML file using DOM parser.
The following is my XML file.
<students>
<student>
<id>1</id>
<name>abc</name>
</student>
<student>
<id>2</id>
<name>xyz</name>
</student>
<student>
<id>3</id>
<name/>
</student>
<student>
<id>4</id>
<name>ijk</name>
</student>
<student>
<id>5</id>
<name></name>
</student>
</students>Consider, I will input 2 fields, ie., id & name. For the matching Id, the name has to be updated.
Though, I have achieved this, but I am unable to update the value for 3rd record, & 5th record ie., id=3 & id=5. Since, these are blank.
Thanks.Some <name> elements have a child node which is a text node. From what you say it appears you know how to change those text nodes.
The other <name> elements don't have any child nodes. But you want one. This suggests to me that you need code that creates a text node and adds it to the <name> element as its child. -
Cannot close an XML file used for parsing
Hi All,
I appears to have difficulty closing (possibly flushing it first) an XML file that was subsequently being parsed without success. The error generated is:
org.jdom.input.JDOMParseException: Error on line 23: The element type "form" must be terminated by the matching end-tag "</form>".
Below is the code snippets of readData() to retrieve (HTML) data from a website, save it to a file, then convert to XML format before returning the new filename:
public String readData() {
try {
URL url = new URL("http://www.abc.com");
URLConnection connection = url.openConnection();
InputStream isInHtml = url.openStream(); // throws an IOException
disInHtml = new DataInputStream(new BufferedInputStream(isInHtml));
System.out.flush();
FileOutputStream fosOutHtml = null;
fosOutHtml = new FileOutputStream("C:\\Temp\\ABC.html");
int oneChar, count=0;
while ((oneChar=disInHtml.read()) != -1)
fosOutHtml.write(oneChar);
isInHtml.close();
disInHtml.close();
fosOutHtml.flush(); // optional
fosOutHtml.close();
try {
File fileInHtml = new File("C:\\Temp\\ABC.html");
FileReader frInHtml = new FileReader(fileInHtml);
BufferedReader brInHtml = new BufferedReader(frInHtml);
String string = "";
while (brInHtml.ready())
string += brInHtml.readLine() + "\n";
fwOutXml = new FileWriter("C:\\Temp\\ABC.xml");
pwOutXml = new PrintWriter(fwOutXml);
light_html2xml html2xml = new light_html2xml();
pwOutXml.print(html2xml.Html2Xml(string));
system.out.flush() // optional
fwOutXml.flush(); // optional
fwOutXml.close();
pwOutXml.flush(); // optional
pwOutXml.close();
return fileInHtml.getAbsolutePath();
// parseData reads the XML file using the name returned by readData()
public void parseData(String XMLFilename)
try
FileReader frInXml = new FileReader(FileName);
BufferedReader brInXml = new BufferedReader(frInXml);
SAXBuilder saxBuilder = new SAXBuilder("org.apache.xerces.parsers.SAXParser"); // JDOMParseException generated.
}These codes would worked when they were in a single method but I have since placed some structure around them using a number methods.
This issue has risen in th past where I have been able to close the XML file prior to reading them again. However, I don't have a solution for it this time round.
I am running JDK 1.6.0_10, Netbeans 6.1, JDOM 1.1 on Windows XP platform.
Any assistance would be appreciated.
Many thanks,
JackHi Alain,
I have added the additional I/O statements in the finally clause as follows but the problem still persisted:
readData()
// reading data (html) from the webpage and save it in html format.
try {
catch { . }
finally {
System.out.flush();
isInHtml.close();
disInHtml.close();
fosOutHtml.flush();
fosOutHtml.getFD().sync();
fosOutHtml.close();
// convert the html webpage format to xml format
try {
catch { . }
finally {
System.out.flush();
fwOutXml.flush();
fwOutXml.close();
pwOutXml.flush();
pwOutXml.close();
Below is a short listing of the new XML file:
<?xml version="1.0" encoding="iso-8859-1" ?>
- <html>
- <head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<meta name="keywords" content="California, cities, towns, villages, list, zipcodes, postal codes, united states, ca" />
<meta name="description" content="Cities, towns and suburbs in California, United States (CA) starting with A" />
<title>Cities and Towns in California starting with A ABC Company</title>
<link rel="stylesheet" href="http://www.abc.com/style.css" type="text/css" media="screen" />
</head>
- <body>
<a name="top" />
- <div id="container">
- <div id="header">
<div id="postmark" />
- <a href="http://www.abc.com/" class="imglink">
<img id="logoimg" src="http://www.abc.com/images/zipcodes.gif" width="192" height="33" alt="Zipcodes America Logo" />
</a>
<hr />
</div>
- <div id="nav">
- <ul>
- <li>
<a href="http://www.abc.com/" title="Home Page">Home</a>
</li>
- <li>
<strong>Search</strong>
(zipcode or suburb)
- <div class="hide">
<form method="post" action="http://www.abc.com/search" /> // line 23
</div>
<input type="text" name="q" class="searchbox" alt="Search query" />
<br />
<input type="submit" value="find!" class="searchbutton" alt="Perform search" />
<div class="hide" />
</li>
What I find it interesting is that it is possible to parse the above XML file with the same parseData() from another class without any problem. As a result, I have come to the following conclusion so far:
( i ) There is some file locking that is prevent saxBuilder from parsing the XML file at the time.
( ii ) The light_html2xml does not appears to have correctly converted over the orginal Html to Xml but some how it has been picked up by the parser in the same class, but not by the same parser from another class.
( iii ) I would like to use another conversion tool such as Tagsoup in place of light_html2xml to determine where the cause of this issue is coming from. As a result, would you or anyone be able to assist me coming up with a few lines of conversion statements using Tagsoup since I am not familiar with using this tool?
( iv ) light_html2xml is good as it strip out all namespace, DTD, Entity Resolver, etc and only return what I need. JTidy does correct conversion but include namespace, DTD, Entity Resolver which makes parsing difficulty.
Many thanks again,
Jack -
Reading from XML file using DOM parser.
Hi,
I have written the following java code to read the XML file and print the values. It reads the XML file. It gets the node NAME and prints it. But it returns null when trying to get the node VALUE. I am unable to figure out why.
Can anyone please help me with this.
Thanks and Regards,
Shweta
import java.io.*;
import java.net.*;
import java.util.*;
import oracle.xml.parser.v2.*;
import org.w3c.dom.*;
import org.xml.sax.SAXException;
public class ReadNodes
private static XMLDocument mDoc;
public ReadNodes () {
try {
DOMParser lParser = new DOMParser();
URL lUrl = createURL("mot.xml");
System.out.println("after creating the URL object ");
lParser.setErrorStream(System.out);
lParser.showWarnings(true);
lParser.parse(lUrl);
mDoc = lParser.getDocument();
System.out.println("after creating the URL object "+mDoc);
lParser.reset();
} catch (Exception e) {
e.printStackTrace();
} // end catch block
} // End of constructor
public void read() throws DOMException {
try {
NodeList lTrans = this.mDoc.getElementsByTagName("TRANSLATION");
for(int i=0;i<lTrans.getLength();i++) {
NodeList lTrans1 = lTrans.item(i).getChildNodes();
System.out.println("lTrans1.item(0).getNodeName : " + lTrans1.item(0).getNodeName());
System.out.println("lTrans1.item(0).getNodeValue : " + lTrans1.item(0).getNodeValue());
System.out.println("lTrans1.item(1).getNodeName : " + lTrans1.item(1).getNodeName());
System.out.println("lTrans1.item(1).getNodeValue : " + lTrans1.item(1).getNodeValue());
} catch (Exception e) {
System.out.println("Exception "+e);
e.printStackTrace();
} catch (Throwable t) {
System.out.println("Exception "+t);
public static URL createURL(String pFileName) throws MalformedURLException {
URL url = null;
try {
url = new URL(pFileName);
} catch (MalformedURLException ex) {
File f = new File(pFileName);
String path = f.getAbsolutePath();
String fs = System.getProperty("file.separator");
System.out.println(" path of file : "+path +"separator " +fs);
if (fs.length() == 1) {
char sep = fs.charAt(0);
if (sep != '/')
path = path.replace(sep, '/');
if (path.charAt(0) != '/')
path = '/' + path;
path = "file://" + path;
System.out.println("path is : "+path);
// Try again, if this throws an exception we just raise it up
url = new URL(path);
} // End catch block
return url;
} // end method create URL
public static void main (String args[]) {
ReadNodes mXML = new ReadNodes();
mXML.read();
The XML file that I am using is
<?xml version = "1.0"?>
<DOCUMENT>
<LANGUAGE_TRANS>
<TRANSLATION>
<CODE>3</CODE>
<VALUE>Please select a number</VALUE>
</TRANSLATION>
<TRANSLATION>
<CODE>5</CODE>
<VALUE>Patni</VALUE>
</TRANSLATION>
<TRANSLATION>
<CODE>6</CODE>
<VALUE>Status Messages</VALUE>
</TRANSLATION>
<TRANSLATION>
<CODE>7</CODE>
<VALUE>Progress</VALUE>
</TRANSLATION>
<TRANSLATION>
<CODE>8</CODE>
<VALUE>Create Data Files...</VALUE>
</TRANSLATION>
<TRANSLATION>
<CODE>9</CODE>
<VALUE>OK</VALUE>
</TRANSLATION>
</LANGUAGE_TRANS>
</DOCUMENT>because what you want is not the node value of CODE but the node value of the text nodes into it!
assuming only one text node into it, try this:
System.out.println("lTrans1.item(0).getNodeName : " + lTrans1.item(0).getFirstChild().getNodeValue()); -
Hello
Can some one tell me How do I go about splitting a large XML int smaller files using the SAX Parser.
I have ruled out the use of dom taking memory overhead into consideration.
I should be able to pass the number of records that go into each files
dynamically.
If some one can share their code snippet, that would be great
cheer
rachansI need each split file to be well formed, its not just chopping the big file into pieces...
the structure of large file is something like this
<root>
<header>
</header>
<body>
<records>
</records>
<records>
</records>
</body>
</root>
now the split file looks like this
<root>
<header>
</header>
<body>
<records>
</records>
</body>
</root>
I will need to split by a number, if say 2 then each file will have 2 records.....the header is the same for all files...hope this explanation helps.. -
Parsing the large XML ( 1GB) using SAX PARSER
We have very large XMLs being generated by processes. These XMLs should be validated first and then parsed next. We have implementation that works for small files. My question is
how can we validate and parse large XMLs with SAX parser?The same way as parsing a small XML file, no? Why don't you try it? Then if you have problems that you can't solve, ask about them here.
-
Reading xml file with sax parser: unknown protocol: c
Hi,
I've been googling around, and the best I can find is that the file name:
File test = new File("lib/test/parseTest/validate-test.xml");should be a url:
File test = new File("File://lib/test/parseTest/validate-test.xml");but I'm working on a linux machine and can't put "File://c:/pathToFile/file.xml"
Also, I did some testing and I can read a small xml file with just a few elements, but on large complex files, I get that error.
anyone ever run into this before?
bp
Edited by: badperson on Nov 1, 2008 2:19 PMbadperson wrote:
I've been googling around, and the best I can find is that the file name:
File test = new File("lib/test/parseTest/validate-test.xml");should be a url:
File test = new File("File://lib/test/parseTest/validate-test.xml");
No, that's wrong. The parameter for that constructor is a file path (relative or absolute). Not a URL. You must have misunderstood whatever you read.
but I'm working on a linux machine and can't put "File://c:/pathToFile/file.xml"What kind of a Linux machine is this which has a C drive? You must have misunderstood whoever told you to do that. -
Read any XML File Elements using SAX Parser in J2se
Hi All
I can able to parsed one structured XML file using SAX
Sample code :
// ===========================================================
// SAX DocumentHandler methods
// ===========================================================
public void startDocument() throws SAXException {
logger.info("Start of document");
public void endDocument() throws SAXException {
logger.info("End of document");
public void startElement(String namespaceURI, String localName, // local
// name
String qualName, // qualified name
Attributes attrs) throws SAXException {
elemName = new String(localName); // element name
if (elemName.equals(""))
elemName = new String(qualName); // namespaceAware = false
tagPosition = TAG_START;
// Set the string for accumulating the text in a tag to empty
elemChars = "";
// If the element name is "row", create a new row instance
// If the element is "indexxid", "ModelPrice", or "ModelSpread",
// the value will be read in the method "characters" and stored.
if (elemName.equals("row")) {
row = new IndexRow();
numRows++;
// logger.info("Number of numRow:"+numRows);
} // end method startElement
public void endElement(String namespaceURI, String simpleName, // simple
// name
String qualName // qualified name
) throws SAXException {
elemName = new String(simpleName);
if (elemName.equals(""))
elemName = new String(qualName); // namespaceAware = false
tagPosition = TAG_END;
String indexId = new String();
Double dblVal = new Double(0);
// If element name is "row", put the current row in the map for row
// instances
if (elemName.equals("row")) {
if (numRows <= 5) { logger.info("Row is: " + row.toString()); }
//ABX
//indexRows.put(row.getIndexxId(), row);
if (family.equals("ABX.HE")){
indexRows.put(row.getIndexREDId(), row);
else {
//CDX ITRXX
indexRows.put(row.getIndexxId(), row);
} else if (elemName.equals("IndexID")) {
row.setIndexxId(elemChars);
// Leave double value at default of zero if there are no chars
if (elemChars.trim().length() != 0) {
dblVal = new Double(elemChars);
row.setCompositeSpread(dblVal);
indexId = row.getIndexxId();
} else if (elemName.equals("REDCode")) {
row.setRedCode(elemChars);
else if (elemName.equals("Name")) {
row.setRowName(elemChars);
} else if (elemName.equals("Series")) {
row.setSeries(elemChars);
} else if (elemName.equals("Version")) {
row.setVersion(elemChars);
} else if (elemName.equals("Term")) {
row.setTerm(elemChars);
} else if (elemName.equals("Maturity")) {
row.setMaturity(elemChars);
} else if (elemName.equals("OnTheRun")) {
row.setOnTheRun(elemChars);
} else if (elemName.equals("Date")) {
row.setRowDate(elemChars);
} else if (elemName.equals("Depth")) {
row.setDepth(elemChars);
else if (elemName.equals("Heat")) {
// logger.info("Chars for element " + elemName + " are '" +
// elemChars + "'");
// Leave double value at default of zero if there are no chars
if (elemChars.trim().length() != 0) {
dblVal = new Double(elemChars);
row.setHeat(dblVal);
indexId = row.getIndexxId();
// ABX.HE
else if (elemName.equals("IndexREDId")){
row.setIndexREDId(elemChars);
else if (elemName.equals("Coupon")){
row.setCoupon(elemChars);
if (elemName.equals("Ontherun")) {
row.setOnTheRun(elemChars);
} // end method endElement
public void characters(char buf[], int offset, int len) throws SAXException {
// If at end of element, there will be no characters
if (tagPosition == TAG_END) {
return;
// The characteres method may be called more than once
// for an element if the internal buffer fills up.
// Append the characters until the end of the element.
String strVal = new String(buf, offset, len);
elemChars = elemChars + strVal;
} // end method characters
} // end class MarkItIndexLoader
but the problem is i want to read (parse) any XML file means any Elemets would be change any time using SAX .In the above example
else if (elemName.equals("Heat")) {
else if (elemName.equals("IndexREDId")){
} else if (elemName.equals("Maturity")) {
like above I am doing hard code Elements names and reading the values so i don't want hard coding the elements names I want to read any element name and value dynamically.
If i give any one below XML file i want to read the Elements and displaying to console without changing any code i want to read the XML document.
EX:
Student.XML: <root>..</StName>..</StAge>...</root>
Employee.XML: <root>..</EmpName>..</EmpAge>...</root>
CdCatalog.XML: <root>..</Cdtitle>...</CdNumber>...</root>
I need one java program can ready any type of XML file elements and send to the Database table.
Please any one done like this task please suggest some reference links or books or sample snippet which can help me to develop program in my requirement.
Thanks in advance
Regards
satishYou should ask in the Java forum.
Regards
Stefan -
Parsing an xml file using xerces DOM parser
Hi
I want to parse a simple xml file using DOM parser.
The file is
<Item>
<SubItem>
<title>SubItem0</title>
<attr1>0</attr1>
<attr2>0</attr2>
<attr3>0</attr3>
</SubItem>
<SubItem>
<title>SubItem1</title>
<attr1>1</attr1>
<attr2>0</attr2>
<attr3>0</attr3>
</SubItem>
<SubItem>
<title>SubItem2</title>
<attr1>1</attr1>
<attr2>1</attr2>
<attr3>0</attr3>
<SubItem>
<title>SubItem20</title>
<attr1>2</attr1>
<attr2>1</attr2>
<attr3>0</attr3>
</SubItem>
<SubItem>
<title>SubItem21</title>
<attr1>1</attr1>
<attr2>1</attr2>
<attr3>0</attr3>
</SubItem>
</SubItem>
</Item>
I just want to parse this file and want to store the values in desired datastructures,
I am trying using DOM parser, since it gives a tree structure, which is ok in this case.
public void init()
InputReader ir =new InputReader("Habsys");
Document doc =ir.read("Habitat");
System.out.println(doc);
traverse(doc);
private void traverse(Document idoc)
NodeList lchildren=idoc.getElementsByTagName("SubItem");
for(int i=0;i<lchildren.getLength();i++)
String lgstr=lchildren.item(i).getNodeName();
if(lgstr.equals("SubItem"))
traverse(lchildren.item(i));
private void traverse (Node node) {
int type = node.getNodeType();
if (type == Node.ELEMENT_NODE)
System.out.println ("Name :"+node.getNodeName());
if(!node.hasChildNodes())
System.out.println ("Value :"+node.getNodeValue());
NodeList children = node.getChildNodes();
if (children != null) {
for (int i=0; i< children.getLength(); i++)
traverse (children.item(i));
But I am not getting required results, a lot of values I am getting as null
Could anybody tell me how to retrieve the data from the xml file, I simply want to read data and store it in data structures. For eg, for tag Subitem with title as ' SubItem1' has attr1 as '1', attr2 as'0' and attr3 as '0'.
Thanks
GauravCheck This Sample Code....
public void amethod(){
DocumentBuilderFactory dbf = null;
DocumentBuilder docBuilder = null;
Document doc = null;
try{
dbf = DocumentBuilderFactory.newInstance();
db = dbf.newDocumentBuilder();
doc = db.parse(New File("path/to/your/file"));
Node root = doc.getDocumentElement();
System.out.println("Root Node = " + root.getNodeName());
readNode(root);
}catch(FactoryConfigurationError fce){ fce.printStackTrace();
}catch(ParserConfigurationException pce){ pce.printStackTrace();
}catch(IOException ioe){ ioe.printStackTrace();
}catch(SAXException saxe){ saxe.printStackTrace();
private void readNode(Node node) {
System.out.println("Current Node = " + node.getNodeName());
readAttributes(node);
readChildren(node);
private void readAttributes(Node node) {
if (!node.hasAttributes())
return;
System.out.println("Attributes:");
NamedNodeMap attrNodes = node.getAttributes();
for (int i=0; i<attrNodes.getLength(); i++) {
Attr attr = (Attr)attrNodes.item(i);
System.out.println(attr.getNodeName() + " => " + attr.getNodeValue());
private void readChildren(Node node) {
if (!node.hasChildNodes())
return;
System.out.println("Value/s:");
NodeList childNodes = node.getChildNodes();
for (int i=0; i<childNodes.getLength(); i++) {
Node child = (Node)childNodes.item(i);
if (child.getNodeType() == Node.ELEMENT_NODE) {
readNode(child);
continue;
if (child.getNodeType() == Node.TEXT_NODE) {
if (child.getNodeValue()!=null)
System.out.println(child.getNodeValue()); -
Code to read xml file and display that data using sax parser
Hai
My problem I have to read a xml file and display the contents of the file on console using sax parser.here you go
-
How to create new XML file using retreived XML content by using SAX API?
hi all,
* How to create new XML file using retreived XML content by using SAX ?
* I have tried my level best, but output is coming invalid format, my code is follows,
XMLFileParser.java class :-
import java.io.StringReader;
import java.io.StringWriter;
import javax.xml.transform.OutputKeys;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerConfigurationException;
import javax.xml.transform.TransformerException;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMResult;
import javax.xml.transform.sax.SAXSource;
import javax.xml.transform.sax.SAXTransformerFactory;
import javax.xml.transform.sax.TransformerHandler;
import javax.xml.transform.stream.StreamResult;
import org.w3c.dom.Document;
import org.xml.sax.Attributes;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.XMLFilterImpl;
public class PdfParser extends XMLFilterImpl {
private TransformerHandler handler;
Document meta_data;
private StringWriter meta_data_text = new StringWriter();
public void startDocument() throws SAXException {
void startValidation() throws SAXException {
StreamResult streamResult = new StreamResult(meta_data_text);
SAXTransformerFactory factory = (SAXTransformerFactory) SAXTransformerFactory.newInstance();
try
handler = factory.newTransformerHandler();
Transformer transformer = handler.getTransformer();
transformer.setOutputProperty(OutputKeys.ENCODING, "UTF-8");
transformer.setOutputProperty(OutputKeys.INDENT, "yes");
handler.setResult(streamResult);
handler.startDocument();
catch (TransformerConfigurationException tce)
System.out.println("Error during the parse :"+ tce.getMessageAndLocation());
super.startDocument();
public void startElement(String namespaceURI, String localName,
String qualifiedName, Attributes atts) throws SAXException {
handler.startElement(namespaceURI, localName, qualifiedName, atts);
super.startElement(namespaceURI, localName, qualifiedName, atts);
public void characters(char[] text, int start, int length)
throws SAXException {
handler.characters(text, start, length);
super.characters(text, start, length);
public void endElement(String namespaceURI, String localName,
String qualifiedName) throws SAXException {
super.endElement("", localName, qualifiedName);
handler.endElement("", localName, qualifiedName);
public void endDocument() throws SAXException {
void endValidation() throws SAXException {
handler.endDocument();
try {
TransformerFactory transfactory = TransformerFactory.newInstance();
Transformer trans = transfactory.newTransformer();
SAXSource sax_source = new SAXSource(new InputSource(new StringReader(meta_data_text.toString())));
DOMResult dom_result = new DOMResult();
trans.transform(sax_source, dom_result);
meta_data = (Document) dom_result.getNode();
System.out.println(meta_data_text);
catch (TransformerConfigurationException tce) {
System.out.println("Error occurs during the parse :"+ tce.getMessageAndLocation());
catch (TransformerException te) {
System.out.println("Error in result transformation :"+ te.getMessageAndLocation());
} CreateXMLFile.java class :-
Sax.startDocument();
Sax.startValidation();
Sax.startElement("", "pdf", "pdf", new AttributesImpl());
Sax.startElement("", "basic-metadata", "basic-metadata", new AttributesImpl());
String xmp_str = new String(meta_data.getByteArray(),"UTF8");
char[] xmp_arr = xmp_str.toCharArray();
Sax.characters(xmp_arr, 0, xmp_arr.length);
Sax.endElement("", "pdf", "pdf");
Sax.endValidation();
Sax.endDocument();
Sax.endElement("", "basic-metadata", "basic-metadata");* In CreateXMLFile.java
class, I have retreived the xml content in the meta_data object, after that i have converted into character array and this will be sends to SAX
* In this case , the XML file created successfully but the retreived XML content added as an text in between basic-metadata Element, that is, retreived XML content
is not an XML type text, it just an Normal text Why that ?
* Please help me what is the problem in my code?
Cheers,
JavaImranSax.startDocument();
Sax.startValidation();
Sax.startElement("", "pdf", "pdf", new AttributesImpl());
Sax.startElement("", "basic-metadata", "basic-metadata", new AttributesImpl());
String xmp_str = new String(meta_data.getByteArray(),"UTF8");
char[] xmp_arr = xmp_str.toCharArray();
Sax.characters(xmp_arr, 0, xmp_arr.length);
</code><code>Sax.endElement("", "basic-metadata", "basic-metadata");</code>
<code class="jive-code jive-java">Sax.endElement("", "pdf", "pdf");
Sax.endValidation();
Sax.endDocument();
* I HAVE CHANGED MY AS PER YOUR SUGGESTION, NOW SAME RESULT HAS COMING.
* I AM NOT ABLE TO GET THE EXACT OUTPUT.,WHY THAT ?
Thanks,
JavaImran{code} -
Hello
I need to convert xml files to csv format using SAX Parser. The following code & outputs are as below:
XML file:
<Library>
<Book>
<Title>Professional JINI</Title>
<Author>bs</Author>
<Publisher>Oreilly Publications</Publisher>
</Book>
<Book>
<Title>XML Programming</Title>
<Author>java</Author>
<Publisher>Mann Publications</Publisher>
</Book>
</Library>
public class BooksLibrary extends DefaultHandler
protected static final String XML_FILE_NAME = "C:\\library1.xml";
public static void main (String argv [])
// Use the default (non-validating) parser
SAXParserFactory factory = SAXParserFactory.newInstance();
try {
FileOutputStream fos=new FileOutputStream("C:/test.txt");
// Set up output stream
out = new OutputStreamWriter (fos, "UTF8");
// Parse the input
SAXParser saxParser = factory.newSAXParser();
saxParser.parse( new File(XML_FILE_NAME), new BooksLibrary() );
} catch (Throwable t) {
t.printStackTrace ();
System.exit (0);
static private Writer out;
//===========================================================
// Methods in SAX DocumentHandler
//===========================================================
public void startDocument ()
throws SAXException
showData ("<?xml version='1.0' encoding='UTF-8'?>");
newLine();
public void endDocument ()
throws SAXException
try {
newLine();
out.flush ();
} catch (IOException e) {
throw new SAXException ("I/O error", e);
public void startElement (String name, Attributes attrs)
throws SAXException
showData ("<"+name);
if (attrs != null) {
for (int i = 0; i < attrs.getLength (); i++) {
showData (" ");
showData (attrs.getLocalName(i)+"=\""+attrs.getValue (i)+"\"");
showData (">");
public void endElement (String name)
throws SAXException
showData ("</"+name+">");
public void characters (char buf [], int offset, int len)
throws SAXException
String s = new String(buf, offset, len);
showData (s);
//===========================================================
// Helpers Methods
//===========================================================
// Wrap I/O exceptions in SAX exceptions, to
// suit handler signature requirements
private void showData (String s)
throws SAXException
try {
out.write (s);
out.flush ();
} catch (IOException e) {
throw new SAXException ("I/O error", e);
// Start a new line
private void newLine ()
throws SAXException
//String lineEnd = System.getProperty("line.separator");
try {
out.write (", ");
} catch (IOException e) {
throw new SAXException ("I/O error", e);
--------------------------------------------------------------------------------------------------output is as follows:
<?xml version='1.0' encoding='UTF-8'?>,
Professional JINI
bs
Oreilly Publications
XML Programming
java
Mann Publications
Can anyone please tell me how to remove that indentation space & get the output as :
<?xml version='1.0' encoding='UTF-8'?>, Professional JINI, bs, Oreilly Publications, XML Programming, java, Mann Publications
ThanksBy the way, there is a new feature in Java 5.0 (Tiger) called "Annotations."
Since your code extneds DefaultHandler, you could specify a line with
@Override
before the definition of each of your methods. If you had used these, the compiler would have given an error since your methods did not override the methods of DefaultHandler.
(If your code implemented ContentHandler, by contrast, using @Override is invalid because you need to implement all of the methods defined in the interface definition.)
The other comment is that the safest way to handle characters() data is to use a StringBuilder/Buffer (StringBuilder is only valid in 5.0, StringBuffer has been around since Release 1.0) that you define in the startElement method. Use the append method to gather data presented to you in the characters() method and use toString() to harvest the data in the endElement method.
Dave Patterson
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