Sql Help: same address diff phone

Question

hello every one,
i am having problem finding pid with same address and diff phone number, i am having difficulti finding it, i am able to find the pid with more then one record for one pid.
please help me.
WITH prov AS (
SELECT '700804' pid FROM dual UNION ALL
SELECT '6325886' pid FROM dual UNION ALL
SELECT '8007504' pid FROM dual UNION ALL
SELECT '8007500' pid FROM dual
office AS
SELECT '700804' pid , '7495 ' OID , '7937' locid ,9132549495 Tel  FROM dual UNION ALL
SELECT '700804' pid , '7496 ' OID , '84785' locid ,6202329240 Tel  FROM dual UNION ALL
SELECT '700804' pid , '7497 ' OID , '226174' locid ,9132549495 Tel  FROM dual UNION ALL
SELECT '700804' pid , '2843169 ' OID , '1381976' locid ,9132549495 Tel  FROM dual UNION ALL
SELECT '700804' pid , '2075990 ' OID , '7936' locid ,9132549495 Tel  FROM dual UNION ALL
SELECT '700804' pid , '2593350 ' OID , '1302121' locid ,9133904800 Tel  FROM dual UNION ALL
SELECT '6325886' pid , '994858 ' OID , '569831' locid ,5634216000 Tel  FROM dual UNION ALL
SELECT '6325886' pid , '2773186 ' OID , '1356079' locid ,5634215104 Tel  FROM dual UNION ALL
SELECT '6325886' pid , '2551157 ' OID , '1024134' locid ,5634213408 Tel  FROM dual UNION ALL
SELECT '6325886' pid , '2985680 ' OID , '1449948' locid ,5634213040 Tel  FROM dual UNION ALL
SELECT '6325886' pid , '2152445 ' OID , '1132731' locid ,5636591548 Tel  FROM dual UNION ALL
SELECT '6325886' pid , '2773187 ' OID , '1356095' locid ,NULL Tel  FROM dual UNION ALL
SELECT '6325886' pid , '2730132 ' OID , '696373' locid ,5636599137 Tel  FROM dual UNION ALL
SELECT '8007504' pid , '4078448 ' OID , '377656' locid ,8009623303 Tel  FROM dual UNION ALL
SELECT '8007504' pid , '4078450 ' OID , '1665053' locid ,6185292247 Tel  FROM dual UNION ALL
SELECT '8007504' pid , '4078451 ' OID , '1225238' locid ,8009623303 Tel  FROM dual UNION ALL
SELECT '8007504' pid , '2659200 ' OID , '1321265' locid ,6185490721 Tel  FROM dual UNION ALL
SELECT '8007504' pid , '3966923 ' OID , '377655' locid ,6185490721 Tel  FROM dual UNION ALL
SELECT '8007504' pid , '3966925 ' OID , '1638128' locid ,6185490721 Tel  FROM dual UNION ALL
SELECT '8007500' pid , '3966900 ' OID , '377600' locid ,7325493200 Tel  FROM dual
, loc AS
SELECT  '7936' locid, 'Po Box 910' address, 'Andover' city, 'KS'state  FROM dual UNION ALL
SELECT  '7937' locid, 'PO Box 910' address, 'Andover' city, 'KS'state  FROM dual UNION ALL
SELECT  '84785' locid, '2525 N Broadway' address, 'Pittsburg' city, 'KS'state  FROM dual UNION ALL
SELECT  '226174' locid, '11918 So Strangline Rd' address, 'Olathe' city, 'KS'state  FROM dual UNION ALL
SELECT  '377655' locid, '818 E Broadway' address, 'Sparta' city, 'IL'state  FROM dual UNION ALL
SELECT  '377656' locid, '818 E Broadway St' address, 'Sparta' city, 'IL'state  FROM dual UNION ALL
SELECT  '569831' locid, '1227 E Rusholme St' address, 'Davenport' city, 'IA'state  FROM dual UNION ALL
SELECT  '696373' locid, '865 Lincoln Rd # L10' address, 'Bettendorf' city, 'IA'state  FROM dual UNION ALL
SELECT  '1024134' locid, 'PO Box 310083' address, 'Des Moines' city, 'IA'state  FROM dual UNION ALL
SELECT  '1132731' locid, '1008 11th St' address, 'De Witt' city, 'IA'state  FROM dual UNION ALL
SELECT  '1225238' locid, 'Po Box 95968' address, 'Oklahoma City' city, 'OK'state  FROM dual UNION ALL
SELECT  '1302121' locid, '801 N Mur Len Rd #102586' address, 'Olathe' city, 'KS'state  FROM dual UNION ALL
SELECT  '1321265' locid, '405 W Jackson St' address, 'Carbondale' city, 'IL'state  FROM dual UNION ALL
SELECT  '1356079' locid, '2546 Tech Dr' address, 'Bettendorf' city, 'IA'state  FROM dual UNION ALL
SELECT  '1356095' locid, 'Po Box 811' address, 'Cedar Rapids' city, 'IA'state  FROM dual UNION ALL
SELECT  '1381976' locid, '801 N Mur Len Rd #102' address, 'Olathe' city, 'KS'state  FROM dual UNION ALL
SELECT  '1449948' locid, '1228 E Rusholme St #302' address, 'Davenport' city, 'IA'state  FROM dual UNION ALL
SELECT  '1638128' locid, 'Po Box 96348' address, 'Oklahoma City' city, 'OK'state  FROM dual UNION ALL
SELECT  '1665053' locid, '420 Deer Lake Dr W' address, 'Carbondale' city, 'IL'state  FROM dual UNION ALL
SELECT  '377600' locid, '200 Blicke st' address, 'Edison' city, 'NJ'state  FROM dual
/*SELECT x.pid,
       x.address,
       x.city,
       x.state,
       o.tel
  FROM office o,
       loc l,*/
       (SELECT   P.pid,
                 SUBSTR (UPPER (address), 1, 10) address,
                 city,
                 state,
                 COUNT (*) AS loccount
            FROM office o,
                 prov P,
                 loc l
           WHERE o.pid = P.pid
             AND o.locid = l.locid
        GROUP BY P.pid,
                 SUBSTR (UPPER (address), 1, 10),
                 city,
                 state
          HAVING COUNT (*) > 1)
     i got output as under, i from below result i want to display 700804 and 8007504 as thgis pid has same address and diff phone at same location for
pid 700804 th address is same but the phone is also same. i want to display pid, address along with both diff. phone numbers.
PID     ADDRESS     CITY     STATE     LOCCOUNT
700804     801 N MUR      Olathe     KS     2
700804     PO BOX 910     Andover     KS     2
8007504     818 E BROA     Sparta     IL     2Thank you in advance for help

Answer 1

Hi,
So you want to display the full adress, not the shortened, standardized version that you're using for comparisions. In that case, include both versions in ol, and give them distinct names.
Aside from that, the solution I posted gets the results you requested.
The last condition is an inequality. The site remove the operator. I'll edit it.
You're sample data doesn't have an example of this, but if you had complete duplicates for a pid with duplicate addresses and more than one phone number, then each of the duplicates would appear in the result set. (Duplicate one of the rows that you are ultimately selecing from office to see what I mean.) If that's a problem, change "SELECT" in the main query tto "SELECT DISTINCT".
If you need prov for something you're not sharing with the rest of us, then add it back to ol, just like you had it originally.
The following is basically the same solution I posted before, but it includes all of the above:
WITH  ol  AS
    SELECT  o.pid,
            SUBSTR (UPPER (address), 1, 10) address_1_10,
            address,
            city,
            state,
            tel
    FROM    office o,
            prov P,   -- prov table is not needed for the problem as given
            loc l
    WHERE   o.pid = P.pid
    AND     o.locid = l.locid
SELECT DISTINCT  *
FROM    ol      m   -- m is for main
WHERE   EXISTS (
               SELECT  NULL
               FROM    ol
               WHERE   pid = m.pid
               AND     address_1_10 = m.address_1_10
               AND     city = m.city
               AND     state = m.state
               AND     tel != m.tel
               );