SQL Query Assistance Required for Full Outer Join

Hi,
Lets say I have two tables, i.e:
TAB_A (colA1, colA2, colA3, colA4)
TAB_B (colB1, colB2, colB3, colB4) where colB2 is a FK to colA1
I am after an SQL query that will cater for both the following two scenarios.
Scenario 1:
TAB_A has two rows of data, i.e
(1, ABC100, 1, WG_A)
(2, ABC100, 2, WG_B)
TAB_B has one row of data, i.e
(1, 1, EMP_222, 4)
I use the following SQL:
select a.*, b.*
from tab_a a FULL OUTER JOIN tab_b b ON (a.colA1 = b.colB2)
where a.colA2 = 'ABC100'
This returns two rows:
1, ABC100, 1, WG_A, 1, 1, EMP_222, 4
2, ABC100, 2, WG_B
Now, what I actually would like my query to do is actually only return the row where a tab_b record exists, i.e, should only return one record:
1, ABC100, 1, WG_A, 1, 1, EMP_222, 4
This I can achieve by using a RIGHT OUTER JOIN instead above, but this causes issue with my scenario 2, which is the following set-up
Scenario 2:
TAB_A has only one row of data this time, i.e
(2, ABC100, 2, WG_B)
TAB_B has no data at all this time
This returns no rows but I actually now want this single record from tab_a returned.
I basically require an SQL query that will cater for both the top 2 scenarios, i.e, if a tab_b record exists from the outer join then only return this record along with tab_a data. If a tab_b record doesn't exist, then only return the tab_a record.
Hope the above makes sense.
Thanks.

Is it what you need (not very elegant) ?
SQL> select * from t_outer;
        ID CODE
         1 100
         2 100
SQL> select * from t_inner;
no rows selected
SQL> with tab1 as (
  2  select a.id a_id, a.code, b.id b_id from t_outer a join t_inner b on
  3  (a.id = b.id and a.code = '100'))
  4  select * from tab1
  5  union all
  6  select a.*, null from t_outer a where not exists (
  7  select 1 from tab1)
  8  and a.code = '100'
  9  /
      A_ID CODE             B_ID
         1 100
         2 100
SQL> insert into t_inner values(2);
1 row created.
SQL> with tab1 as (
  2  select a.id a_id, a.code, b.id b_id from t_outer a join t_inner b on
  3  (a.id = b.id and a.code = '100'))
  4  select * from tab1
  5  union all
  6  select a.*, null from t_outer a where not exists (
  7  select 1 from tab1)
  8  and a.code = '100'
  9  /
      A_ID CODE             B_ID
         2 100                 2
Rgds.

Similar Messages

  • Help Required in full outer Join

    I feel the below query can be changed to full outer join. But, I've not been able to do so.
    I require your help in changing it to full outer join. My current query is
    SELECT CLAIMNO,'1' INDX FROM D_CLAIM@CMS2PROD
    WHERE clntsys=76500 and facility=76501 and filecreatedt='18-feb-2011' and fileupdatedt is null
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    SELECT CLAIMNO,'1' FROM D_CLAIM
    WHERE clntsys=76500 and facility=76501 and filecreatedt='18-feb-2011' and fileupdatedt is null
    UNION
    SELECT CLAIMNO,'2' FROM D_CLAIM
    WHERE clntsys=76500 and facility=76501 and filecreatedt='18-feb-2011' and fileupdatedt is null
    MINUS
    SELECT CLAIMNO,'2' FROM D_CLAIM@cms2prod
    WHERE clntsys=76500 and facility=76501 and filecreatedt='18-feb-2011' and fileupdatedt is null

    donisback wrote:
    I feel the below query can be changed to full outer join. But, I've not been able to do so.
    I require your help in changing it to full outer join. My current query is
    SELECT CLAIMNO,'1' INDX FROM D_CLAIM@CMS2PROD
    WHERE clntsys=76500 and facility=76501 and filecreatedt='18-feb-2011' and fileupdatedt is null
    MINUS
    SELECT CLAIMNO,'1' FROM D_CLAIM
    WHERE clntsys=76500 and facility=76501 and filecreatedt='18-feb-2011' and fileupdatedt is null
    UNION
    SELECT CLAIMNO,'2' FROM D_CLAIM
    WHERE clntsys=76500 and facility=76501 and filecreatedt='18-feb-2011' and fileupdatedt is null
    MINUS
    SELECT CLAIMNO,'2' FROM D_CLAIM@cms2prod
    WHERE clntsys=76500 and facility=76501 and filecreatedt='18-feb-2011' and fileupdatedt is null
    I do not think that query is doing what you think that it is doing - on first inspection, it was not doing what I thought either due to the order in which the UNION and MINUS operators are performed. If the FILECREATEDT column is defined as a DATE, your query is relying on an implicit date conversion - in such a case, you should replace:
    filecreatedt='18-feb-2011'With:
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    CREATE TABLE T1 AS
    SELECT
      ROWNUM*2 C1,
      TRUNC(SYSDATE)+ROWNUM*2 C2
    FROM
      DUAL
    CONNECT BY
      LEVEL<=10;
    CREATE TABLE T2 AS
    SELECT
      ROWNUM*3 C1,
      TRUNC(SYSDATE)+ROWNUM*3 C2
    FROM
      DUAL
    CONNECT BY
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    SELECT
      C1,
      C2
    FROM
      T1
    MINUS
    SELECT
      C1,
      C2
    FROM
      T2;
    C1 C2
    2 28-FEB-11
    4 02-MAR-11
    8 06-MAR-11
    10 08-MAR-11
    14 12-MAR-11
    16 14-MAR-11
    20 18-MAR-11
    SELECT
      C1,
      C2
    FROM
      T2
    MINUS
    SELECT
      C1,
      C2
    FROM
      T1;
    C1 C2
    3 01-MAR-11
    9 07-MAR-11
    15 13-MAR-11
    21 19-MAR-11
    24 22-MAR-11
    27 25-MAR-11
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    SELECT
      C1,
      C2
    FROM
      T1
    MINUS
    SELECT
      C1,
      C2
    FROM
      T2
    UNION
    SELECT
      C1,
      C2
    FROM
      T2
    MINUS
    SELECT
      C1,
      C2
    FROM
      T1;
    C1 C2
    3 01-MAR-11
    9 07-MAR-11
    15 13-MAR-11
    21 19-MAR-11
    24 22-MAR-11
    27 25-MAR-11
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    SELECT
    FROM
      (SELECT
        C1,
        C2
      FROM
        T1
      MINUS
      SELECT
        C1,
        C2
      FROM
        T2)
    UNION
    SELECT
    FROM
      (SELECT
        C1,
        C2
      FROM
        T2
      MINUS
      SELECT
        C1,
        C2
      FROM
        T1);
    C1 C2
    2 28-FEB-11
    3 01-MAR-11
    4 02-MAR-11
    8 06-MAR-11
    9 07-MAR-11
    10 08-MAR-11
    14 12-MAR-11
    15 13-MAR-11
    16 14-MAR-11
    20 18-MAR-11
    21 19-MAR-11
    24 22-MAR-11
    27 25-MAR-11
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      T1.C1,
      T1.C2
    FROM
      T1,
      T2
    WHERE
      T1.C1=T2.C1(+)
      AND T2.C1 IS NULL
    UNION
    SELECT
      T2.C1,
      T2.C2
    FROM
      T1,
      T2
    WHERE
      T2.C1=T1.C1(+)
      AND T1.C1 IS NULL;
    C1 C2
    2 28-FEB-11
    3 01-MAR-11
    4 02-MAR-11
    8 06-MAR-11
    9 07-MAR-11
    10 08-MAR-11
    14 12-MAR-11
    15 13-MAR-11
    16 14-MAR-11
    20 18-MAR-11
    21 19-MAR-11
    24 22-MAR-11
    27 25-MAR-11
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    SELECT
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    FROM
      T1 FULL OUTER JOIN T2
        ON T1.C1=T2.C1
    MINUS
    SELECT
      T1.C1,
      T1.C2
    FROM
      T1,
      T2
    WHERE
      T1.C1=T2.C1;
    C1 C2
    2 28-FEB-11
    3 01-MAR-11
    4 02-MAR-11
    8 06-MAR-11
    9 07-MAR-11
    10 08-MAR-11
    14 12-MAR-11
    15 13-MAR-11
    16 14-MAR-11
    20 18-MAR-11
    21 19-MAR-11
    24 22-MAR-11
    27 25-MAR-11
    30 28-MAR-11Or just with a full outer join with a WHERE clause:
    SELECT
      NVL(T1.C1,T2.C1) C1,
      NVL2(T1.C1,T1.C2,T2.C2) C2
    FROM
      T1 FULL OUTER JOIN T2
        ON T1.C1=T2.C1
    WHERE
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    C1 C2
    3 01-MAR-11
    9 07-MAR-11
    15 13-MAR-11
    21 19-MAR-11
    24 22-MAR-11
    27 25-MAR-11
    30 28-MAR-11
    8 06-MAR-11
    20 18-MAR-11
    2 28-FEB-11
    10 08-MAR-11
    4 02-MAR-11
    14 12-MAR-11
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    Charles Hooper
    Co-author of "Expert Oracle Practices: Oracle Database Administration from the Oak Table"
    http://hoopercharles.wordpress.com/
    IT Manager/Oracle DBA
    K&M Machine-Fabricating, Inc.

  • Full outer join

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        AUDIT_DATE TIMESTAMP (6) NOT NULL ENABLE,
        AUDIT_ACTION          VARCHAR2(30 BYTE) NOT NULL ENABLE,
        AUDIT_USER            VARCHAR2(8 BYTE) NOT NULL ENABLE,
        FEE_BANDS_ID          NUMBER NOT NULL ENABLE,
        FEE_RULE              VARCHAR2(10 BYTE) NOT NULL ENABLE,
        FEE_BAND_LOWER_LIMIT  NUMBER(19,0),
        FEE_BAND_HIGHER_LIMIT NUMBER(19,0),
        RATE_PERCENT          NUMBER(11,4),
        RATE_NUMBER           NUMBER(21,2),
        CAL_BASED_ON          CHAR(1 BYTE) NOT NULL ENABLE,
        REC_SEQ               NUMBER(5,0) NOT NULL ENABLE)
        FEE_BANDS_AUD
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    INSERT INTO FEE_BANDS_AUD1 VALUES('18-10-10 06:53:08.659000000 AM','UPDATE','sdn',2,'NSK',101,9999999999999999999,1,0,'B',1);
    INSERT INTO FEE_BANDS_AUD1 VALUES('18-10-10 06:54:51.354000000 AM','UPDATE','sdn',1,'NSK',0,100,11,0,'B',2);
    INSERT INTO FEE_BANDS_AUD1 VALUES('18-10-10 06:54:51.354000000 AM','UPDATE','sdn',2,'NSK',101,9999999999999999999,33,0,'B',2);
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    INSERT INTO FEE_BANDS_AUD1 VALUES('18-10-10 07:15:16.354000000 AM','UPDATE','sdn',2,'NSK',101,200,33,0,'B',3);
    INSERT INTO FEE_BANDS_AUD1 VALUES('18-10-10 07:15:16.354000000 AM','UPDATE','sdn',3,'NSK',201,9999999999999999999,1,0,'B',3);
    INSERT INTO FEE_BANDS_AUD1 VALUES('18-10-10 07:15:53.341000000 AM','UPDATE','sdn',1,'NSK',0,100,11,0,'B',4);
    INSERT INTO FEE_BANDS_AUD1 VALUES('18-10-10 07:15:53.341000000 AM','UPDATE','sdn',2,'NSK',101,200,33,0,'B',4);
    INSERT INTO FEE_BANDS_AUD1 VALUES('18-10-10 07:15:53.341000000 AM','UPDATE','sdn',3,'NSK',201,9999999999999999999,2,0,'B',4);     
    INSERT INTO FEE_BANDS_AUD1 VALUES('18-10-10 07:18:52.118000000 AM','UPDATE','sdn',1,'NSK',0,100,11,0,'B',5);
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    Yes, it's possible.
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    http://tahiti.oracle.com/pls/db92/db92.drilldown?levelnum=2&toplevel=a96540&method=FULL&chapters=0&book=&wildcards=1&preference=&expand_all=&verb=&word=full+outer+join+#a96540
    In the SQL Reference you can find an example

  • Full outer join Bug or my misunderstanding?

    CREATE GLOBAL TEMPORARY TABLE BP_ATTRIBUTE_CHARVAL_GTT
       (     "ATTRIBUTE_ID" NUMBER(10,0),
         "PARTNER_ID" NUMBER(10,0),
         "CHAR_VALUE" VARCHAR2(4000 BYTE),
         "LAST_UPDATE_DATE" DATE,
         "DISABLE_DATE" DATE
       ) ON COMMIT DEETE ROWS ;
    CREATE  TABLE BP_ATTRIBUTE_CHARVAL
       (     "ATTRIBUTE_ID" NUMBER(10,0),
         "PARTNER_ID" NUMBER(10,0),
         "CHAR_VALUE" VARCHAR2(4000 BYTE),
         "LAST_UPDATE_DATE" DATE,
         "DISABLE_DATE" DATE
    REM INSERTING into BP_ATTRIBUTE_CHARVAL
    Insert into BP_ATTRIBUTE_CHARVAL (ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (888854,710326,'1',to_date('29-NOV-06','DD-MON-RR'),to_date('01-JAN-06','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL (ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (591330,710326,'01',to_date('09-FEB-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL (ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (591321,710326,'N',to_date('09-FEB-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL (ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (591331,710326,'00',to_date('09-FEB-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL (ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (591329,710326,'01',to_date('09-FEB-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL (ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (591332,710326,'01',to_date('09-FEB-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL (ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (591324,710326,'2',to_date('09-FEB-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL (ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (591333,710326,'01',to_date('09-FEB-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL (ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (591323,710326,'X1',to_date('09-FEB-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL (ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (591334,710326,'BS',to_date('09-FEB-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    REM INSERTING into BP_ATTRIBUTE_CHARVAL_GTT
    Insert into BP_ATTRIBUTE_CHARVAL_GTT(ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (591330,707408,'01',to_date('29-MAR-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL_GTT(ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (591321,707408,'N',to_date('23-JAN-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL_GTT(ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (591331,707408,'00',to_date('23-JAN-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL_GTT(ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (591329,707408,'01',to_date('23-JAN-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL_GTT(ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (591332,707408,'00',to_date('29-MAR-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL_GTT(ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (591324,707408,'2',to_date('29-MAR-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL_GTT(ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (591333,707408,'01',to_date('23-JAN-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL_GTT(ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (591323,707408,'X1',to_date('23-JAN-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL_GTT(ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (591334,707408,'BS',to_date('23-JAN-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL_GTT(ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (876570,707408,'01',to_date('29-MAR-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL_GTT (ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (876568,707408,'1234560003264801',to_date('29-MAR-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL_GTT(ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (876569,707408,'f3a1d996-720e-4e0a-989c-6d4f3e8e629a',to_date('29-MAR-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    Insert into BP_ATTRIBUTE_CHARVAL_GTT(ATTRIBUTE_ID,PARTNER_ID,CHAR_VALUE,LAST_UPDATE_DATE,DISABLE_DATE) values (874948,707408,'20060318000000',to_date('29-MAR-06','DD-MON-RR'),to_date('07-NOV-01','DD-MON-RR'));
    select 707408,    
           decode(g.attribute_id,NULL,c.attribute_id,g.attribute_id) attribute_id,
           case
           when c.last_update_date is null and g.last_update_date is not null
           then
              g.char_value
            when g.last_update_date is null and c.last_update_date is not null 
            then
              c.char_value
            when g.last_update_date >= c.last_update_date
            then
                 g.char_value
           else
                c.char_value
           end   char_value,        
           decode(g.last_update_date,c.last_update_date,g.last_update_date,c.last_update_date) last_update_date,
           decode(g.disable_date,c.disable_date,g.disable_date,c.disable_date) disable_date
    from bp_attribute_charval_gtt g
    full outer join
         bp_attribute_charval c
    on c.attribute_id = g.attribute_id    
    where c.partner_id=710326;Hi Guys
    When I run the above query I get a problem.
    I am expecting to see is a merge of all the attribute_id's and their values.
    The query does not appear to be merging the data as intended.
    My understanding of the full outer join is that its a combination of left and outer joins,
    so the above query is intended to return with the total number of unique attributes
    and their appropriate values
    a) I have a bug in the Sql
    b) This is an oracle bug
    c) My understanding is incorrect
    Please Help
    Message was edited by:
    Keith Jamieson (fixed insert statements for gtt )

    How do you expect a full outer join operation when you have given --
    where c.partner_id=710326;According to your supplied data - i don't think your query can perform that full outer join operation because of that filtration. Just remove that last condition and checked it. You will get your desired result - hopefully.
    "It's like you want to view the things by closing down your both eyes". Do you think it will pay?
    Regards.
    Satyaki De.

  • [8i] Need help with full outer join combined with a cross-join....

    I can't figure out how to combine a full outer join with another type of join ... is this possible?
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    (     record_id     NUMBER     NOT NULL     
    ,     workstation     VARCHAR2(4)
    ,     my_value     NUMBER
         CONSTRAINT my_tab1_pk PRIMARY KEY (record_id)
    INSERT INTO     my_tab1
    VALUES(1,'ABCD',10);
    INSERT INTO     my_tab1
    VALUES(2,'ABCD',15);
    INSERT INTO     my_tab1
    VALUES(3,'ABCD',5);
    INSERT INTO     my_tab1
    VALUES(4,'A123',5);
    INSERT INTO     my_tab1
    VALUES(5,'A123',10);
    INSERT INTO     my_tab1
    VALUES(6,'A123',20);
    INSERT INTO     my_tab1
    VALUES(7,'????',5);
    CREATE TABLE     my_tab2
    (     workstation     VARCHAR2(4)
    ,     wkstn_name     VARCHAR2(20)
         CONSTRAINT my_tab2_pk PRIMARY KEY (workstation)
    INSERT INTO     my_tab2
    VALUES('ABCD','WKSTN 1');
    INSERT INTO     my_tab2
    VALUES('A123','WKSTN 2');
    INSERT INTO     my_tab2
    VALUES('B456','WKSTN 3');
    CREATE TABLE     my_tab3
    (     my_nbr1     NUMBER
    ,     my_nbr2     NUMBER
    INSERT INTO     my_tab3
    VALUES(1,2);
    INSERT INTO     my_tab3
    VALUES(2,3);
    INSERT INTO     my_tab3
    VALUES(3,4);And, the results I want to get:
    workstation     sum(my_value)     wkstn_name     my_nbr1     my_nbr2
    ABCD          30          WKSTN 1          1     2
    ABCD          30          WKSTN 1          2     3
    ABCD          30          WKSTN 1          3     4
    A123          35          WKSTN 2          1     2
    A123          35          WKSTN 2          2     3
    A123          35          WKSTN 2          3     4
    B456          0          WKSTN 3          1     2
    B456          0          WKSTN 3          2     3
    B456          0          WKSTN 3          3     4
    ????          5          NULL          1     2
    ????          5          NULL          2     3
    ????          5          NULL          3     4I've tried a number of different things, googled my problem, and no luck yet...
    SELECT     t1.workstation
    ,     SUM(t1.my_value)
    ,     t2.wkstn_name
    ,     t3.my_nbr1
    ,     t3.my_nbr2
    FROM     my_tab1 t1
    ,     my_tab2 t2
    ,     my_tab3 t3
    ...So, what I want is a full outer join of t1 and t2 on workstation, and a cross-join of that with t3. I'm wondering if I can't find any examples of this online because it's not possible....
    Note: I'm stuck dealing with Oracle 8i
    Thanks!!

    Hi,
    The query I posted yesterday is a little more complicated than it needs to be.
    Since my_tab2.workstation is unique, there's no reason to do a separate sub-query like mt1; we can join my_tab1 to my_tab2 and get the SUM all in one sub-query.
    SELECT       foj.workstation
    ,       foj.sum_my_value
    ,       foj.wkstn_name
    ,       mt3.my_nbr1
    ,       mt3.my_nbr2
    FROM       (     -- Begin in-line view foj for full outer join
              SELECT        mt1.workstation
              ,        SUM (mt1.my_value)     AS sum_my_value
              ,        mt2.wkstn_name
              FROM        my_tab1   mt1
              ,        my_tab2   mt2
              WHERE        mt1.workstation     = mt2.workstation (+)
              GROUP BY   mt1.workstation
              ,        mt2.wkstn_name
                    UNION ALL
              SELECT      workstation
              ,      0      AS sum_my_value
              ,      wkstn_name
              FROM      my_tab2
              WHERE      workstation     NOT IN (     -- Begin NOT IN sub-query
                                               SELECT      workstation
                                       FROM      my_tab1
                                       WHERE      workstation     IS NOT NULL
                                     )     -- End NOT IN sub-query
           ) foj     -- End in-line view foj for full outer join
    ,       my_tab3  mt3
    ORDER BY  foj.wkstn_name
    ,       foj.workstation
    ,       mt3.my_nbr1
    ,       mt3.my_nbr2
    ;Thanks for posting the CREATE TABLE and INSERT statements, as well as the very clear desired results!
    user11033437 wrote:
    ... So, what I want is a full outer join of t1 and t2 on workstation, and a cross-join of that with t3. That it, exactly!
    The tricky part is how and when to get SUM (my_value). You might approach this by figuring out exactly what my_tab3 has to be cross-joined to; that is, exactly what should the result set of the full outer join between my_tab1 and my_tab2 look like. To do that, take your desired results, remove the columns that do not come from the full outer join, and remove the duplicate rows. You'll get:
    workstation     sum(my_value)     wkstn_name
    ABCD          30          WKSTN 1          
    A123          35          WKSTN 2          
    B456          0          WKSTN 3          
    ????          5          NULL          So the core of the problem is how to get these results from my_tab1 and my_tab2, which is done in sub-query foj above.
    I tried to use self-documenting names in my code. I hope you can understand it.
    I could spend hours explaining different parts of this query in more detail, but I'm sure I'd waste some of that time explaining things you already understand. If you want an explanation of somthing(s) specific, let me know.

  • Query with FULL OUTER JOIN , help pleaseeeeeeeeeeee...

    Hi everyone,
    I'm trying to write a query for a report in Oracle SQL, but i just can't figure out how to do it.
    I'm using Oracle 10g release 1.0 database and i execute my queris in SQL* PLUS ( eventually i'm gonna use them in Oracle Report Builder ) .
    here's what i have:
    i have four tables that are used for our inventory application. lets call them INCOMMING , INCOMMING_ITEMS , OUTGOING , OUTGOING_ITEMS.
    as you may have guessed , INCOMMING_ITEMS is the detail table for INCOMMING ( joined by IID column) and also OUTGOING_ITEMS is the detail table for OUTGOING ( joined by OID column ).
    here is the structure of them :
    INCOMMING
    IID varchar2
    CDATE date
    INCOMMING_ITEM
    IID varchar2
    PART_NO number
    QTY number
    OUTGOING
    OID varchar2
    CDATE date
    OUTGOING_ITEM
    OID varchar2
    PART_NO number
    QTY number
    now , the query i want, should return part_no , cdate , sum of OUTGOING qty , sum of INCOMMING qty .
    the result of the query should be sth like this :
    part_no     cdate     O_qty     I_qty
    100     01/05/06     10     0
    100     01/05/07     20     60
    200     01/06/02     0     50
    300     01/06/02     30     40
    this means that for some dates and for some parts, i may not have INCOMMING or OUTGOING data, but if at least one of the 2 last columns has a non-zero data, i should show the row ( like the first and third rows of my example result), and if both have data for the same PART_NO and the same CDATE, both should be showed in the same row. ( like the second row in my example result)
    i tried so much and came up with several huge and also time consuming queries, but then i read abt FULL OUTER JOIN somewhere and tried using that. here is what i came up with :
    SELECT
    PART_NO , CDATE , sum(II.QTY) I_QTY , SUM (OI.QTY) O_QTY
    FROM
         (OUTGOING O INNER JOIN OUTGOING_ITEM OI USING ( OID ) )
    FULL OUTER JOIN
         (INCOMMING I INNER JOIN INCOMMING_ITEM II USING ( IID ) )
    ON ( I.CDATE = O.CDATE AND II.PART_NO = OI.PART_NO)
    WHERE
    I.CDATE = :PARAMETER1
    AND O.CDATE = :PARAMETER1
    GROUP BY
    PART_NO , CDATE
    this query is short and fast , but the results r not what i expected. i mean, although i have used FULL OUTER JOIN in the query , but the results i get r sth like this :
    part_no     cdate     O_qty     I_qty
    100     01/05/07     20     60
    300     01/06/02     30     40
    which means only the rows that has both values are returned.
    any change i make to this query would make the SQL* PLUS hang , like when i use the cartesian product of two large tables, so i guess my changes wheren't in the right direction.
    i think its possible to write this query using FULL OUTER JOIN syntax, but i just can't find it.
    Can anybody pleaseeeeeeeeeeeee help me?
    thanx in advance,
    Maryam.

    Note: I wrote this on the fly -- hope there is no syntax errors, otherwise forgive me -- but you get the idea..
    select
    fromUnionAll.cdate, fromUnionAll.part_no,
    sum(fromUnionAll.O_qty) O_qty,
    sum(fromUnionAll.I_qty) I_qty
    from
    select
    iinner.cdate, iinner.part_no, 0 O_qty, iinner.I_qty
    from
    select
    i.cdate, ii.part_no,
    /* added the case only for the extreme case when there is
    no record anywhere for the given CDATE in INCOMMING_item */
    sum( ( case when ii.qty is not null then ii.qty else 0 end) ) I_qty
    from
    incomming i,
    incomming_item ii
    where
    i.iid = ii.iid (+)
    group by i.cdate, ii.part_no
    ) iinner
    union all
    select
    oinner.cdate, oinner.part_no, oinner.O_qty, 0 I_qty
    from
    select
    o.cdate, oi.part_no,
    /* added the case only for the extreme case when there is
    no record anywhere for the given CDATE in OUTGOING_item */
    sum( ( case when oi.qty is not null then oi.qty else 0 end) ) O_qty
    from
    outgoing o,
    outgoing_item oi
    where
    o.oid = oi.oid (+)
    group by o.cdate, oi.part_no
    ) oinner
    ) fromUnionAll
    group by fromUnionAll.cdate, fromUnionAll.part_no;
    --Samson                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                       

  • How to merge 3 different query results using full outer join?

     Hi all This is my my query for 2 results
    with t1 as (
    select trans.crAcc_id,trans.cr_amt,row_number() over (order by trans.head_id) rn from Acttrans trans,
     Acttranhead head where trans.head_id in(select link_id from acttrans where head_id=12) and trans.crAcc_id!=0
     and head.head_id=trans.head_id
    t2 as (
    select trans.drAcc_id,trans.dr_amt,head.[Vouc_No],head.[Vouc_Date] ,head.[Check_No],head.[Check_Date],head.[stat],row_number() over (order by trans.head_id) rn from Acttrans trans,
     Acttranhead head where trans.head_id=12 and trans.drAcc_id!=0
     and head.head_id=trans.head_id
     select t1.crAcc_id, t1.cr_amt,t2.[Vouc_No],t2.[Vouc_Date] ,t2.[Check_No],t2.[Check_Date],t2.[stat],t2.drAcc_id,t2.dr_amt from t1
      full outer join t2 on t1.rn = t2.rn
    Query 3: SELECT [CrAcc_Id]  FROM [KSSDATA].[dbo].[ActTrans] where head_id=12 and crAcc_id!=0
    and i want to add Query3 result to the ABOVE RESULT but i am unable add third result using full outer join
    Thanks
    Balu D

    >>>but i am unable add third result using full outer join
    Do you get the error or wrong result?
    Best Regards,Uri Dimant SQL Server MVP,
    http://sqlblog.com/blogs/uri_dimant/
    MS SQL optimization: MS SQL Development and Optimization
    MS SQL Consulting:
    Large scale of database and data cleansing
    Remote DBA Services:
    Improves MS SQL Database Performance
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    Business Intelligence

  • Can we implement the custom sql query in CR for joining the two tables

    Hi All,
    Is there anyway to implement the custom sql query in CR for joining the two tables?
    My requirement here is I need to write sql logics for joining the two tables...
    Thanks,
    Gana

    In the Database Expert, expand the Create New Connection folder and browse the subfolders to locate your data source.
    Log on to your data source if necessary.
    Under your data source, double-click the Add Command node.
    In the Add Command to Report dialog box, enter an appropriate query/command for the data source you have opened.
    For example:
    SELECT
        Customer.`Customer ID`,
        Customer.`Customer Name`,
        Customer.`Last Year's Sales`,
        Customer.`Region`,
        Customer.`Country`,
        Orders.`Order Amount`,
        Orders.`Customer ID`,
        Orders.`Order Date`
    FROM
        Customer Customer INNER JOIN Orders Orders ON
            Customer.`Customer ID` = Orders.`Customer ID`
    WHERE
        (Customer.`Country` = 'USA' OR
        Customer.`Country` = 'Canada') AND
        Customer.`Last Year's Sales` < 10000.
    ORDER BY
        Customer.`Country` ASC,
        Customer.`Region` ASC
    Note: The use of double or single quotes (and other SQL syntax) is determined by the database driver used by your report. You must, however, manually add the quotes and other elements of the syntax as you create the command.
    Optionally, you can create a parameter for your command by clicking Create and entering information in the Command Parameter dialog box.
    For more information about creating parameters, see To create a parameter for a command object.
    Click OK.
    You are returned to the Report Designer. In the Field Explorer, under Database Fields, a Command table appears listing the database fields you specified.
    Note:
    To construct the virtual table from your Command, the command must be executed once. If the command has parameters, you will be prompted to enter values for each one.
    By default, your command is called Command. You can change its alias by selecting it and pressing F2.

  • Full outer join query giving error

    Hi I have written the below query to get the fields below as an out put but am getting the error missing keyword..am not understanding where did i missed..i have done step by step query analysis..but could not find the error.
    Please help me in resolving the issue.
    Expected output Columns :*
    COUNTRY , TRN_TYPE ,SKU ,BIX_Customer ,PERIOD ,CURRENTSTOCK ,STOCK_VALUE ,SALES ,SALES_VALUE ,TARGET
    Query :_
    select (case when a.country is null then b.country when b.country is null then c.country else a.country end) AS COUNTRY,
    (case when a.Sale_Type is null then b.Stk_type when b.stk_type is null then c.Stk_type else a.Sale_Type end) AS TRN_TYPE,
    (case when a.sku is null then b.sku when b.sku is null then c.sku else a.sku end) AS SKU,
    (case when a.bix_customer is null then b.bix_customer_code when b.bix_customer_code is null then c.bix_customer_code else a.bix_customer end)AS BIX_Customer ,
    (case when a.period is null then TO_number(b.period) when b.period is null then TO_NUMBER(c.period) else a.period end) AS PERIOD,
    nvl(b.CURRENTSTOCK,0) AS CURRENTSTOCK,
    nvl(b.stock_value,0) AS STOCK_VALUE,
    nvl(a.sales,0) AS SALES,
    nvl(a.SALES_VALUE,0) AS SALES_VALUE,
    nvl(c.TARGET_QTY,0) AS TARGET
    from
    (select UPPER(c.cust_country_name) AS COUNTRY,
    DECODE(ds.account_key,7156,'SAMPLE',7157,'BONUS',7485,'SALE') AS Sale_Type,
    substr(i.item_code,7) AS SKU,
    c.bix_customer_code AS BIX_Customer,
    ds.descr as descr ,
    ds.period as period,
    sum(ds.quantity) AS SALES,
    sum(case when ds.local_value is null then ds.euro_value else ds.local_value END) AS SALES_VALUE
    FROM distributor_sales ds, customer c, item i
    where ds.customer_key=c.customer_key
    and ds.item_key= i.item_key
    group by ds.period,
    ds.account_key,
    c.cust_country_name,
    substr(i.item_code,7),
    c.bix_customer_code,
    ds.descr) a
    full outer join
    (SELECT UPPER(b.cust_country_name) AS COUNTRY,
    DECODE(s.stock_type,'SALE','SALE','SALES','SALE','BONUS','BONUS','SAMPLE','SAMPLE') AS Stk_type,
    substr(c.item_code,7) AS SKU,
    s.descr as descr,
    s.period as period,
    b.bix_customer_code,
    sum(s.CLOSING_STOCK) CURRENTSTOCK,
    sum(s.closing_stock*s.cif_price) STOCK_VALUE
    FROM STOCK s, customer b, item c
    WHERE s.customer_key=b.customer_key
    and s.item_key= c.item_key
    group by
    s.descr,
    s.stock_type,
    s.period, b.bix_customer_code,b.cust_country_name,substr(c.item_code,7) ) b
    full outer join
    (SELECT UPPER(cu.cust_country_name) AS COUNTRY,
    DECODE(t.description,'SALES TARGET','SALE') AS Stk_type,
    substr(it.item_code,7) AS SKU,
    t.channel as channel,
    t.period as period,
    cu.bix_customer_code as bix_customer_code,
    sum(t.quantity) TARGET_QTY
    FROM sales_target t, customer cu, item it
    WHERE t.customer_key=cu.customer_key
    and t.item_key= it.item_key
    group by
    t.channel,
    t.description,
    t.period, cu.bix_customer_code,cu.cust_country_name,substr(it.item_code,7) ) c
    on a.SKU=b.SKU
    and a.sku=c.SKU
    and b.sku=c.SKU
    and a.BIX_Customer=b.bix_customer_code
    and a.BIX_Customer=c.bix_customer_code
    and b.bix_customer_code=c.bix_customer_code
    and a.Sale_Type=b.Stk_type
    and a.Sale_Type=c.Stk_type
    and b.Stk_type=c.Stk_type
    and a.descr=b.descr
    and b.descr=c.channel
    and a.descr=c.channel
    and a.country=b.country
    and a.country=c.COUNTRY
    and b.country=c.COUNTRY
    and a.period=b.period
    and a.period=c.period
    and b.period=c.period;

    <tt>Oracle Database 11g Enterprise Edition Release 11.2.0.2.0 - 64bit Production</tt>
    You must be aware that you must cascade full outer joins
    with
    t1 as
    (select 1 key,1.1 data from dual union all
    select 3,1.3 from dual union all
    select 6,1.6 from dual union all
    select 7,1.7 from dual
    t2 as
    (select 2 key,2.2 data from dual union all
    select 3,2.3 from dual union all
    select 4,2.4 from dual union all
    select 6,2.6 from dual
    t3 as
    (select 4 key,3.4 data from dual union all
    select 5,3.5 from dual union all
    select 6,3.6 from dual union all
    select 7,3.7 from dual
    select nvl(x.key,t3.key) key,
           x.data_1,
           x.data_2,
           t3.data data_3
      from (select nvl(t1.key,t2.key) key,
                   t1.data data_1,
                   t2.data data_2
              from t1
                   full outer join
                   t2
                on t1.key = t2.key
           ) x
           full outer join
           t3
        on t3.key = x.key
    order by keyunless you can live with duplicate key rows you cannot avoid whenever all table pairs contain common keys (try the below using data from above)
    select coalesce(t1.key,t2.key,t3.key) key,
           t1.data data_1,
           t2.data data_2,
           t3.data data_3
      from t1
           full outer join
           t2
        on t1.key = t2.key
           full outer join
           t3
        on t3.key = t1.key
       and t3.key = t2.key
    order by key
    select coalesce(t1.key,t2.key,t3.key) key,
           t1.data data_1,
           t2.data data_2,
           t3.data data_3
      from t2
           full outer join
           t3
        on t2.key = t3.key
           full outer join
           t1
        on t1.key = t2.key
       and t1.key = t3.key
    order by key
    select coalesce(t1.key,t2.key,t3.key) key,
           t1.data data_1,
           t2.data data_2,
           t3.data data_3
      from t1
           full outer join
           t3
        on t1.key = t3.key
           full outer join
           t2
        on t2.key = t1.key
       and t2.key = t3.key
    order by keyRegards
    Etbin
    Edited by: Etbin on 10.4.2013 9:53
    If you're after
    select *
      from (select *
              from (select *
                      from t1
                   ) a
                   full outer join
                   (select *
                      from t2
                   ) b
                on t1.key = t2.key
           ) x
           full outer join
           t3
        on t3.key = x.key
    order by keyyou're presently at
    select *
      from (
                   (select *
                      from t1
                   ) a
                   full outer join
                   (select *
                      from t2
                   ) b
                on t1.key = t2.key
           ) x
           full outer join
           t3
        on t3.key = x.key
    order by keyORA-00933: SQL command not properly ended

  • Full Outer Join Help please

    Using : Oracle 11.2.0.1 on Windows XP
    create table tab40(bno varchar2(1),pno varchar2(7),weight number(3),lineno number(3));
    insert into tab40 values ('1','1115027',36,1);
    insert into tab40 values ('2','1115100',25,2);
    insert into tab40 values ('3','1115200',50,3);
    insert into tab40 values ('1','1112510',60,4);
    insert into tab40 values ('+','1112610',6,5);
    insert into tab40 values ('+','1112710',4,6);
    insert into tab40 values ('+','1110710',1,7);
    insert into tab40 values ('2','1117014',79,8);
    insert into tab40 values ('+','1117000',9,9);
    insert into tab40 values ('+','1117001',2,10);
    insert into tab40 values ('1','1317001',200,11);
    insert into tab40 values ('1','1697001',20,12);
    insert into tab40 values ('2','2997001',40,13);
    insert into tab40 values ('1','2996001',44,14);
    SQL> select * from tab40;
    B PNO         WEIGHT     LINENO
    1 1115027         36          1
    2 1115100         25          2
    3 1115200         50          3
    1 1112510         60          4
    + 1112610          6          5
    + 1112710          4          6
    + 1110710          1          7
    2 1117014         79          8
    + 1117000          9          9
    + 1117001          2         10
    1 1317001        200         11
    B PNO         WEIGHT     LINENO
    1 1697001         20         12
    2 2997001         40         13
    1 2996001         44         14
    14 rows selected.
    SQL>create table tab41(bno varchar2(1),pno varchar2(7),weight number(3),lineno number(3));
    insert into tab41 values ('1','1115027',36,1);
    insert into tab41 values ('2','1115100',25,2);
    insert into tab41 values ('3','1115200',50,3);
    insert into tab41 values ('1','1112510',60,4);
    insert into tab41 values ('+','1112610',6,5);
    insert into tab41 values ('+','1110710',1,6);
    insert into tab41 values ('2','1117014',79,7);
    insert into tab41 values ('+','1117000',9,8);
    insert into tab41 values ('1','1317001',200,9);
    insert into tab41 values ('1','1697001',20,10);
    insert into tab41 values ('2','2997001',40,11);
    insert into tab41 values ('1','2996001',44,12);
    insert into tab41 values ('+','1112710',4,13);
    insert into tab41 values ('+','3332710',8,14);
    SQL> select * from tab41;
    B PNO         WEIGHT     LINENO
    1 1115027         36          1
    2 1115100         25          2
    3 1115200         50          3
    1 1112510         60          4
    + 1112610          6          5
    + 1110710          1          6
    2 1117014         79          7
    + 1117000          9          8
    1 1317001        200          9
    1 1697001         20         10
    2 2997001         40         11
    B PNO         WEIGHT     LINENO
    1 2996001         44         12
    + 1112710          4         13
    + 3332710          8         14
    14 rows selected.
    SQL>Required Output :
    A       B          C          D        E       F          G          H
    1 1112510         60          4        1 2996001         44         12
    + 1112710          4          6        + 1112710          4         13
    2 1117014         79          8
    + 1117001          2         10
                                           1 2996001         44         12
                                           + 3332710          8         14Logic : The plus sign in Bno indicates that Packet No. was sent to customer with last non plus signed number packet (order by lineno) i.e. for example in tab40 there is line no. 6 whose master packet number is 1112510 (previous non plus signed rows's PNO). Now come to required output; which is showing that these plus signed packets (whose master PNO is that) are not as per tab40 vs tab41 something like full outer join between tab40 and tab41. Example :
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    + 1117001 is associated with 1117014 in tab40, while it is not in tab41.
    vice versa;
    + 3332710 is associated with 2996001 in tab41, while it is not in tab40.
    I mean, if only plus marked row's PNO's mater packet number is not equal to master PNO(previous non plus marked BNO) in both the table, it should be part of the select query please. Generally this happens, when our packing department gets late delivery of prior master packet, so they just send the small packet with immediate available one (non plus) packet.
    Kindly let me; i am clear in my request or i should elaborate more. This may be more complex, because may be bad table/data design, but i need the output by select query please help me.
    Regards.
    Edited by: user12050217 on Jan 3, 2012 3:57 AM

    Yes, you have perfectly understood my question... just i added lineno > 1
    SELECT bno,
    pno,
    weight,
    lineno
    FROM ( SELECT tab40.*, lag (bno) OVER (ORDER BY pno) prev_bno
    FROM tab40
    ORDER BY pno)
    WHERE bno = '+' OR prev_bno = '+' and lineno > 1
    ORDER BY lineno
    and it worked, because there are no chances that plus marked row will be having lineno <=1
    B PNO         WEIGHT     LINENO
    1 1112510         60          4
    + 1112610          6          5
    + 1112710          4          6
    + 1110710          1          7
    2 1117014         79          8
    + 1117000          9          9
    + 1117001          2         10
    7 rows selected.

  • Using full outer join of subqueries named using with clause

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    that's line 29. Maybe you get a better idea if you strip your operation of all the unneccessary elements until it works.
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  • Full Outer Join Help Needed

    Hi All,
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    hi Divya,
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  • Forcing full outer join between two facts according to common dimensions

    Hi everyone,I have an issue with the way obiee "joins" 2 fact tables regarding according to common dimensions.
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    If you use the fact vertical capabilities of OBIEE, it will normally perform a full outer join :
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    Check here for an example (replace the fact cross join by your second fact table F2)
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  • Fact vertical capabilities - Full outer Join - How to?

    Hi,
    I have the same problem described in another post: Forcing full outer join between two facts according to common dimensions
    I will use the same example:
    Let's assume 2 fact tables F1 and F2 and 2 dimension D1 and D2.
    Fi is joined to Dj thanks to IDs.
    F1 and F2 have got aggregates sum(mes1), respectively sum(mes2).
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    The reply was a link to fact vertical capabilities of OBIEE
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    (http://gerardnico.com/wiki/dat/obiee/bi_server/design/obiee_densification_design_preservation_dimension)
    In this post the solution is to add a dummy fact table to force a crossjoin.
    This solution don't work in my case because I don't need to return all the members of the dimension, I just need to return the dimension member that are joined to both facts..
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    Thanks...

    I found what was the real problem:
    I have two diferent physical and logical Facts with 4 common dimensions and 1 dimesion that only affect to the second fact.
    In my report I'm filtering for this last dimension so the OBI use this query (the more restrictive) and made a left join with the second result...
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  • Using FILTER after a FULL OUTER JOIN problem in OWB

    Hi,
    I’m using OWB 11.2.
    In an OWB mapping I need to detect every changes (Insert, Update, Delete) made to the data of a table. In order to find these changes I need to use “FULL OUTER JOIN” and a “FILTER” to join current table to previous table.
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    I don’t know how to make OWB generate my desired SQL. Please help me…

    Works ok on 11.2.0.3
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