SQL Query help ( On connect By level clause)
Hi all,
I have this query developed with data in with clause.
With dat As
select '@AAA @SSS @DDD' col1 from dual union all
select '@ZZZ @XXX @TTT @RRR @ZZA' col1 from dual
Select regexp_substr( col1 , '[^@][A-Z]+',1,level) Show from dat
connect by level <= regexp_count(col1, '@');Current output :-
SHOW
AAA
SSS
DDD
RRR
ZZA
TTT
RRR
ZZA
XXX
DDD
RRR
SHOW
ZZA
TTT
RRR
ZZA
. . .1st row comes fine, But next row data is getting duplicated. And total record count = 30. I tried with some but didn't work.
Expected output :-
SHOW
AAA
SSS
DDD
ZZZ
XXX
TTT
RRR
ZZAI need some change on my query and I am not able to find that. So anybody can add on that or can also provide some different solution too.
Thanks!
Ashutosh
Hi,
When you use something like "CONNECT BY LEVEL <= x", then at least one of the following must be true:
(a) the table has no more than 1 row
(b) there are other conditions in the CONNECT BY clause, or
(c) you know what you are doing.
To help see why, run this query
SELECT SYS_CONNECT_BY_PATH (dname, '/') AS path
, LEVEL
FROM scott.dept
CONNECT BY LEVEL <= 3
;and study the results:
PATH LEVEL
/ACCOUNTING 1
/ACCOUNTING/ACCOUNTING 2
/ACCOUNTING/ACCOUNTING/ACCOUNTING 3
/ACCOUNTING/ACCOUNTING/RESEARCH 3
/ACCOUNTING/ACCOUNTING/SALES 3
/ACCOUNTING/ACCOUNTING/OPERATIONS 3
/ACCOUNTING/RESEARCH 2
/ACCOUNTING/RESEARCH/ACCOUNTING 3
/ACCOUNTING/RESEARCH/RESEARCH 3
/ACCOUNTING/RESEARCH/SALES 3
/ACCOUNTING/RESEARCH/OPERATIONS 3
/ACCOUNTING/SALES 2
/ACCOUNTING/SALES/ACCOUNTING 3
84 rows selected.
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SQL Query Help - Is this possible or impossible????
Hi guys,
I need help with an SQL query that I'm trying to develop. It's very easy to explain but when trying to implement it, I'm struggling to achieve the results that I want.....
For example,
I have 2 tables
The first table is:
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insert into company values ('Ford', 1902, 'USA');
insert into company values ('BMW', 1910, 'Germany');
insert into company values ('Tata', 1922, 'India');The second table is:
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insert into models values ('Ford', 'Mondeo', 10000, 2010, 0);
insert into models values ('Ford', 'Galaxy', 12000, 2008, 0);
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insert into models values ('BMW', '535d', 32000, 2006, 0);
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insert into models values ('Tata', 'Safari', 4000, 1999, 0);
insert into models values ('Tata', 'Sumo', 5500, 1996, 1);
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SELECT
com.manufacturer,
com.date_established,
com.location,
DECODE(nvl(mod.current_production_status, '0'), '0', '-', mod.model),
DECODE(nvl(mod.current_production_status, '0'), '0', '-', mod.price),
DECODE(nvl(mod.current_production_status, '0'), '0', '-', mod.year),
mod.current_production_status
FROM
company com,
models mod
WHERE
mod.manufacturer = com.manufacturer
and com.manufacturer IN ('Ford', 'BMW', 'Tata')
and mod.current_production_status IN (1,0)
ORDER BY
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com.manufacturer com.date_established com.location mod.model mod.price mod.year mod.current_production_status
Ford 1902 USA Escort 10000 1992 1
BMW 1910 Germany - - - 0
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The rule is only one record per manufacturer is allowed to have a current_production_status of 1 (so only one model from the selection the manufactuer offers is allowed to be discontinued).
So the query should output the one row where current_production_status is 1 for each manufacturer.
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My query as it is above will output all the records where current status is 1 or 0 like this
com.manufacturer com.date_established com.location mod.model mod.price mod.year mod.current_production_status
Ford 1902 USA Escort 10000 1992 1
Tata 1922 India Sumo 5500 1998 1
Ford 1902 USA - - - 0
Ford 1902 USA - - - 0
BMW 1910 Germany - - - 0
BMW 1910 Germany - - - 0
BMW 1910 Germany - - - 0
Tata 1922 India - - - 0
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Any ideas how I can achieve the result I need?
Thanks!
P.S. Database version is '10.2.0.1.0'Hi Vishnu,
Karthiks query helped...
But this is the problem I am facing...
SELECT
com.manufacturer,
com.date_established,
com.location,
DECODE(nvl(mod.current_production_status, '0'), '0', '-', mod.model),
DECODE(nvl(mod.current_production_status, '0'), '0', '-', mod.price),
DECODE(nvl(mod.current_production_status, '0'), '0', '-', mod.year),
mod.current_production_status
FROM
company com,
models mod
WHERE
mod.manufacturer = com.manufacturer
and com.manufacturer = 'Ford'
and mod.current_production_status IN (1,0)
ORDER BY
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and com.manufacturer = 'Ford'will be dependent on front end user input....
When I run the query above I get all the rows where current_production_status is either 1 or 0.
I only require the rows where current_production_status is 1.
So if I amend it to look like this:
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BUT if a user now passes in more than one manufacturer EG:
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So like this:
com.manufacturer com.date_established com.location mod.model mod.price mod.year mod.current_production_status
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SQL query optimization by changinf the WHERE clause
Hi all,
I need to know about the SQL query performance improvement by changing the WHERE clause. Consider a query :
select * from student where country ='India' and age = 20
Say, country = 'India' filters 100000 records and age = 20 filters 2000 records if given one by one. Now can anyone tell if the performance of the query can be changed by changing the query like this :
select * from student where age = 20 and country ='India'
as first where clause will give 2000 results and next filter will be applicable on only 2000 rows. While in the former query first where clause would give 100000 rows and seconde filter, hence, would be applicable on 100000 rows???
Kindly explain.
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Abhideepin general the order of the where condition should not be important. However there are a few exeptions where sometimes it might play a role. Sometimes this is called order of filter conditions. Among others it depends on RBO or CBO used, Oracle Version, Indexes on the columns, statistic information on the table and the columns, CPU statistics in place etc.
If you want to make this query fast and you know that the age column has much better selectivity then you can simply put an index on the age column. An index on the country column is probably not useful at all, since to little different values are in this column. If you are already in 11g I would suggest to use a composite index on both columns with the more selective in first position.
Edited by: Sven W. on Nov 17, 2008 2:23 PM
Edited by: Sven W. on Nov 17, 2008 2:24 PM -
Hi,
I require help for sql query. The query will be like
"SELECT * FROM XYZ WHERE TEXT = 'h*s' "
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“homes”
“houses”
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SELECT *
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Edited by: OrionNet on Feb 2, 2009 12:33 AM -
Sql query - help reqd (new)
Hi,
I have follwing dataset
"herb with garden"
"garden without herb"
"herb with zbc"
"garden with pqr"
Now i want sql query like
select * from table where text1 = "herb and garden"
This should populate
herb with garden
garden without herb
And
select * from table where text1 = "herb or garden"
This should populate
"herb with garden"
"garden without herb"
"herb with zbc"
"garden with pqr"SQL> with t
2 as
3 (
4 select 'herb with garden' str from dual union all
5 select 'garden without herb' str from dual union all
6 select 'herb with zbc' str from dual union all
7 select 'garden with pqr' str from dual
8 )
9 select *
10 from t
11 where lower(str) like '%herb%'
12 and lower(str) like '%garden%'
13 /
STR
herb with garden
garden without herb
SQL> with t
2 as
3 (
4 select 'herb with garden' str from dual union all
5 select 'garden without herb' str from dual union all
6 select 'herb with zbc' str from dual union all
7 select 'garden with pqr' str from dual
8 )
9 select *
10 from t
11 where lower(str) like '%herb%'
12 or lower(str) like '%garden%'
13 /
STR
herb with garden
garden without herb
herb with zbc
garden with pqr -
Sql query help,i need a query to get like this without union clause
empno ename sum(sal) sum(deptno)
200 tom 2000 10
201 smith 3000 10
202 alfred 3000 20
total 8000 40Hi,
group by rollup (empno,ename) add one row in the end of each same group empno,ename : empno ename sum(sal) sum(deptno) and one in the end ( total)
but group by rollup ((empno,ename)) add only one row in the end total ..... SQL> select nvl(to_char(empno),'Total'), ename,sum(sal),sum(deptno)
2 from emp
3 group by rollup (empno,ename)
4 /
NVL(TO_CHAR(EMPNO),'TOTAL') ENAME SUM(SAL) SUM(DEPTNO)
7900 JAMES 950 30
7900 950 30
7369 SMITH 800 20
7369 800 20
7499 ALLEN 1600 30
7499 1600 30
7521 WARD 1250 30
7521 1250 30
7566 JONES 2975 20
7566 2975 20
7654 MARTIN 1250 30
7654 1250 30
7698 BLAKE 2850 30
7698 2850 30
7782 CLARK 2450 10
7782 2450 10
7788 SCOTT 3000 20
7788 3000 20
7839 KING 5000 10
7839 5000 10
7844 TURNER 1500 30
7844 1500 30
7876 ADAMS 1100 20
7876 1100 20
7902 FORD 3000 20
7902 3000 20
7934 MILLER 1300 10
7934 1300 10
Total 29025 310
29 rows selected.
SQL> select nvl(to_char(empno),'Total'), ename,sum(sal),sum(deptno)
2 from emp
3 group by rollup ((empno,ename));
NVL(TO_CHAR(EMPNO),'TOTAL') ENAME SUM(SAL) SUM(DEPTNO)
7900 JAMES 950 30
7369 SMITH 800 20
7499 ALLEN 1600 30
7521 WARD 1250 30
7566 JONES 2975 20
7654 MARTIN 1250 30
7698 BLAKE 2850 30
7782 CLARK 2450 10
7788 SCOTT 3000 20
7839 KING 5000 10
7844 TURNER 1500 30
7876 ADAMS 1100 20
7902 FORD 3000 20
7934 MILLER 1300 10
Total 29025 310
15 rows selected.
SQL> Edited by: Salim Chelabi on May 9, 2009 5:12 PM
Edited by: Salim Chelabi on May 9, 2009 5:28 PM -
Hi,
I was wondering if I could have some help with the query I have below for this general data set, please? I need to do it in a single SQL statement. We're currently running Oracle 10g. The piece I'm struggling with is identifying that the person has all the items in a collection and to include the collection in the resulting collection of items.
persons_items
person item
Ted cup
Ted saucer
Ted plate
Ted fork
Alice book
Alice thimble
Alice knife
Alice cup
Joe cup
Joe saucer
Joe plate
Joe knife
Joe fork
Joe spoon
Jessica spatula
Jessica dish
collections
collection_name item
crockery cup
crockery saucer
crockery plate
cutlery knife
cutlery fork
cutlery spoon
Query:
What single items and collections does Ted have? fork, crockery
What single items and collections does Alice have? book, thimble, knife, cup
What single items and collections does Joe have? crockery, cutlery
What single items and collections does Jessica have? spatula, dish
Thanks in advance.
PatExpanding on Brendan's solution...
For 11g:
SQL> ed
Wrote file afiedt.buf
1 WITH person_items AS (
2 SELECT 'Ted' person, 'cup' item FROM DUAL UNION
3 SELECT 'Ted', 'saucer' FROM DUAL UNION
4 SELECT 'Ted', 'plate' FROM DUAL UNION
5 SELECT 'Ted', 'fork' FROM DUAL UNION
6 SELECT 'Alice', 'book' FROM DUAL UNION
7 SELECT 'Alice', 'thimble' FROM DUAL UNION
8 SELECT 'Alice', 'knife' FROM DUAL UNION
9 SELECT 'Alice', 'cup' FROM DUAL UNION
10 SELECT 'Joe', 'cup' FROM DUAL UNION
11 SELECT 'Joe', 'saucer' FROM DUAL UNION
12 SELECT 'Joe', 'plate' FROM DUAL UNION
13 SELECT 'Joe', 'knife' FROM DUAL UNION
14 SELECT 'Joe', 'fork' FROM DUAL UNION
15 SELECT 'Joe', 'spoon' FROM DUAL UNION
16 SELECT 'Jessica', 'spatula' FROM DUAL UNION
17 SELECT 'Jessica', 'dish' FROM DUAL
18 ), collections AS (
19 SELECT 'crockery' collection_name, 'cup' item FROM DUAL UNION
20 SELECT 'crockery', 'saucer' FROM DUAL UNION
21 SELECT 'crockery', 'plate' FROM DUAL UNION
22 SELECT 'cutlery', 'knife' FROM DUAL UNION
23 SELECT 'cutlery', 'fork' FROM DUAL UNION
24 SELECT 'cutlery', 'spoon' FROM DUAL
25 ), person_item_colls AS (
26 SELECT pi.person, pi.item, co.collection_name,
27 Count(*) OVER (PARTITION BY pi.person, co.collection_name) n_col
28 FROM person_items pi
29 LEFT JOIN collections co
30 ON co.item = pi.item
31 )
32 select person, listagg(collection_name,',') within group (order by collection_name) as collections
33 from (
34 SELECT DISTINCT person, collection_name
35 FROM person_item_colls
36 WHERE collection_name IS NOT NULL
37 AND n_col > 1
38 UNION ALL
39 SELECT person, item
40 FROM person_item_colls
41 WHERE collection_name IS NULL
42 OR n_col = 1
43 )
44* group by person
SQL> /
PERSON COLLECTIONS
Alice book,cup,knife,thimble
Jessica dish,spatula
Joe crockery,cutlery
Ted crockery,forkFor 10g:
SQL> ed
Wrote file afiedt.buf
1 WITH person_items AS (
2 SELECT 'Ted' person, 'cup' item FROM DUAL UNION
3 SELECT 'Ted', 'saucer' FROM DUAL UNION
4 SELECT 'Ted', 'plate' FROM DUAL UNION
5 SELECT 'Ted', 'fork' FROM DUAL UNION
6 SELECT 'Alice', 'book' FROM DUAL UNION
7 SELECT 'Alice', 'thimble' FROM DUAL UNION
8 SELECT 'Alice', 'knife' FROM DUAL UNION
9 SELECT 'Alice', 'cup' FROM DUAL UNION
10 SELECT 'Joe', 'cup' FROM DUAL UNION
11 SELECT 'Joe', 'saucer' FROM DUAL UNION
12 SELECT 'Joe', 'plate' FROM DUAL UNION
13 SELECT 'Joe', 'knife' FROM DUAL UNION
14 SELECT 'Joe', 'fork' FROM DUAL UNION
15 SELECT 'Joe', 'spoon' FROM DUAL UNION
16 SELECT 'Jessica', 'spatula' FROM DUAL UNION
17 SELECT 'Jessica', 'dish' FROM DUAL
18 ), collections AS (
19 SELECT 'crockery' collection_name, 'cup' item FROM DUAL UNION
20 SELECT 'crockery', 'saucer' FROM DUAL UNION
21 SELECT 'crockery', 'plate' FROM DUAL UNION
22 SELECT 'cutlery', 'knife' FROM DUAL UNION
23 SELECT 'cutlery', 'fork' FROM DUAL UNION
24 SELECT 'cutlery', 'spoon' FROM DUAL
25 ), person_item_colls AS (
26 SELECT pi.person, pi.item, co.collection_name,
27 Count(*) OVER (PARTITION BY pi.person, co.collection_name) n_col
28 FROM person_items pi
29 LEFT JOIN collections co
30 ON co.item = pi.item
31 )
32 select person, ltrim(sys_connect_by_path(collection_name,','),',') as collections
33 from (
34 select person, collection_name, row_number() over (partition by person order by collection_name) as rn
35 from (
36 SELECT DISTINCT person, collection_name
37 FROM person_item_colls
38 WHERE collection_name IS NOT NULL
39 AND n_col > 1
40 UNION ALL
41 SELECT person, item
42 FROM person_item_colls
43 WHERE collection_name IS NULL
44 OR n_col = 1
45 )
46 )
47 where connect_by_isleaf = 1
48 connect by person = prior person and rn = prior rn + 1
49* start with rn = 1
SQL> /
PERSON COLLECTIONS
Alice book,cup,knife,thimble
Jessica dish,spatula
Joe crockery,cutlery
Ted crockery,fork -
SQL Query : Getting specific datatype in select clause
Hi
I want to write one query that returns me the values inside a table based on the datatype of column(s) of the table. For e.g. I need only those columns of the table in select clause where the datatype of the column is VARCHAR.
Can you please help me on this?Use the "user_tab_columns" Data Dictionary to get the columns and build the SQL Dynamically.
Thanks,
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SQL Query Help: Average of Sums !
Hi Folks !
I've been tasked with wirting a program that queries Oracle DB. And I'm not used to SQL a lot. May be my question is very basic. Please bear with me.
I've simplified the table structure for this question.
The table Order has 4 fields:
1. Order_id
2. Trial_No.
3. Response_Time.
4. Order_Time
Now the first two fields (Order_id, Trial_number) together make up the Primary Key (It is a composite key). My goal is to find the Average Response time for each Order ID in the past 10 minutes. Order_Time is the time at which Order was placed. An order can take more than one trail to complete the order. Order Reponse time is the sum of all the Trail response times.
A basic query like this
select AVG(Response_Time) from Order where Order_time < sysdate -10/1440.
gives me the Average of the response time but here is the catch : It produces the Average no matter how many trials the Order had. An order's response time is SUM of all the Trail Response times it had.
Consider the following data in the table
Order_id Trial_No Resopnse_Time (ms)
1 1 1000
2 1 1000
2 2 1000
2 3 1000
If I just use "select AVG(RESPONSE_Time), it will result in 1000ms. (4000/4).
But in reality, Order 2 had taken 3000ms to complete (3 trials). And the Avg Order Response time should be (1000+3000)/2 = 2000ms. Can you see it?
In other words, How do I calcluater the Avg of the sums of the rows, instead of Avg of all the rows. I've gone through some docs about 'group by' clause and 'subqueries', but don't seem to find the answer.
Thanks very much for reading such a long post. Looking forward to some guideance.
- KYou'll want some analytics on this:
SYS%xe> --select sum(sum_resp_time)/sum(rn) avg
SYS%xe> --from (
SYS%xe> with dataset as
2 (select 1 Order_id, 1 Trial_No, 1000 Response_Time from dual union all
3 select 2 , 1 , 1000 from dual union all
4 select 2 , 2 , 1000 from dual union all
5 select 2 , 3 , 1000 from dual
6 )
7 select order_id
8 , response_time
9 , row_number() over ( partition by order_id order by order_id) rn
10 , sum(response_time) over ( partition by order_id order by order_id) sum_resp_time
11 from dataset
12 -- ) where rn = 1;
ORDER_ID RESPONSE_TIME RN SUM_RESP_TIME
1 1000 1 1000
2 1000 1 3000
2 1000 2 3000
2 1000 3 3000
4 rijen zijn geselecteerd.
Verstreken: 00:00:02.15
SYS%xe> select sum(sum_resp_time)/sum(rn) avg
2 from (
3 with dataset as
4 (select 1 Order_id, 1 Trial_No, 1000 Response_Time from dual union all
5 select 2 , 1 , 1000 from dual union all
6 select 2 , 2 , 1000 from dual union all
7 select 2 , 3 , 1000 from dual
8 )
9 select order_id
10 , response_time
11 , row_number() over ( partition by order_id order by order_id) rn
12 , sum(response_time) over ( partition by order_id order by order_id) sum_resp_time
13 from dataset
14 ) where rn = 1;
AVG
2000
1 rij is geselecteerd.But you could do without them, as Raj showed.
( I guess this is one of my weirdest queries ;-) )
Edited by: hoek on Apr 7, 2009 6:17 PM -
hi guys
i have sample data as mentioned below... need to find the duplicate rows where cd=cd and dt1=dt1 and tm1 difference should be less than or equal to 4 hrs..
i can get the data with the query written below but my problem is that i am not allowed to use in-built sql server function... can you help me in writing the same without using in-built function...
CREATE TABLE #t (id INT,dt1 datetime, tm1 datetime,cd varchar(10))
INSERT INTO #t VALUES (101,'2013-04-24','1900-01-01 12:20:00.000','TC')
INSERT INTO #t VALUES (101,'2013-04-24','1900-01-01 12:30:00.000','TC')
INSERT INTO #t VALUES (101,'2013-08-02','1900-01-01 14:30:00.000','MN')
INSERT INTO #t VALUES (101,'2013-08-02','1900-01-01 15:07:00.000','MN')
INSERT INTO #t VALUES (101,'2013-07-06','1900-01-01 09:07:00.000','XY')
INSERT INTO #t VALUES (101,'2013-11-27','1900-01-01 09:50:00.000','LM')
INSERT INTO #t VALUES (101,'2013-07-06','1900-01-01 15:07:00.000','XY')
select * From #t
WITH MyCTE (rn,id, dt1, tm1, cd)
AS(
select row_number() over (partition by id ORDER BY dt1, tm1) rn,* from #t
select case when ((dt1 = lead_start_Date) and (ct <='4.0') and (base_cd = lead_cd)) then 'Duplicate_Req' else '' end dt123,* from
select abs(convert(decimal(5,1),datediff(MI,lead_Start_time,tm1)/60.00)) ct, * from
SELECT base.rn b_rn,LEAd.rn l_rn,BASE.id
,BASE.dt1
,BASE.tm1
,base.cd base_cd
,LEAD.dt1 LEAD_START_DATE
,LEAD.tm1 LEAD_START_TIME
,lead.cd lead_cd
--,DATEADD(dd,-1,LEAD.dt1) EXPECTED_END_DATE
FROM MyCTE BASE
LEFT JOIN MyCTE LEAD ON BASE.id = LEAD.id
AND BASE.rn = LEAD.rn+1
) b
)cif this code will not work for you then not sure if there are any other options
Converted the CTE into an actual temp table.
CTE and barebones T-SQL code are included in the script below.
CREATE TABLE #t (id INT,dt1 datetime, tm1 datetime,cd varchar(10))
INSERT INTO #t VALUES (101,'2013-04-24','1900-01-01 12:20:00.000','TC')
INSERT INTO #t VALUES (101,'2013-04-24','1900-01-01 12:30:00.000','TC')
INSERT INTO #t VALUES (101,'2013-08-02','1900-01-01 14:30:00.000','MN')
INSERT INTO #t VALUES (101,'2013-08-02','1900-01-01 15:07:00.000','MN')
INSERT INTO #t VALUES (101,'2013-07-06','1900-01-01 09:07:00.000','XY')
INSERT INTO #t VALUES (101,'2013-11-27','1900-01-01 09:50:00.000','LM')
INSERT INTO #t VALUES (101,'2013-07-06','1900-01-01 15:07:00.000','XY')
INSERT INTO #t VALUES (101,'2013-08-02','1900-01-01 15:07:00.000','MN')
select * From #t
;WITH MyCTE (rn,id, dt1, tm1, cd)
AS(
select row_number() over (partition by id ORDER BY dt1, tm1) rn,* from #t
select case when ((dt1 = lead_start_Date) and (ct <='4.0') and (base_cd = lead_cd)) then 'Duplicate_Req' else '' end dt123,* from
select abs(convert(decimal(5,1),datediff(MI,lead_Start_time,tm1)/60.00)) ct, * from
SELECT base.rn b_rn,LEAd.rn l_rn,BASE.id
,BASE.dt1
,BASE.tm1
,base.cd base_cd
,LEAD.dt1 LEAD_START_DATE
,LEAD.tm1 LEAD_START_TIME
,lead.cd lead_cd
--,DATEADD(dd,-1,LEAD.dt1) EXPECTED_END_DATE
FROM MyCTE BASE
LEFT JOIN MyCTE LEAD ON BASE.id = LEAD.id
AND BASE.rn = LEAD.rn+1
) b
)c
select * into #copy From #t order by id, cd, dt1, tm1
alter table #copy add seqno int identity(1,1)
select distinct y.id,y.cd,y.dt1,y.tm1,y.seqno,case when z.cd is not null then 'Duplicate_Req' else '' end dt123
from #copy y
left outer join
(select a.id,a.cd,a.dt1,a.tm1
From #copy a
left outer join #copy b
on a.id = b.id
and a.cd = b.cd
and a.dt1 = b.dt1
where a.seqno > b.seqno
and abs(datediff(MINUTE,b.tm1,a.tm1)) <= 240) z
on y.id = z.id
and y.cd = z.cd
and y.dt1 = z.dt1
and y.tm1 = z.tm1
order by y.dt1,y.tm1
drop table #copy
drop table #t -
SQL Query for Database Connections
What would be the proper syntax or DBA table to query and find out how many database connections there are currently? Thanks for all of your help!!
Marlanselect * from v$session;Some entries in this view are dynamic processes (type = 'BACKGROUND') and you may want to exclude those depending on your requirements.
-
Hello,
I need help with SQL... My database version is Oracle 10g Release 1.2.
I have two table with the exact same structure as follows...
create table t1(cust_id number(5), zone_number number(2), part_number varchar2(10))
create table t2(cust_id number(5), zone_number number(2), part_number varchar2(10))
I need a query that would give me two counts per pairs of customer between t1 and t2..
1.Count of part_number matches between the same zones in table 1 and table 2 for pairs of customers
for Customer 1 and 10 for zone 1 this total shoulb be 2 because between cust 1 and 10 for Zone 1 there are two part number matches A and B.
for Customer 1 and 10 for zone 2 this total shoulb be 0 because between cust 1 and 10 for Zone 2 there are no part number matches
for Customer 1 and 20 for zone 1 this total shoulb be 0 because between cust 1 and 20 for Zone 1 there are no part number matches
for Customer 1 and customer 20 zone 2 this total shoulb be 0 because between cust 1 and 20 for Zone 2 there is one part number matches , which is 'F'
for Customer 1 and customer 20 zone 3 this total shoulb be 0 because there is no zone 3 for Customer 1
same way
.. cust 2 and cust 10 Zone 1 counts and zone2 counts
.. for 2 and cust 20 zone 1, 2, and 3 counts
2. Total unique Part nmbers between the same zones for pairs of customers in table 1 and table2
for example
unique part numbers between cust 1 and 10 for zone 1 are A,B and C so the count should be 3
unique part numbers between cust 1 and 10 for zone 2 are B,F, D and E so the count should be 3
unique part numbers between cust 1 and 20 for zone 1 are A,B,C and G so the count should be 4
and so on so forth
insert into t1 values(1, 1, 'A')
insert into t1 values(1, 1, 'B')
insert into t1 values(1, 1, 'C')
insert into t1 values(1, 2, 'B')
insert into t1 values(1, 2, 'F')
insert into t1 values(1, 2, 'D')
insert into t1 values(1, 2, 'E')
insert into t1 values(2, 1, 'F')
insert into t1 values(2, 2, 'G')
insert into t1 values(2, 2, 'H')
insert into t2 values(10, 1, 'A')
insert into t2 values(10, 1, 'B')
insert into t2 values(10, 2, null)
insert into t2 values(20, 1, 'G')
insert into t2 values(20, 2, 'F')
insert into t2 values(20, 2, 'H')
insert into t2 values(20, 3, 'I')
insert into t2 values(20, 3, 'J')
My query result should be as follows...
cust1 cust2 zone pn_match_count total_unique_pn_count
1 10 1 2 3
1 10 2 0 4
1 20 1 0 4
1 20 2 1 5
1 20 3 0 2
2 10 1 0 3
2 10 2 0 2
2 20 1 0 2
2 20 2 1 3
2 20 3 0 2
I would really appreciate your help in writing this query.
Thanks in Advanceuser00 wrote:
No, that doesn't do it... I get no results with this query becuase the Cust_id in table 1 and table 2 are not the same.Yeah, I only realised that after I posted my query. I had interpreted pairs as "matching pairs" when what you meant was "permutations".
Cheers, APC
blog: http://radiofreetooting.blogspot.com -
SQL Query Help/ Converts seconds to day:hr:mi:se
I have query that returns value in seconds. How i will convert those seconds in DAY:HOUR:MIN:SEC in the same query? What will be the mathematical formulae or alogorithim for this?
Thanks
Munis Warsi
nullSeriously, you post 750+ lines of unformatted SQL statement and a completely unreadable and unformatted explain plan and you expect people to be able to help with that?
From what I can see it looks like some sort of query against an Oracle APPS database, and there are numerous calls to PL/SQL functions in there, so you're creating a multitude of context switches between the SQL and PL engines... that's known to cause performance problems.
Take a read of the discussions linked in the FAQ: Re: 3. How to improve the performance of my query? / My query is running slow.
And also consider if your question would be better asked in the Oracle Apps forum space instead.
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