Start Configuration Using CIO

Question

Hi,
I am using CIO object to start a Configuration from OA Framework. below is the code followed by the error am encountering.
======= Start Code =========
Context context = new CZWebAppsContext("HostName","Port","vis");
System.out.println("------------- Context object created ----------");
ConfigParameters cp = new ConfigParameters(79160); // 79160 is Model ID.
System.out.println("------------- ConfigParameters object created ----------");
CIO cioObject = new CIO();
System.out.println("------------- CIO object created ----------");
Calendar modelLookupDate = Calendar.getInstance(); // current date and time
cp.setModelLookupDate(modelLookupDate);
System.out.println("-------------Start CZ Libraries ----------");
cioObject.checkForCZLibraries();
System.out.println("------------- CZ Libraries ----------");
Configuration config = cioObject.startConfiguration(cp,context);
System.out.println("------------- Configuration object created ----------");
========= End Code ==========
====== Error Log =========
oracle.apps.fnd.framework.OAException: oracle.jbo.JboException: JBO-29000: Unexpected exception caught: java.lang.UnsatisfiedLinkError, msg=no czlce in java.library.path
at oracle.apps.fnd.framework.OAException.wrapperException OAException.java:888)
     at oracle.apps.fnd.framework.OAException.wrapperException(OAException.java:864)
     at OAErrorPage.jspService(OAErrorPage.jsp:35)
======== Error Log =======
Could any one plz help me in finding the solution?
Regards,
Adarsh

Answer 1

Thanks Mukul. I got the session id.
Could you help me with my next step.
I need to launch the configurator UI to create new configurations and pass back the headerid and rev number to the current page.
I am confused here and need some guidance.
Should I follow Oracle® Configurator,Extensions and Interface Object Developer’s Guide Release 11i -->Example 5–1 Creating a Configuration Object (MyConfigCreator.java)
or should I refer to chapter 9 Session Initialization, and initialize the cz's UI servlet.
Actually I hardcoded the values in the initialize xml and was able to launch the particular UI which I had hardcoded. I do not know how to retrieve ui_def_id for the particular model name I enter in the form.It needs to be dynamic , than hardcoded.
Here is what I did:
<form action=................/CZInitialize.jsp method="post" id="test1" name="test1">
<input type="hidden" name="XMLmsg" value='<initialize>
<param name="database_id">skm123_dbc</param>
<param name="user">test</param>
<param name="pwd">1234abc</param>
<param name="calling_application_id">708</param>
<param name="responsibility_id">24190</param>
<param name="ui_def_id">186540</param>
<param name="ui_type">JRAD</param>
Please Help.
Thanks