Strings escaping problem

I need to pass a file location into a method as a parameter.
The input to the method is like this in a java properties file.
//Example file location as entered in properties file
C:\home\apps_dev\tomcat\apache-tomcat-6.0.16\shared\lib\QAWSERVE.INII know about escaping but since this is user input, the filename will not be escaped by the user.
I have to pass it to the another method in this original format
C:\home\apps_dev\tomcat\apache-tomcat-6.0.16\shared\lib\QAWSERVE.INIMy problem is, since the backslash character is an escape character, it doesn't resolve as a proper file location.
This is the code I have written
    this.iniFile = properties.getProperty("ini-file");
    System.out.println(" INI-FILE IS "+iniFile);this is the output.
INI-FILE IS C:homeapps_dev        omcatapache-tomcat-6.0.16sharedlibQAWSERVE.INII need to make the output just like the original. How can this escaping be done
Edited by: gcameo on Jul 13, 2009 3:21 AM
Edited by: gcameo on Jul 13, 2009 3:22 AM

gcameo wrote:
the properties file is all I have got. Its an application that already exists. We can try going by xml but the impact will be too much for just a single configuration.
I am looking at parsing it myself but have never done so so I looking on the internet. If any of you guys can give me any pointers that will be great.
My other option is to hard code the file into a specific location, but that is bad coding practise and dont feel good about that.
Anyway am impressed how you clearly understood my bone of contention..
RegardsOpen a e.g a FileReader and wrap it in a BufferedReader. Call readLine in a loop and split each line on the first "=". The left part is the key, the right part is the value. You can place each key and value in a Properties object that you have instantiated, and return that instance.
Kaj

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Message was edited by:
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Message was edited by:
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