Submit statement is not working

i am trying to use submit statment in FM but i am not getting control when submit get executed..
Return is not working ..
any help regarding this will be appreciated
Edited by: James rammstein on Jun 30, 2009 5:14 PM

There may be list output from what you are submitting.
Try EXPORTING LIST TO MEMORY along with AND RETURN.

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Insert statement will not work if select statement has less number of colum

Hi,
One of my thread is already resolved on the following URL : unable to insert rows into the table
DROP TABLE TEMP;
CREATE TABLE TEMP AS SELECT * FROM CASE_101 WHERE 1=2;
DECLARE
S VARCHAR2(200);
STMT VARCHAR2(500);
begin
for C in (select TABLE_NAME INTO S from USER_TABLES where TABLE_NAME like 'CASE%' TABLE_NAME NOT like '%OLD' and Num_ROWS > 0 order by TABLE_NAME) loop
STMT := 'INSERT INTO TEMP SELECT * FROM ';
STMT:=STMT || C.TABLE_NAME;
EXECUTE IMMEDIATE STMT;
dbms_output.put_line(c.table_name);
end loop;
end;
i am facing now some different; almost all the tables have same number of columns except in few of tables have some additional columns. As above i am creating a table "TEMP" who has highest column temp(by doing some manual process). The table who has less columns than "TEMP" table : Insert statement will not work. 'INSERT INTO TEMP SELECT * FROM less_columns_table_name'.
Please let me know , how can i execute proper way.
Thanks.
Best Regards
Arshad

user13360241 wrote:
Hi,
One of my thread is already resolved on the following URL : unable to insert rows into the table
DROP TABLE TEMP;
CREATE TABLE TEMP AS SELECT * FROM CASE_101 WHERE 1=2;
DECLARE
S VARCHAR2(200);
STMT VARCHAR2(500);
begin
for C in (select TABLE_NAME INTO S from USER_TABLES where TABLE_NAME like 'CASE%' TABLE_NAME NOT like '%OLD' and Num_ROWS > 0 order by TABLE_NAME) loop
STMT := 'INSERT INTO TEMP SELECT * FROM ';
STMT:=STMT || C.TABLE_NAME;
EXECUTE IMMEDIATE STMT;
dbms_output.put_line(c.table_name);
end loop;
end;
i am facing now some different; almost all the tables have same number of columns except in few of tables have some additional columns. As above i am creating a table "TEMP" who has highest column temp(by doing some manual process). The table who has less columns than "TEMP" table : Insert statement will not work. 'INSERT INTO TEMP SELECT * FROM less_columns_table_name'.
Please let me know , how can i execute proper way.
Thanks.
Best Regards
Arshadmore often than not "TEMP" tables are NOT required & are highly inefficient in Oracle.
Either only specify explicit column in TEMP to get data,
or provide value for "extra" column in TEMP

CASE Statement is not working Derived table

Hi All,
in the bello SQL Statement case statement is not working in derived table. I am new to creation of derived table if any body knows plz kinldy help me out on this.
SELECT x.market, x.droprate as med1
FROM
(select upper(market_name) as market, fulldate as date_value,
     (sum([Dy_LOT_DROPS_N][Dy_OB_HO_DROPS][Dy_NonRF_Drop]))/
          nullif(sum(CASE WHEN (month(BBHDLY.FullDate)}>= 6 and { year(BBHDLY.FullDate)} = 2011) or {fn year(IDENSLABBHDLY.FullDate)} > 2011
THEN BBHDLY.Dy_Calls - BBHDLY.Dy_HO_CHAN_ALLOC ELSE BBHDLY.Dy_Calls END),0)*100 as droprate
from BBHDLY sla
inner join Dim mkt
     on sla.bts_name = mkt.bts_name and sla.SectorID = mkt.Sector_Id
               where fulldate >= GETDATE()-46
               group by market_name, fulldate) x,
(select market_name as market, fulldate as date_value,
(sum([Dy_LOT_DROPS_N][Dy_OB_HO_DROPS][Dy_NonRF_Drop]))/
          nullif(sum(CASE WHEN ({fn month(BBHDLY.FullDate)}>= 6 and {fn year(BBHDLY.FullDate)} = 2011) or {fn year(BBHDLY.FullDate)} >
2011 THEN BBHDLY.Dy_Calls - BBHDLY.Dy_HO_CHAN_ALLOC ELSE BBHDLY.Dy_Calls END),0)*100 as droprate
from BBHDLY sla
inner join Dim mkt
     on sla.bts_name = mkt.bts_name and sla.SectorID = mkt.Sector_Id
               where fulldate >=GETDATE()-46
               group by market_name, fulldate) y
where x.market = y.market
GROUP BY x.droprate, x.market
HAVING
   SUM(CASE WHEN y.droprate <= x.droprate
      THEN 1 ELSE 0 END)>=(COUNT(*)+1)/2 AND
   SUM(CASE WHEN y.droprate >= x.droprate
      THEN 1 ELSE 0 END)>=(COUNT(*)/2)+1
Thanks

It looks like SQL Server or Sybase given that you're using getdate().
As such, Vinesh's comment to use decode is wrong - decode is Oracle syntax.
Looking at your statement again, I've noticed the following:
you have no { to match the first } - not sure why you're using them anyway.
you haven't given x.market a name - use x.market as market instead
use coalesce instead of nullif if you're on SQL Server.

Insert statement is not working for z table.

Hi experts,
My insert statement is not working.
I have used follwing code to update z table .
INSERT ztable FROM TABLE gt_table.
here i have checked gt_table and its filled up with all the records properly.
now the problem is in this table i have 15 fields and it inserts 14 fields of it but
the last field is never inserted though in gt_table i can see value for last fields also.
I have added this field in ztable recently . so i also used se14 to adjust table but still i am facing same problem.
please help me out.
thanks,
Neo

> > Table maintainance will have nothing to do with
> this
> > issue.
>
> It does sometimes when you are trying to see the
> values from SM30 instead of SE16. The value may be
> there, but it may just not seen in SM30 because the
> table maintenance hasn't registered the addition of
> new field.
>
> Another place to look at is the activation log to see
> if there are any warnings issued there.
You shouldn't use SM30 to view table entries. You use this transaction to maintain the table entries. Pure and Simple.

Delete Statement is not working correctly

Hello,
The following delete statement is not working correctly.
If I press delete it will delete everything in the category table
I don't know whats wrong with it.
----delete row from category if there is not infrastructure to support------
IF :P12_DFCY_SEQNO4 IS NOT NULL AND :P12_DFCY_CATG_C = '7' THEN
DELETE FROM DFCY_CATG
WHERE NOT EXISTS(SELECT I.DFCY_SEQNO
FROM DFCY_CATG C, DFCY_CATG_INFRSTRCTR I
WHERE C.DFCY_SEQNO = I.DFCY_SEQNO
AND :P12_DFCY_SEQNO4 = I.DFCY_SEQNO);
end if;
Thanks
Mary

Hi,
IF :P12_DFCY_SEQNO4 IS NOT NULL AND :P12_DFCY_CATG_C = '7' THEN
DELETE FROM DFCY_CATG
WHERE NOT EXISTS(SELECT I.DFCY_SEQNO
FROM DFCY_CATG C, DFCY_CATG_INFRSTRCTR I
WHERE C.DFCY_SEQNO = I.DFCY_SEQNO
AND :P12_DFCY_SEQNO4 = I.DFCY_SEQNO);
end if;So, if P12_DFCY_SEQNO4 does not exist, then I would expect all records to be deleted because the NOT EXISTS() function would just return TRUE for every record on the table. Somewhere in the statement, I would expect to see something that links between the table being deleted from and the NOT EXISTS() data or, perhaps, using the P12_DFCY_CATG_C value as a filter?
Andy

Delete statement is not working.

Hi,
find the code. Here the delete statement is not working and i am getting sy-subrc = 4. although ,
xe1edp10-idnkd = 34596 and dint_edidd -sdata = 34596.
please help me ...
loop at dekek_x.
loop at dint_edidd where segnam = 'E1EDP10'.
if dekek_x-stpin = 1 .
CLEAR xe1edp10.
MOVE dint_edidd-sdata TO xe1edp10.
delete dint_edidd where sdata = xe1edp10-idnkd.
endif.
endloop.

1st thing..
i tried this :
tables: edidd, e1edp10.
edidd-sdata = '315934 EA 017'.
WRITE edidd-sdata.
move edidd-sdata to e1edp10.
IF edidd-sdata = e1edp10-idnkd.
WRITE: e1edp10-idnkd.
else.
WRITE: 'nothing'.
ENDIF.
output
>315934 EA 017
>315934 EA 017
2nd thing,.
your loop inside loop doesnt make any sense as they are not related any where.
3rd thing:
the fields are not type compatible.. this might be the reason for wrong delete statement..
and 1 more clarification:
TABLES: edidd, e1edp10.
DATA :it TYPE TABLE OF edidd WITH HEADER LINE.
edidd-sdata = '315934 EA 017'.
WRITE edidd-sdata.
APPEND edidd TO it.
edidd-sdata = '315934 EA 018'.
APPEND edidd TO it.
LOOP AT it." where segnam = 'E1EDP10'.
CLEAR e1edp10.
MOVE it-sdata TO e1edp10.
DELETE it WHERE sdata = e1edp10-idnkd.
ENDLOOP.
in this also delete is working perfectly fine... you run and check..

SORT statement is not working!

Hi frdz,
Below SORT statement is not working. Can any one explain me why this is happening.
SORT i_bseg ASCENDING BY belnr bukrs
                    DESCENDING kunnr.
I have table content as below.
BELNR      BUKRS KUNNR
0016000000|CROP |
0016000000|CROP |0008910168
Before and after the sort content order is same.
I want to sort the content like below.
0016000000|CROP |0008910168
0016000000|CROP |
Is there any thing wrong with the sort statement???
i_bseg is defined as TYPE STANDARD TABLE OF
Sort criteria must not change i. e ascending by belnr and bukrs and descending by kunnr.
Thanks,
Vinod.

hi vinod,
this is because on your statement, you are sorting BUKRS in descending order and KUNNR in ASCENDING order.
please take note that the sort order should come after the sorted field. if no order is given, the default which is ASCENDING will be used.
do your sorting like this
SORT i_bseg BY belnr bukrs kunnr DESCENDING.
regards,
Peter

SELECT statement does not work if characters ## are contained in field

Hi Experts,
I have the following statement:
select single field1
    from table1
    into var1
    where field2 = text.
This is a very simple statement that is working for me almost always correct. However there is a situation where the system is not able to find the record in my table. If text is equal to JAN##2011 the system won't deliver a result even if I have an entry in table1 with exactly this value.
TABLE1
field1 field2
rome JAN##2011
paris JAN2011
only if text is JAN2011 the select will find a result.
all fields are defined as CHAR.
Thanks in advanced

Hi Alberto,
probably ## is not ## :-).
is the visible representation used by ABAP to show any non-displayable characters as control characters like TAB, CR, LF, FF and the like.
In debugger you can switch to HEX display of values, if you see something like 0A0D you can find this using CL_ABAP_CHAR_UTILITIES constant attributes.
Regards
Clemens

Message statement is not working?

I would like to place a message in the following method:
It's defined like this:
Position & cannot be delimited because the position is occupied until &
This is in the program:
MESSAGE: s029(zpom_001) WITH st_hrp1001-objid(8) st_hrp1001-endda(8), display like 'E'.
I inserted the (display like 'E' ) in so I can get the RED 'X' error message. If I take out the display like 'E', it works.
I get the following error:
Three-digit error number XXX required in the "MESSAGE EXXX..." statement.
Thanks for any help you can give?
Jeff

Satish,
That did not work...
If I remove the part of the message ( Display like 'E' ) it works...... But if I want to get a RED X error message, what would I do?
JeffG

ADOBE LiveCycle Designer 8 - EMAIL SUBMIT BUTTON DOES NOT WORK

I created a new form in Adobe LiveCycle Designer 8, but the email submit button, nor a regular button assigned with a 'submit' function will do anything. It should initiate a new Outlook email but it does not. My default programs are set correctly (default email program and the default "mailto" program are set to Outlook). This document was created not only with ALC8, but on a Windows Vista PC with MS Office 2007. I ran a test to see if it would work on a WinXP SP2 machine with Office 2003 and it still did not work.
Can anyone help?

Alan
Though not an expert, I've created a few forms with the Submit by Email button. If you've already done this then sorry for asking, but did you go through the Acrobat Distribution (Forms>Distribute Forms)process after creating the form in LC8? As far as I can tell the email submit button doesn't work without this stage.
This confirms the email submission address, then sets up a dataset to be saved in a location of your choice.
filename_dataset_0001.pdf
then a file type that can be edited, saved and submitted by Reader users:
filename_pub_0001.pdf
You can save this to your intranet server or email direct to the recipient.
When the submit button is then used you receive a copy of the whole form which on opening will prompt you to add it to the dataset. Receiving and adding multiple forms to the data set is straightforward. You will see them all listed in the viewer above the form itself. From here you can also then select and export the data to Excel via xml or as a csv file.
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That's about the limit of my knowledge I'm afraid, therefore if you have already tried this and are still having problems then hopefully someone else can help out.
Regards

I opened my form and downloaded the form to post on my website... but the submit button is not working.

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Hi,
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Insert -> email link. In my DW it looks lik this:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>eMail</title>
</head>
<body>
<a href="mailto:[email protected]">eMail</a>
</body>
</html>
The users click into the word "eMail" your eMail-program wil start.
Naturally there are som other ways, like this for example:
<td width="35%"><input id="send" type="submit" name="Submit" value="send" />
I suggest first try or test the easy way.
Hans-G.

CWB - Salary Plan - Review and Submit section is not working

Hi All,
I am implementing Compensation Workbench and after successfully plan design I am able to see the plan on CWB admin home. Set Budgets and Allocate Compensation functions are working perfectly but Review and Submit and Manage Approval Functions are not working , means when I access the Review and submit section the submit for approval button even all other buttons are not working means when press, nothing happen, it looks that no code is written behind the buttons.
first of all I would like to confirm that without this Can we Increase the salary amount in the payroll elements? if this is the necessary part Can we bypass this part after doing Allocate compensation function ? If no bypass then kindly suggest what to do because I am unable to update the employees salaries due to this problem.
Regards,

Hi, Any update guruz.

Submit button is not working

I have created a fillable web form using the FormsCentral app on my mac.
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It tests perfectly, and we sent out a link to the formscentral link to all staff and for some people it does not work. They can see the form and fill in data, but the show/hide stuff doesn't perform correctly and the submit button doesn't work.
Works for me in Safari and Firefox, and seems sketchy in IE - works for some but not others.
Any thoughts?

The first thing to confirm is that the form is an HTML/web form and not a PDF embedded in the browser, if it is a PDF please see this FAQ: http://forums.adobe.com/docs/DOC-4142
Assuming you or your customers/users are having problems submitting the HTML/web form - the most common cause of show/hide logic not working and the Submit button not working is Javascript is not enabled in the web browser.
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Confirm that Javascript is enabled (required for FormsCentral forms):
http://www.javatester.org/javascript.html
Clear the browser cache
Try disabling browser plugins
If using Internet Explorer check to see if the page is in "Compatibility View" mode and if so try turning it off
Try a different web browser
I know that this is made more difficult by the fact that it is not you reporting this issue but your customers and you may not have acess to try the steps above...
If these steps don't resolve the issue please respond with the operating system you are on (Mac or Windows) and which web browser and version you are using.
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Cursor 'mouseover' state change not working in Chrome

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This forum software is very tricky; updates to forum posts sometimes need to be done three or four times until it "takes". I have been able to update your original post.
Now that it is actually readable, I will go and have a look at it.

Submit button does not work

Hi,
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Any ideas
Thanks

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Submit statement is not working

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