Synchronize Local WF Tables is reverting partitions to NOLOGGING

On ATG.H RUP 4 and 5, there is a bug where the daily Synchronize WF Local Tables concurrent request set is reverting partitions of WF_LOCAL_ROLES to NOLOGGING. If you attempt to restore a database or clone when this request set has run between your hot backup time and your requested restore time, you will not be able to log in due to:
ORA-01578: Oracle data block corrupted (file #66, block #106574)
ORA-26040: Data block was loaded using the NOLOGGING option
ORA-06512: at "APPS.WF_DIRECTORY", line 649
The block corresponds to applsys.wf_local_roles.
Note 433280.1 indicated this is fixed in ATG.H RUP6.
Partitions in Workflow Local Tables are Automatically Switched to NOLOGGING
http://metalink.oracle.com/metalink/plsql/ml2_documents.showDocument?p_database_id=NOT&p_id=433280.1
RUNNING SYNCHRONIZE WF LOCAL TABLES CHANGES PARTITION TO NOLOGGING.
https://metalink.oracle.com/metalink/plsql/showdoc?db=Bug&id=5942254
During a Backup, WF_LOCAL_ROLES Is Showing Corrupt Block
http://metalink.oracle.com/metalink/plsql/ml2_documents.showDocument?p_database_id=NOT&p_id=369535.1
I hacked around it by truncating wf_local_roles in the target, then exported it from the source, imported in the target instance and ran the Synchronize WF Local Tables request set:
Unable To Login After Clone
http://metalink.oracle.com/metalink/plsql/ml2_documents.showDocument?p_database_id=NOT&p_id=418130.1
We altered all the wf_local_roles partitions to logging yesterday in the source instance, and one reverted back to nologging today already. Pretty annoying...

thanks michael for sharing that with us
fadi

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Cl_gui_alv_grid:exporting protected table data MT_OUTTAB to local int.table

Hi guys,
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Hi,
not yet any suggestion?
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Aggregate tables have many partitions per request

We are having some performance issues dealing with aggregate tables and
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some analysis, we can see that for many of our aggregates, there are
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issues. But we don;t understand why they are being created.
I have even tried deleting the aggregate (all aggregate F tables and
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partitions than requests. (we also notice that many of the partitions
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partition displays to help illustrate the issue.
Any help would be appreciated.
Brad Daniels
302-275-1980
215-592-2219

Ideally the aggregates should get compressed by themselves - there could be some change runs that have affected the compression.
Check the following :
1. See if compressing the cube and rolling up the aggregates will merge the partitions.
2. What is the delta mode for the aggregates ( are you loading deltas for aggregates or full loads ) ?
3. Aggregates are partitioned according to the infocube and since you are partitioning according to the requests - the same is being done on the aggregates.
Select another partitioning characteristic if possible. - because it is ideally recommended that request should not be used for partitioning.
Arun
Assign points if it helps..

Modify HUGE HASH partition table to RANGE partition and HASH subpartition

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C_NBR CHAR(12),
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LINE_ID CHAR(2))
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PARTITION TEST_PART_200010 VALUES LESS THAN(200010),
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Data: -
INSERT INTO TEST_PART
VALUES ('2000',200001,'CM');
INSERT INTO TEST_PART
VALUES ('2000',200009,'CM');
INSERT INTO TEST_PART
VALUES ('2000',200010,'CM');
VALUES ('2006',NULL,'CM');
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How do I change the current partition of the table from HASH partition to RANGE partition and a sub-partition (HASH) without losing the data and existing indexes?
The table after restructuring should look like the one below
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YRMO_NBR NUMBER(6),
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Pls advice
Thanks in advance

Sorry for the confusion in the first part where I had given a RANGE PARTITION instead of HASH partition. Pls read as follows;
I have a table with 130,000,000 rows hash partitioned as below
----HASH PARTITION--
CREATE TABLE TEST_PART(
C_NBR CHAR(12),
YRMO_NBR NUMBER(6),
LINE_ID CHAR(2))
PARTITION BY HASH (C_NBR)
PARTITIONS 2
STORE IN (PCRD_MBR_MR_02, PCRD_MBR_MR_01);
CREATE INDEX TEST_PART_IX_001 ON TEST_PART(C_NBR,LINE_ID);
Data: -
INSERT INTO TEST_PART
VALUES ('2000',200001,'CM');
INSERT INTO TEST_PART
VALUES ('2000',200009,'CM');
INSERT INTO TEST_PART
VALUES ('2000',200010,'CM');
VALUES ('2006',NULL,'CM');
COMMIT;
Now, I need to keep this table from growing by deleting records that fall b/w a specific range of YRMO_NBR. I think it will be easy if I create a range partition on YRMO_NBR field and then create the current hash partition as a sub-partition.
How do I change the current partition of the table from hash partition to range partition and a sub-partition (hash) without losing the data and existing indexes?
The table after restructuring should look like the one below
COMPOSIT PARTITION-- RANGE PARTITION & HASH SUBPARTITION --
CREATE TABLE TEST_PART(
C_NBR CHAR(12),
YRMO_NBR NUMBER(6),
LINE_ID CHAR(2))
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SUBPARTITION BY HASH (C_NBR) (
PARTITION TEST_PART_200009 VALUES LESS THAN(200009) SUBPARTITIONS 2,
PARTITION TEST_PART_200010 VALUES LESS THAN(200010) SUBPARTITIONS 2,
PARTITION TEST_PART_200011 VALUES LESS THAN(200011) SUBPARTITIONS 2,
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Pls advice
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Will there performance improvement over separate tables vs single table with multiple partitions?

Will there performance improvement over separate tables vs single table with multiple partitions? Is advisable to have separate tables than having a single big table with partitions? Can we expect same performance having single big table with partitions? What is the recommendation approach in HANA?

Suren,
first off a friendly reminder: SCN is a public forum and for you as an SAP employee there are multiple internal forums/communities/JAM groups available. You may want to consider this.
Concerning your question:
You didn't tell us what you want to do with your table or your set of tables.
As tables are not only storage units but usually bear semantics - read: if data is stored in one table it means something else than the same data in a different table - partitioned tables cannot simply be substituted by multiple tables.
Looked at it on a storage technology level, table partitions are practically the same as tables. Each partition has got its own delta store & can be loaded and displaced to/from memory independent from the others.
Generally speaking there shouldn't be too many performance differences between a partitioned table and multiple tables.
However, when dealing with partitioned tables, the additional step of determining the partition to work on is always required. If computing the result of the partitioning function takes a major share in your total runtime (which is unlikely) then partitioned tables could have a negative performance impact.
Having said this: as with all performance related questions, to get a conclusive answer you need to measure the times required for both alternatives.
- Lars

Regarding 'FREE' ABAP Keyword in the local internal table

Hi Experts,
//sorry for my english ;(
Our ABAP Development leader forced us to use FREE ABAP Keyword on Local internal table like below situation.
and I really don't get it.
-below-
FORM GET_DATA.
DATA: LT_ITAB TYPE TABLE OF SFLIGHT.
SELECT * FROM ZTABLE INTO TABLE LT_TABLE
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I know that GC(garbage collector) will release memory area of LT_ITAB.
but why do i have to release directly FREE LT_ITAB memory area?
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Guys, why don't you read ABAP help?
From ABAP help about FREE:
For internal tables, FREE has the same effect as the REFRESH statement, though the entire memory area occupied by the table rows is released, and the initial memory area remains unoccupied
About REFRESH:
This statement sets an internal table itab to its initial value, meaning that it deletes all rows of the internal table. The memory space required for the table is freed up to the initial memory size INITIAL SIZE. For itab, you must specify an internal table.
To delete all rows and free the entire memory space occupied by rows, you can use the statement FREE.
About INITAIL SIZE:
After the optional addition INITIAL SIZE, you can specify a number of rows n as a numeric literal or numeric constant to adjust the size of the first block in the memory that is reserved by the system for an internal table of the table type. Without this addition, if the number 0 is entered, or the value of n exceeds a maximum value, the system automatically allocates an appropriate memory area.
To summarize:
Using free allows you to immediately free the initial space reserved by the kernel for an internal table.
I am lazy to look for it, but I don't think it ever exceeds few Kb.
regards,
Yuri

Is it possible a partition table create a partition itself?

Hi,
I migrated a table to range partition table by years on production system.
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When a new record comes for year 2011 and if there is no partition for 2011 the table should be create new partition for 2011 itself?
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regards,

Hi,
I haven't tried EXECUTE_IMMEDIATE. It doesn't matter because I haven't found how the partition name concatenate a variable automatically.
DB version is 10.2.0.1.
table script is:
CREATE TABLE INVOICE_PART1
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CREATOR VARCHAR2(8 BYTE) NOT NULL,
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INITRANS 1
MAXTRANS 255
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MAXEXTENTS 2147483645
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INITRANS 1
MAXTRANS 255
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MAXEXTENTS 2147483645
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How to make a table to be partitioned automatically in 10.1.0.2.0 ?

Hi
I am using Oracle database 10.1.0.2.0.
I created a table. I have done partition on Date column.
Initially I created partitions for 2007 year.
Now I should create partitions for 2008 year. So every year, I have to add partitions manually.
Could any one help me, how can I automate this process.?
Thank you,
Regards,
Gowtham sen.

I don't know.. how much it would effect.
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If I use trigger, it would verify..whether the value in the coumn is new value or not.
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Create local temp table

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Alter range partition table to Interval partitioning table.

Hi DBA's,
I have a very big range partitioned table.
Recently we have upgraded our database to 11gR2 which has a feautre called interval partitioning.
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If you ignore the "alter session set NLS_CALENDAR=PERSIAN;" during create/alter, everything else seems to work.
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Table Compression on Partitions

Hi,
Can any help how to implement Table compression on Partitions?
Thanks in advance

Here is two examples for you.
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SQL>create table test_compress1
(t_id number(10),
tname varchar2(30)) partition by range (t_id)
(partition p0 values less than (50) compress
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compress ;
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SQL>create table test_compress2
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Postifx user unknown in local recipient table

Good morning --
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Thanks, Mihalis.
I do not us su -l -- just plain old su. And echo $USER returns the correct user (that is, the one I su'd into).
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The problem resolves temporarily if I restart postfix, but it returns within a few cycles (the cron job runs every three minutes.
The error message repeats itself for each mail item that fetchmail parses. Here's the last bit of a fetchmail's results:
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Fetchmail, Postfix user unknown in local recipient table

Hello all --
My fetchmail job has been failing to get mail to my mailbox with this error:
SMTP error: 450 4.1.1 <username@localhost>: Recipient address rejected: User unknown in local recipient table
(I replace my actual user name with "username")
The problem goes away temporarily if I stop and restart postfix, but it comes back almost immediately.
I'm having a hard time finding any clues in postfix's log. I'm not too sure what to look for, and it's pretty voluminous!
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AlanNYC wrote:
If I turn off local recipient checking, will I actually get my mail?
Yes, all email properly addressed should be delivered to you without problems.
The line only affects improperly addressed email, in this case allowing them to be accepted instead of rejected.
Since you are running Spamassassin and an IMAP server, I suggest also using the line
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If you find postfix giving you problems after adding the lines, simply delete them or comment them out by adding a hash mark to the front of the line, e.g.
#localrecipientmaps =
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I assume you're testing your changes using a separate email account, but in case you're not: sign up for a free email account with any of a number of free email services (Gmail, Yahoo) and test your postfix install as you make changes using the free account.

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Thanks,
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Debugger issue - local variable table missing

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Thanks,
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How about using javac?

Synchronize Local WF Tables is reverting partitions to NOLOGGING

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