SYSAUX for XML Repository?
Hi,
I'm new in the xml db oracle (10g).
With the command "create or replace directory XML_DIR as '/home/foo/xml';" I've created a DIRECTORY object that points where I saved the XML files. Now some questions worry me...
Is it a correct way to store xml files into oracle database?
In what tablespace has the directory XML_DIR been created?
I'm afraid the user SYS is the owner of this directory, though I've used my own user foo. Why? Is it this like that?
So, I think that XML DB Repository uses the SYSAUX, but I don't want to use it for that. What do I have to do to use another tablespace? Is it possible not to use SYSAUX?
Thank you in advance.
Look up CREATE DIRECTORY in your version's SQL manual and you will find something like
>>
All directories are created in a single namespace and are not owned by an individual schema. You can secure access to the BFILEs stored within the directory structure by granting object privileges on the directories to specific users.
<<
You will also find the following
>>
When you create a directory, you are automatically granted the READ and WRITE object privileges on the directory, and you can grant these privileges to other users and roles
<<
Directories have always been owned by user SYS. Access is controled by granting READ and WRITE on them. The creator has READ and WRITE plus the ability to grant access to the object.
How you store XML depends on your needs. Oracle provides XML data types you can use within the database and it also provides XML data load parsing and extraction procedures.
My personal view is that relational databases are used best when the product is used to store relational data. If you XML output create it on extraction. If you just need to keep track of XML files then consider using BFILE data types to do this.
HTH -- Mark D Powell --
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=============
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YanHi,
Thans for your reply.
This is the DTD for my xmldoc.
<!ELEMENT Data (Department+)>
<!ELEMENT EmployeeID (#PCDATA)>
<!ATTLIST EmployeeID col (EMPID) #IMPLIED>
<!ELEMENT Education (EmployeeID, Sequence, Dgree)>
<!ATTLIST Education table NMTOKEN #IMPLIED>
<!ELEMENT Employee (EmployeeName, EmployeeID, DepartmentID, Education*)>
<!ATTLIST Employee table NMTOKEN #IMPLIED>
<!ELEMENT EmployeeName (#PCDATA)>
<!ATTLIST EmployeeName col NMTOKEN #IMPLIED>
<!ELEMENT DepartName (#PCDATA)>
<!ATTLIST DepartName col NMTOKEN #IMPLIED>
<!ELEMENT Table (Column+)>
<!ATTLIST Table importType NMTOKEN #IMPLIED>
<!ATTLIST Table parentTable NMTOKEN #IMPLIED>
<!ATTLIST Table tag NMTOKEN #IMPLIED>
<!ATTLIST Table columns NMTOKEN #IMPLIED>
<!ATTLIST Table name NMTOKEN #IMPLIED>
<!ELEMENT DepartID (#PCDATA)>
<!ATTLIST DepartID col NMTOKEN #IMPLIED>
<!ELEMENT MetaData (Table+)>
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<!ATTLIST Sequence col NMTOKEN #IMPLIED>
<!ELEMENT Dgree (#PCDATA)>
<!ATTLIST Dgree col NMTOKEN #IMPLIED>
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<!ATTLIST DepartmentID col NMTOKEN #IMPLIED>
<!ELEMENT Column (#PCDATA)>
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Yan -
Hi all,
I am learning XPATH and XQUERY from the Book "Pro T-SQL 2008 Programmer's Guide" written by Michael Coles, (published by apress). I copied the Code Listing 12-8 FOR XML PATH Using XPath Node Tests (listed below) and executed it in my
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-- 16 March 2015 0935 AM
USE AdventureWorks;
GO
SELECT
p.NameStyle AS "processing-instruction(nameStyle)",
p.BusinessEntityID AS "Person/@ID",
p.ModifiedDate AS "comment()",
pp.PhoneNumber AS "test()",
FirstName AS "Person/Name/First",
MiddleName AS "Person/Name/Middle",
LastName AS "Person/Name/Last",
EmailAddress AS "Person/Email"
FROM Person.Person p
INNER JOIN Person.EmailAddress e
ON p.BusinessEntityID = e.BusinessEntityID
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ON p.BusinessEntityID = pp.BusinessEntityID
FOR XML PATH;
I got the following error message:
Msg 6850, Level 16, State 1, Line 2
Column name 'test()' contains an invalid XML identifier as required by FOR XML; '('(0x0028) is the first character at fault.
I have no ideas why I got this error message. Please kindly help and advise me how to resolve this error.
Thanks in advance, Scott ChangHi Michelle, Thanks for your nice response.
I corrected the mistake and executed the revised code. It worked nicely.
I just have one question to ask you about the appearance of the xml output of my Co;les12_8.sql:
<row>
<?nameStyle 0?>
<Person ID="1" />
<!--2003-02-08T00:00:00-->697-555-0142<Person><Name><First>Ken</First><Middle>J</Middle><Last>Sánchez</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="2" />
<!--2002-02-24T00:00:00-->819-555-0175<Person><Name><First>Terri</First><Middle>Lee</Middle><Last>Duffy</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="3" />
<!--2001-12-05T00:00:00-->212-555-0187<Person><Name><First>Roberto</First><Last>Tamburello</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="4" />
<!--2001-12-29T00:00:00-->612-555-0100<Person><Name><First>Rob</First><Last>Walters</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="5" />
<!--2002-01-30T00:00:00-->849-555-0139<Person><Name><First>Gail</First><Middle>A</Middle><Last>Erickson</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="6" />
<!--2002-02-17T00:00:00-->122-555-0189<Person><Name><First>Jossef</First><Middle>H</Middle><Last>Goldberg</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="7" />
<!--2003-03-05T00:00:00-->181-555-0156<Person><Name><First>Dylan</First><Middle>A</Middle><Last>Miller</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="8" />
<!--2003-01-23T00:00:00-->815-555-0138<Person><Name><First>Diane</First><Middle>L</Middle><Last>Margheim</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="9" />
<!--2003-02-10T00:00:00-->185-555-0186<Person><Name><First>Gigi</First><Middle>N</Middle><Last>Matthew</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="10" />
<!--2003-05-28T00:00:00-->330-555-2568<Person><Name><First>Michael</First><Last>Raheem</Last></Name><Email>[email protected]</Email></Person></row>
<row>
<?nameStyle 0?>
<Person ID="11" />
<!--2004-12-29T00:00:00-->719-555-0181<Person><Name><First>Ovidiu</First><Middle>V</Middle><Last>Cracium</Last></Name><Email>[email protected]</Email></Person></row>
<row>
I feel this xml output is not like the regular xml output. Do you know why it is diffrent from the regular xml xml output? Please comment on this matter.
Thanks,
Scott Chang
What do you mean by regular xml document? Are you referring to fact that its missing a root element? if yes it can be added as below
USE AdventureWorks;
GO
SELECT
p.NameStyle AS "processing-instruction(nameStyle)",
p.BusinessEntityID AS "Person/@ID",
p.ModifiedDate AS "comment()",
pp.PhoneNumber AS "text()",
FirstName AS "Person/Name/First",
MiddleName AS "Person/Name/Middle",
LastName AS "Person/Name/Last",
EmailAddress AS "Person/Email"
FROM Person.Person p
INNER JOIN Person.EmailAddress e
ON p.BusinessEntityID = e.BusinessEntityID
INNER JOIN Person.PersonPhone pp
ON p.BusinessEntityID = pp.BusinessEntityID
FOR XML PATH('ElementName'),ROOT('RootName');
replace ElementName and RootName with whatever name you need to set for element as well as the root element
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