System.arraycopy for objects?

Question

I am getting weird results here. I create an array of Test2 objects. The Test2 toString method simply returns the args from the constructor. When I try to copy the array using arraycopy, I just get the number 3 in the second array. Why is this happening?
     Test2[] ar1 = new Test2[7];
          Test2[] ar2 = new Test2[9];
          ar1[0] = new Test2("1");
          ar1[1] = new Test2("2");
          ar1[2] = new Test2("3");
          ar1[3] = new Test2("4");
          ar1[4] = new Test2("5");
          ar1[5] = new Test2("6");
          ar1[6] = new Test2("7");
          for(int i = 0; i < ar1.length; i++){
               System.out.print(ar1[i] + ", ");
          System.out.println();
          System.arraycopy(ar1, 0, ar2, 0, 5);
          for(int i = 0; i < ar2.length; i++){
               System.out.print(ar1[2] + ", ");
          }This is the output:
1, 2, 3, 4, 5, 6, 7,
3, 3, 3, 3, 3, 3, 3, 3, 3,
My textbook says that copying the array will copy the reference to the object. Why isn't it working? I must be missing something obvious. Thanks in advance.
ps. When I remove the toString method, all the elements of the second array have the reference of the third object. This is the address for the third element of the first array:
Test2@3bad086a, Test2@3bad086a, Test2@3bad086a, Test2@3bad086a, Test2@3bad086a, Test2@3bad086a
Edited by: 837443 on Feb 27, 2011 10:40 AM

Answer 1

837443 wrote:
I must be missing something obvious. Um, yeah.
          for(int i = 0; i < ar2.length; i++){
               System.out.print(ar1[2] + ", ");
ps. When I remove the toString method, all the elements of the second array have the reference of the third object. No, they don't.
This is the address for the third element of the first array:It's not the address.