T.code FBL5N: a problem with the print of the output list

Hi All,
with reference to the t.code FBL5N, I have a problem with the print of the output list of the report.
When I execute the print, I obtain one customer for each page printed.
I wonder if is possible to obtain more customers for each page printed.
Could anyone help me?
Thanks
Gandalf
Edited by: Umberto Gandalf on Dec 21, 2008 10:36 PM

Hi,
Though personally i havent tried this option, check the same
Go to Menu: Settings >> Switch List
This will make the value displayed in ALV format and then try taking print outs.
Regards,
Sridevi

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Problems with the output of an array

Hallo,
I have got problems with giving out an array.
I declared two arrays and puted them out, but with the
resultarray it doesn�t work. Cansomebody help me?
Here is a runtime output:
Grad eingeben!
1
Koeffizienten eingeben!
1
2
1x^0 + 2x^1 +
1
Grad eingeben!
3
Koeffizienten eingeben!
2
3
4
5
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p:1
this:3
And here is the source code
// Die Klasse Polynom dient dem Umgang mit dem Polynom
//Sie enth�llt die Methoden:
//   > public void readCoeffizients()
//   > public void show()
//   > public int getGrad()
//   > public Polynom add(Polynom p)
//Und den Konstruktor:
//   > public Polynom(int n)
public class Polynom
private int grad;
int [] coeffizient;
private Polynom q1;
public Polynom(int n) //Konstruktor mit Stanard-Initialisierung
    this.grad = -1;
    this.coeffizient = new int [n+1];
    for(int i=1; i<(n+1); i++)
      this.coeffizient[i] = 0;
public void readCoeffizients() // Methode zum Einlesen der Koeffizienten
    this.grad = (coeffizient.length)-1;
    System.out.println("Koeffizienten eingeben!");
    for(int i=0; i<(grad+1);i++)
      this.coeffizient[i] = Eingabe.intValue();
public void show() // Methode zum Ausgeben des Polynoms
    for (int i=0; i<(this.getGrad()+1);i++)
      System.out.print(coeffizient[i] + "x^" + i + " + ");
    System.out.println();
public int getGrad()
    return this.grad;
public Polynom add(Polynom p) // Methode zum Addieren zweier Polynome
    System.out.println("\np:" + p.getGrad());
    System.out.println("this:" + this.getGrad());
    if(p.getGrad() >= this.getGrad()) // Vorgehen falls p.getGrad() gr��er als this.getGrad()
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      grad = p.getGrad();
      for(int i=0; i<(this.getGrad()+1);i++)
        q1.coeffizient[i] = this.coeffizient[i] + p.coeffizient;
for(int i=(this.getGrad()+1);i<(p.getGrad()+1);i++)
q1.coeffizient[i] = p.coeffizient[i];
else // Vorgehen falls this.getGrad() gr��er als p.getGrad()
q1 = new Polynom(this.getGrad());
grad = this.getGrad();
for(int i=0; i<(p.getGrad()+1);i++)
q1.coeffizient[i] = this.coeffizient[i] + p.coeffizient[i];
for(int i=(p.getGrad()+1);i<(this.getGrad()+1);i++)
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return q1; // R�ckgabe des Ergebnisspolynoms
// Diese Klasse testet die Klasse Polynom
public class Test
public static void main(String[] args)
System.out.println("Grad eingeben!");
Polynom p1 = new Polynom(Eingabe.intValue());
p1.readCoeffizients();
p1.show();
System.out.println(p1.getGrad());
System.out.println("Grad eingeben!");
Polynom p2 = new Polynom(Eingabe.intValue());
p2.readCoeffizients();
p2.show();
System.out.println(p2.getGrad());
//Polynom p3 = (p2.add(p1));
//p3.show();
(p2.add(p1)).show();
Thanks for your help!

Ehm, this should really be obvious: because in the
first two cases you are using the constructor
and readCoeffizients(), whereas in the third
case you are only using the constructor.You?re right, but I initiate grad in the add method.Then look again: you don't! You are calling the constructor, but the constructor is not assigning grad in a proper way. If you are refering to the line grad = p.getGrad();this is in fact equal to this.grad = p.getGrad();But this.grad is not q1.grad (which is private). Assign grad in the constructor only (where it belongs) or better still don't use grad at all and derive the degree of the polynom from the length of the coefficients array.

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%ALDImageFileName: Speicher:image.jpg
%ALDImageDimensions: 30 30
%ALDImageCropRect: 0 0 30 30
%ALDImageCropFixed: 0 0 30 30
%ALDImagePosition: 203.8677 344.8913 203.8677 359.2913 218.2677 359.2913 218.2677 344.8913
%ALDImageType: 4 8
%%BeginObject: image
[14.4 0 0 14.4 203.868 344.891 ]ct
snap_to_device
Adobe_AGM_Image/AGMIMG_fl cf /ASCII85Decode fl /RunLengthDecode filter ddf
<<
/T 1
/W 30
/H 30
/M[30 0 0 -30 0 30 ]
/BC 8
/D[0 1 0 1 0 1 0 1 ]
/DS [
[AGMIMG_fl 30 string /rs cvx /pop cvx] cvx
[AGMIMG_fl 30 string /rs cvx /pop cvx] cvx
[AGMIMG_fl 30 string /rs cvx /pop cvx] cvx
[AGMIMG_fl 30 string /rs cvx /pop cvx] cvx
/O 3
>>
%%BeginBinary: 1
img
p&G-p!<E*"!<<3"!!!&i!!30$!Vl`q!V$-m!WW3&!r`0#!Wh]h!!20]!WW3$qZ$^!!!!&f!!30$!WE'!
!WE'$!<<*#nc/[l!W<!#!WW3%h>dNVnGiXl!<<-)!!*'"!<<2f!<*$!!<3)a!!!&t!!*-%kl:\ar;Zm"
!!2He#6G2G(D[>Z!<*#e!!WKUEK,/l!r`0"!V$.!!Wi?'-t[mD-NjDN!!2Zk!!3#u"T\]4$OR%8!!!&h
!!<6)*\I@D!\,8pq>g3h%KQP0';ta-rr2ho&-2b3mf3Y*Q/q,jk2D[9"76'h!=o#B!Y,22n,Nn!!!=Q!
0.ee,0/"XS!VHHl!!E<'!"[l]rrUsd!Ug!r&'a/!k3(mej38#8mJm8&'`/UF'`J.(!"8l.+"o,p/hSe-
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jlEuS!!2Ng#S7^d%KHtR'bTm7!s/H(/-mj['`\n!/1Ukk!"985s8@'?Du]k7%KHP#!"8l0$KC71C'%l,
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D;u0+!!<qtS-&0["T\T'$5EXA!!33:%da5t!<<]/!!3u<!V$-o!<<*#!FZ$-!!A;d!!2ipq#CKu!<?7$
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rVup!q#Gp~>
%%EndBinary
%%EndObject
Orginal image Size 553,9 KB
After decoding the size is only 1,8 KB
First try.
public class ASCII85Decode {
private ByteBuffer buf;
* initialize the decoder with byte buffer in ASCII85 format
private ASCII85Decode(ByteBuffer buf) {
this.buf = buf;
* get the next character from the input.
* @return the next character, or -1 if at end of stream
private int nextChar() {
// skip whitespace
// returns next character, or -1 if end of stream
while (buf.remaining() > 0) {
char c = (char) buf.get();
if (!isWhiteSpace(c)) {
return c;
// EOF reached
return -1;
public static boolean isWhiteSpace(int c) {
return (c == ' ' || c == '\t' || c == '\r' || c == '\n'
|| c == 0 || c == 12);
// 0=nul, 12=ff
* decode the next five ASCII85 characters into up to four decoded
* bytes. Return false when finished, or true otherwise.
* @param baos the ByteArrayOutputStream to write output to, set to the
* correct position
* @return false when finished, or true otherwise.
private boolean decode5(ByteArrayOutputStream baos)
throws PDFParseException {
// stream ends in ~>
int[] five = new int[5];
int i;
for (i = 0; i < 5; i++) {
five[i] = nextChar();
if (five[i] == '~') {
if (nextChar() == '>') {
break;
} else {
throw new PDFParseException(
"Bad character in ASCII85Decode: not ~>");
} else if (five[i] >= '!' && five[i] <= 'u') {
five[i] -= '!';
} else if (five[i] == 'z') {
if (i == 0) {
five[i] = 0;
i = 4;
} else {
throw new PDFParseException(
"Inappropriate 'z' in ASCII85Decode");
} else {
throw new PDFParseException(
"Bad character in ASCII85Decode: " + five[i]
+ " (" + (char) five[i] + ")");
if (i > 0) {
i -= 1;
int value = five[0] * 85 * 85 * 85 * 85 + five[1] * 85 * 85
* 85 + five[2] * 85 * 85 + five[3] * 85 + five[4];
for (int j = 0; j < i; j++) {
int shift = 8 * (3 - j);
baos.write((byte) ((value >> shift) & 0xff));
return (i == 4);
* decode the bytes
* @return the decoded bytes
private ByteBuffer decode() throws PDFParseException {
// start from the beginning of the data
buf.rewind();
// allocate the output buffer
ByteArrayOutputStream baos = new ByteArrayOutputStream();
// decode the bytes
while (decode5(baos)) {
return ByteBuffer.wrap(baos.toByteArray());
* decode an array of bytes in ASCII85 format.
* <p>
* In ASCII85 format, every 5 characters represents 4 decoded
* bytes in base 85. The entire stream can contain whitespace,
* and ends in the characters '~>'.
* @param buf the encoded ASCII85 characters in a byte buffer
* @param params parameters to the decoder (ignored)
* @return the decoded bytes
public static ByteBuffer decode(ByteBuffer buf)
throws PDFParseException {
ASCII85Decode me = new ASCII85Decode(buf);
return me.decode();
2. Try
public class Ascii85Decode {
private final FileOutputStream fos;
private Ascii85Decode() throws FileNotFoundException {
File f = new File("/home/markus/1/test/bild.jpg");
fos = new FileOutputStream(f);
@Override
protected void finalize() throws Throwable {
fos.close();
super.finalize();
public static byte[] decode(byte[] in) throws FileNotFoundException, IOException {
Ascii85Decode ascii85Decode = new Ascii85Decode();
ascii85Decode.setData(in);
ascii85Decode.decode85();
return null;
static long pow85[] = {85 * 85 * 85 * 85, 85 * 85 * 85, 85 * 85, 85, 1};
private byte[] in;
private void setData(byte[] in) {
this.in = in;
void wput(long tuple, int bytes) throws IOException {
switch (bytes) {
case 4:
putchar((int) (tuple >> 24));
putchar((int) (tuple >> 16));
putchar((int) (tuple >> 8));
putchar((int) tuple);
break;
case 3:
putchar((int) (tuple >> 24));
putchar((int) (tuple >> 16));
putchar((int) (tuple >> 8));
break;
case 2:
putchar((int) (tuple >> 24));
putchar((int) (tuple >> 16));
break;
case 1:
putchar((int) (tuple >> 24));
break;
void decode85() throws IOException {
long tuple = 0;
int c, count = 0;
int i=0;
for (;;) {
switch (c = in[i]) {
default:
if (c < '!' || c > 'u') {
System.err.println("%s: bad character in ascii85 region: %#o\n");
System.exit(1);
tuple += (c - '!') * pow85[count++];
if (count == 5) {
wput(tuple, 4);
count = 0;
tuple = 0;
break;
case 'z':
if (count != 0) {
System.err.println("%s: z inside ascii85 5-tuple\n");
System.exit(1);
putchar(0);
putchar(0);
putchar(0);
putchar(0);
break;
case '~':
if (in[i+1] == '>') {
if (count > 0) {
count--;
tuple += pow85[count];
wput(tuple, count);
c = in[i+1];
return;
System.err.println("%s: ~ without > in ascii85 section\n");
System.exit(1);
case '\n':
case '\r':
case '\t':
case ' ':
case '\0':
case '\f':
case '\b':
case 0177:
break;
i++;
private void putchar(int l) throws IOException {
//System.out.write(l);
fos.write(l);
Does anybody have an idea to solve the problem?

A scan from string function can be used as per the attachment. The double \ ('\\') is in the format string in order to interpret the '\' characters in your input string as literal characters and not special formatting.
Message Edited by Dennis Knutson on 07-10-2006 03:53 PM
Attachments:
Scan From String.JPG ‏5 KB

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<removed by moderator>
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BOILERPLATE TEXT:
Note that this is boilerplate text.
If you give complete and detailed information about your setup and the issue at hand,
such as your platform (Mac or Win),
exact versions of your OS, of Photoshop (not just "CS6", but something like CS6v.13.0.6) and of Bridge,
your settings in Photoshop > Preference > Performance
the type of file you were working on,
machine specs, such as total installed RAM, scratch file HDs, total available HD space, video card specs, including total VRAM installed,
what troubleshooting steps you have taken so far,
what error message(s) you receive,
if having issues opening raw files also the exact camera make and model that generated them,
if you're having printing issues, indicate the exact make and model of your printer, paper size, image dimensions in pixels (so many pixels wide by so many pixels high). if going through a RIP, specify that too.
etc.,
someone may be able to help you (not necessarily this poster, who is not a Windows user).
a screen shot of your settings or of the image could be very helpful too.
Please read this FAQ for advice on how to ask your questions correctly for quicker and better answers:
http://forums.adobe.com/thread/419981?tstart=0
Thanks!

Problem with delay printing utilizing a canon IR c1030 with the lasted drivers

Hi, I am a total noob at Mac OS
I have Macbook pro with Mountain Lion installed I also have conected to our organization a Airport Express which I use around the office. The problem is that my department have a network printer Canon IR C1030 which I installed the lasted driver UFRII but when I print its takes a very long time and most time a get the error code: 9 and out of 10 pages I get only 3 to 4.my guesss is that is a problem with the Airport Express and latency but I am not sure. could someone give me a clue what to do next
Thanks in advance

Does the iR C1030 have support for WiFi or is it using it's built-in Ethernet port to connect to the AirPort Express? Or are you using the USB port on the C1030 to connect to the Express?
If the C1030 is connecting to the Express via Ethernet, then as a test I would suggest you connect the MacBook Pro to the Express via Ethernet also.
Note that if there is only a single Ethernet port on the Express then you will need a unswitched hub to connect to this port on the Express and then you can connect the Mac and C1030 to the other Ethernet ports on the hub.
If you get the same latency when printing from Mac for this Ethernet-only setup, then this would confirm that it is not a WiFi issue and there is something else contributing to the delay.

There is a problem with the security certificate of the proxy server. Error code 18 and 38.

Hi All,
After several hours and a short night of sleep I'm out of ideas and hopefully someone here can help me trying to solve this one. First of all the situation:
Exchange 2013 on a remote location with a CA-certificate.
Outlook 2010 and 2013 on different locations, locally installed and on RDS.
When I open Outlook on my laptop all is fine, no errors, good sync, no problem. But when I open Outlook on our Remote Desktop Servers with Outlook 2013 I'm getting errors like "There is a problem with the security certificate of the proxy server. The
name on the security certificate is invalid or does not match the name of the site. Outlook is unable to connect to this server. (Error code 18)". Opening Outlook 2010 the message is the same, but the error code now is 38.
After this Outlook opens and is working, there's one more error though. After a while an security warning pops up with the message: "Information you exchange with this site cannot be viewed or changed by others. However, there is a problem with the
site's security certificate. * The security certificate was issued by a company you have not chosen to trust. View the certificate to determine whether you want to trust the certifying authority. * The security certificate is valid. * The name on the security
certificate is invalid or does not match the name of the site."
Strangest thing is, it is the certificate of my RDS! It isn't my valid en officially bought certificate from my mailserver. What's going on? I'm out of options, what I've tried so far (in random order):
- restarting mailserver and AD;
- restarting switches;
- restarting routers;
- restarting RDS, AD and all other servers;
- bypassed proxyserver for RDS;
- created a new profile;
- checked recently installed updates;
- checked certificate on mailserver;
- checked RDS on a different location, working fine.
Nothing helped, what can I do next? Please advice.
Regards.

Found a thread that solves half my problem (https://social.technet.microsoft.com/Forums/office/en-US/70d18244-889a-4d95-ac3f-e234672a82b2/there-is-a-problem-with-the-proxy-servers-security-certificate-error-when-starting-outlook?forum=exchangesvrclients).
The first message can be suppressed by adding this to the Exchange config:
set-outlookprovider -Identity EXCH -CertprincipalName msstd:webmail.domain.tld
set-outlookprovider -Identity EXPR -CertprincipalName msstd:webmail.domain.tld
Giving the command get-outlookprovider, gives me empty information regarding the certprinipalname. Filled
this and after recreating the profile or deleting the ost-file I still have the second alert with the local certificate of my RDS.
Not completely where I want to be, any help regarding the second alert is greatly appreciated!

While installing adobe creative cloud , getting the following error msg " There seems to be a problem with the download process. Error code:201"

while installing adobe creative cloud , getting the following error msg " There seems to be a problem with the download process. Error code:201"

Creative Cloud Help / Error downloading Creative Cloud applications
http://helpx.adobe.com/creative-cloud/kb/error-downloading-cc-apps.html

T.code FBL5N: a problem with the print of the output list

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