T-SQL Script to find the backup job details

Question

Hi,
I have a requirement to get the below details:
1) Database Name
2) Backup Job Name
3) Database Type (Full/Differential/Log)
4) Recovery Model
5) Time of the SQL Backup Job.
Please help me in getting all these things in single query as I have to collate information from many queries to get the information. We have 100+ servers and need to update this information.
Thanks in advance!
Regards,
Sharath

Answer 1

DECLARE @db_name VARCHAR(100)
SELECT @db_name = DB_NAME()
SELECT TOP ( 30 )
s.server_name,
s.database_name,
CASE s.[type]
WHEN 'D' THEN 'Full'
WHEN 'I' THEN 'Differential'
WHEN 'L' THEN 'Transaction Log'
END as BackupType,
s.recovery_model,
s.backup_finish_date,
s.backup_start_date,
DATEDIFF(mi,s.backup_start_date , s.backup_finish_date)/60 as Total_Time_in_Hours,
cast(CAST(s.backup_size / 1024 / 1024 / 1024 AS INT) as varchar(14))
+ ' ' + 'GB' as bkSize,
CAST(s.first_lsn AS varchar(50)) AS first_lsn,
CAST(s.last_lsn AS varchar(50)) AS last_lsn,
m.physical_device_name
FROM msdb.dbo.backupset s
inner join msdb.dbo.backupmediafamily m ON s.media_set_id = m.media_set_id
WHERE s.database_name = @db_name
ORDER BY backup_start_date desc,
backup_finish_date