Table Partitioning in Oracle 8i

Can tables be partitioned in Oracle 8i Standard Edition, or do I have to have the Enterprise Edition? I'm trying to deal with backup of a large database, and want to consider performinig partial backups to save time/resources. Thanks.

Hi,
You need entreprise edition for that.
no other way

Similar Messages

  • Automatic table partitioning in Oracle 11g

    Hi All,
    I need to implement automatic table partitioning in Oracle 11g version, but partitioning interval should be on daily basis(For every day).
    I was able to perform this for Monthly and Yearly but not on daily basis.
    create table part
    (a date)PARTITION BY RANGE (a)
    INTERVAL (NUMTOYMINTERVAL(1,'*MONTH*'))
    (partition p1 values less than (TO_DATE('01-NOV-2007','DD-MON-YYYY'))
    Table created
    create table part
    (a date)PARTITION BY RANGE (a)
    INTERVAL (NUMTOYMINTERVAL(1,'*YEAR*'))
    (partition p1 values less than (TO_DATE('01-NOV-2007','DD-MON-YYYY'))
    Table createdBut if i use DD or DAY instead of YEAR or MONTH it fails......Please suggest me how to perform this on daily basis.
    SQL>
      1  create table part
      2  (a date)PARTITION BY RANGE (a)
      3  INTERVAL (NUMTOYMINTERVAL(1,'*DAY*'))
      4  (partition p1 values less than (TO_DATE('01-NOV-2007','DD-MON-YYYY'))
      5* )
    SQL> /
    INTERVAL (NUMTOYMINTERVAL(1,'DAY'))
    ERROR at line 3:
    ORA-14752: Interval expression is not a constant of the correct type
    SQL> create table part
    (a date)PARTITION BY RANGE (a)
    INTERVAL (NUMTOYMINTERVAL(1,'*DD*'))
    (partition p1 values less than (TO_DATE('01-NOV-2007','DD-MON-YYYY'))
    );  2    3    4    5
    INTERVAL (NUMTOYMINTERVAL(1,'DD'))
    ERROR at line 3:
    ORA-14752: Interval expression is not a constant of the correct typePlease suggest me to resolve this ORA-14752 error for using DAY or DD or HH24
    -Yasser

    Yes, for differenct partitions for different months.
    interval (numtoyminterval(1,'MONTH'))
    store in (TS1,TS2,TS3)
    This code will store data in partitions in tablespaces TS1, TS2, and TS3 in a round robin manner.
    for Day wise day yes you can store
    INTERVAL (NUMTODSINTERVAL(1,'day')) or
    INTERVAL (NUMTODSINTERVAL(2,'day')) or
    INTERVAL (NUMTODSINTERVAL(3,'day')) or
    INTERVAL (NUMTODSINTERVAL(4,'day')) or
    INTERVAL (NUMTODSINTERVAL(5,'day')) or
    INTERVAL (NUMTODSINTERVAL(n,'day'))

  • Table Partitioning in Oracle 9i

    Hi all,
    I have a question on partitioning in Oracle 9i.
    I have a parent table with primary key A1 and attribute A2. A2 is not a primary key but I would to create partition for the table based on this attribute. I have a child table with attribute B1 being a foreign key to A1.
    I wish to perform a data purging on the parent and child table. I'll purge the parent table based on A2, but for the child table, it will be inefficient if I delete all records in child table where parent.A1 = child.B1. Should I add a new attribute A2 to the child table, partition the child table based on this attribute or is there a better way to do it?
    Thanks in advance for all replies.
    Cheers,
    Bernard

    Bernard
    Right 100K in the parent...but how many in the child ?
    I guess it comes back to what I said earlier...you can either take the hit on the cascaded delete to get out the records on the child table or you can denormalise the column down onto the child table in order to partition by it.
    I'm building a Data Warehouse currently and we're using the denormalise approach on a couple of tables in order to allow them to be equipartitioned and enable easier partition management and DML operations as you've indicated....but our tables have 100's of millions of rows in them so we really need to do that for manageability.
    100K records in the parent - provided the ratio to the child is not such that on average each deleted parent has 100's of children is probably not too onerous, especially for a monthly batch process - the question there would be how much time do you have to do this at the end of the month ? I'd probably suggest you set up a quick test and benchmark it with say 10K records as a representative sample (can do all 100K if you have time/space) - then assess that load/time against your month end window....if its reasonably quick then no need to compromise your design.
    You should also consider whether the 100K is going to remain consistent over time or is it going to grow rapidly in which that would sway you towards adding the denormalisation for partitioning approach at the outset.
    HTH
    Jeff

  • Create table, PARTITION, compress ORACLE SUPPORT PLS !

    Can someone PLEASE explain to me the following (read carefully):
    SQL> create table abc
    2 (a number)
    3 PARTITION BY LIST(a)
    4 (PARTITION A_A values (2),
    5 PARTITION A_B values (DEFAULT) COMPRESS);
    Table created.
    SQL> alter table abc add b number;
    alter table abc add b number
    ERROR at line 1:
    ORA-22856: cannot add columns to object tables
    SQL> alter table abc modify partition A_B nocompress;
    Table altered.
    SQL> alter table abc add b number;
    alter table abc add b number
    ERROR at line 1:
    ORA-22856: cannot add columns to object tables
    SQL> drop table abc;
    Table dropped.
    SQL> create table abc
    2 (a number)
    3 PARTITION BY LIST(a)
    4 (PARTITION A_A values (2),
    5 PARTITION A_B values (DEFAULT));
    Table created.
    SQL> alter table abc modify partition A_B compress;
    Table altered.
    SQL> alter table abc add b number;
    Table altered.
    I definetelly think this is a BUG !

    14464, 00000, "Compression Type not specified"
    // *Cause: Compression Type was not specified in the Compression Clause.
    // *Action: specify Compression Type in the Compression Clause.                                                                                                                                                                                                                                                                                                                                                                                   

  • Table parttioning in Oracle 9i

    Does table partitioning in Oracle 9i has to do anything with Oracle licensing?

    Yes. When you login using sqlplus, you get this message,
    SQL*Plus: Release 9.2.0.3.0 - Production on Tue Jun 30 13:36:25 2009
    Copyright (c) 1982, 2002, Oracle Corporation.  All rights reserved.
    Connected to:
    Oracle9i Enterprise Edition Release 9.2.0.4.0 - 64bit Production
    With the Partitioning, OLAP and Oracle Data Mining options
    JServer Release 9.2.0.4.0 - Production
    SQL>Cheers
    Sarma.

  • Table Partition on daily basis in oracle 10g

    I Want to create partition based on sysdate on daily basis.
    There will be 8 partitions. Every day data's will be get loaded into this table and everyday 8th day old data ill be get truncated.
    CREATE TABLE CUST_WALLET_BALANCE_7DAYS
    ( ID  VARCHAR2(250),
       A_DATE  VARCHAR2(11),
       LAST_PROCESS_DATE DATE,
      DD_OF_PROCESS_DATE  NUMBER(2),
      CONSTRAINT CUST_WALLET_BALANCE_7DAYS_PK PRIMARY KEY (ID,A_DATE))
      PARTITION BY RANGE (DD_OF_PROCESS_DATE)
      ( PARTITION DAY1 VALUES LESS THAN (TO_NUBER(TO_CHAR(TRUNC(SYSDATE)),'DD')),
        PARTITION DAY2 VALUES LESS THAN (TO_NUBER(TO_CHAR(TRUNC(SYSDATE-1)),'DD')),
        PARTITION DAY3 VALUES LESS THAN (TO_NUBER(TO_CHAR(TRUNC(SYSDATE-2)),'DD')),
        PARTITION DAY4 VALUES LESS THAN (TO_NUBER(TO_CHAR(TRUNC(SYSDATE-3)),'DD')),
        PARTITION DAY5 VALUES LESS THAN (TO_NUBER(TO_CHAR(TRUNC(SYSDATE-4)),'DD')),
        PARTITION DAY6 VALUES LESS THAN (TO_NUBER(TO_CHAR(TRUNC(SYSDATE-5)),'DD')),
        PARTITION DAY7 VALUES LESS THAN (TO_NUBER(TO_CHAR(TRUNC(SYSDATE-6)),'DD')),
        PARTITION DAY8 VALUES LESS THAN (TO_NUBER(TO_CHAR(TRUNC(SYSDATE-7)),'DD'))
    THIS WONT WORKS OUT. SO PLEASE SUGGEST ME WITH BETTER SOLUTION.

    Original thread here: Table Partition on daily basis in oracle 10g
    Please do not start duplicate questions for the same topic.
    Locking this thread

  • Introduction of Oracle Table Partitions into PeopleSoft HRMS environment

    I would like to pose a general question and see if anyone has found any published advice / suggestions from PeopleSoft or Oracle on this. I believe that Oracle table partitioning isn't supported through the PeopleTools application designer functionality. Most likely this is done for platform independence. However, we were thinking about implementing table partitioning for performance and the ability to refresh test instances with subsets worth of data instead of the entire database.
    I know that this would be a substantial effort, but was wondering if anyone had any documentation on this type of implemention. I've read some articles from David Kurtz on the subject, and it sounds like these were all custom jobs for each individual client. Was looking for something more generic on this practice from PeopleSoft or Oracle...
    Regards,
    Jay

    Thanks for the article Nicolas. I will add that to my collection, good reference piece.
    I think you gasped the gist of the query, which was I know that putting partitioning into a PeopleSoft application is going to be highly specific to the client and application that you are running. But what I looking for was something like a baseline guide for implementing partitioning in a PeopleSoft application as a whole.
    In other words, something like notifiaction that the application designer panels would be affected since they don't have the ability to manage partitions. Therefore, any changes to tables that would utilize partitioning would need to be maintained at the database level and no longer utilize the DDL generated from PeopleTools Application Designer. Other consideration would be, like maybe a list of tables that would be candidates for partitioning based on the application, in my case HRMS. And maybe, suggestions on what column should be used for partitioning, etc...All of which are touched on in your identified article about putting partitioning in at the database level for a generic application.
    Thanks for your help, it is much appreciated...
    Jay

  • Table partitioning (intervel partitioning) on existing tables in oracle 11g

    Hi i'm newbie to table partitioning. I'm using 11g. I have table of size 32 gb (which has 22 million records) and i want to apply interval partition on that table. I created a empty table with a partition having columns same as source table and take dump of the source table and import into the new partition table. can you please suggest how to import table dump into new table? also is there any other better idea to do the same.

    Hi,
    imp user/password file=exp.dmp ignore=y
    The ignore=y causes the import to skip the table creation and continues to load all rows.
    On the other hand, you can insert data into the partitioned table with a subquery from the non-partitioned table such as follows;
    insert into patitioned_table
    select * from original_table;
    Hope it helps,

  • Oracle Tables Partitioning

    I am planning for table partitioning of existing tables...
    database is production 10gR1 i need it to upgrade to 11gR2 and also implement table partitioning. what should be the best way to do so with minimum downtime and zero data loss. Please advice. size of the tables are 20 to 40GB.. source database is in solaris and planning to migrate on linux.

    my question is for partitioning with minimum downtime with zero data loss.
    the scenario is like
    I took a export of source table and create a new partitioned table with different name, then import the data into new table, drop the source table and rename the new partitioned table with the source tables's name. Its all fine because there will be very minimum downtime but here we will loss some data. It is because the transactions which are done in the mean time will not be in the exported file. Is there any way another..? I hope you got my question.

  • Getting error while importing a table partition

    Hi,
    I am trying to import a table partition from OEM and occurred with following error:
    Job IMPORT000042 has been reopened at Friday, 13 June, 2008 14:44
    Restarting "SYSMAN"."IMPORT000042":
    Processing object type TABLE_EXPORT/TABLE/TBL_TABLE_DATA/TABLE/TABLE_DATA
    ORA-31693: Table data object "SCOTT"."CONTAINER":"PARTITION_5" failed to load/unload and is being skipped due to error:
    ORA-06502: PL/SQL: numeric or value error
    LPX-00210: expected '<' instead of 'n'
    Job "SYSMAN"."IMPORT000042" completed with 1 error(s) at 14:44
    Job state: COMPLETED
    Thanks

    What's the source and target database Oracle version?
    What's the character set of both databases?

  • Give me the sql query which calculte the table size in oracle 10g ecc 6.0

    Hi expert,
    Please  give me the sql query which calculte the table size in oracle 10g ecc 6.0.
    Regards

    Orkun Gedik wrote:
    select segment_name, sum(bytes)/(1024*1024) from dba_segments where segment_name = '<TABLE_NAME>' group by segment_name;
    Hi,
    This delivers possibly wrong data in MCOD installations.
    Depending on Oracle Version and Patchlevel dba_segments does not always have the correct data,
    at any time esp. for indexes right after being rebuild parallel (Even in DB02 because it is using USER_SEGMENTS).
    Takes a day to get the data back in line (never found out, who did the correction at night, could be RSCOLL00 ?).
    Use above statement with "OWNER = " in WHERE for MCOD or connect as schema owner and use USER_SEGMENTS.
    Use with
    segment_name LIKE '<TABLE_NAME>%'
    if you like to see the related indexes as well.
    For partitioned objects, a join from dba_tables / dba_indexes to dba_tab_partitions/dba_ind_partitions to dba_segments
    might be needed, esp. for hash partitioned tables, depending on how they have been created ( partition names SYS_xxxx).
    Volker

  • Foreign keys at the table partition level

    Anyone know how to create and / or disable a foreign key at the table partition level? I am using Oracle 11.1.0.7.0. Any help is greatly appreciated.

    Hmmm. I was under the impression that Oracle usually ignores indices on columns with mostly unique and semi-unique values and prefers to do full-table scans instead on the (questionable) theory that it takes almost as much time to find one or more semi-unique entries in an index with a billion unique values as it does to just scan through three billion fields. Though I tend to classify that design choice in the same category as Microsoft's design decision to start swapping ram out to virtual memory on a PC with a gig of ram and 400 megs of unused physical ram on the twisted theory that it's better to make the user wait while it needlessly thrashes the swapfile NOW than to risk being unable to do it later (apparently, a decision that has its roots in the 4-meg win3.1 era and somehow survived all the way to XP).

  • Problems Faced with Partitions in Oracle 9i.

    I have a doubt regarding the partitions in Oracle 9i can you please help me regarding this?
    Create table t1
    ( x number,
    y number,
    z number);
    insert into t1 values (1,1,1);
    insert into t1 values (2,2,2);
    insert into t1 values (3,3,3);
    Create table t2
    x number,
    y number,
    z number
    partition by range(x)
    partition p1 values less than(2),
    partition p2 values less than(3),
    partition p3 values less than(4),
    partition p4 values less than(maxvalue)
    alter table t2 exchange partition p1 with table t1;
    SQL> alter table t2 exchange partition p1 with table t1;
    alter table t2 exchange partition p1 with table t1
    ERROR at line 1:
    ORA-14099: all rows in table do not qualify for specified partition
    WHAT DOES THIS ERROR MESSAGE MEAN? I AM NOT ABLE TO UNDERSTAND THIS? WHAT NEED's TO BE DONE TO RESOLVE THIS?
    alter table t2 exchange partition p1 with table t1 WITHOUT VALIDATION;
    SQL> SELECT * FROM T2;
    X Y Z
    1 1 1
    2 2 2
    3 3 3
    SQL> SELECT * FROM T2 PARTITION(P1);
    X Y Z
    1 1 1
    2 2 2
    3 3 3
    SQL> SELECT * FROM T2 PARTITION(P2);
    no rows selected
    SQL> SELECT * FROM T2 PARTITION(P3);
    no rows selected
    (i) Why i am facing this error ORA-14099: while partitioning? Can you please brief me about this ?
    (ii) why there is not data's in the PARTITIONS p2 &p3 after the partitions is exchanged WITHOUT VALIDATION options?
    what is going with this method?
    (iii) Also can you please explain me with an example how to partitions a table having milliion of records with EXCHANGE PARTITION Options with MULITPLE partition segment's (say partition based on status id column with 6 differnt values i am thinking to use list partitions using status_id as partition key) ?
    Also i have tried the below approch is this a right approch? please correct me if i am wrong.
    Create table t1
    ( x number,
    y number,
    z number);
    insert into t1 values (1,1,1);
    insert into t1 values (2,2,2);
    insert into t1 values (3,3,3);
    commit;
    Create table t2
    x number,
    y number,
    z number
    partition by range(x)
    partition p1 values less than(2),
    partition p2 values less than(3),
    partition p3 values less than(4),
    partition p4 values less than(maxvalue)
    SQL> insert into t2 select * from t1;
    3 rows created.
    SQL> commit;
    Commit complete.
    SQL> SELECT * FROM T2 PARTITION(P1);
    X Y Z
    1 1 1
    SQL> SELECT * FROM T2 PARTITION(P2);
    X Y Z
    2 2 2
    SQL> SELECT * FROM T2 PARTITION(P3);
    X Y Z
    3 3 3
    SQL> SELECT * FROM T2 PARTITION(P4);
    no rows selected
    EXPLAIN PLAN
    FOR SELECT * FROM T2 WHERE X = 1
    | Id | Operation | Name | Rows | Bytes | Cost | Pstart| Pstop |
    | 0 | SELECT STATEMENT | | 1 | 9 | 2 | | |
    | 1 | TABLE ACCESS FULL | T2 | 1 | 9 | 2 | 1 | 1 |
    Now my question is what is problem instead of using EXCHANGE PARTITION why caun't we follow this above approch?
    to partition a non-partitioned table?
    Thanks,
    Rajesh.

    The value of 3 should obviously should go into the partition P3.Then why are you putting it into p1?
    Your command,
    <tt>    alter table t2 exchange partition <b>p1</b> with table t1;</tt>
    will swap partition p1 with the contents of table t1, leaving you with partition p1 containing the three values that were in t1. At first it told you there were rows in t1 that did not belong in that partition, but you used FORCE so it put them in anyway.
    btw there are notes in the FAQ about how to use ** tags to format your posts.
    ~Edited by: William Robertson on Oct 15, 2008 6:49 AM~                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                           

  • Vertical table partition?

    Hi,
    our database contains XML documents in 11 languages, one table for each language. Besides, there is meta information about each document which is the same for each language. Therefore, this meta information has been placed in a separate table.
    Now to the problem: common database queries search in the documents (Intermedia) as well
    in the meta data, what means that there is a join between the table that contains the documents (columns: key, documenttext) and the table that contains the meta information (columns: key and 18 others). Unfortunately after having located documents via Intermedia index, Oracle reads the corresponding data blocks for extracting the key. Because the documents are up to 4K, Oracle reads much information that it does not need. Is it possible to have a vertical partition of the documents table in order to be able to efficiently read only the key information instead of the whole table rows?
    Thank You for any hint,
    Markus

    Thanks For your comment and sorry for delay my Internet got down yesterday. Well, As you said throw away existing table structure.. i agree with you but there is a limitation right now. Our application only understand the current structure. Any change in database result to change execution engine. Actually, Our application provide interface to do Ad hoc reporting. we certainly use dimensional modeling but unfortunately our CTO believe existing structure is much better than the dimensional model. it gives the flexibility  to load any data like retail, click stream etc and provide reporting on data. Although, the architecture is bad but they we providing analytic to customer....
    To cut the long story short, they have assigned me a task to improve its performance. i have already improve it performance by using different feature of oracle like table partitioning sub partitioning, indexing and many more... but we want more... i have observed during the data loading process the Update part took much time. if i could do this any other way it would reduced the overall data loading time.. we extract the file from client server and perform transformation according to  business rule and out the result of transformation file in flat file.. finally our application use sql loader to load in flat table then divide it in different table. Some of our existing client have 250 column some are 350 plus...
    i think i have explained much but if you have more question on it i will ready to answer them. Please suggest with your experience how could i improve performance of existing system.

  • Table partitioning and global indexing

    hello all,
    the requirement is to do table partitioning with global indexing! & also thr r almost 60 crores of rows are there! so can you tell me the way which can be done better and also please provide me the procedure with documents?
    thanks in advance!

    Hi,
    have a look at online redefinition of a table, see Oracle Manual (10.2): http://download.oracle.com/docs/cd/B19306_01/server.102/b14231/tables.htm#ADMIN01514
    The steps are described in the manual.
    Herald ten Dam
    Superconsult.nl

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