Testing PHP Code
Hello there,
I'm in the process of creating a website for myself, I've
included a small peice of PHP for a feedback page, the email the
from results to me. However, I shalln't be buying my domain and
hosting until I complete the page (I'm hoping by the end of the
month). Now, does anybody know how I can test the PHP without
having to upload it to the internet.
All the best,
Kristopher (UK).
On Fri, 10 Aug 2007 20:17:15 +0000 (UTC), "MikeL7"
<[email protected]> wrote:
>I would also recommend buying a book that includes
setting up MySQL and Apache
>for PHP, I looked at Davids book at the bookstore and if
your using CS3 it has
>a lot of good examples, i am sure there is one for DW8
to.
I'd suggest this one:
http://foundationphp.com/dreamweaver8/index.php
It includes well written, very comprehensive instructions for
installing
Apache, PHP, and MySQL. If you go that way, be sure to check
the changes
that have been made to some of those programs since the
book's
publication:
http://foundationphp.com/dreamweaver8/updates.php
Gary
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for example:
create table testtable (
order_number number(4),
item_id number(4),
quantity number(8),
item_desc varchar2(16)
insert into testtable values (1001,1,10,'apple');
insert into testtable values (1001,2,20,'banana');
insert into testtable values (1002,2,50,'banana');
insert into testtable values (1002,1,30,'apple');
insert into testtable values (1003,3,60,'orange');
insert into testtable values (1004,3,50,'orange');
commit;
Table Test DATA
order_number item_id quantity item_desc
1001 1 10 apple
1001 2 20 banana
1002 2 50 banana
1002 1 30 apple
1003 3 60 orange
1004 3 50 orange
i want to make above sql query output in 3 pages.
order_number item_id quantity item_desc
1001 1 10 apple
1001 2 20 banana
when i click next_page it output below:
order_number item_id quantity item_desc
1002 2 50 banana
1002 1 30 apple
and when i click next_page again it will output below:
order_number item_id quantity item_desc
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using url:http://www.oracle.com/technology/pub/articles/oracle_php_cookbook/fuecks_paged.html
please look at three php code below:
php code:
<?php
$con = oci_connect('apps','apps','prod');
$sql = "select distinct h.order_number,h.order_type_id,h.price_list_id
from oe_order_headers_all h
where to_char(h.ordered_date,'YYYYMMDD') = '20060627'
and h.org_id = 82
order by order_number ASC";
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oci_execute($result);
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echo "<td>order_type</td>";
echo "<td>price_id</td></tr>";
while ($rows = oci_fetch_array($result,BOTH_NUM)) {
echo "<tr><td>". $rows[0]."</td>";
echo "<td>".$rows[1]."</td>";
echo "<td>".$rows[2]."</td></tr>";
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pager_functions.php
<?php
function total_pages($total_rows, $rows_per_page) {
if ( $total_rows < 1 ) $total_rows = 1;
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oci_execute($stmt);
oci_fetch($stmt);
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$sql = "SELECT
FROM
SELECT
r.*, ROWNUM as row_number
FROM
( $select ) r
WHERE
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oci_set_prefetch($stmt, $rows_per_page);
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outpages.php:
<?php
$conn = OCILogon('scott', 'tiger') or die ("Unable to connect to db");
require_once 'pager_functions.php';
$rows_per_page = 3;
$url = 'results.php'; // URL to this script
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!preg_match('/^[0-9]+$/',$_GET['page']) ||
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$_GET['page'] = 1;
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$_GET['page'] = $total_pages;
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$start_row = page_to_row($_GET['page'], $rows_per_page);
// Filter to a single page of rows
$stmt = & paged_result($conn, $sql, $start_row, $rows_per_page);
?>
<table width="600">
<caption>Feedster Top 500 Blogs [#<?php echo $_GET['page']; ?>]</caption>
<thead>
<tr>
<th>Rank</th>
<th>Blog</th>
<th>Inbound Links</th>
</tr>
</thead>
<tbody>
<?php while (OCIFetchinto($stmt,$row,OCI_ASSOC)) { ?>
<tr valign="top">
<td align="right"><?php echo htmlspecialchars($row['RANK']); ?></td>
<td>
">
<?php echo htmlspecialchars($row['NAME']); ?>
</a>
</td>
<td align="right"><?php echo htmlspecialchars($row['LINKS']); ?></td>
</tr>
<?php } ?>
</tbody>
<tfoot>
<tr>
<td colspan="3" align="center">
<?php echo draw_pager($url, $total_pages, $_GET['page']); ?>
</td>
</tr>
</tfoot>
</table>
?>
above two php codes in the same folder
when i run outpages.php it runs below result:
Feedster Top 500 Blogs [#1]
Rank Blog InboundLinks
may be above php code doesn't output what i mean .
who can help me ?Hi,
Your table testtable is defined as follows:
create table testtable (
order_number number(4),
item_id number(4),
quantity number(8),
item_desc varchar2(16)
In your script, you are refering to the columns 'RANK', 'NAME', 'URL' and 'LINKS'!!!
They simly doesn't exist.
You simply copied and pasted a snippet from the oracle-php-cookbook without adapting it to your needs. (And I assume without understanding, what that code will do.)
Greetings from Hamburg
Thorsten Körner -
Hi, I'm running Mac OS X 10.6.6 (Snow Leopard).
I have tried for a couple hours now to install (or activate?) PHP on my Macbook Pro.
I've done the following: Installed mySQL and got the server running, uncommented the LoadModule line in httpd.conf, restarted/started apachectl a bajillion times, made sure websharing is on, and even tried downloading the entropy php package and installing it.
I've done all of these steps. This is what happens:
WHen i go to http://localhost/phpinfo.php on safari, it renders the php info like it should.
However, when I make a file like test.php with just the code <?php phpinfo(); ?> in it, it only displays the code and no information. Likewise, if i make any file ending in .php and open it in safari, there is only raw code shown and no rendering.
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Thanks so much in advance!On 13 Feb 2007 in macromedia.dreamweaver, crash wrote:
>> That can't happen, unless there's some really broken
browser
>> sniffing going on on the server.
>
> Agreed.
>
>> I get some XHTML source code, because the content is
delivered as
>> text/plain. Is that what I'm supposed to see?
>
> That's what I'm seeing - take a look at the same file
through IE.
> Then, try to view this file through IE.
>
http://cooksfab.com/jobs.php
- in IE, it tried to make me download
> the file. I don't think PHP is correctly installed,
perhaps?
It may not be installed at all. Did you try the phpinfo()
method? Put
this in a plain text file named, say, phpinfo.php:
<?php
phpinfo();
?>
If all you get back is that same code, check with your
hosting provider
whether PHP is available at all. (Or yell that it should
be...)
Joe Makowiec
http://makowiec.net/
Email:
http://makowiec.net/email.php -
Hello-
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Firefox 3 displays the php code when pages launched from dreamweaver 8
The problem seems to relate to files opening as —
file:///C:/localweb/ .... when sent from Dreamweaver 8.0 to Firefox
The first html/php page loads correctly from dreamweaver as
processed HTML, a second page linked from either an HTML or php
page also loads correctly, but selecting any link from that or
subsequent pages displays the full php code instead of processed
html layout - so this appears to be a third level or greater
problem.
If I manually substitute -
http://localhost/ — the problem
does not arise.
This is a problem with version 3 of firefox, all previous
versions I used worked fine with both — file:///C:/localweb/
and
http://localhost/
Both prefixes also appear with pure HTML sites, but they load
and function correctly.
Not every php site I have loads with file:///C:/localweb/, so
I am wondering if this relates to something in the php code or
Dreamweaver - I have conn.php set to:
mysql_connect("localhost", "root", "") or die(mysql_error());
I use winxp and have xampp installed - everything worked fine
until I installed Firefox 3> but selecting any link from that or subsequent pages
You are being confused by a) not understanding root relative
vs document
relative links, and b) not understanding how DW previews
files.
If I have a document with a link to an image that looks like
this -
<img src="/images/foo.gif"...
That's what's called a root relative link.
If I preview that document in DW, then the browser gets the
document, sees
the leading "/" and reads that as the root of the hard drive,
since the
browser has no idea where the root of the site is. Thus, the
image is
broken in the preview.
If I have temp files enabled, then DW will secretly convert
the file being
previewed into a temporary file, and hand that to the
browser. This temp
file has had all root relative links converted to document
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(as you will see by looking at the code in the browser), and
has had all
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and js markup embedded in the page. In other words, DW has
made the
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If you do not have temp files enabled, all of these links
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Now - if you are using root relative links, AND you have temp
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These will still work on preview since the browser knows how
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Make sense?
Murray --- ICQ 71997575
Adobe Community Expert
(If you *MUST* email me, don't LAUGH when you do so!)
==================
http://www.projectseven.com/go
- DW FAQs, Tutorials & Resources
http://www.dwfaq.com - DW FAQs,
Tutorials & Resources
==================
"gbiras" <[email protected]> wrote in
message
news:[email protected]...
> The problem seems to relate to files opening as ?
file:///C:/localweb/
> ....
> when sent from Dreamweaver 8.0 to Firefox
>
> The first html/php page loads correctly from dreamweaver
as processed
> HTML, a
> second page linked from either an HTML or php page also
loads correctly,
> but
> selecting any link from that or subsequent pages
displays the full php
> code
> instead of processed html layout - so this appears to be
a third level or
> greater problem.
>
> If I manually substitute -
http://localhost/ ? the problem does
not arise.
>
> This is a problem with version 3 of firefox, all
previous versions I used
> worked fine with both ? file:///C:/localweb/ and
http://localhost/
>
> Both prefixes also appear with pure HTML sites, but they
load and function
> correctly.
>
> Not every php site I have loads with
file:///C:/localweb/, so I am
> wondering
> if this relates to something in the php code or
Dreamweaver - I have
> conn.php
> set to:
>
> mysql_connect("localhost", "root", "") or
die(mysql_error());
>
> I use winxp and have xampp installed - everything worked
fine until I
> installed Firefox 3
> -
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A difficult problem with php code and sql code
it's good place to visit(Paged Result Sets with PHP and Oracle)
http://www.oracle.com/technology/pub/articles/oracle_php_cookbook/fuecks_paged.html
maybe below part php code could not be used in above address's php code.
if((isset($l_company) and $l_company != $rows['COMPANY']) or empty($stmt) and empty($total_pages) ) {
echo "<tr bgcolor='#CCFFCC'>";
echo "<td colspan= 3 align='center'>".$l_company."</td>";
echo "<td >".$totalcomany." </td>";
$totalcomany = 0;
echo "<td > </td>";
echo "</tr>";
$l_company = $rows['COMPANY'];
because the same company in one page could calculate sum while if
the same company in two pages could not do that.
and what do you think of ?
thanks !Hi,
this is because your sql-statement selects only the rows, you need to build this one page.
Neither php nor the given result from your query knows about data wich will be part of the result of another page.
Greetings from Hamburg
Thorsten Körner -
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Now I need to figure out how to decide how hot-to-the-touch is "too hot" for the metal frame at the top of the iMac to decide whether I'm getting adequate fan performance or insufficient. While chatting I initially reported it was cool at the bottom and warm at the top. Apple hadn't asked, but their response prompted me to feel it again, and I'd say the top was hot, not warm - I updated but Apple didn't comment further except to conclude after addressing the other questions that I should take it in for further assessment - don't really want to bother with that. -
I need php code for copy paste our all histroy of browser in a text page.
I need php code for copy paste our all histroy of browser in a text page can any one send me the code please.
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Having trouble with my PHP code. Appers to get stuck on a white page.
HI all,
I have just began having trouble with my PHP code. Was working before and haven't made any changes to the code since last time it worked.
What happens is after the form is submitted it goes to a white page (no text just all white page) and in the address bar it has the path for my php page. what supposed to happen is either it goes to a success page or a error page.
I've had a problem where the info entered is correct but was directed to the error page. i managed to fix that issue but i am puzzled what is happening to my php page now.
Mind you that i didn't write this code i just took over the responsiblities of this website and i am hopping that its a quick fix.
I appreciate any help you could give me. Thank you.
CODE:
<?php
$to = '[email protected]';
$from = '[email protected]';
//Make sure we have some info posted from the form...
if (isset($HTTP_POST_VARS)){
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curl_setopt($ch, CURLOPT_FAILONERROR, 1);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt($ch, CURLOPT_TIMEOUT, 4); //times out after 4s
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
if ($success){
//readfile('http://www.lvpaiutegolf.com/thankyou.html');
curl_setopt($ch, CURLOPT_URL,"http://www.lvpaiutegolf.com/thankyou.html");
header("Location:http://www.lvpaiutegolf.com/thankyou.html");
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// readfile('http://www.lvpaiutegolf.com/error.html');
curl_setopt($ch, CURLOPT_URL,"http://www.lvpaiutegolf.com/error.html");
header("Location:http://www.lvpaiutegolf.com/error.html");
// Output
//$result=curl_exec ($ch);
//curl_close ($ch);
//echo $result'";
?>Insert the install disk and boot from it. Use disk utitlity to repair your drive and check for errors (report any errors back here) then reinstall the os. This should not erase your data.
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