The first row of a radio button is hidden

Dear all
i've a tabular block(4 rows) which contains two radio buttons, at runtime only 3 rows are displayed
thanks in advance for your help
MHassan
Edited by: user5473866 on Oct 9, 2011 5:00 AM

Please read this:
http://blogs.oracle.com/shay/entry/10_commandments_for_the_otn_fo
Without details, it will be difficult to help. There is a long list of reasons why an object may not be visible at runtime. Here are just a few:
1. You have coded the object to not be visible.
2. The object's Visible property is set to No
3. The object is covered by another
As always, the best way to troubleshoot any problem is to simplfy it. Create a new form and create the same objects on the canvas that you have on your failing form. Do not change any of the object properties or add any of your own code. Does it appear correctly when you run it? If so, they you now know that one of the reasons listed above is causing the problem.

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I didn't really have time to dig in and understand your program in depth,
but I have a few tips for you that might things a bit easier:
- You use local variables excessively which really complicates things. Try
not to use them and it will make your life easier.
- If you flowchart the design (very similar to a dataflow diagram, keep in
mind!) you want to gather data, calculate a value from that data, store the
calculation in an array, and loop while the time is in a certain range. So
theres really not much need for a sequence as long as you get rid of the
local variables (sequences also complicate things)
- You loop again if timepassed+1 is still less than some constant. Rather
than messing with locals it seems so much easier to use a shiftregister (if
absolutely necessary) or in this case base it upon the number of iterations
of the loop. In this case it looks like "time passed" is the same thing as
the number of loop iterations, but I didn't check closely. There's an i
terminal in your whileloop to read for the number of iterations.
- After having simplified your design by eliminating unnecessary sequence
and local variables, you should be able to draw out the labview diagram.
Don't try to use the "insert into array" vis since theres no need. Each
iteration of your loop calculates a number which goes into the next position
of the array right? Pass your result outside the loop, and enable indexing
on the terminal so Labview automatically generates the array for you. If
your calculation is a function of previous data, then use a shift register
to keep previous values around.
I wish you luck. Post again if you have any questions. Without a more
detailed understanding of your task at hand it's kind of hard to post actual
code suggestions for you.
-joey
"nelsons" wrote in message
news:[email protected]...
> how do I create a 1d array that takes a single calculation and insert
> the result into the first row and then the next calculation the next
> time the loop passes that point and puts the results in thsecond row
> and so on until the loop is exited.
>
> The attached file is work inprogress, with some dummy data sp that I
> can test it out without having to connect to equipment.
> The second tab is the one that I am having the problem with. the
> output array from the replace element appears to be starting at the
> index position of 1 rather than 0 but that is ok it is still show that
> the new data is placed in incrementing element locations. However the
> main array that I am trying to build that is suppose to take each new
> calculation and place it in the next index(row) does not appear to be
> working or at least I am not getting any indication on the inidcator.
>
> Basically what I am attempting to do is is gather some pulses from
> adevice for a minute, place the results for a calculation, so that it
> displays then do the same again the next minute, but put these result
> in the next row and so on until the specifiied time has expired and
> the loop exits. I need to have all results displayed and keep building
> the array(display until, the end of the test)Eventually I will have to
> include a min max section that displays the min and max values
> calculated, but that should be easy with the min max function.Actually
> I thought this should have been easy but, I gues I can not see the
> forest through the trees. Can any one help to slear this up for me.

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