To Get the earlier records in a table for a particular id neglecting the newer ones

Question

Hi All,
I need to get the older records for a particular id rejecting the newer ones..My Scenarios is as follows..
ID      Result           Date
1        Pass             2015-01-01
1        Fail                2015-03-05
2       Pass                2014-06-07
2       Fail                  2015-02-02
My Output will be 
ID        Result              Date
1          Pass                2015-01-01
2          Pass                 2014-06-07
How can i achieve this....Thanks in advance

Answer 1

Please follow the basic Netiquette of all SQL forums for the past 35+ years on the Internet. Post DDL that follows ISO-11179 rules for data element names. You have no idea; you do not even know that DATE is a reserved word in SQL! Use industry standard
encodings (ISBN, UPC, GTIN, etc) and avoid needless dialect. Give clear specifications. Give sample data. Web need to see the keys and constraints, the DRI, etc.  80-95% of the work in SQL is in the DDL. 
If you do not know that rows are not records, fields are not columns and tables are not files, then you should not be posting. If your tables have no keys, you should not be posting. If you have not tried any DML yourself, you should not be posting. 
>> I need to get the older records [sic] for a particular product_id, rejecting the newer ones..My Scenarios is as follows.. <<
Now we have to do all your typing because of your bad manners. Thanks a lot. Here is a repair job. 
CREATE TABLE Inspections 
(product_id CHAR(5) NOT NULL,
 inspection_date DATE NOT NULL
PRIMARY KEY (product_id, inspection_date),
 inspection_result CHAR(4) NOT NULL
 CHECK (inspection_result IN ('pass', 'fail'))
INSERT INTO Inspections 
VALUES
('prod1', '2015-01-01', 'pass'),
('prod1', '2015-03-05', 'fail'),
('prod2', '2014-06-07', 'pass')
('prod2', '2015-02-02', 'fail'); 
Here is one way to do this: 
WITH X(product_id, inspection_date, inspection_result, first_inspection_date)
AS 
(SELECT product_id, inspection_date, inspection_result,
        MIN(inspection_date) OVER (PARTITION BY product_id) 
   FROM Inspections)
SELECT product_id, inspection_date, inspection_result
 FROM X 
WHERE first_inspection_date = inspection_date;
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