To sort through the every increasing number of apps, why doesn't Apple simply create more granularity in category descriptions for apps? i.e. instead of "financial", there could be 'budget', 'investment', 'bookkeeping', 'analysis', 'trade tools', etc.

Question says it all.

One thing I learned in high tech, was innovation often was so counter intuitive, one didn't think of it until presented with some sort of stimulus or trigger. Such as, an app for sale, description of function/process, etc. Thus, how do I know I want to search for something, if the idea hasn't completely jelled in my mind? Ergo, it would be nice to browse a greater variety of categories; that would enable a greater number of entrepraneurs to display their innovative wares.

Similar Messages

  • Apple Script to Sort through the Address Book

    Dear All,
    I am quite new to Apple and just a learner on Apple-scripts. Its been quite a task to learn.. I would require some help on a few things..
    The script will eventually use numbers to send email and get the user inputs and any yet to reach there..
    After going through lots of scripts to sort through the address book and make a clean address book, i found they are quite slow in processing takes about 20~30 Minutes to get through 2000 Contacts..
    Hence after reading posting of Mr. Koenig & Mr. Hiroto and specifically on deep copy. I have written the following code which does the following on 2000 records within 6~8Mins.
    The Script work its way through all the contact is the address List.. and creates Groups
    1. Duplicate Email Id's — List of Contacts with same email ID's including Contacts where the email Id is entered twice.. (Strange.. Address Book Issue, copy of the email Id under work & home)
    2. Duplicate Phone — List of Contacts with same Phone Numbers including Contacts where the Phone Nos is entered twice.
    3. Duplicate Name — List of Contacts with Same Names
    4. Duplicate No Name — List of Contacts without the First Name and Last Name
    it also sort the Contacts under the following Group which you can edit later with all the information's..
    1. Only Email Ids — List of Contacts with Email ID and No Phone Numbers
    2. Only Phone — List of Contacts with Phone Numbers and No Email Id's
    3. No Email or Phone — List of Contacts with No Email Id's and No Phone numbers (some half completed contacts )
    My Question to the forum is why is the following code still taking too much time..
    set onlyDupEList to every person of group theGroupEmail
    repeat with j from 1 to count of Dup_email
    set tempdata to item j of Dup_email
    if onlyDupEList does not contain {tempdata} then add tempdata to group theGroupEmail
    end repeat
    save application "Address Book"
    and the scripts slows down when the items in the list is quite large (over 800 or so )..
    Any help is appreciated and thanks in advance..
    -- the code ---
    global MsgTitle
    on run
    set MsgTitle to "Search for Duplicates in Address Book Contacts"
    display dialog ¬
    "This Script takes a while to finish" & return & "maybe 10 min or More..." & return & "Depending on the Address Book Contacts." & return & return & "Hence Allow it to run for the while" with title MsgTitle ¬
    with icon 1 ¬
    buttons {"Continue"} ¬
    giving up after 5
    set question to display dialog "Select the Duplicate Search Parameter " with icon 1 with title MsgTitle ¬
    buttons {"Contact Name", "Contacts on Phone & Email Id's", "Quit"} default button 3
    set rtnValue to button returned of question
    if rtnValue is "Quit" then
    -- tell application "Address Book" to quit
    tell me to quit
    end if
    if rtnValue is "Contact Name" then
    -- tell application "Address Book" to quit
    GetDup_byName("Duplicate Name")
    end if
    if rtnValue is "Contacts on Phone & Email Id's" then --Contacts on Phone & Email Id's
    -- tell application "Address Book" to quit
    Get_dup()
    end if
    end run
    --- Search on Name Field ---
    on GetDup_byName(theGroupName)
    set question to display dialog "Do you want to search for duplicates based on Names? " with icon 0 with title MsgTitle ¬
    buttons {"Continue", "Quit"} default button 1
    set rtnValue to button returned of question
    if rtnValue is "Quit" then
    -- tell application "Address Book" to quit
    tell me to quit
    end if
    tell application "Address Book"
    activate
    set biglist to {}
    set NoNameList to {}
    set theGroupNoName to "Duplicates No Names"
    set theGroup to theGroupName
    -- if not (exists (group "Dupilicate Entries")) then
    if not (exists (group theGroup)) then
    make new group with properties {name:theGroup}
    save
    end if
    if not (exists (group theGroupNoName)) then
    make new group with properties {name:theGroupNoName}
    save
    end if
    set the_names to name of people
    repeat with i from 1 to number of items in the_names
    set theName to item i of the_names
    -- return theName
    if theName is not in biglist then
    copy theName to end of biglist
    else
    set counter to (people whose name is theName)
    if (count of counter) > 1 then
    repeat with i from 1 to number of items in counter
    set this_item to item i of counter
    -- display dialog this_item
    add this_item to group theGroup
    end repeat
    -- return counter as string
    end if
    end if
    -- captures the Contacts without Name ---
    if theName contains "@" then
    -- display dialog theName
    set counterList to (people whose name is theName)
    repeat with i from 1 to number of items in counterList
    set this_item to item i of counterList
    -- display dialog this_item
    add this_item to group theGroupNoName
    end repeat
    end if
    -- save application "Address Book"
    end repeat
    save application "Address Book"
    set peopleCount to (count every person)
    -- set peopleCount to 50 -- only for testing --
    repeat with i from 1 to peopleCount
    set first_name to first name of person i as string
    set Last_Name to last name of person i as string
    if first_name is equal to "missing value" and Last_Name is equal to "missing value" then
    -- display dialog first_name & " : " & Last_Name
    set end of NoNameList to (id of person i)
    end if
    end repeat
    repeat with j from 1 to the count of NoNameList
    set tempdata to item j of NoNameList
    -- set testdata to person id tempdata
    -- if (name of groups of testdata does not contain theGroupNoEmail) then
    add tempdata to group theGroupNoName
    -- end if
    end repeat
    save application "Address Book"*)
    display dialog ¬
    "This Script Finished Processing Address Book Contacts the Duplicates are in the group" with title MsgTitle ¬
    with icon 1 ¬
    buttons {"Continue"} ¬
    giving up after 5
    end tell
    end GetDup_byName
    on Get_dup()
    set question to display dialog "Do you want to search for duplicates based on Names? " with icon 0 with title MsgTitle ¬
    buttons {"Continue", "Quit"} default button 1
    set rtnValue to button returned of question
    if rtnValue is "Quit" then
    -- tell application "Address Book" to quit
    tell me to quit
    end if
    tell application "Address Book"
    activate
    set theGroupEmail to "Duplicate Email Id's"
    set theGroupPhone to "Duplicate Phone"
    set theGroupNoEmail to "Only Phone Numbers"
    set thegroupNoPhone to "Only Email Id's"
    set theGroupNoData to "No Email or Phone"
    -- set theGroup to theGroupName
    if not (exists (group theGroupEmail)) then
    make new group with properties {name:theGroupEmail}
    save "Address Book"
    end if
    if not (exists (group theGroupPhone)) then
    make new group with properties {name:theGroupPhone}
    save "Address Book"
    end if
    if not (exists (group theGroupNoEmail)) then
    make new group with properties {name:theGroupNoEmail}
    save "Address Book"
    end if
    if not (exists (group thegroupNoPhone)) then
    make new group with properties {name:thegroupNoPhone}
    save "Address Book"
    end if
    if not (exists (group theGroupNoData)) then
    make new group with properties {name:theGroupNoData}
    save "Address Book"
    end if
    set ListofPeople to people --the_ID
    set ListofEmailID to value of emails of people --the_emails
    -- return ListofEmailID
    set ListofPhones to value of phone of people -- the_phones
    -- return ListofPhones
    set biglist to {}
    set ListEmail_Uniq to {}
    set ListEmail_Dup to {}
    set No_PhoneList to {}
    set No_EmailList to {}
    set No_dataList to {}
    set FlagEmail to false
    set FlagPhone to false
    -- repeat with i from 1 to number of items in the_emails
    repeat with i from 1 to count of ListofEmailID
    set thePersonID to item i of ListofPeople
    set theEmails to item i of ListofEmailID
    if theEmails is equal to {} then
    set end of No_EmailList to thePersonID
    else
    -- set FlagEmail to true
    repeat with j from 1 to count of theEmails
    set tmpdata to item j of theEmails
    -- return tmpdata
    if tmpdata is not in biglist then
    set end of biglist to tmpdata
    set end of ListEmail_Uniq to {tmpdata} & {thePersonID}
    else
    set end of ListEmail_Dup to {tmpdata} & {thePersonID}
    end if
    end repeat
    end if
    end repeat
    -- return ListEmail_Uniq
    -- return ListEmail_Dup
    -- save application "Address Book"
    set biglist to {}
    set ListPhone_Uniq to {}
    set ListPhone_Dup to {}
    -- repeat with i from 1 to number of items in the_emails
    repeat with i from 1 to count of ListofPhones
    set thePersonID to item i of ListofPeople
    set thePhones to item i of ListofPhones
    if thePhones is equal to {} then
    set end of No_PhoneList to thePersonID
    else
    -- set FlagPhone to true
    repeat with j from 1 to count of thePhones
    set tmpdata to item j of thePhones
    -- return tmpdata
    if tmpdata is not in biglist then
    set end of biglist to tmpdata
    set end of ListPhone_Uniq to {tmpdata} & {thePersonID}
    else
    set end of ListPhone_Dup to {tmpdata} & {thePersonID}
    end if
    end repeat
    end if
    end repeat
    -- return ListPhone_Uniq
    -- return ListPhone_Dup
    set the Dup_email to {}
    -- Find the Duplicates from the sorted list --
    repeat with i from 1 to the count of ListEmail_Dup
    set tempdata to item i of ListEmail_Dup
    set dataEmailDup to item 1 of tempdata
    set dataPersonDup to item 2 of tempdata
    repeat with j from 1 to the count of ListEmail_Uniq
    set tempdata to item j of ListEmail_Uniq
    set dataEmailUniq to item 1 of tempdata
    set dataPersonUniq to item 2 of tempdata
    -- display dialog mainEmail1 & "=" & mainEmail2 & " " & mainID1 & "=" & mainID2
    if dataEmailDup is equal to dataEmailUniq then
    set end of Dup_email to dataPersonDup -- & "," & dataPersonUniq
    set end of Dup_email to dataPersonUniq
    end if
    (* -- the code takes lot more time if add to group was used --
    if dataEmailDup is equal to dataEmailUniq then
    set testdata to person id dataPersonDup
    add testdata to group theGroup
    set testdata to person id dataPersonUniq
    add testdata to group theGroup
    end if
    end repeat
    end repeat
    -- return Dup_email
    set the Dup_Phone to {}
    -- Find the Duplicates from the sorted list --
    repeat with i from 1 to the count of ListPhone_Dup
    set tempdata to item i of ListPhone_Dup
    set dataPhoneDup to item 1 of tempdata
    set dataPersonDup to item 2 of tempdata
    repeat with j from 1 to the count of ListPhone_Uniq
    set tempdata to item j of ListPhone_Uniq
    set dataPhoneUniq to item 1 of tempdata
    set dataPersonUniq to item 2 of tempdata
    -- display dialog mainEmail1 & "=" & mainEmail2 & " " & mainID1 & "=" & mainID2
    if dataPhoneDup is equal to dataPhoneUniq then
    set end of Dup_Phone to dataPersonDup -- & "," & dataPersonUniq
    set end of Dup_Phone to dataPersonUniq
    end if
    (*if dataPhoneDup is equal to dataPhoneUniq then
    set testdata to person id dataPersonDup
    add testdata to group theGroup
    set testdata to person id dataPersonUniq
    add testdata to group theGroup
    -- save
    end if*)
    end repeat
    end repeat
    -- return Dup_Phone
    set onlyDupEList to every person of group theGroupEmail
    repeat with j from 1 to count of Dup_email
    set tempdata to item j of Dup_email
    if onlyDupEList does not contain {tempdata} then add tempdata to group theGroupEmail
    end repeat
    save application "Address Book"
    set onlyDupPList to every person of group theGroupPhone
    repeat with j from 1 to count of Dup_Phone
    set tempdata to item j of Dup_Phone
    if onlyDupPList does not contain {tempdata} then add tempdata to group theGroupPhone
    end repeat
    save application "Address Book"
    set onlyPhoneList to every person of group theGroupNoEmail
    repeat with j from 1 to the count of No_EmailList
    set tempdata1 to item j of No_EmailList
    if No_PhoneList does not contain {tempdata1} then
    if onlyPhoneList does not contain {tempdata1} then add tempdata1 to group theGroupNoEmail
    end if
    (*set flagE to false
    repeat with i from 1 to the count of No_PhoneList
    set tempdata2 to item i of No_PhoneList
    if tempdata1 is equal to tempdata2 then
    set flagE to true
    exit repeat
    end if
    end repeat
    if flagE is false then add tempdata1 to group theGroupNoEmail*)
    end repeat
    save application "Address Book"
    set onlyEmailList to every person of group thegroupNoPhone
    repeat with j from 1 to the count of No_PhoneList
    set tempdata1 to item j of No_PhoneList
    if No_EmailList does not contain {tempdata1} then
    if onlyEmailList does not contain {tempdata1} then add tempdata1 to group thegroupNoPhone
    end if
    end repeat
    save application "Address Book"
    set onlyList to every person of group theGroupNoData
    repeat with i from 1 to count of ListofPeople
    if (item i of ListofEmailID is equal to {}) and (item i of ListofPhones is equal to {}) then
    set tempdata to item i of ListofPeople
    if onlyList does not contain {tempdata} then add tempdata to group theGroupNoData
    end if
    end repeat
    save application "Address Book"
    display dialog ¬
    "This Script Finished Processing Address Book Contacts the Duplicates are in the group" with title MsgTitle ¬
    with icon 1 ¬
    buttons {"Continue"} ¬
    giving up after 5
    end tell
    end Get_dup
    on quit
    --set MsgTitle to "Change Email ID's Domain Name"
    save application "Address Book"
    display dialog "Contact Srikanth Kamath at [email protected] for any Help" with title MsgTitle with icon 1 buttons "OK"
    continue quit
    end quit

    Hello Srikanth Kamath,
    I'm not sure you're still following this thread, but anyway here's sample code I said I'd post later.
    --SCRIPT2
    main()
    on main()
    script o
    -- input data
    property xx : {1, 2, 3, 4, 5} -- list of parents
    property yy : {{"g", "h"}, {"a", "b"}, {"b", "e", "f"}, {"e"}, {"c", "d"}} -- list of children per parent
    -- work list
    property pp : {} -- list of children tagged by parent; i.e, lits of {child, parent}
    property qq : {}
    property rr : {}
    -- (1) build list of children tagged by parent
    repeat with i from 1 to count my xx
    set x to my xx's item i
    set y to my yy's item i
    repeat with p in y
    set end of my pp to {p's contents, x}
    end repeat
    end repeat
    --return pp -- {{"g", 1}, {"h", 1}, {"a", 2}, {"b", 2}, {"b", 3}, {"e", 3}, {"f", 3}, {"e", 4}, {"c", 5}, {"d", 5}}
    -- (2) sort tagged list by child as key
    msort(my by_key1, my pp)
    --return pp -- {{"a", 2}, {"b", 2}, {"b", 3}, {"c", 5}, {"d", 5}, {"e", 3}, {"e", 4}, {"f", 3}, {"g", 1}, {"h", 1}}
    -- (3) retrieve parents with duplicate child
    (* retrieve list of {child, parent} for duplicate child *)
    set my qq to uniq(my eq_key1, my pp, {_dup:true})
    --return qq -- {{"b", 2}, {"b", 3}, {"e", 3}, {"e", 4}}
    (* retrieve list of parent *)
    repeat with q in my qq
    set r to q's item 2
    if r is not in my rr then set end of my rr to r
    end repeat
    return rr -- {2, 3, 4}
    end script
    tell o to run
    end main
    on by_key1(x, y)
    msort's comparator for list of lists
    key = item 1, ascending
    returns true iff x and y are out of order
    return x's item 1 > y's item 1
    end by_key1
    on eq_key1(x, y)
    uniq's comparator for list of lists
    key = item 1
    returns true iff x and y are considered equal
    return x's item 1 = y's item 1
    end eq_key1
    on msort(cmp_, aa) -- v1.2f2
    Basic recursive merge sort handler having list sorted in place.
    handler cmp_ : comparator
    * cmp_(x, y) must return true iff list element x and y are out of order.
    list aa : list to be sorted in place
    script o
    property parent : {} -- limit closure to minimum
    property xx : aa -- to be sorted in place
    property xxl : count my xx
    property yy : {}
    property cmp : cmp_
    on merge(p, q, r)
    property xx: source list
    integer p, q, r : absolute indices to specify range to be merged such that
    xx's items p thru r is the target range,
    xx's items p thru (q-1) is the first sublist,
    xx's items q thru r is the second sublist.
    (p < q <= r)
    local i, j, k, xp, xr, yi, yj, ix, jx
    if r - p = 1 then
    set xp to my xx's item p
    set xr to my xx's item r
    if my cmp(xp, xr) then
    set my xx's item p to xr
    set my xx's item r to xp
    end if
    return -- exit
    else
    if p < q - 1 then merge(p, (p + q) div 2, q - 1)
    merge(q, (q + r + 1) div 2, r)
    end if
    At this point, sublits xx[p, q-1] and xx[q, r] have been already sorted (p < q <= r)
    if my cmp(my xx's item (q - 1), my xx's item q) then
    else -- xx[p, q-1] & xx[q, r] are already sorted
    return
    end if
    set yy to my xx's items p thru r -- working copy for comparison
    set ix to q - p
    set jx to r - p + 1
    set i to 1
    set j to q - p + 1
    set k to p
    set yi to my yy's item i
    set yj to my yy's item j
    repeat
    if my cmp(yi, yj) then
    set my xx's item k to yj
    set j to j + 1
    set k to k + 1
    if j > jx then
    set my xx's item k to yi
    set i to i + 1
    set k to k + 1
    repeat until k > r
    set my xx's item k to my yy's item i
    set i to i + 1
    set k to k + 1
    end repeat
    return
    end if
    set yj to my yy's item j
    else
    set my xx's item k to yi
    set i to i + 1
    set k to k + 1
    if i > ix then
    set my xx's item k to yj
    set j to j + 1
    set k to k + 1
    repeat until k > r
    set my xx's item k to my yy's item j
    set j to j + 1
    set k to k + 1
    end repeat
    return
    end if
    set yi to my yy's item i
    end if
    end repeat
    end merge
    on cmp(x, y)
    (* primary comparator *)
    return x > y
    end cmp
    local d, i, j
    if xxl ≤ 1 then return
    if cmp_ = {} then set my cmp to cmp -- comparator fallback
    my merge(1, (xxl + 1) div 2, xxl)
    end script
    tell o to run
    end msort
    on uniq(eq_, aa, {dup:dup}) -- v0.21
    handler eq_ : comparator eq_(x, y) that returns true iff x and y are considered equal
    list aa : pre-sorted list
    (precisely, a list organized such that any duplicate items are adjacent to each other)
    boolean _dup : option whether return unique items or duplicate items
    return duplicate if true, unique otherwise.
    script o
    property parent : {} -- limit closure to minimum
    property xx : aa
    property yy : {}
    property eq : eq_
    on eq(x, y)
    (* primitive comparator *)
    x = y
    end eq
    if eq_ = {} then set my eq to my eq -- comparator fallback
    local t, x, _on
    if (count my xx) < 2 then return my xx's contents
    if _dup then
    set _on to false
    set t to my xx's item 1
    repeat with i from 2 to count my xx
    set x to my xx's item i
    if eq(x, t) then
    set end of my yy to t
    set _on to true
    else if _on then
    set end of my yy to t
    set _on to false
    end if
    set t to x
    end repeat
    if _on then set end of my yy to x
    return my yy's contents -- return duplicate elements
    else
    set t to my xx's item 1
    set end of my yy to t
    repeat with i from 2 to count my xx
    set x to my xx's item i
    if eq(x, t) then
    else
    set end of my yy to x
    set t to x
    end if
    end repeat
    return my yy's contents -- return uinque elements
    end if
    end script
    tell o to run
    end uniq
    --END OF SCRIPT2
    In order to apply it to your current Address Book problem, replace the main() handler with something like the following one.
    --SCRIPT2a (part)
    on main()
    script o
    -- input data
    property xx : {} -- list of parent; given later
    property yy : {} -- list of children per parent; given later
    -- work list
    property pp : {} -- list of children tagged by parent; i.e, lits of {child, parent}
    property qq : {}
    property rr : {}
    -- (0) get input data from AB
    tell application "Address Book"
    tell people
    set xx to its id
    set yy to its every email's value
    end tell
    end tell
    -- (1) build list of children tagged by parent *)
    (* omitted (same as the previous) *)
    -- (2) sort tagged list by child as key
    (* omitted (same as the previous) *)
    -- (3) retrieve parents with duplicate child
    (* omitted (same as the previous) *)
    -- (4) group the retrieved people in AB
    tell application "Address Book"
    repeat with r in my rr
    add person id r to group "duplicate email"
    end repeat
    end tell
    end script
    tell o to run
    end main
    --END OF SCRIPT2a
    Good luck,
    Hiroto
    Message was edited by: Hiroto

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        I definitely understand your concern and I apologize for all the frustration. Verizon Wireless has a strong customer commitment to delivering the best from our service and staff. I am disappointed to hear the service you received did not reflect this commitment.
    I definitely want to help get to the bottom of this and further assist you. Please reply to my direct message so I can access your account and further assist. I am sure we can get this resolved.
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    Follow us on Twitter @VZWSupport

  • Why does apple allow apps in the App Store hijack your Internet when certain websites? Why doesn't apple remove their products from the App Store?.

    Why does apple allow apps in the App Store hijack your Internet when certain websites? Why doesn't apple remove their products from the App Store?.

    Apple saw it as their responsibility since the redirection took me to the App Store. They assisted me in stopping the redirection which is occurring on many peoples iPhones. It's a have java script problem that adking is using to get you to buy their games. The websites work normal and then all of the sudden the website is taken over by adking.com.  You can no longer use the website as it immediately takes you to the App Store without ever showing a popup to cancel the redirection. They were very helpful fixing the problem should others experiencing this specifically with adking.com.
    No need to get defensive. I'm not the only one experiencing the problem Apple said.

  • Why doesn't Apple list the changes in iPhone updates?

    Why doesn't Apple list the changes included with each iteration of iPhone updates? They always post a detailed list of changes for all other major software updates. I wonder why the same is not true for the iPhone, leaving us all guessing and wondering...

    Just to add, Ansuz82 pointed out, Apple's track record is that they don't really ever give full published details about what their updates include in any of their products really. If the iPhone is your first product by Apple you may not be aware of this. To them, saying Bug Fixes is enough. If they publicly add more info, it means they really wanted to get that point out. eg: the 1.1.1 mainly just talked about iTunes WiFi store. 1.1.2 mainly talked about the Tiff exploit fixed and keyboard updates for languages. However, with all, a lot more does get changed than just the key points mentioned. And by a lot, I don't mean a lot that you will see. Have to remember, they are still ironing out the OS for the iPhone. A lot of changes to them is just cleaning up and fixing known bugs that many of us as users may not even know exisit (though we see the outcome of them when apps colide and crash each other).
    Message was edited by: DaVBMan

  • How do I get rid of the red update number on app store?  I have an update for an appmwhich requires ios6 which I cannot get on my iPad and there for cant do the update it is really annoying

    I have an update for an app which I cannot update as it requires ios6 which I cannot get on my iPad - how do I get rid of the little red number?  It is really annoying

    Does this apply?
    If you're asked for the password to your previous Apple ID when signing out of iCloud - Apple Support

  • My sound only works through the ear phones with some apps....

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  • I would like to upgrade to the next step, but because I have many problems with the version 10.4.11, I'm worried that upgrading would create more problems.

    Due to a misunderstanding with [email protected] in September of 2010, many of my applications and important files were put into the trash during a cleaning.  The trash hadn't been deleted, so a CleanApp rep told me to drag my important files to a folder on my desktop.  They were unable to help me with anymore advice with the exception that if I followed the pathway of the application, I could manually restore it to its proper location. 
    This was asking a lot of me because I didn't have the experience or knowledge of undertaking such a massive restoration.  However, I did the best I could.  What had been put in the trash was not just a few files -- there were hundreds of files or apps that I discovered in the trash.  As I said, this was a misunderstanding.  I was left feeling devastated at what had happened. 
    Since then, my iMac Intel Core Duo has been running on its last legs.  I'm surprised I can even get to my email.  As far as using the software that I bought with my iMac, I can't.  I just do the basics.
    What I have been wanting to do is to upgrade to the next level.  However, I worry that if I upgrade a crippled OS X 10.4.11 Tiger, I would be creating more problems than what I already have.  Do you agree that an upgrade would make matters worse? 

    It won't necessarily make it worse, but may not make it better.  I am not familiar with the utility you usedm though anything that cleans or maintains your Mac should be avoided unless you know what you are doing and what it does.  Probably re-installing software from the official sources (download or CDs) is the best way to ensure missing parts are all replaced.
    If this is a core duo and not a core 2 duo then the highest you can go is Snow Leopard 10.6 Get more information about your computer. Go to the Apple in the upper left corner of any window, then "About This Mac", then "More Info..."  Copy and paste the information here, but omit the serial number and Hardware UUID (if present).

  • Sometimes when I push the button on the front of the ipad to leave an app it does not respond. What could be wrong?

    So when I push the front button the screen does not respond to it, as though it was never pushed. I can still maneuver through the app, but I can not exit. I push the button many times with no response and it will randomly recognize the push but it takes time/multiple tries. Is the button broken?

    Try This...
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  • Can you use the same Apple ID on more than one MacBook Pro for updates and applications?

    We just got a few new MacBook Pro's and when I went to install updates it said I need to make an Apple ID.  Can you use the same Apple ID and email address for that Apple ID on multiple machines, or do I need them both to be unique per machine?  I'm not sure how that works when you have multiple machines.

    An Apple ID is a user name you use for everything you do with Apple. Creating an account for an Apple service, such as the iTunes Store or the App Store, creates an Apple ID. Apple ID allows you to access other Apple services.   So you can use the same Apple ID for up to 10 Macs associated with it.
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  • Just upgraded to Mavericks and my HP6100 printer no longer works, when I try to reload the software it says PowerPC apps no longer supported.  Is there a way to use my HP6100 Printer with Mavericks?

    Just upgraded my 2009 iMac (3.06 Ghz, core 2 duo $GB 1067 Mhz DDR3) to Mavericks OSX 10.9.5 and my HP6100 printer no longer works, when I try to reload the software it says PowerPC apps no longer supported.  Printer says the software was improperly installed. Is there a way to use my HP6100 Printer with Mavericks or do I need to go back to Mountain Lion or Snow Leopard? 

    It's not clear whether your printer is included in the Apple list - there is an Officejet 6100 and a couple of other types. Go to the page linked to above and use the browser search for 6100.
    I'm afraid HP are notorious for not supporting older printers - I had the same problem. Probably they hope you will buy another printer (I did, but it was a Canon). I did look on HP's site and couldn't see a driver - you could give it a try (make sure you have the exactly correct printer name):
    http://www8.hp.com/uk/en/support-search.html?tab=1#/qryterm=HP6100&search_search type=s-002
    Alternatively ou could try Gutenprint (open source software):
    http://gimp-print.sourceforge.net/MacOSX.php
    I found it would indeed drive the printer, but the colour dithering wasn't very satisfactory and the duplex printing bolt-on wouldn't work. However as Gutenprint is free it's worth trying to see if it's any good for you.

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