To split a table as two tables with equal no of records

Question

Hi Everyone,
I have a table with size of 100000 records which is reterieved from different tables thats why idx is not in a sequential order. for example
idx
1
5
100 and so on
i want to create two different tables with same number of records but i dont want any duplicate records. Please anyone can help how can i get it.
Best Regards,

Answer 1

Please check the following script - hope that will help you --
SQL>
SQL> set serveroutput on
SQL>
SQL>
SQL> create table test_vaneeza
  2  as
  3   (
  4     select 1 idx,'55 Mary Road' address from dual
  5     union all
  6     select 2, '10 Glenhuntly Road' from dual
  7     union all
  8     select 3, '5 Terrace' from dual
  9     union all
10     select 100, '1212 Dandenong Road' from dual
11     union all
12     select 1000, '12 Liverpool Street' from dual 
13   );
Table created.
SQL>
SQL>
SQL> set lin 1000
SQL>
SQL> select * from  test_vaneeza;
       IDX ADDRESS
         1 55 Mary Road
         2 10 Glenhuntly Road
         3 5 Terrace
       100 1212 Dandenong Road
      1000 12 Liverpool Street
SQL>
SQL>
SQL> drop table gghh;
Table dropped.
SQL>
SQL>
SQL> create table gghh(a  number(10),
  2                     b  varchar2(100));
Table created.
SQL>
SQL>
SQL> drop table ggyy;
Table dropped.
SQL>
SQL>
SQL> create table ggyy(c  number(10),
  2                     d  varchar2(100));
Table created.
SQL>
SQL>
SQL> select count(*) from ggyy;
  COUNT(*)
         0
SQL>
SQL>
SQL> select count(*) from gghh;
  COUNT(*)
         0
SQL>
SQL>  insert all
  2       when rownum<=(select count(distinct idx) from test_vaneeza)/2
  3       then 
  4         into gghh
  5       else
  6         into ggyy
  7      select distinct idx,address
  8      from test_vaneeza;
5 rows created.
SQL>
SQL>
SQL> commit;
Commit complete.
SQL>
SQL>
SQL> select count(*) from ggyy;
  COUNT(*)
         3
SQL>
SQL>
SQL> select count(*) from gghh;
  COUNT(*)
         2
SQL>
SQL>
SQL> select * from ggyy;
         C D
         3 5 Terrace
       100 1212 Dandenong Road
      1000 12 Liverpool Street
SQL>
SQL>
SQL> select * from gghh;
         A B
         1 55 Mary Road
         2 10 Glenhuntly Road
SQL> Regards.
Satyaki De.