Top N rows based on aggregate function

Hi,
I need to get a report in the following format
F_A F_B F_C Count_comb
100 200 300 5
100 201 300 5
100 202 301 4
100 203 111 3
Here, the Count_comb column gives the count of records which have the same (F_A + F_B + F_C) combination. The requirement is to show the Top-N combinations where the tied rows would have the same rank --that is if (100,200,300) combo and (100,201,300) combo have the same count, they should both be ranked the same.
I think this involves performing the rank() function on the count(), for which i was not able to write an SQL. Any help in this direction is appreciated.
Thanks,
<cfdoubt>
PS : Pardon the alignment--i hope you can make out what i mean

Hi Joseph
Hope this query satisfies your Need
Select f_a,f_b,f_c,cnt,     dense_rank() over(order by cnt desc) rk
From (
select f_a,
     f_b,
     f_c,
     count(*) cnt
from test
group by f_a,f_b,f_c
F_A F_B F_C CNT RK
100 200 300 5 1
100 201 300 5 1
100 202 301 4 2
100 203 111 3 3
Regards
Shajesh Nair
[email protected]

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