Tricky count function query
Hi All.
I was trying to write a query for below result set but can not figure out if i can achieve below result set through T-SQL.
Emplid FunctionId Count
1 2
1 3 1
1 4 2
1 4
1 5 3
1 6 4
1 3
2 3
2 3
2 1 1
2 2 2
Description
When an Employee is changing from job/function, am struggling to get incremental number / count for that employ based on no. of funtionid changed.
I need a count only when an employee is going to do something else (another function).
The example above is showing how the count output should be.
am not sure it i need to use any analytical function, any help would be appreciated.
and many thanks in advance for reading my question
Something like
SQL> ed
Wrote file afiedt.buf
1 with x as (
2 select 1 empid, 2 functionid, sysdate dt from dual union all
3 select 1, 3, sysdate+1 from dual union all
4 select 1, 4, sysdate+2 from dual union all
5 select 1, 4, sysdate+3 from dual union all
6 select 2, 3, sysdate+4 from dual union all
7 select 2, 3, sysdate+5 from dual union all
8 select 2, 1, sysdate+6 from dual
9 )
10 select empid,
11 functionid,
12 sum(case when functionid = prior_functionid
13 then 0
14 else 1
15 end) over (partition by empid
16 order by dt)-1 cnt
17 from (
18 select empid,
19 functionid,
20 lag(functionid) over (partition by empid
21 order by dt) prior_functionid,
22 dt
23 from x
24* )
SQL> /
EMPID FUNCTIONID CNT
1 2 0
1 3 1
1 4 2
1 4 2
2 3 0
2 3 0
2 1 1
7 rows selected.appears to work
Justin
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Post Author: krypton
CA Forum: Data Connectivity and SQL
Hi Guys
Can i ask a quick question. I am trying to retrieve data remotely from a SQL Server via crystal reports.
Within the Database Expert I have entered a SQL query to retrive the number of (call center) support calls raised by our customers:-
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Both approaches will never be 100% accurate.
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Ö Enter the selection criteria
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j) Save the Query created
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e) Select the appropriate Query
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I have CR Professional, version 11.0.0.1282 (Crystal Reports XI).
I work at a county health dept and we have a annual medicaid cost report, I am linking Crystal to our EMR billing module. i have my report sorted by insurance, ie medicaid, bcbs, abw, hpm etc. and within each ins group i have the clients ID, DOS (date of service), procedure code, charge amt, ins pmt & patient pmt. i have totaled the charges & pmts for each group-works fine. i even have been able to create the formula to adj out the duplicate entries in the billing module (a service was entered wrong then adjusted out then re-entered correctly-without my formula crystal was pulling both these records and adding them to total charges.)
Where my problem lies and what my question is: I need to count encounters, an encounter is the visit, but each visit could have 2 or more procedure codes. So this results in multiple lines on my report for one visit, which i want for the charges to add correctly, but it makes my visit count to high. So I read about the distinct count function, of which there are three listed & i'm having a hard time understanding the differences. What i tried is: a distinct count of the acct ID-so the same acct ID's are only counted the one time. But some clients see us more than once per year, meaning the acct ID is the same but the DOS is different. For this client that would be 2 visits. But crystal is counting this as 1.
Saying what i want to do is this: Count as 1 when the acct ID and DOS are the same. I've tried using the different distinct counts but when i check my formula it always has errors. So I'm sure my lack of knowledge is what's holding me up-i fully believe crystal can do this.
Any help would be greatly appreciated.I create a dummy table, set up acc_id and DOS and Charge.
Created a running total
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Type of summary Count
Evaluated using a formula
<> previous ()
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My groups were sorted by acc_id and date
where there were multiple visits on the same DOS my count was 0
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Hey, trying to map following structures:
message
-m1
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to
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thanks for your answers.
But I still couldn't understand how to do this. I open the message mapping for field f1, but the count function could only be set on an target-element, so where to set the counters for m1,m2,m3? Do I have to insert extra fields under m1..m3?
If I do the counter would increment with every node, so if I have two times m1, in second tree of m1 a two will be insert. If I use the add function, only for these two tree the result would be three!
@Gangisetty Vijaya Bhaskarudu
Is this just one UDF? From where he knows, which nodes he have to count, if I have more than m1..m3, but only want to count this three?
@ sasitharan
same problem as mentioned above:
this doesn't work:
m1--count---\
I can't use m1 as input for count! Or do I have a wrong count function?
<b>....au damm, answered my own question. Of course. I use COUNTER and you use
COUNT!!!!!!!!!!!! I will try this with COUNT!!</b>
thanks
chris
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