Trying to make a Ping Pong Ball generate in random location

Question

Hey guys and Gals,
im trying to make a pingpong ball, well 2 of them spawn in random locations so that it makes the game a little harder as of right now the ping pong balls spawn right next to each other and untill score 5-6 there right next to each other

Answer 1

I disagree with Caillen.   If somebody is trying to learn a programming language writing a game is an excellent way of learning. In the constructor to the form (or form load function ) you can change the X,Y location of the ball(s). You also want
to make sure the two balls don't overlap. To make the programming simpler I would start the two balls at the same Y coordinate (or X).
See code below.  I used a little clever programming to prevent the two ball from overlapping. The code assumes the left side of the panel x = 0.  If it is not zero then add the X of the left side of the panel to the results.
int widthPanel = 10;
int diameterBall = 2;
Random rand = new Random();
int ball1X = rand.Next(diameterBall / 2, widthPanel - (diameterBall / 2));
//now get a random number that is space not taken up by ball one
int ran2 = rand(0, widthPanel - diameterBall);
int ball1Left = ballX - (diameterBall / 2);
int ball2X = 0;
if(rand2 <= ball1X)
ball2X = rand2;
else
int ball1Right = ballX + (diameterBall / 2);
ran2 -= ball1Left;
ball2X = ball1Right + ran2;
jdweng