Unescape XML

Hi folks,
this is my Oracle Version :-(
BANNER
Oracle9i Enterprise Edition Release 9.2.0.8.0 - 64bit Production
PL/SQL Release 9.2.0.8.0 - Production
CORE 9.2.0.8.0 Production
TNS for IBM/AIX RISC System/6000: Version 9.2.0.8.0 - Production
NLSRTL Version 9.2.0.8.0 - ProductionIf I have an XML document like
<ROWSET>
<ROW>
<TEXT>abc &lt;def&gt;</TEXT>
</ROW>
</ROWSET>I can retrieve the text element like
SQL>SELECT XMLType('<ROWSET><ROW><TEXT>abc <def></TEXT></ROW></ROWSET>').extract('/ROWSET/ROW/TEXT/text()').getStringVal() AS x FROM DUAL;
X
abc &lt;def&gt;but I need it like
X
abc <def>Please help!
Urs

You could use REPLACE:
SQL> SELECT replace(replace(XMLType('<ROWSET><ROW><TEXT>abc <def></TEXT></ROW></ROWSET>')
2 .extract('/ROWSET/ROW/TEXT/text()').getStringVal(),'<','<'),'>','>') AS x
3 FROM DUAL;
X
abc <def>Max
[My Italian Oracle blog|http://oracleitalia.wordpress.com/2010/01/07/creare-documenti-office-da-plsql/]

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Hi Tony!
I took a long weekend so I'm just now getting back to my problem!
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I want to extract
<bp:NAME ***stufff***>(I want this part)</bp:NAME>This tag can occur is serval places. For example here;
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***bunch of tags***
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</bp:COMMENT>
<bp:SYNONYMS rdf:datatype="xsd:string">Nuclear receptor subfamily 3 group C member 3</bp:SYNONYMS>
<bp:SYNONYMS rdf:datatype="xsd:string">PR</bp:SYNONYMS>
<bp:NAME rdf:datatype="xsd:string">Progesterone receptor</bp:NAME>
−<bp:ORGANISM>
−<bp:bioSource rdf:ID="CPATH-LOCAL-112384">
<bp:NAME rdf:datatype="xsd:string">Homo sapiens</bp:NAME>
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−<bp:unificationXref rdf:ID="CPATH-LOCAL-112385">
<bp:DB rdf:datatype="xsd:string">NCBI_TAXONOMY</bp:DB>
<bp:ID rdf:datatype="xsd:string">9606</bp:ID>
</bp:unificationXref>
</bp:TAXON-XREF>
</bp:bioSource>
</bp:ORGANISM>
<bp:SHORT-NAME rdf:datatype="xsd:string">PRGR_HUMAN</bp:SHORT-NAME>
−<bp:XREF>
−<bp:relationshipXref rdf:ID="CPATH-LOCAL-112386">
<bp:DB rdf:datatype="xsd:string">ENTREZ_GENE</bp:DB>
<bp:ID rdf:datatype="xsd:string">5241</bp:ID>
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</bp:XREF>
−<bp:XREF>
−<bp:unificationXref rdf:ID="CPATH-LOCAL-112387">
<bp:DB rdf:datatype="xsd:string">UNIPROT</bp:DB>
<bp:ID rdf:datatype="xsd:string">P06401</bp:ID>
</bp:unificationXref>
</bp:XREF>
−<bp:XREF>
−<bp:unificationXref rdf:ID="CPATH-LOCAL-112388">
<bp:DB rdf:datatype="xsd:string">UNIPROT</bp:DB>
<bp:ID rdf:datatype="xsd:string">A7X8B0</bp:ID>
</bp:unificationXref>
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−<bp:XREF>
−<bp:relationshipXref rdf:ID="CPATH-LOCAL-112389">
<bp:DB rdf:datatype="xsd:string">GENE_SYMBOL</bp:DB>
<bp:ID rdf:datatype="xsd:string">PGR</bp:ID>
</bp:relationshipXref>
</bp:XREF>
−<bp:XREF>
−<bp:relationshipXref rdf:ID="CPATH-LOCAL-112390">
<bp:DB rdf:datatype="xsd:string">REF_SEQ</bp:DB>
<bp:ID rdf:datatype="xsd:string">NP_000917</bp:ID>
</bp:relationshipXref>
</bp:XREF>
−<bp:XREF>
−<bp:unificationXref rdf:ID="CPATH-LOCAL-112391">
<bp:DB rdf:datatype="xsd:string">UNIPROT</bp:DB>
<bp:ID rdf:datatype="xsd:string">Q9UPF7</bp:ID>
</bp:unificationXref>
</bp:XREF>
−<bp:XREF>
−<bp:unificationXref rdf:ID="CPATH-LOCAL-113580">
<bp:DB rdf:datatype="http://www.w3.org/2001/XMLSchema#string">CPATH</bp:DB>
<bp:ID rdf:datatype="http://www.w3.org/2001/XMLSchema#string">27885</bp:ID>
</bp:unificationXref>
</bp:XREF>
</bp:protein>Edited by: Dani3ll3 on Nov 19, 2009 2:51 AM

Dani3ll3 wrote:
Thanks a lot after I did that the regular expression worked. :)Good. But remember that in real life, you would then have to apply the XML rules to get the actual contents of the text node. For example it might be a CDATA section or it might include characters like ampersands which have been escaped and which you need to unescape. That's why it's better to use a proper parser, as already suggested.
It seems to me this forum is full of posts where people are doing homework questions which teach them to do things the wrong way. But of course there's nothing the student can do about that.

Unescape XML

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