Unix master shell script to run jobs in parallel with dependency

Question

I need a master shell script which would call the following shell scripts as per below order. Kindly note that if any shell script fails then the master shell script should abort.
Level 1     PRODUCTS
     SP_ROST_DLY_STG_lD
     SP_ROST_DLY_ITG_lD
After Level 1 completes run below two shell scripts in parallel:
Level 2     SP_IDL_EDGE_CON_POSTN_STG_Ld ,     SP_IDL_EDGE_ACCT_POSTN_STG_LD
After Level 2 completes run below shell scripts as per the seqeunce and in parallel:
Level 3     SP_IDL_EDGE_ACCT_STG_LD ,     SP_IDL_EDGE_CONT_STG_LD
     SP_IDL_EDGE_ACCT_STG_VAL ,     SP_IDL_EDGE_CONT_STG_VAL
     SP_IDL_EDGE_ACCT_ITG_Ld ,     SP_IDL_EDGE_CON_ITG_Ld
After Level 3 completes run below shell scripts as per the seqeunce and in parallel:
Level 4     SP_IDL_EDGE_CONT_POSTN_ITG_LD ,     SP_IDL_EDGE_VISITS_LD
     SP_IDL_EDGE_ACCT_POSTN_ITG_LD ,     SP_IDL_EDGE_VISITS_DTL_LD

Answer 1

can i avoid using set -e and use some other method so that if there is an error in previous job then the next job is not triggered.Sure, but it is ugly.
The below is not the only way to do this...
Wrap every place you start another script with:
$ if ! MYSCRIPT; then
    echo Script MYSCRIPT failed. >&2
    exit 1
fibut the wrapper for parallel scripts is even worse:
$ MYSCRIPT &
$ MYSCRIPT_JOBNO=$!
$ MYSCRIPT2 &
$ MYSCRIPT2_JOBNO=$!
$ MYSCRIPT_STATUS=`wait ${MYSCRIPT_JOBNO}`
$ if [ ${MYSCRIPT_STATUS} -ne 0 ]; then
    echo Script MYSCRIPT failed. >&2
    exit 1
fi
$ MYSCRIPT2_STATUS=`wait ${MYSCRIPT2_JOBNO}`
$ if [ ${MYSCRIPT2_STATUS} -ne 0 ]; then
    echo Script MYSCRIPT2 failed. >&2
    exit 1
fi
...Now, doesn't a simple 'set -e' look much better?