Update using Like Operator

My table Name is
DESC FUNCTIONS
Func_Id VARCAHR2(15)
dESCRIPTION VARCAHR2(100)
fLAG VARCHAR2(1)
This table is haivng the following data
SA100
SB100
SA105
SB105
SC105
SA200
SB200
SA205
SB205
SA300
SB300
I want to implement the below update
Update functions set flag = 'Y' where func_id like 'S%100'
Update functions set flag = 'Y' where func_id like 'S%200'
Update functions set flag = 'Y' where func_id like 'S%300'
How can i implement the above 3 SQLs into a Single SQL statement?
How can i merge the above 3 SQls into a Single SQL?

You could also use regexp_like:
with functions as
select 'SA100' func_id from dual union all
select 'SB100' func_id from dual union all
select 'SA105' func_id from dual union all
select 'SB105' func_id from dual union all
select 'SC105' func_id from dual union all
select 'SA200' func_id from dual union all
select 'SB200' func_id from dual union all
select 'SA205' func_id from dual union all
select 'SB205' func_id from dual union all
select 'SA300' func_id from dual union all
select 'SB300' func_id from dual
select * from functions where regexp_like(func_id,'^S.*[123]00$')
Update functions set flag = 'Y' where regexp_like(func_id,'^S.*[123]00$');

Similar Messages

Problem in JDBC , when using LIKE operator. - VERY URGENT

Problem in JDBC , when using LIKE operator.
LINE 1 : String temp = "AA";
LINE 2 : String query = "select * from emp where EMPNAME like '*temp*' ";
LINE 3 : Staement st = con.createStaement();
LINE 4 : ResultSet rs = st.executeQuery(query);
'*' character is not getting evaluated. In MS ACCESS2000 only * is accepted instead of '%'. Moreover in MS ACCESS the like operator has to be used within double quotes as a String. whereas in other databases, it accepts single quotes as a String.
Ex:
In MS ACCESS
     select * from emp where ename like "*aa*";
Other Databases
     select * from emp where ename like '%aa%';
In my situation iam passing a Variable inside a like operator and '*' is used.
For the above Scenario, Please help me out.
If possible Kindly let me know the exact Syntax.
Please give me the answer as LINE1,LINE2,LINE3,LINE4,
I have verified in JDBC Spec also, it has been specified to use escape sequence.that too did not work.
Due to this, My project is in hold for about 4 days. I could not find a suitable solution.
Please help me out.

I made a LIKE clause work with M$ Access, using PreparedStatement and the % wildcard:
            escapeStr                   = "%";
            String sql                  = "SELECT USERNAME, PASSWORD FROM USERS WHERE USERNAME LIKE ?";
            PreparedStatement statement = connection.prepareStatement(sql);
            statement.setString(1, ("user" + escapeStr));
            ResultSet resultSet         = statement.executeQuery();
            while (resultSet.next())
                System.out.println("username: " + resultSet.getObject("USERNAME") + " password: " + resultSet.getObject("PASSWORD"));

How to use like operator in loop

Hi I am trying to use like operation in loop condition. the code is as follows:
loop at lt_mara into l_mara where l_mara like '%XXX'.
endloop
when i have the like operator like above its giving me an error that i cannot use like operator. Is there anyway that i can use like operation in loop at condition,
Thanks in advance

using the ranges with CP option we can do that..
Populate the ranges mentioned below..
data: r_matnr type range of matnr,
w_matnr like line of r_matnr.
w_matnr-low = '%XXX'.
w_matnr-sign = 'I'.
w_matnr-option = 'CP'.
append w_matnr to r_matnr.
loop at lt_mara into l_mara where matnr in r_matnr.
endloop
Regards
Vijay Babu Dudla

How to use LIKE operator in plsql

Hi
I wanted to select certain rows using like operator in plsql(Input should be given by the user). I have given my experiment here .I couldn't get any result.
As per sql syntax while using LIKE operator we should give search criteria within single quote.where as in plsql if we give within single quote its takes as string so no output is comming.what is solution ? How to use like operator in plsql?
sql syntax
SQL>SELECT customer_name FROM customer_header
WHERE customer_name LIKE 'B%' ; customer_name
Bala murali
Babu
Basker
plsql syntax
PROCEDURE pro_custheader_like ( v_cname IN varchar2
     ,answer OUT type_refcur_customer) IS
     BEGIN
     OPEN answer FOR
     SELECT customer_name FROM customer_header
          WHERE customer_name LIKE ( ' v_cname ' );
END pro_custheader_like;
execution command
sql>variable answer refcursor;
sql>set serveroutput on
sql>exec package_name.pro_custheader_like( 'R',:answer);
plsql successfully completed
sql>print :answer
no row selected
by
balamuralikrishnan.s

plsql syntax
PROCEDURE pro_custheader_like ( v_cname IN
varchar2
,answer OUT
type_refcur_customer) IS
N
     OPEN answer FOR
     SELECT customer_name FROM customer_header
WHERE customer_name LIKE ( v_cname );
END pro_custheader_like;
Try it without any quotes. And, let us know your feedback.
Regards.
Satyaki De.
Message was edited by:
Satyaki_De

Using Like Operator For Parameter Fields

Hi All,
I have been figuring around this for few days, appreciated anyone know this could assit me
I have a report which having a mobile no parameter fields.
In my database, my mobile no was not a clean entry.
For eg, a standard mobile number from Malaysia was 60126143331.
1) 60 - indicate country code (MYS)
2) 12 - indicate mobile operator
3) 6143331 - indicate phone number
Usually, peoples will entry it as 6012-6143331 or 012-6143331 or 0126143331 or 60126143331. In my CR report, i have a static mobile no selection. Currently, my filter selection will be as below:
{pax.mobile_no} = {?p_mobileno}
any possible to change it to like? meaning to say, if user enter 012-6143331 it will know that this was 6012-6143331 and the records will be selected into the report.
Appreciated anyone know this could assits.
Thanks in advance.
Regards,
CK

Hi,
tq for ur prompt reply.
D value in my database r not fix, some mobile no could b 7 digits some could b up to 12 digits. But I jz want user to enter mobile no in 10 digits only. Example, mobile no in db wa 60126661233. However, user input in parameter selection could only 0126661233 without 6. In some situation if mobile no in db was 6012-6661233, user input willb only 0126661233 n this input will b match with data in db using like operator.
I m wondering can this b archieve in cr?
Tq
regards,
ck

How to pass variable into lov sql query using like operator

hi.
i want to use a lov where i want to pass a variable using like operator.
my query is
select empno,name from table where empno like ':ed%';
my empno is A001 TO A199 AND B001 TO B199 so i want show either A% or B% empno
how can i do this ?
reagrds

kindly press Shift+F1 at a time you face this error to see the exact Oracle error message.
and provide us with that detail
and its better if you start new topic for that error... because that will be new error,,,
-- Aamir Arif
Edited by: Aamiz on Apr 7, 2010 12:27 PM

How tio use like operator in textitem to get the name

Oracle forms6i
Hai All
I have created an form to create an hierarchy list. I that I had an Text_item how can i use like operator to get the name to select. which trigger i need to use. when i select the name i need to get his employee code and other details
Thanks In Advance
Srikkanth.M

A is the head of Dept 10 and three person are under A namelyHow will you know that B, C and D are under A is there any parent child relationship between Leader and Employee code? If yes, Then you can create the relationship between blocks no need to set where_clause programatically. So, relationship can be like...
leader_block.emp_code = emp_block.leader_code
AND leader_blokc.dep_code = emp_block.dep_codeSo, when you will query data in LEADER block it will show employees which are under LEADER which you queried in LEADER block.
Or if there is no relationship then how will you know that which employee under which leader?
b 002 10 1
c 003 10 1
d 004 10 1
When i enter the name of head corresponding other members in the department will need to display in the
Tabular format Or if you want to query the records only for department relation. Then as you said you create two blocks then create create the relationship using dep_code between those blocks.
like...
leader.dep_code = emp_block.dep_code-Ammad

Get Result using LIKE operator

Hi All,
I am bit confused as to how to get this output using like operator :
select * from table1 where name like 'P&C%';
Here , since '&' is there , sql is prompting me to enter a value for C instead of giving output. I tried using escape but it is not working.
Can anybody tell me how to overcome this problem..?
Thanx.

Alright,
Here you go. In 'SQL Editor' in PL/SQL Developer:
Pulled this off the PL/SQL Developer Manual:
Escape character
If you wish to use an ampersand in the SQL text that should not be interpreted as a substitution variable,
use a double ampersand instead. The following example will retrieve all employees from the ‘R&D’
department:
select * from emp
where emp.deptno in (select dept.deptno from dept
where dname = 'R&&D')
order by empno desc
If the text 'R&D' had been used instead, you would have been prompted for the D variable.

Using Like Operator in a decode function

Hi,
I am trying to find out if I can use the like operator in a decode function
like:
select decode(1234,like '%123%','123 is a match') from dual;
this reults in error ORA-00936: missing expression
is there any way to make this work?
thank you

SQL> ed
Wrote file afiedt.buf
1 WITH tbl AS (SELECT '201aaa' dt FROM DUAL UNION ALL
2               SELECT '123bbb' dt FROM DUAL UNION ALL
3               SELECT '567ccc' dt FROM DUAL UNION ALL
4               SELECT 'ab123ddd' dt FROM DUAL
5               )
6 SELECT dt,CASE WHEN dt like '%123%' THEN 'Match'
7         ELSE 'Not Matched'
8         END With_case
9        ,DECODE(REGEXP_SUBSTR(dt,'123'),NULL,'Not Match','Match')   With_Regexp
10        ,DECODE(INSTR(dt,'123'),0,'Not Match','Match') With_Instr
11        ,DECODE(REPLACE(dt,'123'),dt,'Not Match','Match') With_Replace
12* FROM tbl
SQL> /
DT       WITH_CASE   WITH_REGE WITH_INST WITH_REPL
201aaa   Not Matched Not Match Not Match Not Match
123bbb   Match       Match     Match     Match
567ccc   Not Matched Not Match Not Match Not Match
ab123ddd Match       Match     Match     MatchEdited by: Saubhik on Jul 26, 2010 5:24 AM
Edited by: Saubhik on Jul 26, 2010 5:40 AM
Edited by: Saubhik on Jul 26, 2010 5:40 AM

How to use like operator in IFTHENELSE (BODS)

Hi All,
I want to find the value of ' % ASSOC%' in the name and replace it to 'Assoc.' using ifthenelse.
Can any one help me. Is there any similar fuction as LIKE operator. Can we give LIKE in ifthen else condition.
Thanks in advance

Hi ,
if you have data ASSOC1,ASSOC2
and you want Output like Assoc.1,Assoc.2.
In this condition it is not possible with ifthenelse function
it will return output as Assoc.
Example Source:
If we use if then else condition. Then it will replace all the Data to Assoc.
Or else if you want to replace ASSOC to Assoc. Then you can use Search_Replace also
it will generate a XML script
The expected output as follows in the below screen. As per your requirement you can you any one of this.
Regards,
Akhileshkiran.

How to use LIKE operator with PreparedStatement

Hi, I need to execute a query with the LIKE operator, but using a PreparedStatement. Can I do this, and if so what must my SQL look like with the wildcard characters '%' or '_'?
normal PS example: conn.prepareStatement("select * from mytable where name like ?");
If I try: conn.prepareStatement("select * from mytable where name like ?%");
I get: ORA-00911: invalid character
If I try: conn.prepareStatement("select * from mytable where name like '?%'");
I get: ORA-01006: bind variable does not exist
I must use a PreparedStatement, as my variable may contain illegal characters (like '), and using PreparedStatement.setString(1, var) will automatically escape it for me.
I could also use a normal Statement, but I need to escape my var ... is there a utility that will safely escape a String for an Oracle VARCHAR2??
Thanks in advance,
Stu Miller

Hmm, it seems you are right...
when my variable contains a '%' symbol, the PreparedStatement will NOT escape it, and thus it is treated like a wildcard. Therefore, I can just do
pstmt.setString(1, var+"%");
But, that may return more results than I'm asking for, as when 'var' contains a '%' symbol it is taken as a wildcard too.
I need each character in my variable to be taken literally, and only add a wildcard at the end. Basically, I need a STARTSWITH operator ;-)
It seems to me that escaping the sensitive characters in a String (which will differ depending on which operator is used), should be possible. I could write this, but I was hoping Oracle had already done it for me in some utility class.

Problem in using like Operator

Hi, can any one help me in finding out if we can use a column name in the like operator...
for example i want to compare a column with another column in the same table...
column1 has a value as omer123
and cloumn2 has a value as omer
i just want to find out those records in which column2 contains in column1
column1 column2 column3
omer12 omer This is the one
12jack sda asds
1233 asd asd
12Aug212 dasd adsasd
i want to write a query which will return ' This is the one ' as its col2 is in col1
This is what i wrote but the problem is in the like operator
select t1.cloumn3
from table_name t1,table_name t2
where t1.id = t2.id
and t1.column1 like %t2.column2%
plz help..
thankz

Your wildcard characters need to be quoted, thus:
SELECT t1.column3
FROM table_name t1,
table_name t2
WHERE t1.id = t2.id
AND t1.column1 LIKE '%'||t2.column2||'%' ;

2002 Updation using MOD -Operation.

when we try to update the 2002 infotype using HR_INFOTYPE_OPERATION
it is saving the STDAZ field value as 24
when I pass any value in STDAZ through my frontend?
is typing a message.
: for ex: 1,2,3,4,5,6,7, or 8
For Updation we are using MOD -Operation.

Hi,
STDAZ is automatically calculated from the difference btw BEGUZ and ENDUZ fields.
If you donot fill these fields bur specify STDAZ instead, the system takes the attendance as 1 day and make STDAZ as 24 hours.
Pls use BEGUZ and ENDUZ fields instead of directly updating STDAZ.
Regards,
Dilek

Using like Operator in Prepeared Statement

PreparedStatement s2=dbcon.prepareStatement("Select phone,dnc_message from gsw_donotcall_list_tab where phone=? or dnc_message like ?");
s2.setString(1,number);
s2.setString(2,"%"+smessage+"%");
ResultSet result=s2.executeQuery();
rowfound=result.next();
(Using SQL Server, I am Accepting Parameters from the User by a HTML Page, the user may enter full or partial message, but need to display all the records Satisfying the Criterai
I tried this but dosnt work for DNC_message Field
Can anyone help me i am in great need of this

The problem with that is it produces the following query:
UPDATE COFFEES SET SALES = 75 WHERE COF_NAME LIKE 'Colombian'Which they also show as a normal Statement (rather than a PreparedStatement) and they claim it will work. Well, in most databases it will work, only if COF_NAME contains exactly "Columbian", just like an "=". If you also want it to return "Columbian Prime" or "Wild Columbian" or whatever, your out of luck without the wildcards, and PreparedStatement does not insert them. If you don't belive it works this way, then test it yourself:
create table TEST_IT (
Bogus VARCHAR(20) Primary Key
insert into TEST_IT values ('AAA');
insert into TEST_IT values ('ABA');
insert into TEST_IT values ('ABC');
SELECT * From Test_It Where Bogus LIKE 'A';
SELECT * From Test_It Where Bogus LIKE 'AAA';
SELECT * From Test_It Where Bogus LIKE '%A%';And inspect what the three select statements return.
Edit: I must apologise, and ask the OP what Driver he is using. This may be somewhat Driver dependent. Using the MySQL 3.1.6 Driver and MySQL 4.1.9, it did not escape the "%" symbols and so
setString(1, "%A%");returned 3 rows. So the reason yours is not, may be dependent on the Driver and/or vendor. But in any case, the example shown in the tutorial (the Statement version) would still not work (at least in most DBs).

How to achive equivalent of contains in java using Like operator

Hi,
Could anyone please enlighten me on this issue.
I need to achieve through the query to reduce the unnecessary of loop through.
Lets say:
I have a table called BLACKLISTPASSWORD with column BPW.
example record in column (BPW)
Welcome
Welcome1
Welcome123
I want make a query like
SELECT BPW
FROM BLACKLISTPASSWORD
WHERE lower(BPW) LIKE 'welcome1234%'Expecting a result true if any sequence matches in above case expecting true bcz Welcome123 is there in DB.
Plz correct me in the query to achieve this.
Edited by: Deekay on Aug 2, 2012 12:40 AM

Deekay wrote:
Hi,
Could anyone please enlighten me on this issue.
I need to achieve through the query to reduce the unnecessary of loop through.
Lets say:
I have a table called BLACKLISTPASSWORD with column BPW.
example record in column (BPW)
Welcome
Welcome1
Welcome123
I want make a query like
SELECT BPW
FROM BLACKLISTPASSWORD
WHERE lower(BPW) LIKE 'welcome1234%'Expecting a result true if any sequence matches in above case expecting true bcz Welcome123 is there in DB.
Plz correct me in the query to achieve this.
Edited by: Deekay on Aug 2, 2012 12:40 AMYou can use as
SELECT BPW
FROM BLACKLISTPASSWORD
WHERE lower(BPW) LIKE 'welcome%'This will return
Welcome
Welcome1
Welcome123
If you want Output as
>
Welcome1
Welcome123
>
i.e. Welcome followed by a/more digits; Below works on Oracle 10g or higher.
SELECT BPW
FROM BLACKLISTPASSWORD
WHERE regexp_like(BPW, 'welcome[[:digit]]+', 'i');

Update using Like Operator

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