Using File Name to determine the Receiver

Question

Hi All,
I have to determine the receivers based on the Input file name. I am using the context object File Name in the condition editor. But based on the first 4 characters of the FileName I have to route the file. Can anybody please help how to formulate this expression in the condition editor?
Thanks,
Geetha

Answer 1

Hello Geetha,
         You need to specify this in you mapping as in condition editor you can not specify values at runtime. What you need to do is
-> Select the Extended Reciever Determination in ID
->In IR specify the mapping for determining the receiver (You need to use the another mapping for this)
        . Here copy the MessageType 'Receivers' from the component  as your target MT
          SAP BASIS 7.0 (Depends on your version)-> "htt://sap.com/xi/XI/System" namespace.
       .  Define Message Mapping between Outbound Message Type(The one with your filename) and 
         Standard Message Type u201CReceiversu201D which is as Inbound message type and which is in the SAP
         BASIS -->http://sap.com/xi/XI/System
       . In mapping specify your service based on your First 4 character of your file name(Use SubString)
IF filename -> SubString(0,4) ->Equals ->   filename -> SubString(0,4)  Then  Select Your Service  ( Service in Constant value). ELSE (your logic)
Once you finish this remaining as usual in IR, while InterfaceMapping you select two mapping programs.
Remmber to use the Extended Interface Determination in ID, This resolves your issue.
Regards,
Pasanna