Variable in loop is retaing values from previous loop

Question

Just wondering if anyone can see at a glance what I going wrong here.
I have the following part of a script which is imbedded in another while loop which loops through 5 different items defined by 'accomm_id';
while ($db_field = mysql_fetch_assoc($result)) {
$SQLx = "SELECT price_from FROM AN_pricetable WHERE accomm_id = " . $db_field['accomm_id'];
$resultx = mysql_query($SQLx);
while($row=mysql_fetch_assoc($resultx))
  $price_from[] = $row['price_from'];
  //  do stuff with other column
  //  data if we want
$pricefrom = min($price_from);
$temp = $price_from;
sort($temp, SORT_NUMERIC);
foreach ($temp as $value) {
if ($value > 0){ $pricefrom = $value; break;}}
if ($pricefrom == 0){
          $pricefrom = "TBC";}
The script is supposed to find the lowest price for the particular accomm_id that it is looping through at the time.
The problem is that once the 'lowest price' for the item with the lowest 'lowest price' of all 5 accomms has been found, the following items take on that price, instead of their own particular lowest price. Somehow the '$pricefrom' value is being carried through to the next loop.
The database has several entries for each accomm_id, all with different prices in the 'price_from' field. What I'm trying to find is the lowest for each accomm_id.
Hopefully this is something obvious that I've missed, I just can't see why it won't work!
Thanks

Answer 1

As and alternative I tried;
$SQLx = "SELECT MIN(price_from) AS minimumprice FROM AN_pricetable WHERE accomm_id = " . $db_field['accomm_id'];
$resultx = mysql_query($SQLx);
$pricefrom = mysql_result($resultx,$i,'minimumprice');
if ($pricefrom == 0){
          $pricefrom = "TBC";}
But for some reason it is not returning the minimum for any of the 5 accomms. For example one accom has four rows of prices, 8, 12, 50 and 7, and it is returning 12 as the MIN. What am I doing wrong here?
Thanks