Variable User Exit

Question

Hi have a user exit variable in a query (It must concatenate two characteristics from the user entry parameters).
WHEN 'NOMSOLI'.   " nombre solicitante tarifa compras
      CLEAR: l_s_var, l_s_var2.
      READ TABLE i_t_var_range WITH KEY vnam = 'OS_SALON'
                                                INTO l_s_var.
      IF ( sy-subrc EQ 0 ).
        LOOP AT i_t_var_range INTO l_s_var2 WHERE vnam = 'OS_EDICI'.
          IF ( sy-subrc EQ 0 ).
            CONCATENATE l_s_var-low '.' l_s_var2-low INTO l_s_range-low.
            l_s_range-sign  = 'I'.
            l_s_range-opt   = l_s_var2-opt.
            APPEND l_s_range TO e_t_range.
          ENDIF.
        ENDLOOP.
      ENDIF.
I must to take care the user entry parameters of the query : LE,BT,GE..... <,>, = , ..etc
The final result of the variable shows the follow structure data (because the entry parameters user)::
I   |GE |S028.006  
I   |LE |S028.008  
but when I execute the query, it shows an error about the interval result.
Some one knows how it works when you have more values entry data?
Because always I create user exit variables like:
I   |EQ |S028.006

Answer 1

Hi MP,
The code seems to be OK as per your current requirement. Please clear below mentioned points are correct as per what i understand.
User Input
1. OS_SALON
2. OS_EDICI
-> First input is going to be single.
-> Second input would always be multiple but single values with various options.
-> you need to concatenate first value with all the second values and the options of just 2nd one.
-> After concatenation, you need to validate the result value with the data in the infoprovider.
-> Validated data then needed in output.
I can suggest you some alternate method if it is same what i understand.
Regards
Raj