Version a JSP page?

Hi we r making some projects with JSP as front end and SQL as a back end and we want to version our Site but i dont know how to version a web based application ....cuz we are not using any of activeX controls or any other control/component..........plz help me

Hi we r making some projects with JSP as front end and
SQL as a back end and we want to version our Site but
i dont know how to version a web based application
....cuz we are not using any of activeX controls or
any other control/component..........plz help me
Are you sure everyone is talking about the same thing?
"Version Control" software is used to backup software as developers work on it. It does this by allowing a developer to check in new versions of the code. It also allows a developer to revert to a previous version.
That is what all of the other posts are describing.
But that doesn't have anything to do with 'web' or 'activex'. Unless you are looking for a version control system that is available from the web and does not need to support binary(activex) stuff. But that last seems a little odd since these days binary stuff is often used - word docs, icons, etc.

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                            </form>
                        </div>
                    </td>
                </tr>
            </tbody>
        </table>
    </center>
    <br/><br/><br/><br/><br/><br/><br/><br/><br/><br/><br/><br/><br/><br/>
    <br/><br/><br/>
    <center>Copyright &copy; 2009 Photint FZ LLC</center>
    <center>Powered by Ali Jamali</center>
    <center>Version : 1.0</center>
    </body>
    </html>And you need loginServlet.java
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    import com.ali.entity.user.UserEntity;
    import com.ali.util.HibernateUtil;
    import java.io.IOException;
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    import javax.servlet.ServletException;
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    import javax.servlet.http.HttpServletRequest;
    import javax.servlet.http.HttpServletResponse;
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        private static final long serialVersionUID = 1L;
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                dispatcher.forward(request, response);
                return;
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                e.printStackTrace();
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                dispatcher.forward(request, response);
                return;
            HttpSession session = request.getSession();
            System.err.println(request.getRemoteAddr());
            session.setAttribute("username", user.getFirstName());
            session.setAttribute("userType", user.isAdmin());
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            response.sendRedirect("/PAS/index.jsp");
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    import java.util.ArrayList;
    import java.util.List;
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        public static void logInUser(String username) {
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        public static void logoutUser(String username) {
            if (isUserLoggedIn(username)) {
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        public static boolean isUserLoggedIn(String username) {
            return loggedInUsers.contains(username);
    }If you have any more Q. or any comment , Most welcome
    Thanks
    Ali Jamali

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    Chubha{color}
    {color}

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    follow this steps it works fine.
    regards
    DRA

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