With out try and catch

with out any try and catch is exception handling is possible in java when doing manupulation with database.
assume mydatabase is oracle,if i am going to insert a record of a primarykey field, which is already existing.i don't want to put with in try and catch.This is my case.if u have the answer for this please mail me.
thanks
rajan

assume mydatabase is oracle,if i am going to insert a
record of a primarykey field, which is already existing.
i don't want to put with in try and catch.why not? i thought the fact that checked exceptions get thrown from methods is a good thing, since you're forced either to deal with the fault immediately, or throw to the next level up, possibly transformed into an application-level exception. if methods were to simply return method-specific error codes, nothing forces anything in the program to deal with errors in a reasonable manner. not that exceptions force sensible handling of the fault--but they do force recognition of the fault.
what alternative do you desire?
--p

Similar Messages

Try and Catch don't work on powershell module

Hi everyone,
i'm tring to create a module with a try and catch, but when i call it, the block of expetion doesn't work as i expect, while if i use the code as a function only it works...
Here the code
function global:Process{
param([string]$Process)
######################################MAIL################################
function global:SendMail(){
param([string]$Services)
$Dest="xxx"
$smtpServer = "xxx"
$msg = new-object Net.Mail.MailMessage
$smtp = new-object Net.Mail.SmtpClient($smtpServer)
$msg.From = "xxx"
$msg.To.Add($Dest)
$msg.Subject = "Notification about $Services activity"
$msg.Body = "xxxx"
$smtp.Send($msg)
switch($Process){
"DSP"{
if((Get-Service Fax | ForEach-Object {$_.Status}) -eq "Stopped"){
try
start-service Fax -ea Stop
catch
if ( $error[0].Exception -match "Microsoft.PowerShell.Commands.ServiceCommandException")
$error[0].Exception | Out-File C:\log.txt
$SendMail $Process
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Export-ModuleMember -Function Process
Could you help me? Thanks so much
Cristian

Hello,
You should ask in the
Windows PowerShell forum.
Karl
When you see answers and helpful posts, please click Vote As Helpful, Propose As Answer, and/or Mark As Answer.
My Blog: Unlock PowerShell
My Book:
Windows PowerShell 2.0 Bible
My E-mail: -join ('6F6C646B61726C406F75746C6F6F6B2E636F6D'-split'(?<=\G.{2})'|%{if($_){[char][int]"0x$_"}})

Textfields Try and Catch

Hi All, just a quick question really...
Was wondering how I would go about checking user inputs into textfields?
For example if the user enters the number 12 and you're only allowed to enter numbers between 1-10 how could I send a pop up error message to say "You can only enter numbers between 1-10"
A way I thought about doing this was with a try and catch method, there could be another way of doing this, all other methods appreciated too.
function captureNumbers(evt:MouseEvent):void {
try{
numberSelect.push(Number(number1.text));
catch{
if (numberSelect > 10){
throw new Error("You must choose a number between 1 - 10");
button1.addEventListener( MouseEvent.MOUSE_UP, captureNumbers);
This is what ive got so far which doesn't seem to be working...
Thanks in advance

public class userBean(String user) {
     // Loads user preferences
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     String lname;
     String greeting;
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          Connection conn = null;
          PreparedStatement pstmt = null;
          ResultSet result = null;
          try {
               Class.forName("oracle.jdbc.driver.OracleDriver");
          catch (Exception e) { System.out.println("Can't load JDBC driver:" + e); return; }
               try{
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Repost as question for points: What did I do wrong? (Try and Catch program)

This has to be a try and catch program.
This is the given output sample:
OUTPUT SAMPLE #2 for input.txt: 12345 222256 -3 123 -56784 555557 6345678 x x x 81234 121212 x x 123434 x x 1009098 2099
Please input the name of the file to be opened: input.txt
For number 12345 the sum of digits is: 15
For number 222256 the sum of digits is: 19
Found an integer (-3), but it is negative. Will ignore!
For number 123 the sum of digits is: 6
Found an integer (-56784), but it is negative. Will ignore!
For number 555557 the sum of digits is: 32
For number 6345678 the sum of digits is: 39
For number 81234 the sum of digits is: 18
For number 121212 the sum of digits is: 9
For number 123434 the sum of digits is: 17
For number 1009098 the sum of digits is: 27
For number 2099 the sum of digits is: 20
Here is what I have so far.
import java.util.Scanner;
import java.io.*;// FileNotFoundException
public class Assignment3b {
public static void main (String[]args){
    Boolean fileOpened = true;
    String fileName;
    int n,mod=0,sum=0,t=0;
    Scanner inputFile = new Scanner(System.in);
    System.out.print("Please input the name of the file to be opened: ");
    fileName = inputFile.nextLine();
    System.out.println();
    try {
            inputFile = new Scanner(new File(fileName));
        catch (FileNotFoundException e) {
            System.out.println("--- File Not Found! ---");
            fileOpened = false;
        if (fileOpened) {
          while (inputFile.hasNext()){
            if (inputFile.hasNextInt()){
              n = inputFile.nextInt();
              t=n;
              while(n>0){
                mod = n % 10;
                sum = mod + sum;
                n = n/10;
              System.out.println ("For number " + t + " the sum of digits is : " + sum);
              mod = 0;
              sum = 0;
              while (n<0) {
                System.out.println ("Found an integer (" + t + "), but it negative. Will ignore!");
                inputFile.next();
                n = inputFile.nextInt();
            else {
              inputFile.next();
}Everything seems to work fine until, it is time to deal with negative numbers. How can I fix this. Please put your reply in layman's terms to the best of your ability.
Thanks and God Bless.

// COSC 236                                Assignment # 3
// YOUR NAME: Anson Castelino
// DUE-DATE:
// PROGRAM-NAME: Assignment # 3 Prt2
//import packages
import java.util.Scanner;
import java.io.*;// FileNotFoundException
public class Assignment3b {
public static void main (String[]args){
    Boolean fileOpened = true;
    String fileName;
    int n,mod=0,sum=0,t=0;
    Scanner inputFile = new Scanner(System.in);
    System.out.print("Please input the name of the file to be opened: ");
    fileName = inputFile.nextLine();
    System.out.println();
    try {
            inputFile = new Scanner(new File(fileName));
        catch (FileNotFoundException e) {
            System.out.println("--- File Not Found! ---");
            fileOpened = false;
        if (fileOpened) {
          while (inputFile.hasNext()){
            if (inputFile.hasNextInt()){
              n = inputFile.nextInt();
              t=n;
              while(n>0){
                mod = n % 10;
                sum = mod + sum;
                n = n/10;
              System.out.println ("For number " + t + " the sum of digits is : " + sum);
              mod = 0;
              sum = 0;
              if (n<0) {
                System.out.println ("Found an integer (" + t + "), but it is negative. Will ignore!");
                inputFile.next();
              inputFile.hasNext();
            else {
              inputFile.next();
}Updated code.
current output is as follows:
Please input the name of the file to be opened: [DrJava Input Box]
For number 12345 the sum of digits is : 15
For number 222256 the sum of digits is : 19
For number -3 the sum of digits is : 0 <-------- this part is not suppose to be here.
Found an integer (-3), but it is negative. Will ignore!
For number -56784 the sum of digits is : 0 <-------- this part is not suppose to be here.
Found an integer (-56784), but it is negative. Will ignore!
For number 6345678 the sum of digits is : 39
For number 81234 the sum of digits is : 18
For number 121212 the sum of digits is : 9
For number 123434 the sum of digits is : 17
For number 1009098 the sum of digits is : 27
For number 2099 the sum of digits is : 20
>

Class that contains finally block with out try block

How can we make a class that will contain finally block with out try block.

dkpadhy wrote:
How can we make a class that will contain finally block with out try block.You can�t.
And frankly it seems to me that you don�t understand what you�re doing.
Care to explain further?

How the try and catch blocks work?

For the following section of code from the class QueueInheritanceTest...how the try and catch blocks work?
The Class...
public class QueueInheritance extends List {
public QueueInheritance() { super( "queue" ); }
public void enqueue( Object o )
{ insertAtBack( o ); }
public Object dequeue()
throws EmptyListException { return removeFromFront(); }
public boolean isEmpty() { return super.isEmpty(); }
public void print() { super.print(); }
Testing...
public class QueueInheritanceTest {
public static void main( String args[] ){
QueueInheritance objQueue = new QueueInheritance();
// Create objects to store in the queue
Boolean b = Boolean.TRUE;
Character c = new Character( '$' );
Integer i = new Integer( 34567 );
String s = "hello";
// Use the enqueue method
objQueue.enqueue( b );
objQueue.enqueue( c );
objQueue.enqueue( i );
objQueue.enqueue( s );
objQueue.print();
// Use the dequeue method
Object removedObj = null;
try { while ( true ) {
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objQueue.print();
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If you want a basic introduction to try/catch blocks, read any introductory text or the tutorials on this site.
Here are some:
Sun's basic Java tutorial
Sun's New To Java Center.
JavaRanch. To quote the tagline on their homepage: "a friendly place for Java greenhorns."
In terms of this particular case, it looks like the code is using an exception being thrown to get out of a loop. IMHO that's bad design -- exceptions should be used for exceptional circumstances, and if you use it to get out of a loop, then you're certain it's going to happen, and that means that it's not exceptional.
When you post code, please wrap it in tags so it's legible.

The email address connected to an old itunes account is no longer active. Can't access music i bought many years ago with out it and the old password.

the email address connected to an old itunes account is no longer active. Can't access music i bought many years ago with out it and the old password.

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the email address connected to an old itunes account
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Is there try and catch in oracle query ?

hi
is there try and catch in oracle query ?
try
do some update
catch
if there was error go to here
}

>
is there try and catch in oracle query ?
>
Yes - except it uses BEGIN --- EXCEPTION --- END where BEGIN replaces the try and EXCEPTION replaces the catch.
BEGIN
-- Calculation might cause division-by-zero error.
   pe_ratio := stock_price / net_earnings;
   dbms_output.put_line('Price/earnings ratio = ' || pe_ratio);
EXCEPTION -- exception handlers begin
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END; -- exception handlers and block end here
/The multiple WHEN conditions correspond to using multiple 'catch' statements in Java.

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Help with try and catch

I know I posted this quesiton earlier,but I am sitll having problems. In the following code, the exception IS caught if the user enters a String instead of a Int. But the Exception is NOT caught if the user enters
the "Enter" key.
            do
                          flag=false;
                 //set the quantity to user input
                 System.out.print("Enter the quantity:");
                 try
                   amount = input.nextInt();
                      if (amount > 0) //executes when amount is less then or equal to zero
                         flag=false;
                      } //end of if
                      else
                           System.out.println("You must enter a positive quantity");
                                          flag=true;
                 } //end of try
                 catch (Exception e)
                                  input.nextLine();
                                  System.out.println("You must enter a number");
                                  flag=true;
            }while(flag==true); //end of do while


nextInt won't read "just the enter key"... it blocks until reads "something".
Try something like this instead...
Note: java.io.Console is new in 1.6
package krc.utilz.io;
// usage:
// import krc.utilz.io.Console;
// String name = Console.readLine("Enter your name : ");
// while ( (score=Console.readInteger("Enter a score between 0 and 100 (enter to quit) : ", 0, 100, -1)) != 1) { ... }
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import java.text.DateFormat;
import java.text.SimpleDateFormat;
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private static final java.io.Console theConsole = System.console();
private static final DateFormat dateFormatter = new SimpleDateFormat("dd/MM/yyyy");
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        System.out.println("Oops: "+e);
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    int i = 0;
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    while(true) {
      try {
        response = readLine(prompt);
        return (response!=null && response.trim().length()>0
          ? Integer.parseInt(response)
          : defualt
      } catch (NumberFormatException e) {
        System.out.println("\""+response+"\" cannot be interpreted as an integer!");
      } catch (Exception e) {
        System.out.println("Oops: "+e);
public static int readInteger(String prompt, int lowerBound, int upperBound, int defualt) {
    int i = 0;
    while(true) {
      i = readInteger(prompt, defualt);
      if ( i==defualt || i>=lowerBound && i<=upperBound ) break;
      System.out.println("An integer between "+lowerBound+" and "+upperBound+" (inclusive) is required.");
    return(i);
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    double d = 0;
    String response = null;
    while(true) {
      try {
        response = readLine(prompt);
        if ( response!=null && response.length()>0 ) {
          d = Double.parseDouble(response);
          break;
        System.out.println("A number is required.");
      } catch (NumberFormatException e) {
        System.out.println("\""+response+"\" cannot be interpreted as a number!");
      } catch (Exception e) {
        System.out.println("Oops: "+e);
    return(d);
public static double readDouble(String prompt, double lowerBound, double upperBound) {
    while(true) {
      double d = readDouble(prompt);
      if ( d>=lowerBound && d<=upperBound ) return(d);
      System.out.println("A number between "+lowerBound+" and "+upperBound+" (inclusive) is required.");
public static boolean readBoolean(String prompt) {
    while(true) {
      try {
        String response = readWord(prompt+" (Y/N) : ");
        return response.trim().equalsIgnoreCase("Y");
      } catch (Exception e) {
        System.out.println("Oops: "+e);
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Stack that implements try and catch problem

Hi guys, i'm pretty new to java (and programming all together) , have a difficulties with this calculator i'm working on.
I've got a stack which holds for instance 5 + 6 * 2
which equals 17. What i have is:
Stack<String> expression = new Stack<String>(
while(expression.size() >= 2){
String X = new String();
String Y = new String();
X = expression.pop();
System.out.println("popin stack"+X); //debuggin purposes
try {double x = Double.parseDouble(X);
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                   System.out.println(result);
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else if (X.equals('-')) {
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double y = Double.parseDouble(Y);
String result = Operation.MINUS.eval(x,y);
System.out.println(result);
expression.push(result);
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double y = Double.parseDouble(Y);
String result = Operation.DIVIDE.eval(x,y);
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expression.push(result);
else {
Y = expression.pop();
double y = Double.parseDouble(Y);
String result = Operation.TIMES.eval(x,y);
System.out.println(result);
expression.push(result);
catch () { }
My idea behinde this was i'd used the try statement
to prevent the element being converted to a double if it isn't a String which this can be done to i.e any integer. I'm not sure if i've gone about this right. And have not idea of what i'm suppose to be catchin i.e the throwable?. Any input/direction would be great, thanks.

Hi guys, i'm pretty new to java (and programming all together) , have a difficulties with this calculator i'm working on.
I've got a stack which holds for instance 5 + 6 * 2
which equals 17. What i have is:
Stack<String> expression = new Stack<String>(
while(expression.size() >= 2){
     String X = new String();
     String Y = new String();
     X = expression.pop();
     System.out.println("popin stack"+X); //debuggin purposes
     try {double x = Double.parseDouble(X);
     if (X.equals('+')) {
           Y = expression.pop();
           double y = Double.parseDouble(Y);
           String result = Operation.PLUS.eval(x,y);
           System.out.println(result);
           expression.push(result);
      else if (X.equals('-')) {
           Y = expression.pop();
           double y = Double.parseDouble(Y);
           String result = Operation.MINUS.eval(x,y);
           System.out.println(result);
           expression.push(result);
     else if (X.equals('/')) {
           Y = expression.pop();
           double y = Double.parseDouble(Y);
           String result = Operation.DIVIDE.eval(x,y);
           System.out.println(result);
           expression.push(result);
     else {
           Y = expression.pop();
           double y = Double.parseDouble(Y);
           String result = Operation.TIMES.eval(x,y);
           System.out.println(result);
           expression.push(result);
     catch () { }
} My idea behinde this was i'd used the try statement
to prevent the element being converted to a double if it isn't a String which this can be done to i.e any integer. I'm not sure if i've gone about this right. And have not idea of what i'm suppose to be catchin i.e the throwable?. Any input/direction would be great, thanks.
Edited by: javaUser on Dec 30, 2007 5:59 PM

With out try and catch

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