XML attribute not displayed by stylesheet

HI Gentlemen,
I set up a very simple case where some of the input data is in attributes. It works fine for the element content--firstname, however it does not display the attribute requested. What can be wrong? Please help!
Thanks, regards
Miklos
The XML instance (people.xml):
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="c:\XSL\people.xsl"?>
<people>
<person born="1912" died="1948">
<name>
<firstname>Alan</firstname>
</name>
</person>
</people>
The corresponding stylesheet (people.xsl):
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="person">
<person born="{born}" />
</xsl:template>
</xsl:stylesheet>

Are you opening "people.xml" directly in a web browser?
If so, I think you need to transform to HTML for a proper display.
For example :
people.xml
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="file://c:/XSL/people.xsl"?>
<people>
<person born="1912" died="1948">
<name>
<firstname>Alan</firstname>
</name>
</person>
</people>
people.xsl
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="person">
<html>
   <body>
    <p><xsl:text>First name = </xsl:text><xsl:value-of select="name/firstname"/></p>
    <p><xsl:text>Born = </xsl:text><xsl:value-of select="@born"/></p>
    <p><xsl:text>Died = </xsl:text><xsl:value-of select="@died"/></p>
   </body>
</html>
</xsl:template>
</xsl:stylesheet>Otherwise, you could use any XSLT processor to perform the transformation.

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