XML value being turned into math formula.

I am not using E4X, but here is the scenario:
Okay, so I am bringing in a string with a value of 33E-30 for
Train Id. Java is returning the following XML to my flex component:
<train>
<trainId>33E-30</trainId>
<cars>60</cars>
<length>3751</length>
<weight>2712</weight>
<callTime>null</callTime>
<comments>null</comments>
<eta>2007-10-30 05:00:00.0</eta>
<fromRoad>NS</fromRoad>
<toRoad>UP</toRoad>
<interchange>Elkhart (testing)</interchange>
<locationName>Elkhart (testing)</locationName>
<trainType>R5</trainType>
<latitude>41</latitude>
<longitude>-86</longitude>
<splc>362120</splc>
</train>
I then take the value and put it in a Value Object typed as a
String. Flex then displays the following:
3.2999999999999997e-29
It looks like Flex is treating this as some mathematical
formula instead of as a string, even though it is typed as a
string. Any ideas on how to work around this? I am thinking that it
is happening when the xml is being read into the object.

I did some more research and the it looks like Flex is making
the change in the ResultEvent processing, or it is showing up as
3.299999... in the source attribute of the response object. Rather
odd.
Is there a way to turn of this attempt at scientific
notation?

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Convert data values in columns to another value based on a math formula

ISSUE:
I have a database of emergency incidents with descriptive data and longitude and
latitude. I would like to make a google map out of the information but unfortunately
the X Y coordinates are projected in Florida State Plane West in feet. Google maps
requires WGS84 longitude and latitude in decimal degrees.
PROBLEM:
I have written some code in Transact SQL that will convert the values. But I am at a loss as to how to do the following:
1.) plug in the X Y values from my database using an sql SELECT statement.
2.) apply the formula to convert from State Plane to WGS84 to these X Y values
3.) output the results.
In other words, I have the data and I have the formula, but I am not figuring out how to plug the data into the formula and output the results. I am missing how to tie it all together.
CODE:
DECLARE @Easting DECIMAL(18,10);
--SET @Easting = CAST(I_MapX AS DECIMAL(18,10));
DECLARE @Northing DECIMAL(18,10);
--SET @Northing = CAST(I_MapY AS DECIMAL(18,10));
DECLARE @m2sft DECIMAL(10,10);
SET @m2sft = 1200.0/3937.0;
DECLARE @N0 DECIMAL(3,2);
SET @N0 = 0.0;
DECLARE @E0 DECIMAL(18,11);
SET @E0 = 656166.6666666665;
DECLARE @S0 DECIMAL(12,5);
SET @S0 = 2692050.5001/@m2sft;
DECLARE @K0 DECIMAL(18,18);
SET @K0 = 0.9999411764705882;
DECLARE @a DECIMAL(10,2);
SET @a = 6378137.0/@m2sft;
DECLARE @e DECIMAL(18,17);
SET @e = 0.0818191911198883;
DECLARE @ePrime DECIMAL(18,17);
SET @ePrime = 0.08208852110265381;
DECLARE @r DECIMAL(18,10);
SET @r = 6367449.14577/@m2sft;
DECLARE @V0 DECIMAL(15,12);
SET @V0 = 0.005022893948;
DECLARE @V2 DECIMAL(15,12);
SET @V2 = 0.000029370625;
DECLARE @V4 DECIMAL(15,12);
SET @V4 = 0.000000235059;
DECLARE @V6 DECIMAL(15,12);
SET @V6 = 0.000000002181;
DECLARE @L0 DECIMAL(4,2);
SET @L0 = 82.0;
DECLARE @w DECIMAL(18,10);
SET @w = (@Northing - @N0 + @S0)/(@k0*@r);
DECLARE @of DECIMAL(18,10);
SET @of = @w + (sin(@w)*cos(@w))*(@V0 + @V2*power(cos(@w),2) + @V4*power(cos(@w),4) + @V6*power(cos(@w),6));
DECLARE @Rf DECIMAL(18,10);
SET @Rf = @k0*@a/sqrt((1 - power(@e,2)*power(sin(@of),2)));
DECLARE @EPrime2 DECIMAL(18,10);
SET @EPrime2 = @Easting - @E0;
DECLARE @Q DECIMAL(18,10);
SET @Q = @EPrime2/@Rf;
DECLARE @tf DECIMAL(18,10);
SET @tf = tan(@of);
DECLARE @nf DECIMAL(18,10);
SET @nf = @ePrime*cos(@of);
DECLARE @B2 DECIMAL(18,10);
SET @B2 = -0.5 * @tf * (1 + POWER(@nf,2));
DECLARE @B4 DECIMAL(18,10);
SET @B4 = -1/12*(5 + 3 * POWER(@tf,2) +POWER(@nf,2) * (1-9 * POWER(@tf,2)) - 4 * POWER(@nf,4));
DECLARE @B6 DECIMAL(18,10);
SET @B6 = 1/360*(61 + 90*POWER(@tf,2) + 45*POWER(@tf,4) + POWER(@nf,2)*(46 - 252*POWER(@tf,2) - 90*POWER(@tf,4)));
DECLARE @Latitude DECIMAL(18,10);
SET @Latitude = (@of + @B2*POWER(@Q,2)*(1 + POWER(@Q,2)*(@B4 + @B6*POWER(@Q,2))))*180/(PI());
DECLARE @B3 DECIMAL(18,10);
SET @B3 = -1/6*(1 + 2*POWER(@tf,2) + POWER(@nf,2));
DECLARE @B5 DECIMAL(18,10);
SET @B5 = 1/120*(5 + 28*POWER(@tf,2) + 24*POWER(@tf,4) + POWER(@nf,2)*(6 + 8*POWER(@tf,2)));
DECLARE @B7 DECIMAL(18,10);
SET @B7 = -1/5040*(61 + 662*POWER(@tf,2) + 1320*POWER(@tf,4) + 720*POWER(@tf,6));
DECLARE @L DECIMAL(18,10);
SET @L = @Q*(1 + POWER(@Q,2)*(@B3 + POWER(@Q,2)*(@B5 + @B7*POWER(@Q,2))));
DECLARE @Longitude DECIMAL(18,10);
SET @Longitude = (@L0 - (@L/cos(@of))*180/(PI()))*-1;
SELECT
I_EventNumber
FROM Incident
WHERE I_tTimeDispatch > 'May 7, 2012'
SAMPLE DATA:
Here is some raw data in order to get you started. Please notice the MapX and MapY
coordinates are VARCHAR because they are Florida State Plane projections. The goal is
to take these and turn them into WGS84 longitude and latitude expressed as decimal
degrees to be used in Google maps. NOTE: I can convert from VARCHAR to DECIMAL. I just can't figure out where to plug my database columns into the sql query to output a result.
CREATE TABLE Incidents
I_EventNumber VARCHAR(20)
I_MapY VARCHAR(15)
I_MapX VARCHAR(15)
INSERT INTO Incident
VALUES
(FCW69, 0815312, 0672298)
, (FCW70, 0833311, 0697870)
, (FCW71, 0807747, 0699684)
, (FCW72, 0801252, 0689469)
, (FCW73, 0853491, 0692350)

Here's a way to get the results, all as part of a single extensive query (this would probably be more suited for defining a VIEW, where you could join on the input table with the VIEW to incorporate the computed values.
If you instead had a business situation where you might need to execute this logic from many different places, rewriting as a user defined function might be better. Anyway, for the answer plus a demonstration of the power of CROSS APPLY to generate
interim working values...
Create_Sample_Data:
Declare @Incident TABLE
I_EventNumber VARCHAR(20), I_MapY VARCHAR(15), I_MapX VARCHAR(15)
INSERT INTO @Incident
VALUES
('FCW69', '0815312', '0672298')
, ('FCW70', '0833311', '0697870')
, ('FCW71', '0807747', '0699684')
, ('FCW72', '0801252', '0689469')
, ('FCW73', '0853491', '0692350') /* This insert is SQL 2008 syntax only.. do multiple inserts or a UNION for 2005 */
AsQuery:
Select *
from @INCIDENT
Cross Apply
Select
N0 = 0.0,
E0 = 656166.6666666665,
K0 = 0.9999411764705882,
e = 0.0818191911198883,
ePrime = 0.08208852110265381,
V0 = 0.005022893948,
V2 = 0.000029370625,
V4 = 0.000000235059,
V6 = 0.000000002181,
L0 = 82.0,
Easting = CAST(I_MapX AS DECIMAL(18,10)),
Northing = CAST(I_MapY AS DECIMAL(18,10))
) as CAStatic
Cross Apply
Select m2sft = 1200.0/3937.0,
EPrime2 = Easting - E0
) as CAComputed1
Cross Apply
Select S0 = 2692050.5001/m2sft,
r = 6367449.14577/m2sft,
a = 6378137.0/m2sft
) as CAComputed2
Cross Apply
Select
w = (Northing - N0 + S0)/(k0*r)
) as CAComputed4
Cross Apply
Select
[of] = w + (sin(w)*cos(w))*(V0 + V2*power(cos(w),2) + V4*power(cos(w),4) + V6*power(cos(w),6))
) as CAComputed5
Cross Apply
Select
Rf = k0*a/sqrt((1 - power(e,2)*power(sin([of]),2))),
tf = tan([of]),
nf = ePrime*cos([of])
) as CAComputed6
Cross Apply
Select
Q = EPrime2/Rf,
B2 = -0.5 * tf * (1 + POWER(nf,2)),
B4 = -1/12*(5 + 3 * POWER(tf,2) +POWER(nf,2) * (1-9 * POWER(tf,2)) - 4 * POWER(nf,4)),
B6 = 1/360*(61 + 90*POWER(tf,2) + 45*POWER(tf,4) + POWER(nf,2)*(46 - 252*POWER(tf,2) - 90*POWER(tf,4)))
) as CAComputed7
Cross Apply
Select
Latitude = ([of] + B2*POWER(Q,2)*(1 + POWER(Q,2)*(B4 + B6*POWER(Q,2))))*180/(PI()),
B3 = -1/6*(1 + 2*POWER(tf,2) + POWER(nf,2)),
B5 = 1/120*(5 + 28*POWER(tf,2) + 24*POWER(tf,4) + POWER(nf,2)*(6 + 8*POWER(tf,2))),
B7 = -1/5040*(61 + 662*POWER(tf,2) + 1320*POWER(tf,4) + 720*POWER(tf,6))
) as CAComputed8
Cross Apply
Select
L = Q*(1 + POWER(Q,2)*(B3 + POWER(Q,2)*(B5 + B7*POWER(Q,2))))
) as CAComputed9
Cross Apply
Select
Longitude = (L0 - (L/cos([of]))*180/(PI()))*-1
) as CAComputedLatLong
Notice that each subsequent CROSS APPLY depends on a "working value" column being defined in some previous cross apply, or the working query. There are a few other options, such as leaving off the very last Cross Apply, and computing Longitude as part
of the main query at the beginning, but it works either way.
EDIT: P.S. - By the way, this query is based on the formula in the original poster's query. My formula matches that formula, and I bet it's right (as far as the lat/long conversion), but it could be the formula for Soylent Green, and I wouldn't know any
better... :-)

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I'm just starting out with xslt, and I am have a small problem with unused data being added into the html output from an xsl transformation. The data set is very small and the transdorm is not complicated, but when I do a
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I have include the xml, the transform and the html source recieved at the end of this mail.
Any help would be appreciated.
Cheers
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</project>
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<xsl:stylesheet version="1.0"
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</body>
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</xsl:template>
</xsl:stylesheet>
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<html>
<head>
<title>Greeting</title>
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I want to evaluate a math formula inside of a function, so I can't use dynamic SQL.
I found that the query on an XML-variable with a literal works well.
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Erland Sommarskog, SQL Server MVP, [email protected]

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satyaki>
satyaki>ed
Wrote file afiedt.buf
1 declare
2       cursor c1
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4         select *
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6       r1 c1%rowtype;
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9       loop
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12*   end;
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7934 - MILLER
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