XML version attribute

Question

I am writing java through lotus notes. In it I go out and hit a web service and return the xml data. Once in the xml I use a transformer but I get the following error:
javax.xml.transform.TransformerException: stylesheet requires attribute: version
The code that I have does work when I use my xml as a file instead of in from the web service. I can not find anything that makes tis work. Before I had written this in lotusscript and used the ls2j connector and it worked fine (until the JVM would blow up) so we are dropping the connector and writing it all in java. Here is my code to work with the transformer....
import java.io.StringReader;
import java.io.StringWriter;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;
import org.apache.xalan.processor.*;
import javax.xml.parsers.*;
import javax.xml.transform.dom.*;
import org.w3c.dom.*;
* This class allows you to apply an XSL style sheet against an XML string from within the Lotus Notes environment, without having to place an XSL file on the file system or use a Java Agent.
* Xalan-Java 2.5.0 is required.  It can be downloaded from http://xml.apache.org/xalan-j/ .
* The JavaUserClasses variable in the Lotus Notes notes.ini file must reflect the jar files from Xalan.
public class clsNotesXSLTNTS extends Object
    private String strXml;
    private String strXsl;
    private String strXslUrl;
      * Empty Constructor.
      * @see java.lang.Object#Object()
    public clsNotesXSLTNTS     ()
         super();
      * This method will return the resultant transformation.
      * A url is the default source for the xsl file which is set using setXslUrl().  If it is not found a String input is assumed which is set using setXsl().
      * If a xsl url or a xsl String is not provided, null will be returned.
      * @return String
    public String process() {
        try
               StringReader srXSL;
               StringReader srXML = new StringReader(strXml);
               StringWriter sw = new StringWriter();
                  StreamSource ssXSL;
             TransformerFactory factory = null;
            Transformer transformer = null;
             // determine the source xsl type
             if (this.strXslUrl != null) {
                  ssXSL = new StreamSource(this.strXslUrl);
             else if (this.strXsl != null) {
                  srXSL = new StringReader(strXsl);
                  ssXSL = new StreamSource(srXSL);
             else {
                  return null;
                  // set the sax driver
//                  System.setProperty("org.xml.sax.driver", "org.apache.xerces.parsers.SAXParser");
             try {
                  // create a new factory
          transformer = factory.newTransformer(ssXSL);
             catch(Exception e) {
                  System.out.println("Unable to create Transformer Factory: " + e.getMessage());
             try {           
                 // create a new transformer
                    transformer = factory.newTransformer(ssXSL);
             catch(Exception e) {
                  System.out.println("Unable to create Transformer:" + e.getMessage());
            // get the source xml
            StreamSource xmlsource = new StreamSource(srXML);
            // create a stream for the result of the transformation
            StreamResult output = new StreamResult(sw);
            // transform the input xml using the input xsl
            transformer.transform(xmlsource, output);
               // return the resultant transformation
               return sw.toString();
//          return strXml;
        catch(Exception e)
             e.printStackTrace();
//             System.out.println(strXml);
            return null;
      * Gets the XML string that is to be transformed.
      * @return String
    public String getXml() {
        return strXml;
      * Sets the XML string that is to be transformed.
      * @param pstrXml The XML string.
    public void setXml(String pstrXml) {
        this.strXml = pstrXml;
      * Gets the XSL string that is used to transform the XML string.
      * @return String
     public String getXsl() {
          return strXsl;
      * Sets the XSL string that is used to transform the XML string.
      * @param pstrXsl The XSL string.
     public void setXsl(String pstrXsl) {
          this.strXsl = pstrXsl;
      * Gets the URL of the XSL file that is used to transform the XML string.
      * @return String
     public String getXslUrl() {
          return strXslUrl;
      * Sets the URL of hte XSL file that is used to transform the XML string.
      * @param pstrXslUrl The URL of the XSL file.
     public void setXslUrl(String strXslUrl) {
          this.strXslUrl = strXslUrl;
}to set the XML I use the following code:
          clsNotesXSLTNTS  JXSLT;
          JXSLT = new clsNotesXSLTNTS();
          JXSLT.setXslUrl(strXSLPath);
          JXSLT.setXml(XMLData);
          XMLData = JXSLT.process();where the XMLData is returned from the web services, here is an example file that I printed out to the browser and saved. If I use this file it works, but if I do not put it out to the file system then it does not work.
<?xml version="1.0" encoding="utf-8"?><soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body>
<getInfoByPartialNameSpmpy004Response xmlns="http://tempuri.org/"><getInfoByPartialNameSpmpy004Result>
<params xmlns="http://tempuri.org/"><baseTarget>MainFrame</baseTarget><onLoadFunction>PostLoad()</onLoadFunction><formName>InquirySelection</formName><filePath>C:/notes/data/aptestCOPY.nsf</filePath><isUser>1</isUser><isNewForm>0</isNewForm><searchVendors>1</searchVendors><vendorSearchString>SHER</vendorSearchString><printVendorSelection>1</printVendorSelection><tableBGColor>#FFFEAD</tableBGColor><THClass>normal</THClass><TDClass>normal</TDClass></params><anyType xsi:type="clsVendorInfo"><blnFound>true</blnFound><strNumber>4603232                                                     </strNumber><strName>HOTEL Name       </strName><strAddr1>18TH AT Smoothie ST                       </strAddr1><strAddr2>                                        </strAddr2><strCity>Somewhere             </strCity><strState>PA </strState></anyType></getInfoByPartialNameSpmpy004Result></getInfoByPartialNameSpmpy004Response></soap:Body></soap:Envelope>This file was generated by calling the web service with the program and then printing it out to the browser and cut and paste. Anyone with any thoughts ????
Thanks in advance

Answer 1

I left off the first part of my XSL...
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:ap="http://tempuri.org/" version = "1.0">
     <xsl:strip-space elements="*" />
     <xsl:output method="html" encoding="utf-8"/>