Xml webservices configuration problem

WHILE EXECUTING
set long 500
set pagesize 100
XQUERY declare default element namespace "http://xmlns.oracle.com/xdb/xdbconfig.xsd";
for $doc in fn:doc("/xdbconfig.xml")/xdbconfig/sysconfig/protocolconfig/httpconfig/webappconfig/servletconfig/servlet-list/servlet[servlet-name='orawsv']
return $doc
I GOT AN ERROR
Error starting at line 3 in command:
select column_value from xmltable(' declare default element namespace "http://xmlns.oracle.com/xdb/xdbconfig.xsd";
for $doc in fn:doc("/xdbconfig.xml")/xdbconfig/sysconfig/protocolconfig/httpconfig/webappconfig/servletconfig/servlet-list/servlet[servlet-name='orawsv']
return $doc')
Error at Command Line:4 Column:146
Error report:
SQL Error: ORA-02000: missing COLUMNS keyword
02000. 00000 -  "missing %s keyword"
Please help ,i needed to xml db configuration

showed me this..
Oops! Google Chrome could not connect to 127.0.0.1:8080
when i ran the code
connect / AS sysdba
SELECT dbms_xdb.gethttpport FROM dual;
EXEC dbms_xdb.sethttpport(8080);
ALTER system SET dispatchers='(PROTOCOL=TCP)(SERVICE=$ORACLE_SIDXDB)' comment='Dispatcher enabled for XMLDB Protocol Server' scope = BOTH;
ALTER system SET shared_servers=5 scope=BOTH;
ALTER system register;
grant dba, xdbadmin to test;
alter user test identified by test account unlock;
set echo off
set termout on
set feed off
show user
--Enable the orawsv entry points in xdbconfig.xml
DECLARE
  SERVLET_NAME VARCHAR2(32) := 'orawsv';
BEGIN
DBMS_XDB.deleteServletMapping(SERVLET_NAME);
DBMS_XDB.deleteServlet(SERVLET_NAME);
DBMS_XDB.addServlet(NAME => SERVLET_NAME,
LANGUAGE => 'C',
DISPNAME => 'Oracle Query Web Service',
DESCRIPT => 'Servlet for issuing queries as a Web
Service',
SCHEMA => 'XDB');
DBMS_XDB.addServletSecRole(SERVNAME => SERVLET_NAME,
ROLENAME => 'XDB_WEBSERVICES',
ROLELINK => 'XDB_WEBSERVICES');
DBMS_XDB.addServletMapping(PATTERN => '/orawsv/*',NAME => SERVLET_NAME);
END;
commit;
-- User Name declare USERNAME=SCOTT -- User Password  declare PASSWORD=tiger
-- DBMS_NETWORK_ACL_ADMIN to Validate Grant Permission
begin
dbms_network_acl_admin.drop_acl('/localhost.xml');
  end;
  begin
dbms_network_acl_admin.create_acl('/localhost.xml', 'ACL for 127.0.0.1',
'&USERNAME', true, 'connect');
dbms_network_acl_admin.assign_acl('/localhost.xml', '127.0.0.1'); end;
and typed in url
as
127.0.01:8080/orawsv?wsdl

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    import org.w3c.dom.*;
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    catch (Exception e)
    sw.write("NonParserException: " + e.getMessage());
    return sw.toString();
    This is the code i used initially for validating a xml file against single xml schema (.xsd) file
    In the above code could u tell how to specify the second schema validation code for the incoming xml.
    say i create another Schemadoc for the 2nd xml schema.
    something like this with another parameter(CHAR xsd1) passing to the method
    byte [] docbytes1 = xsd1.getBytes();
    ByteArrayInputStream in1 = new ByteArrayInputStream(docbytes1);
    XMLSchema schemadoc1 = (XMLSchema)builder.build(in1,null);
    DOMParser dp = new DOMParser();
    How to set for the 2nd xml schema validation in the above code or can i combine 2 xml schemas.
    How to go about it
    Rgrds
    Sushant

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