XPath Node Regular Expression

Question

Hi,
Does xpath have a way of getting me all the child nodes with look like 'LEAF%'
where '%' is my wildcard character.
Eg:
SELECT EXTRACT
(XMLTYPE
('<ROOT><LEAF1>01</LEAF1>02<LEAF2></LEAF2><BRANCH>03</BRANCH></ROOT>'),
'/ROOT/*'
FROM DUAL;
I want to extract 'LEAF1' and 'LEAF2' from the xmltype. Is this possible?

Answer 1

Here's the best I can come up with
SQL> select value(NODE)
  2    from table(xmlsequence(extract( xmltype('<ROOT><LEAF1>01</LEAF1>02<LEAF2></LEAF2><BRANCH>03</BRANCH></ROOT>') , '//node()'))) NODE
  3  /
VALUE(NODE)
<ROOT>
  <LEAF1>01</LEAF1>02
  <LEAF2/>
  <BRANCH>03</BRANCH>
</ROOT>
<LEAF1>01</LEAF1>
<LEAF2/>
<BRANCH>03</BRANCH>
SQL> select value(NODE).getRootElement()
  2    from table(xmlsequence(extract( xmltype('<ROOT><LEAF1>01</LEAF1>02<LEAF2></LEAF2><BRANCH>03</BRANCH></ROOT>') , '//node()'))) NODE
  3  /
VALUE(NODE).GETROOTELEMENT()
ROOT
LEAF1
LEAF2
BRANCH
SQL> select value(NODE)
  2    from table(xmlsequence(extract( xmltype('<ROOT><LEAF1>01</LEAF1>02<LEAF2></LEAF2><BRANCH>03</BRANCH></ROOT>') , '//node()'))) NODE
  3   where value(NODE).getRootElement() like 'LEAF%'
  4  /
VALUE(NODE)
<LEAF1>01</LEAF1>
<LEAF2/>
SQL>Waiting to see if Development has a better solution