XSQL: how to specific contentType to return?

Question

Hi
I am trying to replace my JSP code with XSL/XSQL. I want to specify the content type in XSL like I did in the following working JSP.
<?xml version="1.0" encoding="UTF-8"?>
<%@ page contentType="application/output-format;charset=UTF-8" %>
I have tried the following XSL, but it fails
<xsl:stylesheet version = '1.0'
xmlns:xsl='http://www.w3.org/1999/XSL/Transform'>
<xsl:output method="application/output-format" encoding="UTF-8"/>
</xsl:stylesheet>
I know the JSP works because it prompts me to save it when the jsp file is accessed using a browser (Correct), but when the above is accessed via an XSQL file, I see plain text in the browser instead.
Any help is appreciated.
Regards
Michael.

Answer 1

Hi,
a JTable asks the datamodel of the table for the class of a column by the method
(copy out of the documentation)
public Class getColumnClass(int columnIndex)
Returns the most specific superclass for all the cell values in the column. This is used by the JTable to set up a default renderer and editor for the column.
Parameters: columnIndex - the index of the column
Returns: the common ancestor class of the object values in the model.
(end of copy)
that is a method of the TableModel-interface the datamodel of the JTable implements. The AbstractTableModel class has certain default cellrenderers and celleditors for the "basic" types and uses the string-representation of an object (i.e. it's toString()-method) to render it, if it is not a "basic" type. If you want such classes to be rendered and edited in another way, you have to provide own cellrenderers and celleditors for them.
Hope, that helps a little bit
greetings Marsian