Deleting Duplicate Rows in a list

Hey folks, I've scowered around a bit for the answer to this and can't for the life of my figure it out.
I've got a list of ~2,000-3,000 words in the following format:
Fact
Fiction
Funny
Funny
Funny
Funky
etc etc. I am looking to make numbers delete all the duplicate rows such that the above list would become:
Fact
Fiction
Funny
Funky
All of these words are in column A on a separate sheet in a numbers document I'm using to run an experiment. Is there a built in command or something that would do this? (I'm a COMPLETE beginner at using Numbers as a heads up)
Any help with this would be GREATLY appreciated.

Teaghue wrote:
Never mind! I found an old old post explaining that this can't be done in numbers, so I just did it in excel.
Perfectly wrong !
The way to achieve the described goal was described several times in this forum.
*_You just didn't search carefully !_*
Searching for delet AND duplicate return several threads.
Here are two of them.
I didn't made a typo. I used delet so that it retrieve delete as well as deleting
http://discussions.apple.com/thread.jspa?messageID=12992492
http://discussions.apple.com/thread.jspa?messageID=11559125
Yvan KOENIG (VALLAURIS, France) mercredi 2 mars 2011 17:59:40

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How to delete particular row in ALV list display

Hi All,
My requirement is :
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2 deselect all
3 delete.
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type-pools : slis.
tables : zuser_secobjects.
data : t_header1 like zuser_secobjects.
data : begin of it_secobjects occurs 0.
 include structure t_header1.
*data : box,
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data : checkbox type c,
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p_ptype type zuser_secobjects-partner_type default '02',
p_upostn type zuser_secobjects-user_position,
p_sdate like likp-erdat default sy-datum,
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p_cted type zuser_secobjects-created_by,
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case object.
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thanks,
maheedhar.t

HI
In my program checkbox(before the record is displayed)
I used following lines to display checkbox .
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i_field-ddictxt = 'S'.
i_field-seltext_s = '@11@'.
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How to delete duplicate row in certain case

Hi all,
I need you help to delete my duplicate row.
Sample Data in table (table1)
 
Timein
DateIn
locationin useridin
status
08:20:00 01/09/2007
0001
U01
1
08:10:30 01/09/2007
0004
U01
1
07:20:00 01/09/2007
0006
U01
1
08:14:00 01/09/2007
0001
U02
1
06:10:30 01/09/2007
0004
U02
1
08:10:10 01/09/2007
0006
U02
1
 
I need to delete the row in table1 and leave the minimum timein in
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The last output in table1 is like below.
Timein
DateIn
locationin useridin
status
07:20:00 01/09/2007
0006
U01
1
06:10:30 01/09/2007
0004
U02
1
Can i used below sql to output the result;


delete
from
table1 t1 
where
t1.rowid
>


(
select
min(t2.rowID)
from
table1 t2

where
t1.Datein
= t2.Datein


and
t1.Status
=
t2.Status

and
t1.UserIdin
=
t2.UserIdin
order by t2.timein);
 
Thanks
in advanced

Hi Rob,
Just trying to chip in little bit!
Created Table As follows same as you, only two rows with duplicatem user, datein, and timein:
create table table1
as
select '08:20:00' timein, date '2007-09-01' datein, '0001' locationin, 'U01' useridin, 1 status from dual union all
select '08:10:30', date '2007-09-01', '0004', 'U01', 1 from dual union all
select '07:20:00', date '2007-09-01', '0006', 'U01', 1 from dual union all
select '08:14:00', date '2007-09-01', '0001', 'U02', 1 from dual union all
select '06:10:30', date '2007-09-01', '0004', 'U02', 1 from dual union all
select '06:10:30', date '2007-09-01', '0001', 'U02', 1 from dual
If I run your delete statement result row will be as follows:
SQL> select * from table1;
TIMEIN DATEIN LOCA USE STATUS
07:20:00 01-SEP-07 0006 U01 1
06:10:30 01-SEP-07 0004 U02 1
06:10:30 01-SEP-07 0001 U02 1
Here problem is that its not able to delete duplicate rows having same timein and timeout.
So I changed you query as follows:
DELETE FROM tab1
WHERE rowid NOT IN (
 SELECT MIN(rowid)
 FROM tab1
 WHERE (UseridIn, TO_DATE(TO_CHAR(DateIn,'YYYYMMDD') || TimeIn,'YYYYMMDDHH24:MI:SS')) IN
 ( SELECT UseridIn, MIN(TO_DATE(TO_CHAR(DateIn,'YYYYMMDD') || timein,'YYYYMMDDHH24:MI:SS'))
 FROM tab1
 GROUP BY UseridIn)
 GROUP BY UseridIn
If I run your delete statement with little bit of changes, the result row was as follows:
SQL> select * from table1;
TIMEIN DATEIN LOCA USE STATUS
07:20:00 01-SEP-07 0006 U01 1
06:10:30 01-SEP-07 0004 U02 1
Regards,
Raj

How to delete duplicate rows in oracle and retaining last duplicate rows

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user13310594 wrote:
Hi,
I'm having millions of records in the table .Some duplicate values/rows are inserted in it.
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The database we use is Oracle 8i.
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Check the other thread with same question deleting duplicate rows based on three columns in Oracle 8i

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Go to Solution.
Attachments:
array size.vi ‏10 KB

Hello,
THANK YOU for solving my first issue! Attached is the data set that contains the duplicate entries for the x-axis values. The y-axis value may be different, but not the x. I would like to delete the 2nd row that contains the same x-value.
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IN:
28.512000 -115.310532
28.812000 -86.937660
29.112000 -116.877052
29.412000 -87.223625
29.412000 -111.349045
30.012000 -86.510780
30.312000 -112.048187
OUT:
28.512000 -115.310532
28.812000 -86.937660
29.112000 -116.877052
29.412000 -87.223625
30.012000 -86.510780
30.312000 -112.048187
I am thinking of comparig the last x-axis value to the current one, and if it is the same, then not parse that row. The attached VI is as far as I got.
Any help will be greatly appreciated.
Thanks,
hiNi
Attachments:
delete duplicate row.vi ‏8 KB
data.txt ‏1 KB

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Please reply to this post...

Thanks, Nimish for your reply..._
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You could write your own routine. Use an Event Structure with a Key Down event. If the delete key was pressed and the table has focus delete the elements that are selected.
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Deleting Duplicate Rows in a list

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