Descending order for arrays by name

Question

Hi, thank you to all the people who previously helped me before....
Is there a way to sort an array in decending order by name?
I was trying to figure out what to do but this is what i have so far
double [] Salary = new double [10];
String [] Names = new String [10];
int i, j;
for ( i = 0; i < 10; i++)
System.out.print(" Name is: " + Names);
Names[i] = ReadInput.StringRead(); //asks user for Salry
System.out.println(" Salary is: " + Salary[i] );
Salary[i] = ReadInput.readDouble(); //asks user for Names
for (j=0; j < 10; j++)
System.out.println(Names[j] + ": " + Salary[j]);

Answer 1

Smckee6452, thank you for helping me.....
i think i am getting close, but the sorting part (descending by names)part of the code is not working too well
did i miss something??
public class Compare {
public Compare() {
double [] Salary = new double [10];
String [] Names = new String [10];
String nameTemp = new String();
double salaryTemp = 0.0;
for (int i = 0; i < 10; i++)
System.out.print(" Name is: " + Names);
Names[i] = ReadInput.StringRead(); //asks user for Salry
System.out.println(" Salary is: " + Salary[i] );
Salary[i] = ReadInput.readDouble(); //asks user for Names
// for (int j=0; j < 10; j++)
// System.out.println(Names[j] + ": " + Salary[j]);
for (int i = 0; i < 9; i++)
for ( int j = 1; j < 10; j++)
{    //do compare and swapping in here
nameTemp = Names[i];
Names[i] = Names[j];
Names[j] = nameTemp;
salaryTemp = Salary[i];
Salary[i] = Salary[j];
Salary[j] = salaryTemp;
System.out.print(nameTemp);
System.out.println(salaryTemp);